Just to clarify, the reason why the parabola instead of the catenary is the ideal shape for the arch at 23:30 is due to the linear and uniform load distribution? Also if this is the case, wouldn't it also be easier to use the parabola equation directly y=ax²? Thank you!
Just to clarify, the reason why the parabola instead of the catenary is the ideal shape for the arch at 23:30 is due to the linear and uniform load distribution?
Also if this is the case, wouldn't it also be easier to use the parabola equation directly y=ax²? Thank you!
Thanks Clemens for the great lecture:)
Thank you for watching! Join us this week for part 2!
so powerfull tool! Thanks for sharing!
You're so welcome! Thanks for watching!