Jesus, I wish I had this kind of explanation on my university, After lots of struggling understanding this I finally understand it very well. Thank you very much!
Nice :) You´re in the University and they cannot really explain to you what a series circuit it´s like? _That´s hard!! Man, when you´ll get to the point of Kirchoff´s Laws and some other physics material, you will find out that series circuits are easy... or at least easier.. I wish you very good luck :)
I had a mentor that said the ability of a teacher is not judged by what they know, but how much of what they know they can teach and how effectively they can teach it.
The quality of this content is outstanding. If I don't understand something in school I try to find your videos. Thank you for taking the time to create this content. It's appreciated.
Absolutely love these videos! The metaphors used make it so simple to understand, really helping me understand the stuff my teachers just aren't explaining simply! Thanks so much!
I started watching your Basics series and, as someone whom is nowhere a genius when it comes to electricity, this made questions I've had for decades seem so common sense. Thanks for explaining things in laymen's terms!
*summary:* - if you have n resistors in a series, the total resistance in the circuit is the sum of them - current is the same throughout the circuit (think as good as weakest link) - if you have n voltage sources in a series, the total voltage across the circuit is the sum of them - voltage will vary throughout the circuit (it depends on your two points of reference) - resistors take some of the energy of electrons passing through them and convert them into heat
Thank you! Having online classes are already difficult given the less amount of time our professors have to spend during synchronous classes. I can submit my paper for our laboratory experiment with confidence despite just having been given the task alone without discussing anything about the topic.
This is the best!! I used today at work when I had to convert 2V signal to 4 mA signal because the sensor was taking mA and our controller was able to send only 2-10VDC signal and I wasn’t sure how to connect the resistor. Then I watched the video at work, understood everything and everything worked after I placed the 500 Ohms resistor in series. Thank you very much!
How´s that? Do the same way he did ! The cable must be isolated... Then, before you connect everything to the battery, first connect the resistor with the cable. Ok, now, you can connect the cable points to the battery!! When you´ll be ready to measure, grab you Multimeter put it in the right measure position,=Voltage,Current or resistence=, and put the Multimeter terminals on each side of the resistor. And this is how you will have a read ! PS: In that especific case, you can measure the voltage but also the current. So, you apply a known formula__Ohm´s LAw_ The voltage you already know= 9Volts. Now you want to know the Current_! SO, OHm´s Law:: Voltage= Restitance * Current__!!!!! To know now the current::: ::::::: Current = Voltage / Resitance::::: So, Volts= 9 volts / Resistance=10 ohm = TOTAL= 0.9 Amper (current). Sorry for all this, but i felt that you might need it ;)
Currently in Army BET lab, and this stuff went over my head today. Probably would have helped if it wasn't a class done completely by computer with minimal instructor guidance, but that's a complaint for the AAR. Thank you so much for making these videos- I might actually graduate this course.
It's really helpful to study academic lessons otherwise ,.,..,.,its pretty rare to find a healthy video where pretty much all of your questions have been answered.,.,.,.,Thanks again......
This is a great series of videos. Easily followed. Pretty thorough. But, wow! Are they ever repetitive. I guess you wanted every video to stand on its own but I sure would prefer to have a series of trimmed videos.
Where were these videos when I was in highschool smh I would've loved science classes so much more. I love science and learning but holy cow was my education pisspoor. Thank you for the content!!
Let me tell you that i enjoyed your explanation and graphics. Well Done !:) Resume: _Series circuits add up to their values and the current is always the same_Unless the measurement is between two load/resistor terminals. In that case, what is being measured is the load/resistor and not the serial circuit_
Hi, love the video! Have a question though. At the 2:30min mark you show two examples - the left one is 9V battery, 400 Ohm resistor, LED and measured 18.7mA, the right one - 9V battery, 900 Ohm resistor, LED and measured 7.9mA. If there were no LEDs the measurements would have been - left 9/400=22.5mA, right 9/900=10mA. I have done some research and found that for those measurements to be true the left LED should be a yellow LED with a voltage rating of 1.8V doing best performance at 22mA - 1.8V/0.022A=81 Ohm, therefore 9V/(400+81)=18.7mA and the right one should be something like a white LED rated at 3.2V, going at 13-14mA, so 3.2V/0.0135A=237 Ohm, therefore 9V/(900+237)=7.9mA. Is my logic correct, because those measurements battled me hard??
