📕 Class 10th NCERT Batch: https: physicswallah.onelink.me/ZAZB/ekahp2aa 📕 Class 10th Master Plan Series : physicswallah.onelink.me/ZAZB/azn7fjr2 Padhai ko aur easy karne ke liye ye telegram group join karo 🤩 t.me/pwudaanclass10th
13:15- The distance between the two points can be measured using the Distance Formula which is given by: Distance Formula = √ [(x₂ - x₁)2 + (y₂ - y₁)2] Let the points be A(0, 0) and B(36, 15) Hence, x₁ = 0, y₁ = 0, x₂ = 36, y₂ = 15 We know that the distance between the two points is given by the Distance Formula, = √ [(x₂ - x₁)2 + (y₂ - y₁)2]....(1) = √ (36 - 0)2 + 15 - 0)2 = √ [(1296) + (225)] = √1521 = 39 Yes, it is possible to find the distance between the given towns A and B. The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between town A and B will be 39 km. 38:57 - ii) Let A (- 3, 5), B (3, 1), C (0, 3), and D (- 1, - 4) be the four points of the quadrilateral. We know that the distance between any two points is given by the distance formula = √(x₁ - x₂)² + (y₁ - y₂)² To find AB, that is, the distance between points A (- 3, 5) and B (3, 1) by using the distance formula, AB = √(3 + 3)² + (1 - 5)² = √(6)² + (- 4)² = √36 + 16 = √52 = 2√13 units To find BC, that is, distance between points B (3, 1) and C (0, 3) by using the distance formula, BC = √(0 - 3)² + (3 - 1)² = √ (-3)² + (2)² = √9 + 4 = √13 units To find CD, that is, distance between Points C (0, 3), and D (- 1, - 4) by using the distance formula, CD = √(- 1 - 0)² + (- 4 - 3)² = √ (- 1)² + (- 7)² = √1 + 49 = √50 = 5√2 units To find AD, that is, distance between Points A (- 3, 5) and D (- 1, - 4) using distance formula, AD = √(-1 + 3)² + (- 4 - 5)² = √ (2)² + (- 9)² = √4 + 81 = √85 units Since, AB ≠ BC ≠ CD ≠ AD, therefore, no special quadrilateral can be formed from the given vertices. iii) Let A (4, 5), B (7, 6), C (4, 3) and D (1, 2) be the four points of the quadrilateral. We know that the distance between any two points is given by the Distance Formula, Distance Formula = √ (x₁ - x₂)² + (y₁ - y₂)² To find AB, that is, distance between points A (4, 5) and B (7, 6), by using the distance formula, AB = √(7 - 4)² + (6 - 5)² = √3² + 1² = √9 + 1 = √10 units To find BC, that is, distance between points B (7, 6) and C (4, 3) by using the distance formula, BC = √ (4 - 7 )² + (3 - 6)² = √ (- 3)² + 3² = √9 + 9 = √18 units To find CD, that is, distance between points C (4, 3) and D (1, 2) by using the distance formula, CD = √(1 - 4)² + (2 - 3)² = √ (- 3)² + (- 1)² = √9 + 1 = √10 units To find AD i.e. Distance between points A (4, 5) and D (1, 2) using distance formula, AD = √( 1 - 4 )² + ( 2 - 5)² = √ (- 3)² + (- 3)² = √ 9 + 9 = √18 units To find AC, the distance between points A (4, 5) and C (4, 3), we have Diagonal AC = √( 4 - 4 )² + ( 3 - 5)² = √( 0 )² + ( - 2)² = 2 units To find BD, distance between points B (7, 6) and D (1, 2), we have Diagonal BD = √(1 - 7)² + (2 - 6)² = √ ( - 6 )² + ( - 4 )² = √ 36 + 16 = √52 units Since AB = CD and BC = AD, but the diagonals AC ≠ BD, thus the quadrilateral is a parallellogram. 1:21:32 - P, Q, R divides the line segment A (- 2, 2) and B (2, 8) into four equal parts. Point P divides the line segment AQ into two equal parts. Therefore, AP : PB is 1 : 3 Using section formula which is given by P (x, y) = [(mx₂ + nx₁) / m + n , (my₂ + ny₁) / m + n] Hence, coordinates of P = [(1 × 2 + 3 × (- 2)) / (3 + 1), (1 × 8 + 3 × 2) / (3 + 1)] = (- 1, 7/2) Point Q divides the line segment AB into two equal parts Using mid point formula, Q = [(2 + (- 2)) / 2, (2 + 8) / 2] = (0, 5) Point R divides the line segment BQ into two equal parts Coordinates of R = [(2 + 0) / 2, (8 + 5) / 2] = (1, 13/2) 1:58:24- A rhombus has all sides of equal length and opposite sides are parallel. Let A(3, 0), B(4, 5), C(- 1, 4) and D(- 2, - 1) be the vertices of a rhombus ABCD. Also, Area of a rhombus =1/2 × (product of its diagonals) Hence we will calculate the values of the diagonals AC and BD. We know that the distance between the two points is given by the distance formula, Distance formula = √( x₂ - x₁ )2 + (y₂ - y₁)2 Therefore, distance between A (3, 0) and C (- 1, 4) is given by Length of diagonal AC =√ [3 - (-1)]2 + [0 - 4]2 = √(16 + 16) = 4√2 The distance between B (4, 5) and D (- 2, - 1) is given by Length of diagonal BD = √[4 - (-2)]2 + [5 - (-1)]2 = √(36 + 36) = 6√2 Area of the rhombus ABCD = 1/2 × (Product of lengths of diagonals) = 1/2 × AC × BD Therefore, the area of the rhombus ABCD = 1/2 × 4√2 × 6√2 square units = 24 square units
