Implementation of Question-4 of biweekly :- using ll=long long int; class Solution { public: ll count1_in_ith_pos(ll i,ll x){ ll tot=x+1; ll fullCycles=tot/((1LL
For Lc weekly 4th question: Bhaiya you taught O(n^3*2^n) approach,With hint1 given in leetcode(that perm[0]=0 always gives one of the optimal answer) , it can be optimised to O(n^2*2^n), as we no need to track first in dp state. And bhaiya O(n^2*2^n) is giving AC, can you please elaborate why perm[0]=0 always gives one of the optimal answer
All cyclic permutations of a permutation have the same score. lets say for some input 1, 3, 0, 4, 2 is an optimal permutation then all cyclic variations of this will also give same score hence 0 4 2 1 3 will also give same score which is lexicographically smaller.
Implementation of Question-4 of biweekly :- using ll=long long int;
class Solution {
public:
ll count1_in_ith_pos(ll i,ll x){
ll tot=x+1;
ll fullCycles=tot/((1LL
For Lc weekly 4th question:
Bhaiya you taught O(n^3*2^n) approach,With hint1 given in leetcode(that perm[0]=0 always gives one of the optimal answer) , it can be optimised to O(n^2*2^n), as we no need to track first in dp state.
And bhaiya O(n^2*2^n) is giving AC, can you please elaborate why perm[0]=0 always gives one of the optimal answer
All cyclic permutations of a permutation have the same score. lets say for some input 1, 3, 0, 4, 2 is an optimal permutation then all cyclic variations of this will also give same score hence 0 4 2 1 3 will also give same score which is lexicographically smaller.
@@TusharRaghav thank you
Sir
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Sir please from next time do in order of 4,3,2,1 because it is very difficult to wait to participate for last question till last of session
Yes please
Then we might rather do only last … because for anyone before that… it will be too hard.
I like the flow. I guess 2 hour of upsolving 8 problem is just fine
bhaiya in ques 3 of biweekly , why we not use parition dp (form 4) ??
form 2 has better complexity. How to calculate answert for l to r?