It's not a given that it's a 9 volt that's just a basic shape to use for the model. Your supposed to find the voltage in that scenario by converting the miliamps to amps, 18.7 x 1000 and then x 400 ohms gives you a 7.48 volt battery
I’m on Christmas break for college and I’m here watching videos to have knowledge for next semester. I can’t believe I’m saying this but I am a nerd 😂.
very helpful and easy to understand! hope you could make one content regarding RCD function and use and difference of RCD'S and BREAKERS? Keep it up, God Bless
He explains thing very well. I thought that video was going to explain DC Series Circuits but the entire thing was about resistors. Useful but not what the title claimed.
Hi ;) I understand what you are saying, but i think the best way for you to understand how a series circuits works it´s just thinking about this: In a series circuit the current that flows it´s always the same.... The only thing that can happen is that there are voltage drops. And that is why if you measure between those resistances, there will always be voltage drops. ..But the electric current is always the same... And remember this: In circuits of this type, what is in series will add up the values. ..As is the case with resistances ...I think very briefly, this is a series circuit ..
So it doesn't matter where within the circuit that the resistors are placed? I've seen diagrams that show a simple battery and LED setup with the resistor "before" and "after" the LED light. If electrons are flowing from the battery and the resistor is needed to effectively slow down or de-pressurize the electricity to keep the LED light safe, how is it that they can appear after the LED in the circuit? This may seem stupid but I simultaneously get it and don't get it. I get how "they do the same job anywhere in a circuit" may be right but something in my brain thinks that makes no sense. Edit: Ok, looked around and I learned that it doesn't matter because of a basic rule that I guess I took too literally with the water analogy. I'm glad I was able to get to this altered (but correct) way of seeing it now, as opposed to later. *Voltage is equal across the circuit from beginning to end, immediately. Meaning that a resistor anywhere has the same effect across the circuit* So, don't think of this in the sense of electrons bursting out of the source and flowing like a tidal wave across the circuit. That "start here and run to the end" idea isn't exactly right. Think of it in the sense that the moment the circuit is complete it has a set, stable voltage from the beginning and end at essentially the same time BECAUSE of what voltage is/means. In this sense you have to lose or alter the water analogy a bit. This seems like a basic notion but I'm clearly not alone because a google search came back with literally hundreds of discussions about this very topic/question. Haha. It must be a way that some of us interpret the water anlogy as we applied it a bit too literally or strictly.
Thanks for pointing this out. I assumed to protect the LED it would have to be upstream, like a fuse, but this makes sense, the resistor can act like a valve to control flow either upstream or downstream.
Man, I love your explanations. Please give us more. I am now making my own playlists from your videos and really absorb everything. I even got a notebook and take notes. Is Paypal the only way to buy you a beer ? (I just hate paypal) . Cheers . Keep up the wonderful work.
Thanks Paul, I have a question, if we apply the same concept about more resistance gives less current, into a circuit in a house. Why when we have a lot of items working in the same time (resistor is high), the current in the circuit gets overloaded and the circuit breaker trips. Shouldnt the current passing that circuit be less due to the high resistance? Which means CB should not trip. Hope my question make sense 😅
@@EngineeringMindset hloo sir, if in house there is a parallel connecting,then voltage same for all but current split as more as aploncse are connect. So this mean that appliances work on low current or we can say current not influence as much as voltage.plz and. Me
@The Engineering Mindset I have a question. If at 8:09 the Voltage drop accross the resistor is 9 Volts, then doesn't that mean that the circuit has lost all of it's potential difference and then there is no longer any current running through the wire after the resistor because there is no longer a difference in voltage? Thank you for your consideration of my question, I am really stumped and have throughly enjoyed your videos enough to want to endorse you. That's how much I appreciate you
Because if the supply voltage is 9 volts, then if the voltage drops by 9 volts, then shouldn't there be net 0 volts left after the resistor? Thank you so much for the help.