00:01 Coordinate Geometry and NCERT back exercises discussed in the video 01:57 Coordinate geometry is a scoring chapter with easy concepts but requires careful calculations. 06:20 Understanding coordinate geometry concepts and distance formula 08:29 Summary of Coordinate Geometry concepts and formulas 13:02 Understanding the concept of collinear points 15:03 Coordinate Geometry and Collinearity 20:14 Explaining how to determine if three points are collinear or form an isosceles triangle 22:52 Using operations with coordinate geometry 27:30 Understanding the concept of a square in geometry 29:46 Understanding the concept of squares in coordinate geometry 33:58 Understanding and applying the distance formula 36:07 Understanding coordinate geometry concepts and calculations 40:18 Understanding coordinates and distance from x-axis 42:11 Understanding distance from x and y axis 46:56 Explaining the process of squaring and removing under roots 48:58 Finding a point with equal distance from two given points on the x-axis 53:22 Key points on solving equations in Coordinate Geometry 56:06 Summarizing coordinate geometry concepts for Class 10th Board 1:00:59 Solving equations using coordinate geometry 1:03:32 Understanding section formula for finding coordinates of a point 1:07:53 Section formula helps find coordinates of a point dividing a line segment 1:10:04 Finding coordinates of a point which divides a line segment 1:14:46 Introduction to Coordinate Geometry concepts. 1:16:45 Explaining how to find coordinates using formulas 1:21:19 Understanding the concept of mid point formula 1:23:21 Explaining the section formula and midpoint formula 1:27:57 Understanding and calculating coordinates of flags and distance formula 1:30:36 Understanding coordinates and midpoint in geometry 1:35:06 Understanding the division ratio of a line segment 1:37:19 Understanding the division of line segments on the x-axis 1:41:39 Understanding the concept of Taken in Order 1:43:54 Understanding of midpoints and diagonals in coordinate geometry 1:48:16 Finding the center and coordinates of a circle 1:50:31 Understanding the mid point formula and its application. 1:55:03 Understanding and finding coordinates using ratios 1:57:21 Formula for Area of Rhombus requires halving product of diagonals
I am feeling confident about my maths now..... growing up... I have only heard my mom and dad and everyone that I am not worth anything... I can't do anything in my life.... but now I can see the light of hope
AARE BHAI BOARDS HI SAB KUCH NHI HOTA HAI BHAI JAISA EX LO TUMSE KABHI KISI NA 9TH KA RESULT 8TH KA RESULT POCHA HAI OR POCHA BHI HOGA TO EK YA 2 BARR PHIRR SAB BHUL GYE N BOARD SIRF MANNAT KRNE SIKHATA HAI KI AAGE KUCH KAR PAO OR YE YAAD RKNA ... TUM HO ISS LIYA BOARD HAI BOARD HAI ISS LIYA TUM NHI ....
almost exactly same condition with my parents as well. I remember ive been hearing such words like my memory is weak, that i mug up everything and do not understand a single thing in my textbooks, from age 5 onwards. The effect of hearing things like that constantly, is that, even though i am in 10th now, i still have low self esteem, i am now shy to participate in a competion, i am under confident and cant make rapid decisions as i always end up doubting myselt due to my parents. Lets be strong for ourselves.
Love u sir. Aankhe dard ho gayi. 4 hours tak continuousely aapke saath solve karke chapter khatam kar diya. Finally SATISFIED. Abki bar 95 percent paar.
