The quality of this content is outstanding. If I don't understand something in school I try to find your videos. Thank you for taking the time to create this content. It's appreciated.
I had a mentor that said the ability of a teacher is not judged by what they know, but how much of what they know they can teach and how effectively they can teach it.
Jesus, I wish I had this kind of explanation on my university, After lots of struggling understanding this I finally understand it very well. Thank you very much!
Nice :) You´re in the University and they cannot really explain to you what a series circuit it´s like? _That´s hard!! Man, when you´ll get to the point of Kirchoff´s Laws and some other physics material, you will find out that series circuits are easy... or at least easier.. I wish you very good luck :)
I started watching your Basics series and, as someone whom is nowhere a genius when it comes to electricity, this made questions I've had for decades seem so common sense. Thanks for explaining things in laymen's terms!
Absolutely love these videos! The metaphors used make it so simple to understand, really helping me understand the stuff my teachers just aren't explaining simply! Thanks so much!
Thank you! Having online classes are already difficult given the less amount of time our professors have to spend during synchronous classes. I can submit my paper for our laboratory experiment with confidence despite just having been given the task alone without discussing anything about the topic.
Currently in Army BET lab, and this stuff went over my head today. Probably would have helped if it wasn't a class done completely by computer with minimal instructor guidance, but that's a complaint for the AAR. Thank you so much for making these videos- I might actually graduate this course.
This is the best!! I used today at work when I had to convert 2V signal to 4 mA signal because the sensor was taking mA and our controller was able to send only 2-10VDC signal and I wasn’t sure how to connect the resistor. Then I watched the video at work, understood everything and everything worked after I placed the 500 Ohms resistor in series. Thank you very much!
This is a great series of videos. Easily followed. Pretty thorough. But, wow! Are they ever repetitive. I guess you wanted every video to stand on its own but I sure would prefer to have a series of trimmed videos.
It's really helpful to study academic lessons otherwise ,.,..,.,its pretty rare to find a healthy video where pretty much all of your questions have been answered.,.,.,.,Thanks again......
Man, I love your explanations. Please give us more. I am now making my own playlists from your videos and really absorb everything. I even got a notebook and take notes. Is Paypal the only way to buy you a beer ? (I just hate paypal) . Cheers . Keep up the wonderful work.
very helpful and easy to understand! hope you could make one content regarding RCD function and use and difference of RCD'S and BREAKERS? Keep it up, God Bless
Where were these videos when I was in highschool smh I would've loved science classes so much more. I love science and learning but holy cow was my education pisspoor. Thank you for the content!!
*summary:* - if you have n resistors in a series, the total resistance in the circuit is the sum of them - current is the same throughout the circuit (think as good as weakest link) - if you have n voltage sources in a series, the total voltage across the circuit is the sum of them - voltage will vary throughout the circuit (it depends on your two points of reference) - resistors take some of the energy of electrons passing through them and convert them into heat
He explains thing very well. I thought that video was going to explain DC Series Circuits but the entire thing was about resistors. Useful but not what the title claimed.
Hi ;) I understand what you are saying, but i think the best way for you to understand how a series circuits works it´s just thinking about this: In a series circuit the current that flows it´s always the same.... The only thing that can happen is that there are voltage drops. And that is why if you measure between those resistances, there will always be voltage drops. ..But the electric current is always the same... And remember this: In circuits of this type, what is in series will add up the values. ..As is the case with resistances ...I think very briefly, this is a series circuit ..
Let me tell you that i enjoyed your explanation and graphics. Well Done !:) Resume: _Series circuits add up to their values and the current is always the same_Unless the measurement is between two load/resistor terminals. In that case, what is being measured is the load/resistor and not the serial circuit_
I’m on Christmas break for college and I’m here watching videos to have knowledge for next semester. I can’t believe I’m saying this but I am a nerd 😂.
Hi, love the video! Have a question though. At the 2:30min mark you show two examples - the left one is 9V battery, 400 Ohm resistor, LED and measured 18.7mA, the right one - 9V battery, 900 Ohm resistor, LED and measured 7.9mA. If there were no LEDs the measurements would have been - left 9/400=22.5mA, right 9/900=10mA. I have done some research and found that for those measurements to be true the left LED should be a yellow LED with a voltage rating of 1.8V doing best performance at 22mA - 1.8V/0.022A=81 Ohm, therefore 9V/(400+81)=18.7mA and the right one should be something like a white LED rated at 3.2V, going at 13-14mA, so 3.2V/0.0135A=237 Ohm, therefore 9V/(900+237)=7.9mA. Is my logic correct, because those measurements battled me hard??