After the resistor, the voltage is 0v, because we can only measure the difference in voltage across two points. So if we measure with reference to ground which is 0V and the other probe is also connected to ground then there is no difference so we would read 0V. Maybe if you had a very very precise multimeter you could read like 0.001V or something because the wire will have some resistance, unless you measure at exactly the same point. The voltage difference is still across the load (resistor) so current will still flow, the electrons must flow back to complete the circuit and keep the chemical reaction of the battery going.
In the circuit with an led and resistors you calculate the current as if the resistors were connected to 9v directly. Shouldn't it be 6v because the led is dissipating 3v?
Yes, but that would make the video too complicated, especially since LED voltages vary quite alot depending on type. Ignoring the LED voltage in this case also is an error on the "safe" side, because in reality the LED will get less current than calculated.
Quick question : At 8:14 you say Total current = 9v/10Ω = 0.9A R1 Voltage drop = 0.9A x 10Ω = 9V My question is if my 9V battery was initially rated 2A. Using this formulae, no matter the original amperage of the battery, the equated (end results) will always be 0.9A?
Amp ratings for things like batteries or power supplies tells you the maximum amperage that the device can handle safely; a 2A rating doesn't mean that the battery will supply 2A in all cases.
The examples are a simplification. A battery has an internal resistance (not on purpose, that's just how the chemistry works). If you draw 2A out of a 9V battery you will most likely just get a few volts at the terminals, because the rest is already lost to the internal resistance. 9V batteries aren't made for high currents.
Sorry if this is a confusing or dumb. When he talks about watts in the end of the video, is he talking about it being the power consumption of the all the resistors? Or if he were to put a light bulb on to the circuit, That the bulb would be powered with how ever many watts with a 9V battery at the end of the of the circuit.
great video ! Does it mean if We used conventional flow from positive to negative, the resistant will be on the positive branch ? I am confused with the diagram drawings
Great videos! It would be nice if you could so nicely explain a) transistors, and b) rectifiers also while youre in a go, which are hardest for me to learn via youtube :P Thx!
7:32 you show an animation of a resistor and electrons flowing through it. you say, the same amount of electrons enter and exit. wouldn't this mean, the same current? But according to I = U / R, current is indeed altered through a resistor. Does the animation visualize the so called "energy loss" of the electrons? How can electrons lose energy, if not by slowing down?
@@johnellison1635 assuming you’re asking about testing them in series without disconnecting them from the circuit individually, you will get the cumulative effect of the resistors before the resistors down the circuit. To test an individual resistor; you must isolate said resistor from circuit or else your reading will be incorrect. Hope this helped.
Albret Einstein once said "if you cant explain to a 5 yr old, you don't know it well enough" or something like that and you could show this to a 3rd grade class and they would become geniuses
Excellent video sir, kindly let me know this, IS that any time limit for dc current measurement in SERIES like 10 seconds or i can leave my multimeter connected in SERIES while battery is charging the whole time ?
@@littlegenius6932 but my multimeter printed on ( 10 amp dc current measurement for 10 sec ) still i can measure it for long time or should i use shunt thanks for your reply
thank you very much I love it very nice and interesting video I learned so much from you very well explain I think you should make a book a simple book with the screen snip with simple comments I am in the line of Electronics I have several books in electronic but it is so complicated to understand your video is really very simple to understand thanks
⚠️ *Found this video super useful?* Buy Paul a coffee to say thanks: ☕
PayPal: www.paypal.me/TheEngineerinMindset
any chance we can a video about mechanical interlocking in switchgears?