The distance between the two points can be measured using the Distance Formula which is given by: Distance Formula = √ [(x₂ - x₁)2 + (y₂ - y₁)2] Let the points be A(0, 0) and B(36, 15) Hence, x₁ = 0, y₁ = 0, x₂ = 36, y₂ = 15 We know that the distance between the two points is given by the Distance Formula, = √ [(x₂ - x₁)2 + (y₂ - y₁)2]....(1) = √ (36 - 0)2 + 15 - 0)2 = √ [(1296) + (225)] = √1521 = 39 Yes, it is possible to find the distance between the given towns A and B. The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between town A and B will be 39 km. 38:57 - ii) Let A (- 3, 5), B (3, 1), C (0, 3), and D (- 1, - 4) be the four points of the quadrilateral. We know that the distance between any two points is given by the distance formula = √(x₁ - x₂)² + (y₁ - y₂)² To find AB, that is, the distance between points A (- 3, 5) and B (3, 1) by using the distance formula, AB = √(3 + 3)² + (1 - 5)² = √(6)² + (- 4)² = √36 + 16 = √52 = 2√13 units To find BC, that is, distance between points B (3, 1) and C (0, 3) by using the distance formula, BC = √(0 - 3)² + (3 - 1)² = √ (-3)² + (2)² = √9 + 4 = √13 units To find CD, that is, distance between Points C (0, 3), and D (- 1, - 4) by using the distance formula, CD = √(- 1 - 0)² + (- 4 - 3)² = √ (- 1)² + (- 7)² = √1 + 49 = √50 = 5√2 units To find AD, that is, distance between Points A (- 3, 5) and D (- 1, - 4) using distance formula, AD = √(-1 + 3)² + (- 4 - 5)² = √ (2)² + (- 9)² = √4 + 81 = √85 units Since, AB ≠ BC ≠ CD ≠ AD, therefore, no special quadrilateral can be formed from the given vertices. iii) Let A (4, 5), B (7, 6), C (4, 3) and D (1, 2) be the four points of the quadrilateral. We know that the distance between any two points is given by the Distance Formula, Distance Formula = √ (x₁ - x₂)² + (y₁ - y₂)² To find AB, that is, distance between points A (4, 5) and B (7, 6), by using the distance formula, AB = √(7 - 4)² + (6 - 5)² = √3² + 1² = √9 + 1 = √10 units To find BC, that is, distance between points B (7, 6) and C (4, 3) by using the distance formula, BC = √ (4 - 7 )² + (3 - 6)² = √ (- 3)² + 3² = √9 + 9 = √18 units To find CD, that is, distance between points C (4, 3) and D (1, 2) by using the distance formula, CD = √(1 - 4)² + (2 - 3)² = √ (- 3)² + (- 1)² = √9 + 1 = √10 units To find AD i.e. Distance between points A (4, 5) and D (1, 2) using distance formula, AD = √( 1 - 4 )² + ( 2 - 5)² = √ (- 3)² + (- 3)² = √ 9 + 9 = √18 units To find AC, the distance between points A (4, 5) and C (4, 3), we have Diagonal AC = √( 4 - 4 )² + ( 3 - 5)² = √( 0 )² + ( - 2)² = 2 units To find BD, distance between points B (7, 6) and D (1, 2), we have Diagonal BD = √(1 - 7)² + (2 - 6)² = √ ( - 6 )² + ( - 4 )² = √ 36 + 16 = √52 units Since AB = CD and BC = AD, but the diagonals AC ≠ BD, thus the quadrilateral is a parallellogram. 1:21:32 - P, Q, R divides the line segment A (- 2, 2) and B (2, 8) into four equal parts. Point P divides the line segment AQ into two equal parts. Therefore, AP : PB is 1 : 3 Using section formula which is given by P (x, y) = [(mx₂ + nx₁) / m + n , (my₂ + ny₁) / m + n] Hence, coordinates of P = [(1 × 2 + 3 × (- 2)) / (3 + 1), (1 × 8 + 3 × 2) / (3 + 1)] = (- 1, 7/2) Point Q divides the line segment AB into two equal parts Using mid point formula, Q = [(2 + (- 2)) / 2, (2 + 8) / 2] = (0, 5) Point R divides the line segment BQ into two equal parts Coordinates of R = [(2 + 0) / 2, (8 + 5) / 2] = (1, 13/2) 1:58:24- A rhombus has all sides of equal length and opposite sides are parallel. Let A(3, 0), B(4, 5), C(- 1, 4) and D(- 2, - 1) be the vertices of a rhombus ABCD. Also, Area of a rhombus =1/2 × (product of its diagonals) Hence we will calculate the values of the diagonals AC and BD. We know that the distance between the two points is given by the distance formula, Distance formula = √( x₂ - x₁ )2 + (y₂ - y₁)2 Therefore, distance between A (3, 0) and C (- 1, 4) is given by Length of diagonal AC =√ [3 - (-1)]2 + [0 - 4]2 = √(16 + 16) = 4√2 The distance between B (4, 5) and D (- 2, - 1) is given by Length of diagonal BD = √[4 - (-2)]2 + [5 - (-1)]2 = √(36 + 36) = 6√2 Area of the rhombus ABCD = 1/2 × (Product of lengths of diagonals) = 1/2 × AC × BD Therefore, the area of the rhombus ABCD = 1/2 × 4√2 × 6√2 square units = 24 square units
Sir mera kl exam hai and now 1:01 AM This is the third chapter after areas related to circle and statistics. 😂😂 Whose exam is tomorrow and watching this
