I like more to leave the answer as 1 + 1 / log 2. Although this leaves a log expression in the denominator of the fraction, I think it is more practical than 2 + log (base 2) 5, because it uses base 10. Of course both expressions are the same value and correct.
Log2^x=log(2*10) Or xlog2=log2+log10 Or x=(log2+log10) /log2 =1+(log10/log2) =log10+(log 10/log2) =(log 10×log2+log 10) /log 2 =(log2+1) /log2 Now i do not calculate, this is only for you.
great , thank you 👏👏👏
Excelente explicação
I like more to leave the answer as 1 + 1 / log 2.
Although this leaves a log expression in the denominator of the fraction, I think it is more practical than 2 + log (base 2) 5, because it uses base 10.
Of course both expressions are the same value and correct.
x=log20/log2=(log2+log10)/log2=1+1/log2
x≈1+1/0.301≈1301/301≈4.322
Deviation is about 0.0003
2^4.322≈20.001
May i ask what deviation refers to? I am learning
Log2^x=log(2*10)
Or xlog2=log2+log10
Or x=(log2+log10) /log2
=1+(log10/log2)
=log10+(log 10/log2)
=(log 10×log2+log 10) /log 2
=(log2+1) /log2
Now i do not calculate, this is only for you.
Approximately 4 plus minus.