Bro u r great because u r giving free education for everyone 💯 ..........
@@girisworkshop2131 because he's already rich at ❤ and he is one of the super engineer, he eats electrons to live so he
doesn't need to be greedy :)
I am
Me
Jesus, I wish I had this kind of explanation on my university, After lots of struggling understanding this I finally understand it very well. Thank you very much!
I second that ahaha
Nice :) You´re in the University and they cannot really explain to you what a series circuit it´s like? _That´s hard!!
Man, when you´ll get to the point of Kirchoff´s Laws and some other physics material, you will find out that series circuits are easy... or at least easier..
I wish you very good luck :)
are you asking Jesus if you should have had this type of information in university?
I still don’t get it…. 😰
Don't take the Lord's name in vain
Genius is the ability to not only master a subject but also to pass that ability to others effectively. Thank you for your efforts.
Genius level
I had a mentor that said the ability of a teacher is not judged by what they know, but how much of what they know they can teach and how effectively they can teach it.
The quality of this content is outstanding. If I don't understand something in school I try to find your videos. Thank you for taking the time to create this content. It's appreciated.
My Friend, 0,0195 Amper! Thanks, the lessons are excellent
The Answer is 0.0195A. Thank you for creating these videos. Extremely helpful.
Or 19.5 Milliamps
am i dumb? i got 0.02A
@@jonjon4575 Your calculator would have just rounded the number up, sounds like you still got the correct answer.
@@jonjon4575 yeah, it got round up.
impossible to know exactly without knowing the wire size and composition. the max amps possible are still lower than .02 though.
Absolutely love these videos! The metaphors used make it so simple to understand, really helping me understand the stuff my teachers just aren't explaining simply! Thanks so much!
I started watching your Basics series and, as someone whom is nowhere a genius when it comes to electricity, this made questions I've had for decades seem so common sense. Thanks for explaining things in laymen's terms!
*summary:*
- if you have n resistors in a series, the total resistance in the circuit is the sum of them
- current is the same throughout the circuit (think as good as weakest link)
- if you have n voltage sources in a series, the total voltage across the circuit is the sum of them
- voltage will vary throughout the circuit (it depends on your two points of reference)
- resistors take some of the energy of electrons passing through them and convert them into heat
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Excellent
انت جامد بجد معرفش ليه المدرسين مش بيستعملوه طرق مبسطه كدا
Thank you ^^
Yes
This channel has helped me so much with sparky school thank you all!
Thank you! Having online classes are already difficult given the less amount of time our professors have to spend during synchronous classes. I can submit my paper for our laboratory experiment with confidence despite just having been given the task alone without discussing anything about the topic.
jeez, uploading this video in 4k must of taken hours, this guy is amazing!
wow dude, i was struggling to understand electricity for soooooo long its been a year, u popped up in my recommended, i feel blessed
This is the best!! I used today at work when I had to convert 2V signal to 4 mA signal because the sensor was taking mA and our controller was able to send only 2-10VDC signal and I wasn’t sure how to connect the resistor. Then I watched the video at work, understood everything and everything worked after I placed the 500 Ohms resistor in series. Thank you very much!
5:54 I tested this and my results are different. If I put 10 ohms on a 9V power source I get burned fingers instead of 9V
Your resistor power rating has to be higher than the power consumption of the resistor.
Then YOU'll become the resistor, you must put the multimeter in your correct pole!
How´s that? Do the same way he did ! The cable must be isolated... Then, before you connect everything to the battery, first connect the resistor with the cable. Ok, now, you can connect the cable points to the battery!!
When you´ll be ready to measure, grab you Multimeter put it in the right measure position,=Voltage,Current or resistence=,
and put the Multimeter terminals on each side of the resistor.