@@priyanshipiyush high weightage vale chapter padh and half yearly ke NCERT pura kr ke jao. Usse at least concept clear ho jayega. And try your best 💪 and don't worry agr nhi hua toh yeh half yearly hi h boards mai achha perform krna baki all the best 😊😀
On Saturday is exam but before 1 hrs I was very afraid thinking that this is Very tough chapter but after 1hrs video and solving in rough before sir explanation it's seems like very easy
📕 Class 10th NCERT Batch: https: physicswallah.onelink.me/ZAZB/ekahp2aa
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I know ap nhi dekhoge because team dekhe ge but u are my motivation ❤❤
Sir sample paper layo basic ka
Sir mai up board se hu phir bhi aap ka video dekhta hu kyo ki shamgh ata hai ❤
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Sir basic ka sample paper
Hello guys 98%above wale like ko nahi to pakka fail hoge 😂😂😂😂😂
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Vote for goal 99% like karo fail nahi hona hai to
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Jisne comment Kiya hai woh toh paka fail1000%
I would rather fail than like this
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😢 mareko
Standard or ye basic math kya hote h yarr bohot bar suna h
@@AnjaliPalawat standard maths or basic dono easy hai
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Me who is topper in 9th class👽
13:15-
The distance between the two points can be measured using the Distance Formula which is given by: Distance Formula = √ [(x₂ - x₁)2 + (y₂ - y₁)2]
Let the points be A(0, 0) and B(36, 15)
Hence, x₁ = 0, y₁ = 0, x₂ = 36, y₂ = 15
We know that the distance between the two points is given by the Distance Formula,
= √ [(x₂ - x₁)2 + (y₂ - y₁)2]....(1)
= √ (36 - 0)2 + 15 - 0)2
= √ [(1296) + (225)]
= √1521
= 39
Yes, it is possible to find the distance between the given towns A and B.
The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between town A and B will be 39 km.
38:57 -
ii) Let A (- 3, 5), B (3, 1), C (0, 3), and D (- 1, - 4) be the four points of the quadrilateral.
We know that the distance between any two points is given by the distance formula = √(x₁ - x₂)² + (y₁ - y₂)²
To find AB, that is, the distance between points A (- 3, 5) and B (3, 1) by using the distance formula,
AB = √(3 + 3)² + (1 - 5)²
= √(6)² + (- 4)²
= √36 + 16
= √52
= 2√13 units
To find BC, that is, distance between points B (3, 1) and C (0, 3) by using the distance formula,
BC = √(0 - 3)² + (3 - 1)²
= √ (-3)² + (2)²
= √9 + 4
= √13 units
To find CD, that is, distance between Points C (0, 3), and D (- 1, - 4) by using the distance formula,
CD = √(- 1 - 0)² + (- 4 - 3)²
= √ (- 1)² + (- 7)²
= √1 + 49
= √50
= 5√2 units
To find AD, that is, distance between Points A (- 3, 5) and D (- 1, - 4) using distance formula,
AD = √(-1 + 3)² + (- 4 - 5)²
= √ (2)² + (- 9)²
= √4 + 81
= √85 units
Since, AB ≠ BC ≠ CD ≠ AD, therefore, no special quadrilateral can be formed from the given vertices.
iii) Let A (4, 5), B (7, 6), C (4, 3) and D (1, 2) be the four points of the quadrilateral.
We know that the distance between any two points is given by the Distance Formula,
Distance Formula = √ (x₁ - x₂)² + (y₁ - y₂)²
To find AB, that is, distance between points A (4, 5) and B (7, 6), by using the distance formula,
AB = √(7 - 4)² + (6 - 5)²
= √3² + 1²
= √9 + 1
= √10 units
To find BC, that is, distance between points B (7, 6) and C (4, 3) by using the distance formula,
BC = √ (4 - 7 )² + (3 - 6)²
= √ (- 3)² + 3²
= √9 + 9
= √18 units
To find CD, that is, distance between points C (4, 3) and D (1, 2) by using the distance formula,
CD = √(1 - 4)² + (2 - 3)²
= √ (- 3)² + (- 1)²
= √9 + 1
= √10 units
To find AD i.e. Distance between points A (4, 5) and D (1, 2) using distance formula,
AD = √( 1 - 4 )² + ( 2 - 5)²
= √ (- 3)² + (- 3)²
= √ 9 + 9
= √18 units
To find AC, the distance between points A (4, 5) and C (4, 3), we have
Diagonal AC = √( 4 - 4 )² + ( 3 - 5)²
= √( 0 )² + ( - 2)²
= 2 units
To find BD, distance between points B (7, 6) and D (1, 2), we have
Diagonal BD = √(1 - 7)² + (2 - 6)²
= √ ( - 6 )² + ( - 4 )²
= √ 36 + 16
= √52 units
Since AB = CD and BC = AD, but the diagonals AC ≠ BD, thus the quadrilateral is a parallellogram.
1:21:32 -
P, Q, R divides the line segment A (- 2, 2) and B (2, 8) into four equal parts.
Point P divides the line segment AQ into two equal parts.
