The refractive index "n" in the formula "constructive interference 2dn=(m+1/2)lamda" is the index of the secondary(the middle) media, right? I assume there are 3 media from up to the bottom (like air- oil- water)
For my Physics HL IA, I'm thinking of exploring Beer-Lambert's Law by seeing how concentration and color (in wavelength) of a solution affects its light absorbance. Is this a viable topic or is it too simple?
It can be a good topic - it always depends on how you approach it. I recommend talking it over with your teacher to make sure. The simplest idea can still be made into a good IA if you set it up thoughtfully. If you're going to do an experiment (which it seems like you should with what you described), make sure you take lots of data points, that you be aware of what variables you manipulate (how will you vary the concentration?) and what you measure (how will you measure absorbance?), and be very meticulous about your error analysis. Then compare what you got to what you expected, make sure you can put in a few graphs to show your results (line of best fit it nice, especially if you can find the uncertainty on the line of best fit). Make sure you discuss what your results mean, how they compare to what's expected. Good luck! Beer-Lambert's law sounds like a fun one!
when you have 600 lines/mm, and you're trying to convert it into metres, you basically multiply the numerator and denominator by 1m. hence, it becomes: (600 lines) * metre / mm * metre since there's 1000mm in 1 metre, you can change "metre" to "1000 mm." As we're trying to get rid of the mm, and it's there in the denominator, we convert the metre on the numerator to 1000mm. therefore, we multiply it.
@@abhishekaandrew5100 1 millimetre = 1*10^(-3) metres Or 1 millimetre = 0.001 metres If you multiply both sides by 1000 (or 10^3) You get 1000 millimetres = 1 metre
What should you put if you have a question that asks you for the total number of orders you can see in a diffraction grating and you get a decimal. n=2.82, what should the total number of orders seen be? The answer key says 5 even though n=2.82 and I don’t understand why
I'd need to see the entire question to know how to answer that, unfortunately. Each question has some setup parts that can be tricky so it's important to read the entire context. Good luck! Cheers, Mitch
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Isnt constructive interference 2dn=(m+1/2)lamda ? That is what wrote on textbook
Yes, you're correct - that was a typo on my part! I've added a note in the video . Thanks for noticing!
The refractive index "n" in the formula "constructive interference 2dn=(m+1/2)lamda" is the index of the secondary(the middle) media, right? I assume there are 3 media from up to the bottom (like air- oil- water)
For my Physics HL IA, I'm thinking of exploring Beer-Lambert's Law by seeing how concentration and color (in wavelength) of a solution affects its light absorbance. Is this a viable topic or is it too simple?
It can be a good topic - it always depends on how you approach it. I recommend talking it over with your teacher to make sure. The simplest idea can still be made into a good IA if you set it up thoughtfully. If you're going to do an experiment (which it seems like you should with what you described), make sure you take lots of data points, that you be aware of what variables you manipulate (how will you vary the concentration?) and what you measure (how will you measure absorbance?), and be very meticulous about your error analysis. Then compare what you got to what you expected, make sure you can put in a few graphs to show your results (line of best fit it nice, especially if you can find the uncertainty on the line of best fit). Make sure you discuss what your results mean, how they compare to what's expected. Good luck! Beer-Lambert's law sounds like a fun one!
2:19 it's from the fellowship of the ring not game of thrones season 1😭
8:17 for the conversion aren't you supposed to divide it by 1000?
when you have 600 lines/mm, and you're trying to convert it into metres, you basically multiply the numerator and denominator by 1m. hence, it becomes:
(600 lines) * metre / mm * metre
since there's 1000mm in 1 metre, you can change "metre" to "1000 mm." As we're trying to get rid of the mm, and it's there in the denominator, we convert the metre on the numerator to 1000mm.
therefore, we multiply it.
@@TrueBK77 i still dont understand cause in the data booklet the conversion from mm to m is always 10^-3 right?
@@abhishekaandrew5100 1 millimetre = 1*10^(-3) metres
Or
1 millimetre = 0.001 metres
If you multiply both sides by 1000 (or 10^3)
You get 1000 millimetres = 1 metre
@@TrueBK77 oh now I get it thank you so much🙏🙏🙏
What should you put if you have a question that asks you for the total number of orders you can see in a diffraction grating and you get a decimal. n=2.82, what should the total number of orders seen be? The answer key says 5 even though n=2.82 and I don’t understand why
I'd need to see the entire question to know how to answer that, unfortunately. Each question has some setup parts that can be tricky so it's important to read the entire context. Good luck! Cheers, Mitch
It's 5 because two on each side and one in the middle.
1/600000 on my calc is showing as 2*10^-6 m ? am i hallucinating?
probably
lamps are not coherent
Depends on the lamp :) Cheers, Mitch