And this is how you will have a read !
PS: In that especific case, you can measure the voltage but also the current. So, you apply a known formula__Ohm´s LAw_
The voltage you already know= 9Volts.
Now you want to know the Current_! SO, OHm´s Law:: Voltage= Restitance * Current__!!!!! To know now the current:::
::::::: Current = Voltage / Resitance::::: So, Volts= 9 volts / Resistance=10 ohm = TOTAL= 0.9 Amper (current).
Sorry for all this, but i felt that you might need it ;)
@@sophiacristina some devices will show negative reading though
Check our new Multimeter tutorial out ➡️ th-cam.com/video/4lAyzRxsbDc/w-d-xo.html
Crazy how much easier this was to understand compared to my online tafe videos, really mades a huge difference
Thank you...
Its the best explanation, l ever had..
Great efforts for making us understand, will never be forgiven.
Answer for your last question
0.019 amps
Led will work.
Currently in Army BET lab, and this stuff went over my head today. Probably would have helped if it wasn't a class done completely by computer with minimal instructor guidance, but that's a complaint for the AAR.
Thank you so much for making these videos- I might actually graduate this course.
watchin this for a&p school, ur a godsend for actually explaining WHY things happen and not just "thats how it works"
This series is amazing. It has to be the best on TH-cam for teaching g this subject. Thank you very much for taking the time and effort to make this.
excellent video! It addresses all of my doubts on series circuits
Very good. explanation of KVL Kirchhoff's voltage law and KCL Kirchhoff's current law. Well done.
Thank you
Less than 2mA.
Thanks for the quality content.
Love this, thanks for making It so interactive
It's really helpful to study academic lessons otherwise ,.,..,.,its pretty rare to find a healthy video where pretty much all of your questions have been answered.,.,.,.,Thanks again......
Thank you sir for a simple but clearer explaination about series circuit
So much resistant that the empire strikes back
😂😂😂
Best comment by far. Didn't have to scroll any further.
thank you so much! the comparison of voltage to pressure made it so much easier for me to "get" the concept of voltage/p.d. !!!
Thanks!
this would be a small coffee paul
Thank you, Corey!
This is a great series of videos. Easily followed. Pretty thorough.
But, wow! Are they ever repetitive. I guess you wanted every video to stand on its own but I sure would prefer to have a series of trimmed videos.
Where were these videos when I was in highschool smh I would've loved science classes so much more. I love science and learning but holy cow was my education pisspoor. Thank you for the content!!
Great video!! Very clear and easy to understand
You make electronics seem simple.
Can you be my father?
This is a best Channel i had ever seen please make more helpful videos
Let me tell you that i enjoyed your explanation and graphics. Well Done !:)
Resume:
_Series circuits add up to their values and the current is always the same_Unless the measurement is between two load/resistor terminals. In that case, what is being measured is the load/resistor and not the serial circuit_
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Hi, love the video! Have a question though. At the 2:30min mark you show two examples - the left one is 9V battery, 400 Ohm resistor, LED and measured 18.7mA, the right one - 9V battery, 900 Ohm resistor, LED and measured 7.9mA. If there were no LEDs the measurements would have been - left 9/400=22.5mA, right 9/900=10mA. I have done some research and found that for those measurements to be true the left LED should be a yellow LED with a voltage rating of 1.8V doing best performance at 22mA - 1.8V/0.022A=81 Ohm, therefore 9V/(400+81)=18.7mA and the right one should be something like a white LED rated at 3.2V, going at 13-14mA, so 3.2V/0.0135A=237 Ohm, therefore 9V/(900+237)=7.9mA. Is my logic correct, because those measurements battled me hard??
It's not a given that it's a 9 volt that's just a basic shape to use for the model. Your supposed to find the voltage in that scenario by converting the miliamps to amps, 18.7 x 1000 and then x 400 ohms gives you a 7.48 volt battery
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
I swear, every engineering class I've taken so far has been taught better on TH-cam than they have been by my profs.