It's not a given that it's a 9 volt that's just a basic shape to use for the model. Your supposed to find the voltage in that scenario by converting the miliamps to amps, 18.7 x 1000 and then x 400 ohms gives you a 7.48 volt battery
How´s that? Do the same way he did ! The cable must be isolated... Then, before you connect everything to the battery, first connect the resistor with the cable. Ok, now, you can connect the cable points to the battery!! When you´ll be ready to measure, grab you Multimeter put it in the right measure position,=Voltage,Current or resistence=, and put the Multimeter terminals on each side of the resistor. And this is how you will have a read ! PS: In that especific case, you can measure the voltage but also the current. So, you apply a known formula__Ohm´s LAw_ The voltage you already know= 9Volts. Now you want to know the Current_! SO, OHm´s Law:: Voltage= Restitance * Current__!!!!! To know now the current::: ::::::: Current = Voltage / Resitance::::: So, Volts= 9 volts / Resistance=10 ohm = TOTAL= 0.9 Amper (current). Sorry for all this, but i felt that you might need it ;)
Great videos! It would be nice if you could so nicely explain a) transistors, and b) rectifiers also while youre in a go, which are hardest for me to learn via youtube :P Thx!
Thanks Paul, I have a question, if we apply the same concept about more resistance gives less current, into a circuit in a house. Why when we have a lot of items working in the same time (resistor is high), the current in the circuit gets overloaded and the circuit breaker trips. Shouldnt the current passing that circuit be less due to the high resistance? Which means CB should not trip. Hope my question make sense 😅
@@EngineeringMindset hloo sir, if in house there is a parallel connecting,then voltage same for all but current split as more as aploncse are connect. So this mean that appliances work on low current or we can say current not influence as much as voltage.plz and. Me
Sorry if this is a confusing or dumb. When he talks about watts in the end of the video, is he talking about it being the power consumption of the all the resistors? Or if he were to put a light bulb on to the circuit, That the bulb would be powered with how ever many watts with a 9V battery at the end of the of the circuit.
@@EngineeringMindset in this one you mention that the one for parallel circuits will be down below but it wasn't. And in your other videos also the links you mention would be down below are usually not there because your description has only selected highlighted links in the electrical section for every description. I don't mind searching them separately but it would still be great if you could add the links you mention at the top of your description or in your pinned comment. Thank you 😭
OK thanks, it's usually a long process from making the video to getting it published so sometimes I miss these links. If yiu find any more let me know and I'll update
@@EngineeringMindset indeed it is a long process ! Your content is much appreciated ! And your IG has some very worth it memes, I recently visited the page 😂😂 Thanks and keep up the good work ! :)) 🤙🏻🤙🏻
@The Engineering Mindset I have a question. If at 8:09 the Voltage drop accross the resistor is 9 Volts, then doesn't that mean that the circuit has lost all of it's potential difference and then there is no longer any current running through the wire after the resistor because there is no longer a difference in voltage? Thank you for your consideration of my question, I am really stumped and have throughly enjoyed your videos enough to want to endorse you. That's how much I appreciate you
Because if the supply voltage is 9 volts, then if the voltage drops by 9 volts, then shouldn't there be net 0 volts left after the resistor? Thank you so much for the help.
After the resistor, the voltage is 0v, because we can only measure the difference in voltage across two points. So if we measure with reference to ground which is 0V and the other probe is also connected to ground then there is no difference so we would read 0V. Maybe if you had a very very precise multimeter you could read like 0.001V or something because the wire will have some resistance, unless you measure at exactly the same point. The voltage difference is still across the load (resistor) so current will still flow, the electrons must flow back to complete the circuit and keep the chemical reaction of the battery going.
great video ! Does it mean if We used conventional flow from positive to negative, the resistant will be on the positive branch ? I am confused with the diagram drawings
The math is basic and simple to understand but I didn't find this tutorial particularly intuitive for someone starting from zero understanding trying to grasp electricity & circuits. Why are there resistors in this circuit at all (i.e. what is the application?). What is the significance of voltage drops? Can you address the seeming counterintuitiveness of wattage decreasing as more resistance is added?
