How to Design an RF Power Amplifier: The Basics

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  • เผยแพร่เมื่อ 22 ธ.ค. 2024

ความคิดเห็น • 49

  • @taf209
    @taf209 9 ปีที่แล้ว +5

    Great video! This is the most intuitive explanation of class A power amplifier. More useful than any textbook!

  • @samgalaxy1176
    @samgalaxy1176 8 ปีที่แล้ว +1

    To The Gentleman @
    Keysight EEsof EDA
    A Big Thank You For Posting This Series On TH-cam!

  • @MohammadAMaktoomi
    @MohammadAMaktoomi 9 ปีที่แล้ว +5

    Yet another very good initiative by Keysight. Thanks for wonderful videos.

  • @MehdiKarimian-t3o
    @MehdiKarimian-t3o ปีที่แล้ว +1

    Hi Matt,
    An amazing work!
    I believe you have made a mistake at 3:20. We can not fine total power (RF+DC) using 0.5*Vp*Ip. We can use this formula just when the time domain signal is a single tone without any DC component and any other tones.
    Thanks a lot!

  • @seanalm3127
    @seanalm3127 9 ปีที่แล้ว +4

    Great video. I appreciate the concise refresher as a working professional trying not to bug my FAEs every week :)

  • @tamilchelvanramasamy8733
    @tamilchelvanramasamy8733 4 ปีที่แล้ว

    Thanks for your elucidation about the basics of PA

  • @uav-pixel9046
    @uav-pixel9046 ปีที่แล้ว

    THE LINK TO THE DISPLAY TEMPLATES IS NOT WORKING

  • @denizhankaraca8862
    @denizhankaraca8862 9 ปีที่แล้ว +1

    Hi, thanks for the video. I have a question regarding the load line plot at 11:20 . Assuming the the plots in Id-Vds graph are for equally swept Vgs voltages, the Vgs swing has to be different in positive and negative directions to reach at the Imax and Vmax points. I have observed the same condition also when I simulate some real CMOS transistors. Am I missing something? Thanks in advance.

    • @KeysightEEsofEDA
      @KeysightEEsofEDA  9 ปีที่แล้ว +3

      +Denizhan Karaca
      Good question! You are correct -- the transconductance
      of a CMOS device is not linear -it’s a square law relationship (Id is
      proportional to Vgs-Vt squared) .
      This means that the positive portion of
      the gate (or input) waveform experiences a higher effective gm than the
      negative portion of the waveform. You may find this video on the basic
      classes of operation [th-cam.com/video/GhPqPVlDRPY/w-d-xo.html] interesting, as the
      nonlinearly which you refer to at the input is more explicitly illustrated
      (around 3:00). The video also shows that to get the classical values of
      efficiency for a power amplifier, the trans-conductance is linearized (Id is
      made proportional to Vgs-Vt) - or at least this is done in a mathematical sense
      to derive the waveforms and the corresponding ideal efficiency. Since no
      device actually behaves so nicely as to have a perfectly linear
      transconductance, you can therefore never realize the ideal efficiency values
      for a Power Amplifier in real life!
      This non-ideal transconductance also implies that there is
      no single bias point where the device will be exactly at the brink of turning
      on and off (the so called “threshold” in Class B where exactly half of the
      waveform perfectly conducts). Consequently, most amplifiers biased near
      the Class B threshold point have low or no small signal gain in the lab - in
      other words the Gain vs. Pout plot is highly expansive as power
      increases.
      One of the big challenges in any practical PA design is
      dealing with the effects of these types of non-idealities - in many cases what
      you can actually realize in the lab is far removed from the waveforms and
      loadlines that the theory implies.
      Depending on how you look at it, this
      can either be very disappointing or very exciting and interesting!

    • @denizhankaraca8862
      @denizhankaraca8862 9 ปีที่แล้ว +2

      +Keysight EEsof EDA Thanks for your detailed explanation, it is very clear and helpful.

    • @juliussmith4800
      @juliussmith4800 8 ปีที่แล้ว +1

      Keysight EEsof ED

  • @deepsjack
    @deepsjack 3 ปีที่แล้ว

    Thanks for the Nice Video. Have one Question @ 8.05, How can the current can be pulled from the ground?. I guess the extra current is coming from the Choke.

  • @farrahglick9910
    @farrahglick9910 6 ปีที่แล้ว +2

    Many thanks to you. This is helpful and easy to follow! Cheers.

  • @Steve.Zeinoddin
    @Steve.Zeinoddin 8 ปีที่แล้ว +2

    One word: Brilliant!

  • @akhileshverma7105
    @akhileshverma7105 3 ปีที่แล้ว +1

    Hi, Can you show me how can we get these plots?

  • @mamun4343
    @mamun4343 3 ปีที่แล้ว

    I have one question. You mentioned that "since less current is pulled into the current source, instead it flows in AC sense from the power supply into the load." There is a bias inductor after the supply and if we think of RF( or AC sense) this provides high impedance. So, how is the AC (or RF) current flowing from the supply through the inductor to the load ? Doesn't the inductor resist ac current flowing from the supply into the load ? Can you please explain a bit?

    • @mamun4343
      @mamun4343 3 ปีที่แล้ว

      I would like to add another question: With the similar concept how to explain the envelope current( for modulated signals) flow from the supply to the device and the load for both class A and reduced conduction angle mode operation( class AB/B). Thanks.