Yeah. Best part is, there's less frustration here than in class.
Cool!👍👍👍
Best video regarding this topic
I’m on Christmas break for college and I’m here watching videos to have knowledge for next semester. I can’t believe I’m saying this but I am a nerd 😂.
Nerds run the world, keep learning
same lol
Be proud of it. Society is getting dumber, therefore people who thirst knowledge are getting rarer.
Me: practice to get ready for test
Bruh am doing these in high school
I'm addicted to this series. It's bringing me right back to AP physics.
1:00 thank you for explaining the difference.
very helpful and easy to understand! hope you could make one content regarding RCD function and use and difference of RCD'S and BREAKERS? Keep it up, God Bless
at 08:00 you said 9v dropped br 9 v ,wouldnt that result in 0v ?
He explains thing very well. I thought that video was going to explain DC Series Circuits but the entire thing was about resistors. Useful but not what the title claimed.
Hi ;) I understand what you are saying, but i think the best way for you to understand how a series circuits works it´s just thinking about this:
In a series circuit the current that flows it´s always the same....
The only thing that can happen is that there are voltage drops.
And that is why if you measure between those resistances, there will always be voltage drops.
..But the electric current is always the same...
And remember this: In circuits of this type, what is in series will add up the values.
..As is the case with resistances ...I think very briefly, this is a series circuit ..
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
It’s always nice to learn from you mate cos it’s easy to grasp
Thank you for great explanation 😊
Thank you for this video "DC Series circuits explained" 👍
So it doesn't matter where within the circuit that the resistors are placed?
I've seen diagrams that show a simple battery and LED setup with the resistor "before" and "after" the LED light.
If electrons are flowing from the battery and the resistor is needed to effectively slow down or de-pressurize the electricity to keep the LED light safe, how is it that they can appear after the LED in the circuit?
This may seem stupid but I simultaneously get it and don't get it. I get how "they do the same job anywhere in a circuit" may be right but something in my brain thinks that makes no sense.
Edit: Ok, looked around and I learned that it doesn't matter because of a basic rule that I guess I took too literally with the water analogy. I'm glad I was able to get to this altered (but correct) way of seeing it now, as opposed to later.
*Voltage is equal across the circuit from beginning to end, immediately. Meaning that a resistor anywhere has the same effect across the circuit*
So, don't think of this in the sense of electrons bursting out of the source and flowing like a tidal wave across the circuit. That "start here and run to the end" idea isn't exactly right. Think of it in the sense that the moment the circuit is complete it has a set, stable voltage from the beginning and end at essentially the same time BECAUSE of what voltage is/means. In this sense you have to lose or alter the water analogy a bit.
This seems like a basic notion but I'm clearly not alone because a google search came back with literally hundreds of discussions about this very topic/question. Haha.
It must be a way that some of us interpret the water anlogy as we applied it a bit too literally or strictly.
DannyWilliamH I had the same question/perplexion
Thanks for pointing this out. I assumed to protect the LED it would have to be upstream, like a fuse, but this makes sense, the resistor can act like a valve to control flow either upstream or downstream.
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Thanks, Now I REALLY understand this
thiis video really helped me clesr my igcse circuit concepts
Man, I love your explanations. Please give us more. I am now making my own playlists from your videos and really absorb everything. I even got a notebook and take notes. Is Paypal the only way to buy you a beer ? (I just hate paypal) . Cheers . Keep up the wonderful work.
You are doing a great job brother. Thanks for the help
Sir,zener diode working principle and necessity of zener in electronic projects....
Make Video on it...please sir....
Thanks Paul,
I have a question, if we apply the same concept about more resistance gives less current, into a circuit in a house.