Resistors are used to avoid blowing out components by overwhelming them with more power in the system than they can handle. Otherwise they could explode like the small thin filament of an incandescent lightbulb, unable to handle too much power going through it or the delicate power balance allowing it to shine and give off heat like it’s designed for will turn into an uncontrolled “melt down” of sorts so to speak
Excellent video sir, kindly let me know this, IS that any time limit for dc current measurement in SERIES like 10 seconds or i can leave my multimeter connected in SERIES while battery is charging the whole time ?
@@littlegenius6932 but my multimeter printed on ( 10 amp dc current measurement for 10 sec ) still i can measure it for long time or should i use shunt thanks for your reply
In the circuit with an led and resistors you calculate the current as if the resistors were connected to 9v directly. Shouldn't it be 6v because the led is dissipating 3v?
Yes, but that would make the video too complicated, especially since LED voltages vary quite alot depending on type. Ignoring the LED voltage in this case also is an error on the "safe" side, because in reality the LED will get less current than calculated.
thank you very much I love it very nice and interesting video I learned so much from you very well explain I think you should make a book a simple book with the screen snip with simple comments I am in the line of Electronics I have several books in electronic but it is so complicated to understand your video is really very simple to understand thanks
I understood everything until you got to the power consumption. In your examples, you are showing how much power (watts) the bare circuit consumes without doing any other work (ex light bulb, etc). I understood the fact that the resistor consumes some power because the electrons bump into resistance within the resistor and causes heat (losing power - or consuming power). Therefore, I would have thought as you add more resistance, (the 10 ohm and then the 5 ohm and then another 5 ohm), that the power (watt) usage would have gone up but it went down in the calculation. That is a bit confusing. Maybe it is offset by the fact that the fact that the resistance causes less electrons to flow across the resistors per second and therefore even though there is power usage (heat), the power usage is overall lower by the slower flow of electrons?? Also, very well done set of instruction. I'm going to watch them all. thank you very much.
I agree it is counter intuitive. However, I think it goes like this: as you add more resistors to the series ciruit, the overall current (the current that goes through all of the resistors) goes down (as you said, less electrons flowing). In a series circuit, the current going through any resistor is always the same as the overall current. An equation for power is P = V * I. If 'V' is constant (9 volts), but 'I' decreases (say from .81 amps, to .45 amps) then the total P decreases too (if something on one side of the equation goes down, then something on the other side must go down to remain in equilibrium). This is true for each of the individual resistors also. First we know that V = I * R. Substitute that in for P = V * I, to get P = (I*R) * I = I^2 * R. First you calculate the overall current (by adding up all the resistors to get R total, and using V = I * R total), then you apply that overall current to each of the resistors individually to calculate the power consumed by each resistor. If the overall current is .81 amps, and one of the individual resistors is 10 ohms, then the power for that individual resistor is P = (0.81^2) * 10 = 6.561 watts. If the current is .45 amps (because we added another resistor in series), and the same resistor we considered before (not the resistor that was added) is still 10 ohms, then the power for that individual resistor is P = (0.45^2) * 10 = 2.025 watts. The power consumed by that resistor went down, because the overall current going through it went down.
⚠️ *Found this video super useful?* Buy Paul a coffee to say thanks: ☕
PayPal: www.paypal.me/TheEngineerinMindset
any chance we can a video about mechanical interlocking in switchgears?
Bro u r great because u r giving free education for everyone 💯 ..........
@@girisworkshop2131 because he's already rich at ❤ and he is one of the super engineer, he eats electrons to live so he
doesn't need to be greedy :)
I am
Me
The quality of this content is outstanding. If I don't understand something in school I try to find your videos. Thank you for taking the time to create this content. It's appreciated.
Genius is the ability to not only master a subject but also to pass that ability to others effectively. Thank you for your efforts.
Genius level
I had a mentor that said the ability of a teacher is not judged by what they know, but how much of what they know they can teach and how effectively they can teach it.
Jesus, I wish I had this kind of explanation on my university, After lots of struggling understanding this I finally understand it very well. Thank you very much!
I second that ahaha
Nice :) You´re in the University and they cannot really explain to you what a series circuit it´s like? _That´s hard!!
Man, when you´ll get to the point of Kirchoff´s Laws and some other physics material, you will find out that series circuits are easy... or at least easier..
I wish you very good luck :)
are you asking Jesus if you should have had this type of information in university?
I still don’t get it…. 😰
Don't take the Lord's name in vain
I started watching your Basics series and, as someone whom is nowhere a genius when it comes to electricity, this made questions I've had for decades seem so common sense. Thanks for explaining things in laymen's terms!