Therefore, AP : PB is 1 : 3
Using section formula which is given by P (x, y) = [(mx₂ + nx₁) / m + n , (my₂ + ny₁) / m + n]
Hence, coordinates of P = [(1 × 2 + 3 × (- 2)) / (3 + 1), (1 × 8 + 3 × 2) / (3 + 1)] = (- 1, 7/2)
Point Q divides the line segment AB into two equal parts
Using mid point formula,
Q = [(2 + (- 2)) / 2, (2 + 8) / 2] = (0, 5)
Point R divides the line segment BQ into two equal parts
Coordinates of R = [(2 + 0) / 2, (8 + 5) / 2] = (1, 13/2)
1:58:24-
A rhombus has all sides of equal length and opposite sides are parallel.
Let A(3, 0), B(4, 5), C(- 1, 4) and D(- 2, - 1) be the vertices of a rhombus ABCD.
Also, Area of a rhombus =1/2 × (product of its diagonals)
Hence we will calculate the values of the diagonals AC and BD.
We know that the distance between the two points is given by the distance formula,
Distance formula = √( x₂ - x₁ )2 + (y₂ - y₁)2
Therefore, distance between A (3, 0) and C (- 1, 4) is given by
Length of diagonal AC =√ [3 - (-1)]2 + [0 - 4]2
= √(16 + 16)
= 4√2
The distance between B (4, 5) and D (- 2, - 1) is given by
Length of diagonal BD = √[4 - (-2)]2 + [5 - (-1)]2
= √(36 + 36)
= 6√2
Area of the rhombus ABCD = 1/2 × (Product of lengths of diagonals) = 1/2 × AC × BD
Therefore, the area of the rhombus ABCD = 1/2 × 4√2 × 6√2 square units
= 24 square units
Itna shukriya ki bol bhi na para
Prr igni jarrurat bhi thi nhi vaise
Chat gpt ka kamaal
Last wala √36+36=6√2 kaise aaya
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Abe kseab solution se copy kar daley hai😂
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00:01 Coordinate Geometry and NCERT back exercises discussed in the video
01:57 Coordinate geometry is a scoring chapter with easy concepts but requires careful calculations.
06:20 Understanding coordinate geometry concepts and distance formula
08:29 Summary of Coordinate Geometry concepts and formulas
13:02 Understanding the concept of collinear points
15:03 Coordinate Geometry and Collinearity
20:14 Explaining how to determine if three points are collinear or form an isosceles triangle
22:52 Using operations with coordinate geometry
27:30 Understanding the concept of a square in geometry
29:46 Understanding the concept of squares in coordinate geometry
33:58 Understanding and applying the distance formula
36:07 Understanding coordinate geometry concepts and calculations
40:18 Understanding coordinates and distance from x-axis
42:11 Understanding distance from x and y axis
46:56 Explaining the process of squaring and removing under roots
48:58 Finding a point with equal distance from two given points on the x-axis
53:22 Key points on solving equations in Coordinate Geometry
56:06 Summarizing coordinate geometry concepts for Class 10th Board
1:00:59 Solving equations using coordinate geometry
1:03:32 Understanding section formula for finding coordinates of a point
1:07:53 Section formula helps find coordinates of a point dividing a line segment
1:10:04 Finding coordinates of a point which divides a line segment
1:14:46 Introduction to Coordinate Geometry concepts.
1:16:45 Explaining how to find coordinates using formulas
1:21:19 Understanding the concept of mid point formula
1:23:21 Explaining the section formula and midpoint formula
1:27:57 Understanding and calculating coordinates of flags and distance formula
1:30:36 Understanding coordinates and midpoint in geometry
1:35:06 Understanding the division ratio of a line segment
1:37:19 Understanding the division of line segments on the x-axis
1:41:39 Understanding the concept of Taken in Order
1:43:54 Understanding of midpoints and diagonals in coordinate geometry
1:48:16 Finding the center and coordinates of a circle
1:50:31 Understanding the mid point formula and its application.
1:55:03 Understanding and finding coordinates using ratios
1:57:21 Formula for Area of Rhombus requires halving product of diagonals
💀🙏🏼👍🏻
Parallelogram ❌lologram✅
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Report button 😂
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1:21:26
Point (p) coordinates
(-1,7/2)
Point Q coordinates
(0,5)
And point R coordinates
(1,13/2)
🎉🎉same
I am feeling confident about my maths now..... growing up... I have only heard my mom and dad and everyone that I am not worth anything... I can't do anything in my life.... but now I can see the light of hope
AARE BHAI BOARDS HI SAB KUCH NHI HOTA HAI BHAI JAISA EX LO TUMSE KABHI KISI NA 9TH KA RESULT 8TH KA RESULT POCHA HAI OR POCHA BHI HOGA TO EK YA 2 BARR PHIRR SAB BHUL GYE N BOARD SIRF MANNAT KRNE SIKHATA HAI KI AAGE KUCH KAR PAO
OR YE YAAD RKNA ...
TUM HO ISS LIYA BOARD HAI
BOARD HAI ISS LIYA TUM NHI ....
almost exactly same condition with my parents as well. I remember ive been hearing such words like my memory is weak, that i mug up everything and do not understand a single thing in my textbooks, from age 5 onwards. The effect of hearing things like that constantly, is that, even though i am in 10th now, i still have low self esteem, i am now shy to participate in a competion, i am under confident and cant make rapid decisions as i always end up doubting myselt due to my parents. Lets be strong for ourselves.
