Minimizing Switching Regulator Residue in Linear Regulator Outputs

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  • เผยแพร่เมื่อ 14 ม.ค. 2025

ความคิดเห็น • 34

  • @takatoo
    @takatoo 3 วันที่ผ่านมา +1

    I love how both presenter and viewers are chocking their chicken due to excitement of this presentation. 😊

  • @irgski
    @irgski 2 ปีที่แล้ว +7

    Jim Williams was an analog genius!
    RIP Sir.

  • @OldCanadianguy953
    @OldCanadianguy953 3 หลายเดือนก่อน +1

    The man radiates intellectual honesty. RIP.

  • @capriracer351
    @capriracer351 13 ปีที่แล้ว +40

    RIP Jim Williams. I always enjoyed your writings and the sense of humor that showed in them. I wonder what you and Bob Pease are designing in that great analog world in the sky?

  • @seinfan9
    @seinfan9 4 ปีที่แล้ว +13

    Be wary if your linear regulators are powering oscillators. The ferrite beads can resonate with their switching frequencies and you'll see a massive jump in voltage ripple going back to the power supply!

  • @xDR1TeK
    @xDR1TeK 6 ปีที่แล้ว +8

    Great man, my only regret I got to know his work very late.

  • @christophschuermann6512
    @christophschuermann6512 7 ปีที่แล้ว +2

    The world is now a better place, thanks to you! RIP Jim.

  • @jasoneyes01
    @jasoneyes01 7 ปีที่แล้ว +4

    Thanks Jim! I'm glad you taught me something!

  • @SolidStateWorkshop
    @SolidStateWorkshop 12 ปีที่แล้ว +3

    Thanks Jim! Rest in Peace.

  • @chrischarters376
    @chrischarters376 7 ปีที่แล้ว +2

    Top bloke, serious case of the smarts rip Jim.

  • @danstiurca7963
    @danstiurca7963 2 ปีที่แล้ว

    Jim William's is a switching regulator god.
    Amazing that his wisdom is on TH-cam!
    Really sad to see from the comments he's no longer around. :(

    • @milantrcka121
      @milantrcka121 ปีที่แล้ว

      Jim William's legacy lives on thanks to YT.

  • @duhaiv
    @duhaiv 4 ปีที่แล้ว +1

    Thank you Jim
    Simple and elegant solution

  • @photonictechnologies
    @photonictechnologies 9 ปีที่แล้ว +3

    You absolutely understand electronics.

  • @Cynthia_Cantrell
    @Cynthia_Cantrell 2 หลายเดือนก่อน

    I recommend getting rid of the ripple right at the switcher's output, which means a ferrite bead and / or inductor (depending on frequencies) BEFORE the switcher's output cap. This can be tricky as it can introduce another pole in the feedback loop and turn your power supply into a big oscillator. However, in places where you have a clock somewhere on your board multiplied up into the GHz range, this is necessary. As is filtering that supply with the FB / inductor, large cap as close as possible with the shortest traces possible, and DON'T drop vias to your power plane and ground planes until AFTER this filter.
    If that diode ringing from the switcher makes it on to the power and ground plane, it will bounce those entire planes, and adding ferrite beads around the linear regulator won't help you. The power/ground plane makes a far better transmission line than it does a capacitor, and there is no way to stop the entire ground plane from bouncing around once that noise gets on it. So stop that ringing right at the switcher!

  • @chromosome24
    @chromosome24 3 ปีที่แล้ว +3

    "...parasitic internal pass basically from everywhere to everywhere" hahaha

  • @electronichome1153
    @electronichome1153 4 ปีที่แล้ว +1

    Thanks, Jim!

  • @zhitailiu3876
    @zhitailiu3876 5 ปีที่แล้ว +2

    Great analog magician!

  • @AlexProtopopescu
    @AlexProtopopescu 4 ปีที่แล้ว

    Beautifully explained.