Absolutely love these videos! The metaphors used make it so simple to understand, really helping me understand the stuff my teachers just aren't explaining simply! Thanks so much!
My Friend, 0,0195 Amper! Thanks, the lessons are excellent
The Answer is 0.0195A. Thank you for creating these videos. Extremely helpful.
Or 19.5 Milliamps
am i dumb? i got 0.02A
@@jonjon4575 Your calculator would have just rounded the number up, sounds like you still got the correct answer.
@@jonjon4575 yeah, it got round up.
impossible to know exactly without knowing the wire size and composition. the max amps possible are still lower than .02 though.
Thank you! Having online classes are already difficult given the less amount of time our professors have to spend during synchronous classes. I can submit my paper for our laboratory experiment with confidence despite just having been given the task alone without discussing anything about the topic.
This channel has helped me so much with sparky school thank you all!
jeez, uploading this video in 4k must of taken hours, this guy is amazing!
Currently in Army BET lab, and this stuff went over my head today. Probably would have helped if it wasn't a class done completely by computer with minimal instructor guidance, but that's a complaint for the AAR.
Thank you so much for making these videos- I might actually graduate this course.
انت جامد بجد معرفش ليه المدرسين مش بيستعملوه طرق مبسطه كدا
Thank you ^^
Yes
wow dude, i was struggling to understand electricity for soooooo long its been a year, u popped up in my recommended, i feel blessed
This is the best!! I used today at work when I had to convert 2V signal to 4 mA signal because the sensor was taking mA and our controller was able to send only 2-10VDC signal and I wasn’t sure how to connect the resistor. Then I watched the video at work, understood everything and everything worked after I placed the 500 Ohms resistor in series. Thank you very much!
Crazy how much easier this was to understand compared to my online tafe videos, really mades a huge difference
This series is amazing. It has to be the best on TH-cam for teaching g this subject. Thank you very much for taking the time and effort to make this.
Thank you...
Its the best explanation, l ever had..
Great efforts for making us understand, will never be forgiven.
Answer for your last question
0.019 amps
Led will work.
watchin this for a&p school, ur a godsend for actually explaining WHY things happen and not just "thats how it works"
This is a great series of videos. Easily followed. Pretty thorough.
But, wow! Are they ever repetitive. I guess you wanted every video to stand on its own but I sure would prefer to have a series of trimmed videos.
excellent video! It addresses all of my doubts on series circuits
Very good. explanation of KVL Kirchhoff's voltage law and KCL Kirchhoff's current law. Well done.
Thank you
It's really helpful to study academic lessons otherwise ,.,..,.,its pretty rare to find a healthy video where pretty much all of your questions have been answered.,.,.,.,Thanks again......
Man, I love your explanations. Please give us more. I am now making my own playlists from your videos and really absorb everything. I even got a notebook and take notes. Is Paypal the only way to buy you a beer ? (I just hate paypal) . Cheers . Keep up the wonderful work.
Thanks!
this would be a small coffee paul
Thank you, Corey!
Love this, thanks for making It so interactive
thank you so much! the comparison of voltage to pressure made it so much easier for me to "get" the concept of voltage/p.d. !!!
Thank you sir for a simple but clearer explaination about series circuit
very helpful and easy to understand! hope you could make one content regarding RCD function and use and difference of RCD'S and BREAKERS? Keep it up, God Bless
Where were these videos when I was in highschool smh I would've loved science classes so much more. I love science and learning but holy cow was my education pisspoor. Thank you for the content!!
*summary:*
- if you have n resistors in a series, the total resistance in the circuit is the sum of them
- current is the same throughout the circuit (think as good as weakest link)
- if you have n voltage sources in a series, the total voltage across the circuit is the sum of them
- voltage will vary throughout the circuit (it depends on your two points of reference)
- resistors take some of the energy of electrons passing through them and convert them into heat
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Excellent
This is a best Channel i had ever seen please make more helpful videos
I swear, every engineering class I've taken so far has been taught better on TH-cam than they have been by my profs.
Yeah. Best part is, there's less frustration here than in class.
He explains thing very well. I thought that video was going to explain DC Series Circuits but the entire thing was about resistors. Useful but not what the title claimed.
Hi ;) I understand what you are saying, but i think the best way for you to understand how a series circuits works it´s just thinking about this:
In a series circuit the current that flows it´s always the same....