@@Maahiee we can only hope for our conditions to get better....
Bhiya results kaise aaye please tips dedo stream wagera bhi bata dena :)
😂😂waaah taliyan@@existingmaker
Kal exam hai aur aaj ye dekh rahe yaarrr🙂🥺
Kr bhi kya skte h 😂
Haa bhai mai ab dekh rha hu
Aaj Puri raat padhna padega syllabus complete krne ke liye brother meri fat chuki hai yrr
Ab kya kru kuch samjh nhi aa rha hai yrr
Toh kaisa hua exam kal to Mera last exam hai
J k Bose ka paper kal ha ❤😢😢
December 2024 me kon dekh rha 😂
Me😊
Mee
Me abhi syllabus start kiya hai
You are the best teacher in the world
Haaaaaa
X cordinate is perpendicular distance from y axis
Y cordinate is perpendicular distance from x axis
29:01 ve kmleyaa 😌😌😌🫠🫠🫠🫠🫠🫠🫠🫡🫡🫡🫡🫡☺️☺️☺️🙂
Yeah I'm searching for that.... 29:02
Besttttt teacher❤❤of maths
Love u sir. Aankhe dard ho gayi. 4 hours tak continuousely aapke saath solve karke chapter khatam kar diya. Finally SATISFIED. Abki bar 95 percent paar.
Mai kya hee bolu eatna aacha koi padha hee nhi sakta ❤❤😊
Basic wale. Like kere 😮
Best of luck 🤞 for 11 March 2024
Same to you
U
Dont fear when pw is here gyzzzzz😊 i m waiting for boards 😌😌
The distance between the two points can be measured using the Distance Formula which is given by: Distance Formula = √ [(x₂ - x₁)2 + (y₂ - y₁)2]
Let the points be A(0, 0) and B(36, 15)
Hence, x₁ = 0, y₁ = 0, x₂ = 36, y₂ = 15
We know that the distance between the two points is given by the Distance Formula,
= √ [(x₂ - x₁)2 + (y₂ - y₁)2]....(1)
= √ (36 - 0)2 + 15 - 0)2
= √ [(1296) + (225)]
= √1521
= 39
Yes, it is possible to find the distance between the given towns A and B.
The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between town A and B will be 39 km.
38:57 -
ii) Let A (- 3, 5), B (3, 1), C (0, 3), and D (- 1, - 4) be the four points of the quadrilateral.
We know that the distance between any two points is given by the distance formula = √(x₁ - x₂)² + (y₁ - y₂)²
To find AB, that is, the distance between points A (- 3, 5) and B (3, 1) by using the distance formula,
AB = √(3 + 3)² + (1 - 5)²
= √(6)² + (- 4)²
= √36 + 16
= √52
= 2√13 units
To find BC, that is, distance between points B (3, 1) and C (0, 3) by using the distance formula,
BC = √(0 - 3)² + (3 - 1)²
= √ (-3)² + (2)²
= √9 + 4
= √13 units
To find CD, that is, distance between Points C (0, 3), and D (- 1, - 4) by using the distance formula,
CD = √(- 1 - 0)² + (- 4 - 3)²
= √ (- 1)² + (- 7)²
= √1 + 49
= √50
= 5√2 units
To find AD, that is, distance between Points A (- 3, 5) and D (- 1, - 4) using distance formula,
AD = √(-1 + 3)² + (- 4 - 5)²
= √ (2)² + (- 9)²
= √4 + 81
= √85 units
Since, AB ≠ BC ≠ CD ≠ AD, therefore, no special quadrilateral can be formed from the given vertices.
iii) Let A (4, 5), B (7, 6), C (4, 3) and D (1, 2) be the four points of the quadrilateral.
We know that the distance between any two points is given by the Distance Formula,
Distance Formula = √ (x₁ - x₂)² + (y₁ - y₂)²
To find AB, that is, distance between points A (4, 5) and B (7, 6), by using the distance formula,
AB = √(7 - 4)² + (6 - 5)²
= √3² + 1²
= √9 + 1
= √10 units
To find BC, that is, distance between points B (7, 6) and C (4, 3) by using the distance formula,
BC = √ (4 - 7 )² + (3 - 6)²
= √ (- 3)² + 3²
= √9 + 9
= √18 units
To find CD, that is, distance between points C (4, 3) and D (1, 2) by using the distance formula,
CD = √(1 - 4)² + (2 - 3)²
= √ (- 3)² + (- 1)²
= √9 + 1
= √10 units
To find AD i.e. Distance between points A (4, 5) and D (1, 2) using distance formula,
AD = √( 1 - 4 )² + ( 2 - 5)²
= √ (- 3)² + (- 3)²
= √ 9 + 9
= √18 units
To find AC, the distance between points A (4, 5) and C (4, 3), we have
Diagonal AC = √( 4 - 4 )² + ( 3 - 5)²
= √( 0 )² + ( - 2)²
= 2 units
To find BD, distance between points B (7, 6) and D (1, 2), we have
Diagonal BD = √(1 - 7)² + (2 - 6)²
= √ ( - 6 )² + ( - 4 )²
= √ 36 + 16
= √52 units
Since AB = CD and BC = AD, but the diagonals AC ≠ BD, thus the quadrilateral is a parallellogram.
