@@TendingtoInfinity at 48:28 The equation generally represents an ellipse. i would not say that this represent an ellipse there are some values of a and b to be considered, if a = b the equation will simply represent a circle , if any one of a and b is 0 then the equation will represent two parallel lines. i just want clarify to the stundents who are vaguely saying ellipse
at 48:28 The equation generally represents an ellipse. i would not say that this represent an ellipse there are some values of a and b to be considered, if a = b the equation will simply represent a circle , if any one of a and b is 0 then the equation will represent two parallel lines. i just want clarify to the peoplees who are vagguley saying ellipse
sir at 19:12 if instead of solving the factor dy/dx + y = -x using linear form can we solve it as in reducible to variable seperable form that is dy/dx = -(x+y) from there substituting x+y = z and so dz/dx = dz/dx -1which after substituting in the eqn we get dz/(z-1) = -dx now taking z-1 = u we get the form du/u = -dx and on solving this we get ln(x+y+1) + x -c2 = 0 did i do it correctly ?
This I have said in the video as well, This transformation must be mentioned in the question. But it was not given the question paper, that's why, if this is the scenario then you have to remember this transformation
Na. Dekho, d(dependent variable)/d(independent variable) + P*dependent variable = Q... Eta holo general form.. Ebar 1. LHS e dependent variable er sathe jeta multiplied ache seta holo P and RHS e jeta ache seta holo Q. 2. Amader ei question ta solve korte giye jei form ta eseche sekhane "x" holo dependent variable and "p" holo independent variable. Eibar compare koro.
True, but ekhane sir directly 2 ta cancel out kore diache, p^2 er differentiation hobe 2p and niche o 2 ache square root er jonne, to cancel out hoye jabe.
I have already given him the explanation. Maybe you are new here, you can check the comment section more frequently whether I reply to the doubts or not. aur dekho, burai karne pe bhi reply de raha hu. So sad!
if am able to simply it by myself then whats the use of watching your tutorial? After majority of the steps you are saying "IF U SIMPLIFY". we dont have any issue if the video is long but please do it in detail.\
I see! Actually I believe the students can at least do the basic calculation steps. I hope you have watched some other videos, where the simplification is required I generally elaborate it. But anyway just mention the timestamps where you need clarification I will do that in the comment section only. And if you don't get it even after that also then the practice sessions are there. Lastly I don't want students to be spoonfed I want them to be independent. Anyway looking for your further comment.
You need to be more respectful towards the teacher, especially when he is providing educational content for free. He is expecting you to know the basic things required to solve the problem. If you don't, you can search it up, which will increase your knowledge and give you a better understanding of the concept without being spoon-fed.
At 16:15 wouldn't it be (p-x) (p+x+y) =0 ? It is written (p-x)(p-x+y)=0.
You're absolutely right. That's a mistake. Thank you for the correction.
18:03 correction kar diya sir ne
48:22 equation of an ellipse
Correct answer.
@@TendingtoInfinity at 48:28 The equation generally represents an ellipse. i would not say that this represent an ellipse there are some values of a and b to be considered, if a = b the equation will simply represent a circle , if any one of a and b is 0 then the equation will represent two parallel lines. i just want clarify to the stundents who are vaguely saying ellipse
at 48:28 The equation generally represents an ellipse. i would not say that this represent an ellipse there are some values of a and b to be considered, if a = b the equation will simply represent a circle , if any one of a and b is 0 then the equation will represent two parallel lines. i just want clarify to the peoplees who are vagguley saying ellipse
Right.. thanks for the explanation.
sir at 19:12 if instead of solving the factor dy/dx + y = -x using linear form can we solve it as in reducible to variable seperable form that is dy/dx = -(x+y) from there substituting x+y = z and so dz/dx = dz/dx -1which after substituting in the eqn we get dz/(z-1) = -dx now taking z-1 = u we get the form du/u = -dx and on solving this we get ln(x+y+1) + x -c2 = 0 did i do it correctly ?
Sir 50:42 how y^4=v please explain in question there is y^3 then how you took y^4=v....? 🙏Kindly explain
This I have said in the video as well,
This transformation must be mentioned in the question. But it was not given the question paper, that's why, if this is the scenario then you have to remember this transformation
@@TendingtoInfinity 🙏 thank u sir
Sir 34:43 main y/p Kahan se common liya sir a samajh Nehi aa raha.. sir pls help me
Ota y/p hobe na I guess ota y/2 common niyechi. Likhte ektu bhul hyeche.