  • @jan.tichavsky
    @jan.tichavsky 13 ปีที่แล้ว +10

    LOL at the appnote last page: Megahurts to Minihurts Converter :)

  • @cskabos
    @cskabos 13 ปีที่แล้ว +1

    Very useful info. Thanks Jim

  • @gnagyusa
    @gnagyusa 7 ปีที่แล้ว +1

    Great presentation. Thank you for the info!

  • @cyrus-music
    @cyrus-music 8 หลายเดือนก่อน

    The goat...rip

  • @garymoore3497
    @garymoore3497 2 ปีที่แล้ว

    Ok, so lets discuss how a Surface power supply would go about eliminating switching noise. Looking at the attached drawing, I've captured a generic switching regulator on the left, and have it's output [ Vin ] feed into an EZ81 vacuum tube rectifier [ pins 1 and 7 ]. Output of the EZ81, nice clean DC, as shown [ Vout ]. How is possible ? Let me disclose what is not seen here.
    What is not seen here, the vacuum gap between plates and cathode of the tube. The DC voltage will forward bias the rectifier, thus plate current will flow. However, the switching noise does not jump to the cathode, due to the free-air-space between plate(s) and cathode.
    What does it cost ? First, you need to supply the filaments 6.3 volts, at about 1 amp. Also, in this configuration, series plate resistance on the order of 180/2 ohms. So there is some insertion loss to factor in. However, if the application does not require current sourcing up to 1 amp, other tubes could used, and you would save on filament power. Also, some care is required to set this up, with the dual inputs, or you can red-plate these tubes. I would also recommend some type of simple BITE circuits to keep an eye on tube health and performance. You set this up right, these tube last almost forever. . . . . ..... ... . . ......
    Side notes. I show output filter cap at 100uF. The data sheet for the EZ-81 states 50 uF max. So, why do I run output filter cap at 100uF. It goes back to understanding how data sheets are written. You see, the EZ-81 come out in 1956. At that time, the biggest filter capacitors back then, were these wax and paper rolled jobs, max value was 47uF. So, this is just a guess, but I would say they were saying this tube could handle the biggest cap available. The higher capacity electrolytics did not come out until the mid 1970's. Secondly, there is no issue with surge current for two reasons. 1. This tube rated for 0.5 amp continuous, per plate. 2. It takes about 12 seconds for this tube to warm up, and gently ramp up to full conduction. I even ran this tube feeding a few 1000uF caps over a few days. It did not care. Why? Because a vacuum tube is not an active electronic device. It is a mechanical device, with - certain - electrical - properties. It does not generate any waste heat internal to the device, because is a vacuum between plate and cathode.

  • @aes9217
    @aes9217 8 ปีที่แล้ว

    very nice and informative thanks

  • @ericbader7998
    @ericbader7998 7 ปีที่แล้ว +2

    Would an inductor with a well-known value (LC filter) serve the same purpose or even do a better job?

    • @LinearTechnology
      @LinearTechnology  7 ปีที่แล้ว

      Hello, for an answer by one of our engineers, please visit the Power by Linear technical community at ez.analog.com/community/power. Thanks!

    • @FesZElectronics
      @FesZElectronics 5 ปีที่แล้ว +13

      From what I saw in real life, the ferrite bead is better for 2 reasons - an LC filter made with a proper inductor has a clearly defined resonant frequency and you can get the filter to oscillate at this frequency when applying load steps, so you might filter some noise but generate other unwanted oscilations; on the other hand the ferrite bead behaves like a resistor at high frequency rather than an inductor, this is because its absorbing the magnetic field (and turning it to heat) rather than store it like a proper inductor, so the magnetic energy does not get put back into the circuit.

    • @typedef_
      @typedef_ 3 ปีที่แล้ว +2

      @@FesZElectronics If you could make a video with ferrite bead experiments, it would be very cool.

  • @garymoore3497
    @garymoore3497 2 ปีที่แล้ว

    Surface power supply can filter out all that switching noise . . . .

  • @frosty129
    @frosty129 4 ปีที่แล้ว

    Tried it. Didn't work.

    • @kaikart123
      @kaikart123 4 ปีที่แล้ว

      Don't use black beads