1:21:32 -
P, Q, R divides the line segment A (- 2, 2) and B (2, 8) into four equal parts.
Point P divides the line segment AQ into two equal parts.
Therefore, AP : PB is 1 : 3
Using section formula which is given by P (x, y) = [(mx₂ + nx₁) / m + n , (my₂ + ny₁) / m + n]
Hence, coordinates of P = [(1 × 2 + 3 × (- 2)) / (3 + 1), (1 × 8 + 3 × 2) / (3 + 1)] = (- 1, 7/2)
Point Q divides the line segment AB into two equal parts
Using mid point formula,
Q = [(2 + (- 2)) / 2, (2 + 8) / 2] = (0, 5)
Point R divides the line segment BQ into two equal parts
Coordinates of R = [(2 + 0) / 2, (8 + 5) / 2] = (1, 13/2)
1:58:24-
A rhombus has all sides of equal length and opposite sides are parallel.
Let A(3, 0), B(4, 5), C(- 1, 4) and D(- 2, - 1) be the vertices of a rhombus ABCD.
Also, Area of a rhombus =1/2 × (product of its diagonals)
Hence we will calculate the values of the diagonals AC and BD.
We know that the distance between the two points is given by the distance formula,
Distance formula = √( x₂ - x₁ )2 + (y₂ - y₁)2
Therefore, distance between A (3, 0) and C (- 1, 4) is given by
Length of diagonal AC =√ [3 - (-1)]2 + [0 - 4]2
= √(16 + 16)
= 4√2
The distance between B (4, 5) and D (- 2, - 1) is given by
Length of diagonal BD = √[4 - (-2)]2 + [5 - (-1)]2
= √(36 + 36)
= 6√2
Area of the rhombus ABCD = 1/2 × (Product of lengths of diagonals) = 1/2 × AC × BD
Therefore, the area of the rhombus ABCD = 1/2 × 4√2 × 6√2 square units
= 24 square units
bhai
Anyone come this video in October 😅😅 like nahi kiya toh fail ho gayoege
Kl maths ka paper hai 😗
Haa apka standard hai ya basic
Meera basic@@Angelina-ik3vc
Kal Mera bhi math ka h rbse
Bfkndldncia'smcn ok z'jfbbzse Hindi full idiot Singh idk odik😅😊😂Odin 🎉😅😂
Rbsc bhi hota h 😂@@AnjaliPalawat
Like kro nhi to fail ho jaoge
Mc
Bkl
Bkl
😂😂
Fail hona manjoor hai pr like krna nhi
Ritik sir always rock❤
1:08:43 😂😂best sir bestt😂😂😂😂
Kis kis ko ab dar lag raha hai😢
Mujhe 🥲
Mujhe 😢
100 aa rha hai
Bhai mujhe 😢😢😢
Bilkul nhi lag raha kahi mai Boardphilic to nhi 😅
Good explanation sir Amazing❤
Anyone from October?😂
Yup
Yes brother 😂
@theKalYugBoy1 yup
Me 😂
Haa vo bhi last month
Sir next level understanding sir apki vjh se hi kl preboards me marks ane wale h 🙏🏻🥲🫂
Anyone from 2024-2025
❤
Yup
Yes bro
Yes
Yes
Sir you are best teacher in the world❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Anyone September 😅
😅😂
Ha Bro 🤣 only a revision purpose
Yes😅
🗣
21 September par 23 ko math ka exam h half yearly
1:05:04 ek exercise ki samapati hote hue👀👈🏻
Bhai kya hua, section fornula hi toh hai??
Chameli ko sab log maro usne ek question badha diya bechari champa ki baat mana karke 😂😂
😂😂😂😂
Sir please April se new batch launch kardo jisme aap TH-cam par free main padhoa plz
29:01 Ve kamleya...😂😅
Phir me a Gaya ❤
Thank u sir but solve all the problems not giving us homework 😅😅
Itna kaafi nhi hai kya ??