Why when we have a lot of items working in the same time (resistor is high), the current in the circuit gets overloaded and the circuit breaker trips. Shouldnt the current passing that circuit be less due to the high resistance? Which means CB should not trip. Hope my question make sense 😅
Your house appliances are wired in parallel
@@EngineeringMindset hloo sir, if in house there is a parallel connecting,then voltage same for all but current split as more as aploncse are connect. So this mean that appliances work on low current or we can say current not influence as much as voltage.plz and. Me
Answer me
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Seen our new incredibly detailed MCB video? link: th-cam.com/video/gqEu9t8HwW0/w-d-xo.html
Great channel, it would be great if you make a detailed AC vs DC motors & generators and how to convert one to the other.
DC motors explained th-cam.com/video/GQatiB-JHdI/w-d-xo.html
Amazing video well done, by the way, yes the current will be less than 0.02A
@The Engineering Mindset I have a question. If at 8:09 the Voltage drop accross the resistor is 9 Volts, then doesn't that mean that the circuit has lost all of it's potential difference and then there is no longer any current running through the wire after the resistor because there is no longer a difference in voltage? Thank you for your consideration of my question, I am really stumped and have throughly enjoyed your videos enough to want to endorse you. That's how much I appreciate you
Because if the supply voltage is 9 volts, then if the voltage drops by 9 volts, then shouldn't there be net 0 volts left after the resistor? Thank you so much for the help.
After the resistor, the voltage is 0v, because we can only measure the difference in voltage across two points. So if we measure with reference to ground which is 0V and the other probe is also connected to ground then there is no difference so we would read 0V. Maybe if you had a very very precise multimeter you could read like 0.001V or something because the wire will have some resistance, unless you measure at exactly the same point. The voltage difference is still across the load (resistor) so current will still flow, the electrons must flow back to complete the circuit and keep the chemical reaction of the battery going.
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Very informal, Thank you. Maybe next time I should eat may breakfast before I watch a video like yours :)
In the circuit with an led and resistors you calculate the current as if the resistors were connected to 9v directly. Shouldn't it be 6v because the led is dissipating 3v?
and most LEDs dont like 9v, typically 1.9- 3.6v depending upon color. so increasing resistance not only reduces current but voltage
Yes, but that would make the video too complicated, especially since LED voltages vary quite alot depending on type. Ignoring the LED voltage in this case also is an error on the "safe" side, because in reality the LED will get less current than calculated.
Yup. You remove whatever voltage across the resistor that the LED blocks.
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
0.0195 is the answer which is missing in the video description as said@11:07 :)
0.0196*
the video is very helpful for me. thank you very much.
I actually understood this. Calculated correct answer to last problem. Was happy it was correct, but that's purpose of a formula.. it's proven.
Quick question : At 8:14 you say Total current = 9v/10Ω = 0.9A
R1 Voltage drop = 0.9A x 10Ω = 9V
My question is if my 9V battery was initially rated 2A. Using this formulae, no matter the original amperage of the battery, the equated (end results) will always be 0.9A?
Amp ratings for things like batteries or power supplies tells you the maximum amperage that the device can handle safely; a 2A rating doesn't mean that the battery will supply 2A in all cases.
The examples are a simplification. A battery has an internal resistance (not on purpose, that's just how the chemistry works). If you draw 2A out of a 9V battery you will most likely just get a few volts at the terminals, because the rest is already lost to the internal resistance. 9V batteries aren't made for high currents.
Sorry if this is a confusing or dumb. When he talks about watts in the end of the video, is he talking about it being the power consumption of the all the resistors? Or if he were to put a light bulb on to the circuit, That the bulb would be powered with how ever many watts with a 9V battery at the end of the of the circuit.
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I like the questions at the end they're fun and engageing.
Best part!
great video ! Does it mean if We used conventional flow from positive to negative, the resistant will be on the positive branch ? I am confused with the diagram drawings
What can I say but a massive big thankyou so so informative and so kind for sharing cheers john
Current=9v/460 ohm=0.0195 amp which is less than .02 amp.