The only thing that can happen is that there are voltage drops.
And that is why if you measure between those resistances, there will always be voltage drops.
..But the electric current is always the same...
And remember this: In circuits of this type, what is in series will add up the values.
..As is the case with resistances ...I think very briefly, this is a series circuit ..
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Let me tell you that i enjoyed your explanation and graphics. Well Done !:)
Resume:
_Series circuits add up to their values and the current is always the same_Unless the measurement is between two load/resistor terminals. In that case, what is being measured is the load/resistor and not the serial circuit_
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Less than 2mA.
Thanks for the quality content.
Great channel, it would be great if you make a detailed AC vs DC motors & generators and how to convert one to the other.
DC motors explained th-cam.com/video/GQatiB-JHdI/w-d-xo.html
Great video!! Very clear and easy to understand
It’s always nice to learn from you mate cos it’s easy to grasp
I'm addicted to this series. It's bringing me right back to AP physics.
I’m on Christmas break for college and I’m here watching videos to have knowledge for next semester. I can’t believe I’m saying this but I am a nerd 😂.
Nerds run the world, keep learning
same lol
Be proud of it. Society is getting dumber, therefore people who thirst knowledge are getting rarer.
Me: practice to get ready for test
Bruh am doing these in high school
So much resistant that the empire strikes back
😂😂😂
Best comment by far. Didn't have to scroll any further.
Hi, love the video! Have a question though. At the 2:30min mark you show two examples - the left one is 9V battery, 400 Ohm resistor, LED and measured 18.7mA, the right one - 9V battery, 900 Ohm resistor, LED and measured 7.9mA. If there were no LEDs the measurements would have been - left 9/400=22.5mA, right 9/900=10mA. I have done some research and found that for those measurements to be true the left LED should be a yellow LED with a voltage rating of 1.8V doing best performance at 22mA - 1.8V/0.022A=81 Ohm, therefore 9V/(400+81)=18.7mA and the right one should be something like a white LED rated at 3.2V, going at 13-14mA, so 3.2V/0.0135A=237 Ohm, therefore 9V/(900+237)=7.9mA. Is my logic correct, because those measurements battled me hard??
It's not a given that it's a 9 volt that's just a basic shape to use for the model. Your supposed to find the voltage in that scenario by converting the miliamps to amps, 18.7 x 1000 and then x 400 ohms gives you a 7.48 volt battery
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
You are doing a great job brother. Thanks for the help
thiis video really helped me clesr my igcse circuit concepts
Best video regarding this topic
5:54 I tested this and my results are different. If I put 10 ohms on a 9V power source I get burned fingers instead of 9V
Your resistor power rating has to be higher than the power consumption of the resistor.
Then YOU'll become the resistor, you must put the multimeter in your correct pole!
How´s that? Do the same way he did ! The cable must be isolated... Then, before you connect everything to the battery, first connect the resistor with the cable. Ok, now, you can connect the cable points to the battery!!
When you´ll be ready to measure, grab you Multimeter put it in the right measure position,=Voltage,Current or resistence=,
and put the Multimeter terminals on each side of the resistor.
And this is how you will have a read !
PS: In that especific case, you can measure the voltage but also the current. So, you apply a known formula__Ohm´s LAw_
The voltage you already know= 9Volts.
Now you want to know the Current_! SO, OHm´s Law:: Voltage= Restitance * Current__!!!!! To know now the current:::
::::::: Current = Voltage / Resitance::::: So, Volts= 9 volts / Resistance=10 ohm = TOTAL= 0.9 Amper (current).
Sorry for all this, but i felt that you might need it ;)
@@sophiacristina some devices will show negative reading though
Check our new Multimeter tutorial out ➡️ th-cam.com/video/4lAyzRxsbDc/w-d-xo.html
Thank you for this video "DC Series circuits explained" 👍
Thanks, Now I REALLY understand this
Thank you for great explanation 😊
Your content is soo good
You teach each topic very well
1:00 thank you for explaining the difference.
I like the questions at the end they're fun and engageing.
Best part!
Great videos! It would be nice if you could so nicely explain a) transistors, and b) rectifiers also while youre in a go, which are hardest for me to learn via youtube :P Thx!
Transistor video now live: th-cam.com/video/J4oO7PT_nzQ/w-d-xo.html
Rectifier video here th-cam.com/video/RiRyzLl4Y8U/w-d-xo.html
the video is very helpful for me. thank you very much.
