Integration by Parts | Integrate x^(2)cos(3x) dx by Parts

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  • เผยแพร่เมื่อ 18 ม.ค. 2025

ความคิดเห็น • 11

  • @jakeblake06
    @jakeblake06 2 ปีที่แล้ว +3

    Although everyone is harping on the fact that you made a mistake on the second term... This was a great video and was extremely helpful towards the process of learning how to solve a problem like this. It's very clear that the second term should be positive and not negative and thats such a small mistake to have made. Thanks again for the great video.

  • @Mathsadiq-vt1cr
    @Mathsadiq-vt1cr 2 หลายเดือนก่อน

    Thanks 👍

  • @janelsvids
    @janelsvids 4 ปีที่แล้ว +10

    Did you mean to say x^2 * sin(3x) and not x^2 - sin(3x) towards the end of the equation?

  • @anshu6025
    @anshu6025 2 ปีที่แล้ว +3

    Can u pls explain how it came minus in the second last step ::. X^2 - sin 3x/3 it should me x^2*sin 3x /3 ??

  • @Ben_M_D
    @Ben_M_D 4 ปีที่แล้ว +5

    Why is the second term of the answer -2xcos(3x)/9 instead of a +?

    • @jakeblake06
      @jakeblake06 2 ปีที่แล้ว +1

      Definitely a mistake. I was going to comment the same thing. He sort of touched upon it in the video, but seems like he just overlooked it. Should 100% be a positive.

  • @kaojay4812
    @kaojay4812 3 ปีที่แล้ว +6

    The final answer is incorrect.

  • @yannshoemaker9995
    @yannshoemaker9995 3 ปีที่แล้ว +5

    That's not the right answer!

  • @mrchese6925
    @mrchese6925 2 ปีที่แล้ว +1

    Gracias, saludos des de Mexico :v