These videos have been a really great tool for visualizing the concepts, since Griffith really does leave a lot to the imagination as you said. Students just need to do research beyond the videos, combining resources, to get a better scope of the material.
So the external electric field is proportional to the charge distribution. Clearly the charge distribution isn't causing the external field. So does the external field change the charge distribution? Is this because of induction? Can one conclude that if you were to increase the outside electric field, sigma would increase to compensate?
Yes, the external field changes the charge distribution inside the conductor. The charges inside the conductor are free to move around. If there is any net E field inside the conductor, then the charges will flow until the net E field is zero. In effect, the charge distribution inside the conductor is such that it creates an E field exactly opposite to the external field inside the conductor. (Outside the conductor, magic happens.) Thus, if you doubled the external E field, the E field due to the charge distribution would have to compensate by doubling. Since E is proportional to q, q has to double as well.
“He leaves a lot to your imagination” basically a great summary of the entire textbook 🤦♀️
Yeah, if u have time then it will be a great book but if u don't u can't keep imagining ..
Every time he tells you to imagine a scenario, I'm like "Here we go again....."
These videos have been a really great tool for visualizing the concepts, since Griffith really does leave a lot to the imagination as you said. Students just need to do research beyond the videos, combining resources, to get a better scope of the material.
So the external electric field is proportional to the charge distribution. Clearly the charge distribution isn't causing the external field. So does the external field change the charge distribution? Is this because of induction? Can one conclude that if you were to increase the outside electric field, sigma would increase to compensate?
Yes, the external field changes the charge distribution inside the conductor. The charges inside the conductor are free to move around. If there is any net E field inside the conductor, then the charges will flow until the net E field is zero. In effect, the charge distribution inside the conductor is such that it creates an E field exactly opposite to the external field inside the conductor. (Outside the conductor, magic happens.) Thus, if you doubled the external E field, the E field due to the charge distribution would have to compensate by doubling. Since E is proportional to q, q has to double as well.
Real Physics - OK, that’s what I got from the equations, but wanted to confirm. Makes sense, thanks.
No prob. I'm rusty, but these first chapters are pretty straightforward. Don't ask me about wave guides though -- I'd have to polish up again.
what do you mean by electric field at the surface and outside the surface?
nice and little bit confusing topic ... thanks for making this video
Hi, aren't you forgetting a 2 in the denominator for the electric field just outside the surface, as you did in a previous video?
Thank you for this explanation.
When do we use sigma by epsilon and when do we use sigme by 2x epsilon
Abhimanyu Banerjee half the field is above and half below, so it’s (1/2)σ(Eabove + Ebelow)
thanks
I’ve been loving your videos, but you lost me on this one.
thanxx
🆒️
just confused
What can I do to help? What's confusing?
Real Physics what is the difference between E(above) and E(out)?
You are reading just the book
You are reading just the book