Sir mera kl exam hai and now 1:01 AM
This is the third chapter after areas related to circle and statistics. 😂😂
Whose exam is tomorrow and watching this
Mara kl exam hai smj nahi aa raha kesse padhe kaha se start kare
@@priyanshipiyush high weightage vale chapter padh and half yearly ke NCERT pura kr ke jao. Usse at least concept clear ho jayega. And try your best 💪 and don't worry agr nhi hua toh yeh half yearly hi h boards mai achha perform krna baki all the best 😊😀
Like the comment if Ritik sir is the best teachers
👇
X coordinate -Perpendicular distance from Y-axis
Y coordinate -Perpendicular distance from X-axis
Dhanyawad sir ji ❤
2024-25 students attendance here 🙋🏼♀️
Present miss
Present
@rajg3077 hiii
@@LalitaJunawa-v5e hello
Hiii
Thanks so much ❤❤
Admit card bhi aa chuka hai, padhai abhi tak suru bhi nahi kari hai 😢😢😢😢
Same bro
Mera nhi deya abhi
You are a great teacher 😊
I love you ritik sir ❤❤
Time to gear UP dosto⚡⚡
AAKHRI DIN MATHS KA😌♥️🥺
Same bhaii 😢
😂
46:19 sir ladkhada gye 0 - mtlbllllliuuuuuuuu 🤡🥲......jokes apart sir bohot acha padhate sb samjh aa gya sb....yeh Mai first video sir ki dekhri ❤
Waah sir❤
The answer of question 6th of part (ii) is No any quadrilateral and (iii) is Parallelogram.
Kis kis ke September me school ke exam he 😢
1:47:37 😅😅 ye lologram kyu bolte ho😅😅❤❤❤❤❤
Me watching this one day before pre board
Me watching 1hr before pre-boards
Sir aap bohot ke atcha padata ho 😊😊
Like for will be a topper 😂😂😂
1:21:38 the way babua said 'JANEMAN'😁
Yaar kuch nhi padha bohot dr lg rha 😢😢
hiiiiiiiiiiiiiii
To padho😢
*_Thankk youuu sooo much Sir_* 👍🏻✨
Day_Day_sir ji handsame hota jarha hai😊
Aaaaaaa haaaaaaa😂😂😂😂
Please for 99.999%ka liya nahi to faul hojo gaya sahi ma ji😅
Ex 8.3 Q-4 (x) Answer Done
1:51:24 A And 'b are gay 😂😂
Aree 😂😂
@@AnimeFanboy-m8thi bro
Hi
Respectively 😂😂
💀💀
Who like PW more than school Teachers ❤❤
Mujhe
I like my math teacher by pankaj sar❤❤
Question no 6
2nd one will not form quadrilateral
Reply karna plz
3rd one is a parallelogram
But why the 2nd is not a quadrilateral. May be it is a quadrilateral with unequal sides
39:13
2) quadrilateral
3) parallelogram 😊
Babua board exam ka dar lagna start hone laga hai😢.
😮
29:01🫠🫡☺️☺️🙂🫡🫠🫠🫠😌😌😌ve kamleyaaa
Ritik sir rocked others mathematics teacher socked 😂😂
Dhanyawaad batane ke liye aangrej ki aaulad 😂❤
Kya hoti hai spelling bta bi dete bhaiya
Ok thank you by the way pura sahi likha vo nhi dikha ek spelling mistake ho gayi vo dikhi matlab yeh hai ki log galat chijo ko jayada dekhte hai
B@adityabhadu8249 but thank you and all the best for your board exam 😍🥰
@@priyanshu_rwt 10th m aa gya hai... Itna toh aana chahiye
Thanks sir your video is very helpful for me ❤
1 like got in maths 75 plus
38:57 No quadrilateral 😮39:05 Lologram 😂
39:31 answer (ii) no quadrilateral (iii) parallelogram
Sir you are the only hope for Class 10 students❤❤...just amazing teacher in universe🎉♡♡babua sir op😊
Love you man ❤
12:25 question 2 ends
13:23 question 3 ends
Thank you sir🙏🙏
All the best Inshallah everyone will score 95% in board
On Saturday is exam but before 1 hrs I was very afraid thinking that this is Very tough chapter but after 1hrs video and solving in rough before sir explanation it's seems like very easy
Who knew learning could be so fun? You did! Thanks for everything this year.🔥
39:06 lologram
1:15:28 😂😂❤❤
Half yearly ke liye kaun dhek rha hai 😅 attendance here..✅
Teerfdgfjbgn
Ab ha math ki bari
1:58:53 question 10 th = 24 sq .unit..❤
Kon kon 2024 me August me dekh rha h 😂😂😂
😁
Me 😂last date of August
Pagal abhi September chl raha
September me dekh ra wo bhi maths ke exam ke 3 din pehele
Best maths mentor in the Universe 🎀💌
November mai kon dekh rha 😢
Me also 1.19 pm raat ko vo bhi really 😢😢
Me
@@FactPro7M 1 p m raat nhi hota h😂
December 😂
@Pallavi713 haan 👍
Sir you are best teacher of maths becuse earlier i used to be scared of math but now i don't feel scared at alll 😊😊😊
1:42:49 😂😂😂😂
When is your maths paper in the bord exam ?
DDE5F44FVVRVV
sir exercise 7.2 ka Q5 mein section formula ke jagah midpoint formula bhi use kar sakte hain!!!!!!!!!!!!!!!!!!!
Basic wala like karo
Do only ncert question bro
Lo.10 rupees 😂😂😂
Tip
Ncert enough hai basic valo kae liye 😢?