Hello to every person reading this, for someone who has a better understanding of the topic than i do, at the 10:00 minute mark how does he arrive at P(A)= 0.5, P(B)= 0.4, P(C) = 0.1 Thank you in advance
I think the idea is that the probabilities of your hitting the outer ring, middle ring, and bull's-eye are empirically determined. Those probabilities are then multiplied by the given point values for those outcomes -- values that have been set arbitrarily by whoever is doing the scoring -- to give you the expected value of a single shot.
I think we are performing numerical outcome here, which is A.P(A)+B.P(B)+C.P(C), here A,B,C are elements of our sample space, in case of die, it the sums, that's why we are doing P(12).12
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Hello to every person reading this, for someone who has a better understanding of the topic than i do, at the 10:00 minute mark how does he arrive at P(A)= 0.5, P(B)= 0.4, P(C) = 0.1
Thank you in advance
That lady in the background is really putting in the work
Amazing Explanation with exampless, Please start a series on Calculus for Machine Learning
can u tell me again how did u calculate numbers in 10.06 minutes. p(A) , p(B) etc.
bro can you explain me in detail how you calculate probability of bow and arrow example???
I think the idea is that the probabilities of your hitting the outer ring, middle ring, and bull's-eye are empirically determined. Those probabilities are then multiplied by the given point values for those outcomes -- values that have been set arbitrarily by whoever is doing the scoring -- to give you the expected value of a single shot.
say in more basic terms
thanks for your contrubution, great video.
15:05 why is he suddenly talking about "Spades"? i thought this was a dice problem
For confusion at 12:40 one can refer to this video: th-cam.com/video/boxw_xwtrRc/w-d-xo.html
8:28: What is theoretical probability? Isn't probability of outcome THEORETICAL only?
For the bow and arrow. The expected value for a single shot. Wouldn't that be A=10, which has 50% probability ?
12:41 : The formula seems wrong as for P(12) we see only 1 occurrence. So it should have been P(12).1 and not P(12).12 : Is that correct?
I think we are performing numerical outcome here, which is A.P(A)+B.P(B)+C.P(C), here A,B,C are elements of our sample space, in case of die, it the sums, that's why we are doing P(12).12
That is cool
very difficult to understand
Does Independence mean that they do not intersect?
It means that the change in value of one doesn't affect the other.
Probability 0 doesn't mean impossible.
Then what else does it mean?
@@jhdomino572 Have you studied measure theory?