Recurrence relation : T(n) = 3T(n/2) + n | Show that: 5n² + 2n + 2 = theta(n²) | Bcs 042 dec 23 sol

[@PriyaRajput-xm4vl]

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[@IGNOUverse1]

Always welcome ❤️😊

[@_developer_yash]

Bhai ab yaad aaya 4th semester

[@user-sk_webde]

bhai 3 number ke question me tumnne 2 pages ka solution kaise de diya 🥲

[@IGNOUverse1]

Itna toh Krna hi pdega... Yhi process hai yhi answer hai🥲

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Bhaiya synopsis video detail

[@byeeekosar]

11:33 see this tree

[@IGNOUverse1]

Haa. Kya hua isme ?

[@byeeekosar]

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[@Perchedsparrow]

Bhaiya bhaiya bhaiya thannyouuu 😢😢😢❤❤❤❤❤❤❤❤❤❤❤so muchhhhhh

[@IGNOUverse1]

Welcome didi😊

[@karanarya7440]

C¹ g(n)

[@CodeWithRonit28]

bhai itne jyada badhi process hogi 1 b ki toh kafi time oth isme hi chala jaiga isko normal way se bhi kar sakte hain

[@IGNOUverse1]

Yhi way hai iska.. normal way ke chakkar me kuch bhi likh ke aa jaoge, toh marks nhi milega... Ye question aise hi solve hota hai or yhi shi bhi hai

[@dailydoseoffact1501]

You are the great sir

[@IGNOUverse1]

Thank you ❤️

[@_developer_yash]

Aap to bhul hi gye the hm 4th walo ko

[@jyotisaini2040]

Thanku so much

[@IGNOUverse1]

Most welcome 😊❤️

[@HarshSharma-oo9ly]

Please Upload BCS 54 BCS 52 BCS 53

[@SmileyQ-i6m]

Bhaiya synopsis video detail

[@agustinrai2683]

Bro synopsis kab Dena hai?