Why we should take four states only For 1)There is " aabb " string length is 4 You previously said we should take Minimum string length +1 states Then why we didn't not take 5 states. Please clarify me sir
This is a special example, we don't know length of string. Please like the videos, subscribe to the channel, and share it with your friends. Thanks in advance.
Here 4 problems are explained in this video. A single dfa can't accept all those strings. Plz subscribe to the channel and if possible share with your friends. Thanks in advance..
If you want you can, but 4 states is the most popular method for even and odd problems. Plz subscribe to the channel and if possible share with your friends. Thanks in advance..
for each problem we have 1 final state. totally we have 4 final states. refer video once. Plz subscribe to the channel and if possible share with your friends. Thanks in advance..
Wow 😮 what a explanation TQ u very much sir
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Great sir thinking overall concept higher and easy explanation technique
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Great Explanation Sir .. Thank you very much ☺️👏👏
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Sudhakar anna thopu
Dammuntey aapu🔥🔥🔥
Enduku babu Apadam. Plz subscribe to the channel and if possible share with your friends. Thanks in advance...
Nice explanation sir...Thanks a lott❤❤
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Nice explanation Sir...Thank u so much.
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Very good explanation
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Sir very nice explanation wow
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Good explanation sirr, this video is very helpfull for us
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Well explained sir thank you sir
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Thank you sir❤
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It's easy 😂 i understand 😉 thank you i got GPA 4.00 toc
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Tq sir...for this simple explanation
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Sir compiler part b kardo sir plz😭
Btw amazing explanation as always🎉
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Thank you so much sir...
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Thankuuuuuu sirreee♥️
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good explanation sir please continue your videos on "daa"
Thank you, I will hari.
@@SudhakarAtchala okay sir
Sir 4 diagrams tho one by one explain chesi vunte bagundu
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Sir can initial and final state be same 2:34
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Thankyou very much sir
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Thanks a lot sir for ur teach 😊
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I hv wrote answer like this in exam hope i will get marks🥲
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Thankyou sirrrr
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Tq u so much sir
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Is initial state is same for all?
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Sir why we are applying a on q0 to q1 and again applying on q1 to q0?
why we are not applying a on q0 to q2?
It is your choice but it should accept all strings. Plz subscribe to the channel and if possible share with your friends. Thanks in advance..
Make more videos on theory of computation sir
ya sure manjula.
thank youuuuuu
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nice explanation sir wt about the transition table🥲?
you need to construct in. exam. Please like the videos, subscribe to the channel, and share it with your friends. Thanks in advance.
Sir if the problem is aaaabbb i mean Even no. of a's and odd no. Of b's then is it works? And if yes then how's it works?
q2 is final state
Why we should take four states only
For
1)There is " aabb " string length is 4
You previously said we should take
Minimum string length +1 states
Then why we didn't not take 5 states.
Please clarify me sir
This is a special example, we don't know length of string. Please like the videos, subscribe to the channel, and share it with your friends. Thanks in advance.
but in that automata { aaa, bbb , aaabbb } is not satisfying in that automata
how can i pass this string .
Here 4 problems are explained in this video. A single dfa can't accept all those strings. Plz subscribe to the channel and if possible share with your friends. Thanks in advance..
Tq u sir
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helpful
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Sir why u have taken 4 states
and Why we can't take 3 states
If you want you can, but 4 states is the most popular method for even and odd problems. Plz subscribe to the channel and if possible share with your friends. Thanks in advance..
thank u sir :))
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Tq
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Please sir when given such problems must you draw all the 4 states?
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sir ,can you make a video of dfa using
starting and ending with 00
starting and ending with 0
ending with one 0
having odd number of 1
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Where is final state
for each problem we have 1 final state. totally we have 4 final states. refer video once. Plz subscribe to the channel and if possible share with your friends. Thanks in advance..