Amazing video well done, by the way, yes the current will be less than 0.02A
U have a great way of explaining things! Thank you ❤
Cool!👍👍👍
Thanks Paul,
I have a question, if we apply the same concept about more resistance gives less current, into a circuit in a house.
Why when we have a lot of items working in the same time (resistor is high), the current in the circuit gets overloaded and the circuit breaker trips. Shouldnt the current passing that circuit be less due to the high resistance? Which means CB should not trip. Hope my question make sense 😅
Your house appliances are wired in parallel
@@EngineeringMindset hloo sir, if in house there is a parallel connecting,then voltage same for all but current split as more as aploncse are connect. So this mean that appliances work on low current or we can say current not influence as much as voltage.plz and. Me
Answer me
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Seen our new incredibly detailed MCB video? link: th-cam.com/video/gqEu9t8HwW0/w-d-xo.html
Thanks Paul. I have subscribed and liked as well.
You are great sir! Sir please mak videos on electronic basic elements.... Please sir❤🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺
I actually understood this. Calculated correct answer to last problem. Was happy it was correct, but that's purpose of a formula.. it's proven.
You make electronics seem simple.
Can you be my father?
What can I say but a massive big thankyou so so informative and so kind for sharing cheers john
Sorry if this is a confusing or dumb. When he talks about watts in the end of the video, is he talking about it being the power consumption of the all the resistors? Or if he were to put a light bulb on to the circuit, That the bulb would be powered with how ever many watts with a 9V battery at the end of the of the circuit.
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Great video ! But. The links you mentioned are not down below Paul 😭😭😭😭
Let me know links are missing, I'll add them
@@EngineeringMindset in this one you mention that the one for parallel circuits will be down below but it wasn't. And in your other videos also the links you mention would be down below are usually not there because your description has only selected highlighted links in the electrical section for every description. I don't mind searching them separately but it would still be great if you could add the links you mention at the top of your description or in your pinned comment. Thank you 😭
OK thanks, it's usually a long process from making the video to getting it published so sometimes I miss these links. If yiu find any more let me know and I'll update
@@EngineeringMindset indeed it is a long process ! Your content is much appreciated ! And your IG has some very worth it memes, I recently visited the page 😂😂 Thanks and keep up the good work ! :)) 🤙🏻🤙🏻
thank you for this, love this channel
These videos are the best, but I can't find any on kirchhoff's law? 😢
Great video! Quick question - why is current represented using A? I thought current was represented using I?
An ampere ('A') is the unit used to measure electric current. Current ('I') is a count of the number of electrons flowing through a circuit.
@The Engineering Mindset I have a question. If at 8:09 the Voltage drop accross the resistor is 9 Volts, then doesn't that mean that the circuit has lost all of it's potential difference and then there is no longer any current running through the wire after the resistor because there is no longer a difference in voltage? Thank you for your consideration of my question, I am really stumped and have throughly enjoyed your videos enough to want to endorse you. That's how much I appreciate you
Because if the supply voltage is 9 volts, then if the voltage drops by 9 volts, then shouldn't there be net 0 volts left after the resistor? Thank you so much for the help.
After the resistor, the voltage is 0v, because we can only measure the difference in voltage across two points. So if we measure with reference to ground which is 0V and the other probe is also connected to ground then there is no difference so we would read 0V. Maybe if you had a very very precise multimeter you could read like 0.001V or something because the wire will have some resistance, unless you measure at exactly the same point. The voltage difference is still across the load (resistor) so current will still flow, the electrons must flow back to complete the circuit and keep the chemical reaction of the battery going.
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Yo! Bro
Thanks for good explanation
thank you
great video ! Does it mean if We used conventional flow from positive to negative, the resistant will be on the positive branch ? I am confused with the diagram drawings
Very informal, Thank you. Maybe next time I should eat may breakfast before I watch a video like yours :)
Thank you so much for all of this.
Sir,zener diode working principle and necessity of zener in electronic projects....
Make Video on it...please sir....
Cool, got the Fluke 87v, now I just need to learn how to use it.
amazing I'm very sleepy😴😴
unbelievably just thank you
thanks a lot sir...great explanation
Thank you very much for enlightened my knowledgs
I wish you were my college lecturer 25 years ago.
The math is basic and simple to understand but I didn't find this tutorial particularly intuitive for someone starting from zero understanding trying to grasp electricity & circuits. Why are there resistors in this circuit at all (i.e. what is the application?). What is the significance of voltage drops? Can you address the seeming counterintuitiveness of wattage decreasing as more resistance is added?