@@TendingtoInfinity sir oi khan ta kichutei bujhte parchi na...ami chesta korchilam common newar but oi result ta asche na😢
Thikache..tomar answer tar sathe stick koro apatoto. Ami ota practice set e koriye debo nahoy arekbar
Thank you sir❤
@@TendingtoInfinityThank you sir❤❤
49:10 last question
@TendingtoInfinity sir can we solve the last question using solvable for x method???
Until it is mentioned to use the Clairaut's equation.
26:26
Q=2 and P=2x/p newar kono reason?
Q=2x/p and P=2 toh hote parto?
Na.
Dekho,
d(dependent variable)/d(independent variable) + P*dependent variable = Q...
Eta holo general form..
Ebar
1. LHS e dependent variable er sathe jeta multiplied ache seta holo P and RHS e jeta ache seta holo Q.
2. Amader ei question ta solve korte giye jei form ta eseche sekhane "x" holo dependent variable and "p" holo independent variable. Eibar compare koro.
@@TendingtoInfinity Confusion cleared👍
sir clairauts form using transformation er problem ki gulo korbo
Esechilo kintu .. 2022-23
36:17 akhane -1 ta ki kore remove holo ..??
😢
y/p dp/dy = -1
Then dp/p take edike rakhlam and baki ta odike -1 er sathe multiply kore dilam
Tahole hobe
dp/p = - dy/y
Tarpor shob kichu badike niye chole elam
dp/p + dy/y = 0.
@@TendingtoInfinity thank you sir
@@TendingtoInfinity 35:01 a y/ p commom ki kore gelo .. oii part ta .thik moto understand holo na 😢
Atau aktu bole din sir
Dekho pin kora comment ta. Subidha hobe
@@TendingtoInfinityKothy sir kono comment e pin kora nei
sir apni ki pogo dakhan na 18+ kuchu dakhan na sudu doremon dakhan??
sir 35:29 je 1/2p-1/p-2/p ta simplify kore likhlen ota ami korchilm but 1/p+p aschena amr -1/2p-p asche
Complete koro.
Final answer amar sathe milche kina dekho...
48:35 ellipse form
41:57 sir akhane √a2p2+b2 differentiation 1/2√a2p2+2b hobe na? as per diff of √x = 1/2√x
True, but ekhane sir directly 2 ta cancel out kore diache, p^2 er differentiation hobe 2p and niche o 2 ache square root er jonne, to cancel out hoye jabe.
Thank you for the explanation.
@@TendingtoInfinity you're welcome sir!
Question zyada krte nhi ho sir . practice kaise hogi ?
th-cam.com/users/liveIuGU4QgjqNI?feature=share
Sir derivation ta bugte parlom na, 43.44
Jaha tarif hota h wahi sir khali replie krte h jaha pe koi doubt puchta h ya kuch burai krta h waha nhi replie krte h
I have already given him the explanation. Maybe you are new here, you can check the comment section more frequently whether I reply to the doubts or not.
aur dekho, burai karne pe bhi reply de raha hu. So sad!
if am able to simply it by myself then whats the use of watching your tutorial? After majority of the steps you are saying "IF U SIMPLIFY". we dont have any issue if the video is long but please do it in detail.\
I see!
Actually I believe the students can at least do the basic calculation steps. I hope you have watched some other videos, where the simplification is required I generally elaborate it. But anyway just mention the timestamps where you need clarification I will do that in the comment section only. And if you don't get it even after that also then the practice sessions are there.
Lastly I don't want students to be spoonfed I want them to be independent. Anyway looking for your further comment.
You need to be more respectful towards the teacher, especially when he is providing educational content for free. He is expecting you to know the basic things required to solve the problem. If you don't, you can search it up, which will increase your knowledge and give you a better understanding of the concept without being spoon-fed.
one yr ago don't know about this channel .if known didnt got backlog in math.
Better late than never!
Ebar ar hobe na 😊
@TendingtoInfinity hope so sir🙏🏻🥺
Eq x^2/a^2+y^2/b^2=0
This is an ellipse eq
correct.
♥
Aap bhagwaan ho😢
Arey! Main sirf zariya hu! Bhagwan to ek hi hain!