I want to say thank you. You had helped me so much and I made an A in every class from statics to Structural Analysis. I spread word about you to everyone at Texas Tech university to learn from you. You are the man!
What determines the direction of the curvature loading? Is it just a convention such that the loading is upwards when the beam is under comp at top and tension at bottom?
Im from the middle east but i dont know why i understand in english better than arabic :/ And yeah you are awesome bro you make things easier.. thank you
@ eyeGOPu1 as the loading is a uniformly distributed load UDL so total force on the span = loading per unit distance[w(x)] times the loading distance and the moment about the point is multiply the shear force with the center of its action to the section C so 4m times 5m.
@@structurefree thanks sir. But can you give me idea how to do it in D.I. method? Area-moment is look same in conjugate method but I can't on D.I. method. Thanks.
Mel13z the internal moment diagram would change and consequently the curvature diagram and then the conjugate loading direction would change...give it a shot.
but this beam has to be translated since it has different moment of inertia, how come you not using 250*4 for the translated section AB and 500*3 for BC and taking moment arms respectively
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I want to say thank you. You had helped me so much and I made an A in every class from statics to Structural Analysis. I spread word about you to everyone at Texas Tech university to learn from you. You are the man!
I just love ur sound and approach to solve problem... !!!!
satya prakash patel fo sho.
Thanks for saving my ass before every final exam.
lol he does that me too
thanks for this Video Tutorial Master . ur the man . More Students to come to watch ur videos :) Thanks again
Very helpful. Much better than my teachers. Thanks
BAM!!! good stuff i enjoy the way u explain things
This was extremely helpful, thank you so much for this video m8 :)
watching 2018 structure free is my saviour
thank you Structure free
You are a hero!
thanks for the help, keep the videos coming
Thanks a lot for the videos man! so very helpful! :)
Deflection is the hardest chapter in structure in first 9 chapters
i can proudly saying that you (structure free) is my teacher
u are awesome keep uploading amazing videos like this .... thank for your effort
Thank you, one question would this be considered as a variable section beam?
I love the way you do commentary it gets me siked to do SA
Thaaaaaank you. Big midterm tomorrow on conjugate and double integration method. Didn't understand either one bit till I watched your videos.
+Chad Waisanen tank a u
man you da best
Thanks. do you have another examples for Conjugate beam method?
Love your videos, Always helpful
Do you tutor?! I’m in desperate need and your videos are the only thing that somewhat get me through!
love ur voice so much....
You are amazing thank you!
how do I know if the reactions from the real beam are going to make a rectangular distributed load vs a triangular one in the conjugate beam?
do u have a video for statically indeterminate beams finding the reactions ..
great videos!!!
U R the man .. thanx for the vids
awesome!!!!
that bam sound was amazing 😉
thanks for the lesson
What determines the direction of the curvature loading? Is it just a convention such that the loading is upwards when the beam is under comp at top and tension at bottom?
THANK YOU
Thank You!!!
جامد جدا والله الواحد سهل يدرس بره بس محتاج توفيق ربنا بس
Thank you
Im from the middle east but i dont know why i understand in english better than arabic :/
And yeah you are awesome bro you make things easier.. thank you
thanks for your video really helped me a lot.
@ eyeGOPu1 as the loading is a uniformly distributed load UDL so total force on the span = loading per unit distance[w(x)] times the loading distance and the moment about the point is multiply the shear force with the center of its action to the section C so 4m times 5m.
ثانكس ^^
nice way of xplanation...
i got it
you saved my ass, thanks a metric ton
Holy Shit. God Bless The Internet!
thank you sir.. :))
Thanx Alot
Hey, When you calculate Mc what is the 5m and 1.5m - "is the arm here" ??
May I ask if this problem is also applicable to Double Integration method? thank you :)
You could solve this problem using the double integration method too.
Sir, can use D.I. method and area-moment method here? Or just conjugate method? Thanks!
Yes, just be sure to account for the change in EI.
@@structurefree thanks sir. But can you give me idea how to do it in D.I. method? Area-moment is look same in conjugate method but I can't on D.I. method. Thanks.
Whats statics?
I have a quick question, what will happen if your deflection and angle turned up to be negative and not as they should be (positive) ?
Mel13z the internal moment diagram would change and consequently the curvature diagram and then the conjugate loading direction would change...give it a shot.
Awesome, but your diagram isn't it supposed to be sloping?
Thank Bro.
+Wora B'Wp you're welcome.
+structurefree what if if there is a loading at the center ...where the inertia changes plz hlp?
why did you draw the conjugate beam below the x axis?
If there would have another concentrated moment at B then how would be the curvature diagram??
Okay...I got it.... Thanku....
but this beam has to be translated since it has different moment of inertia, how come you not using 250*4 for the translated section AB and 500*3 for BC and taking moment arms respectively
Your V'c should be equal to
V'c={ (2000N.m^2 / EIab) + (1500N.m^2 / EIbc) }
you should square the meter
see ~ 9:00