The resistor dissipates electricity as heat causing the system to lose some power so that less “work” is able to be done (defined as watts)
Resistors are used to avoid blowing out components by overwhelming them with more power in the system than they can handle. Otherwise they could explode like the small thin filament of an incandescent lightbulb, unable to handle too much power going through it or the delicate power balance allowing it to shine and give off heat like it’s designed for will turn into an uncontrolled “melt down” of sorts so to speak
Great vedio Sir.... Many thanks
You're welcome
THIS WAS AWESOME ❤️
Fantastic.....
Excellent video sir, kindly let me know this, IS that any time limit for dc current measurement in SERIES like 10 seconds or i can leave my multimeter connected in SERIES while battery is charging the whole time ?
There's no time limit.
@@littlegenius6932 but my multimeter printed on ( 10 amp dc current measurement for 10 sec ) still i can measure it for long time or should i use shunt thanks for your reply
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Current=9v/460 ohm=0.0195 amp which is less than .02 amp.
The led will be ok and light up.
Thank you Sir.
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In the circuit with an led and resistors you calculate the current as if the resistors were connected to 9v directly. Shouldn't it be 6v because the led is dissipating 3v?
and most LEDs dont like 9v, typically 1.9- 3.6v depending upon color. so increasing resistance not only reduces current but voltage
Yes, but that would make the video too complicated, especially since LED voltages vary quite alot depending on type. Ignoring the LED voltage in this case also is an error on the "safe" side, because in reality the LED will get less current than calculated.
Yup. You remove whatever voltage across the resistor that the LED blocks.
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thats amazing thanks so much!
Hi! This video is good. I have a question, can You make your videos for spanish too please? Or a translation in spanish. Thanks
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Is There Any Video Related To Node and Loop Analysis?
Thanks for making this video it is very useful.
Please tell me connection of UPS batteries are connected in series or parallel.
Just one wat h of this before starting a DC cor units class gives you a significant chance at a higher grade kids.
thank you very much I love it very nice and interesting video I learned so much from you very well explain I think you should make a book a simple book with the screen snip with simple comments I am in the line of Electronics I have several books in electronic but it is so complicated to understand your video is really very simple to understand thanks
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Do electrons flow back to the negative side of the battery to keep the electrons in the wire constant?
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Good explanation sir
I understood everything until you got to the power consumption. In your examples, you are showing how much power (watts) the bare circuit consumes without doing any other work (ex light bulb, etc). I understood the fact that the resistor consumes some power because the electrons bump into resistance within the resistor and causes heat (losing power - or consuming power). Therefore, I would have thought as you add more resistance, (the 10 ohm and then the 5 ohm and then another 5 ohm), that the power (watt) usage would have gone up but it went down in the calculation. That is a bit confusing. Maybe it is offset by the fact that the fact that the resistance causes less electrons to flow across the resistors per second and therefore even though there is power usage (heat), the power usage is overall lower by the slower flow of electrons??
Also, very well done set of instruction. I'm going to watch them all. thank you very much.
I agree it is counter intuitive. However, I think it goes like this: as you add more resistors to the series ciruit, the overall current (the current that goes through all of the resistors) goes down (as you said, less electrons flowing). In a series circuit, the current going through any resistor is always the same as the overall current. An equation for power is P = V * I. If 'V' is constant (9 volts), but 'I' decreases (say from .81 amps, to .45 amps) then the total P decreases too (if something on one side of the equation goes down, then something on the other side must go down to remain in equilibrium). This is true for each of the individual resistors also. First we know that V = I * R. Substitute that in for P = V * I, to get P = (I*R) * I = I^2 * R. First you calculate the overall current (by adding up all the resistors to get R total, and using V = I * R total), then you apply that overall current to each of the resistors individually to calculate the power consumed by each resistor. If the overall current is .81 amps, and one of the individual resistors is 10 ohms, then the power for that individual resistor is P = (0.81^2) * 10 = 6.561 watts. If the current is .45 amps (because we added another resistor in series), and the same resistor we considered before (not the resistor that was added) is still 10 ohms, then the power for that individual resistor is P = (0.45^2) * 10 = 2.025 watts. The power consumed by that resistor went down, because the overall current going through it went down.
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Amazing !!!
Thanks glad you liked it
Thank you