The led will be ok and light up.
Thank you Sir.
Seen the new LED explained video? so much detail covered! th-cam.com/video/O8M2z2hIbag/w-d-xo.html
Thanks Paul. I have subscribed and liked as well.
Great videos! It would be nice if you could so nicely explain a) transistors, and b) rectifiers also while youre in a go, which are hardest for me to learn via youtube :P Thx!
Transistor video now live: th-cam.com/video/J4oO7PT_nzQ/w-d-xo.html
Rectifier video here th-cam.com/video/RiRyzLl4Y8U/w-d-xo.html
Cool, got the Fluke 87v, now I just need to learn how to use it.
answer is 0.0195652174.
it's almost ~ 0.02A
u must be a really fun person
That’s what I got
Ya that’s right
I wish you were my college lecturer 25 years ago.
Yo! Bro
Thanks for good explanation
thank you
You are great sir! Sir please mak videos on electronic basic elements.... Please sir❤🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺
thank you for this, love this channel
Your content is soo good
You teach each topic very well
7:32 you show an animation of a resistor and electrons flowing through it. you say, the same amount of electrons enter and exit. wouldn't this mean, the same current? But according to I = U / R, current is indeed altered through a resistor. Does the animation visualize the so called "energy loss" of the electrons? How can electrons lose energy, if not by slowing down?
U have a great way of explaining things! Thank you ❤
What if when testing voltage, you test from the end of one resistor to the beginning of the next one?
you still get the voltage drop of the first resistor
@@cenzolyksitruff Hello. Does this apply to the following resistors as well? Cheers.
@@johnellison1635 assuming you’re asking about testing them in series without disconnecting them from the circuit individually, you will get the cumulative effect of the resistors before the resistors down the circuit. To test an individual resistor; you must isolate said resistor from circuit or else your reading will be incorrect. Hope this helped.
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
amazing I'm very sleepy😴😴
unbelievably just thank you
Thank you so much for all of this.
THIS WAS AWESOME ❤️
Hi! This video is good. I have a question, can You make your videos for spanish too please? Or a translation in spanish. Thanks
Española aqui: th-cam.com/video/7JDmvDzb5L8/w-d-xo.html
Thank you very much for enlightened my knowledgs
thanks a lot sir...great explanation
3:35 if there was a third resistor of 10 ohm at the right what would be the voltage across each one?
Check out NEW resistor video, everything covered! ➡️ th-cam.com/video/DYcLFHgVCn0/w-d-xo.html
Great vedio Sir.... Many thanks
You're welcome
Thanks for your videos pal
This is 0,019mA
Albret Einstein once said "if you cant explain to a 5 yr old, you don't know it well enough" or something like that and you could show this to a 3rd grade class and they would become geniuses
Excellent video sir, kindly let me know this, IS that any time limit for dc current measurement in SERIES like 10 seconds or i can leave my multimeter connected in SERIES while battery is charging the whole time ?
There's no time limit.
@@littlegenius6932 but my multimeter printed on ( 10 amp dc current measurement for 10 sec ) still i can measure it for long time or should i use shunt thanks for your reply
Check our new Multimeter tutorial out ➡️ th-cam.com/video/4lAyzRxsbDc/w-d-xo.html
Well I am the weird guy who watch this kind of stuff for fun.
thats amazing thanks so much!
Great video! Quick question - why is current represented using A? I thought current was represented using I?
An ampere ('A') is the unit used to measure electric current. Current ('I') is a count of the number of electrons flowing through a circuit.
thank you very much I love it very nice and interesting video I learned so much from you very well explain I think you should make a book a simple book with the screen snip with simple comments I am in the line of Electronics I have several books in electronic but it is so complicated to understand your video is really very simple to understand thanks
These videos are the best, but I can't find any on kirchhoff's law? 😢
Fantastic.....