    • @KeysightEEsofEDA
      @KeysightEEsofEDA  3 ปีที่แล้ว +1

      These are questions that could take a book’s worth to answer. Briefly, the DC supply provides the energy to the circuit. At the fundamental, the transistor converts this DC energy to a high frequency. It then gets exchanged between the transistor and the RF load network without much further supply interaction (assuming the choke’s designed well). The combination of the current in the load and device will sum to the DC value over a cycle. For that to work (assuming no storage), the load current must go high when the device current goes low - this is kind of a redirection of current from transistor to load during the RF cycle.
      When there is a modulated signal, it contains the high frequency signal, but now there is a lower frequency envelope, changing the input power dynamically. Plot current vs. Pin to see how that may impact the dynamic draw from the supply. For Class A, if it never goes into compression, the DC current does not change much vs. Pin, as you move to Class AB, current does change more with Pin. That means the device will dynamically try to pull current from the supply at the mod bandwidth - and if the bias network is designed well, then the supply will be able to deliver the current dynamically when needed.

    • @mamun4343
      @mamun4343 3 ปีที่แล้ว

      @@KeysightEEsofEDA Many thanks for the detailed answer. I really appreciate that.

  • @aRKad3
    @aRKad3 7 ปีที่แล้ว +1

    The project file link is not working. Please upload the updated link

  • @xiaomingzhang-g4e
    @xiaomingzhang-g4e 6 หลายเดือนก่อน

    What is the value of Vp and Ip?

  • @omaralngar330
    @omaralngar330 8 ปีที่แล้ว +3

    thank you for your efforts
    brilliant explanation

  • @williamlee8768
    @williamlee8768 4 ปีที่แล้ว

    i am a student in UESTC, thank you for your video wih Chinese captions

  • @HalfLife2Beta
    @HalfLife2Beta 7 ปีที่แล้ว

    Hello, I need to know how to do loadpull simulation for a Push Pull RF Power Transistor (with 5 pins). Thanks in advance.

  • @xiaomingzhang-g4e
    @xiaomingzhang-g4e 6 หลายเดือนก่อน

    请问这里的Vp和Ip是多少啊,怎么计算峰值

  • @keepsmiling9443
    @keepsmiling9443 2 ปีที่แล้ว

    Hi pliz i found prb in the installation of ads, in lecence server

  • @aloksahu6698
    @aloksahu6698 4 ปีที่แล้ว

    Where are V_t and I_t defined in data display. I cant find them as eqn in simple_power display page

  • @anon-ly9pu
    @anon-ly9pu 7 ปีที่แล้ว

    The link in the description appears to be dead for this series. Where can I find?

  • @atasarrafinazhad1104
    @atasarrafinazhad1104 7 ปีที่แล้ว +1

    This is so amazing, one of the best videos I have ever watched in my life.
    Would you also please explain why the load has real and imaginary part. Since we always calculate and simulate for RL and load-line theory is based on that. But we always have imaginary part in load-pull simulation.
    Thank you for your time, I appreciate.

    • @KeysightEEsofEDA
      @KeysightEEsofEDA  7 ปีที่แล้ว

      Great! Glad you found it useful! Device parasitics are the culprit. These reactive elements occur between the “ideal” current generator inside the device and the actual output terminal (ie the physical drain connection on your IC/package). The goal is to present a reactive impedance externally which is transformed by the parasitic elements so that it is a real load value intrinsically. In this example, the parasitic elements in the model were zeroed out, hence the real load value.

  • @dandwrasan2342
    @dandwrasan2342 5 ปีที่แล้ว

    Can you please tell me what the phrase “up mixing “ means pls

  • @zianadir
    @zianadir 9 ปีที่แล้ว +1

    great series of videos. explanations are very well done....if possible and in future, a complete RF-Transmitter design explanation video (using ADS) will be interesting...
    thanks

  • @hcovic
    @hcovic 9 ปีที่แล้ว

    great explanation!!! video should have much more views .. thanks man

  • @douglasnderebamutea2928
    @douglasnderebamutea2928 7 ปีที่แล้ว +1

    Thank you, nice tutorials.

  • @tomwu9342
    @tomwu9342 9 ปีที่แล้ว +2

    So good. Thank you.

  • @johnjeromeo.colico1259
    @johnjeromeo.colico1259 4 ปีที่แล้ว

    Cheers to keysight =)

  • @freddyrafaelsanchezsanchez9632
    @freddyrafaelsanchezsanchez9632 8 ปีที่แล้ว +1

    excelente tutorial gracias

  • @SheikhAamirAhsan
    @SheikhAamirAhsan 8 ปีที่แล้ว

    Hey Matt, that was an awesome tutorial. However, I'd like to have your opinion on the impact of S22 on the performance of an RF Power Amplifier. And how it might effect the various Figures of Merit. Thanks. :)

    • @KeysightEEsofEDA
      @KeysightEEsofEDA  8 ปีที่แล้ว +1

      +Sheikh Aamir Ahsan Great question! Matt answered! Check out the blog article: rfdesigntips.blogs.keysight.com/

    • @vysakhk
      @vysakhk 2 ปีที่แล้ว +1

      @@KeysightEEsofEDA can you please reshare the link?

  • @DoughnutFoundation
    @DoughnutFoundation 5 ปีที่แล้ว +3

    Who here is watching this cuz u got a research paper to write?

  • @白桦-e5w
    @白桦-e5w 4 ปีที่แล้ว

    这视频可太牛逼了,国内少有这种讲解性的精品视频。

  • @remanbryuh8503
    @remanbryuh8503 4 ปีที่แล้ว

    Directions not clear FBI at door

  • @saurabh25588
    @saurabh25588 ปีที่แล้ว

    Good and informative but goes way too fast

  • @uttamnag2432
    @uttamnag2432 5 ปีที่แล้ว

    hindi mein vidio banaye