EEVblog 1439 - Analysing Veritasium's Electricity Misconceptions Video

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  • @EEVblog
    @EEVblog  2 ปีที่แล้ว +256

    An extra video with extar comments for those trying to simulate this: th-cam.com/video/lBycH31K-E8/w-d-xo.html

    • @nicholaseastman6915
      @nicholaseastman6915 2 ปีที่แล้ว

      How do people in Australia call it, exactly: Khrushchov's law or Kirchhoff's [ˈkɪʁçhɔf] "Kirk-hoff" law (K. circuit law, K. circuit rules)?

    • @slowhornet4802
      @slowhornet4802 2 ปีที่แล้ว +15

      Both videos (Veritasium's video and Dave's analysis) are very interesting. But I still do not understand why we need wires in real life. From both your and Veritasium's video I understood *if* the energy would be transported along the wire with the speed of light it would take more time than if the energy takes the shortcut (direct path) from the battery to the bulb. His and your experiment show the bulb turns on faster than a "signal" could travel along the wire. So "why do we then even have to have a loop? Why are two separate parallel wires not sufficient to turn on the bulb?" If we need a circuit only because we need some current: use two separate circuits. One wire connecting plus and minus of a battery and another circuit with the light bulb. Both loops close to each other. Now if I would try this with a battery and a light bulb I am sure the wire in the battery loop would get pretty hot and the light bulb would not turn on. Or maybe it would be super dimmed. But if I set up a conventional circuit with battery and bulb in the same loop the bulb would shine brightly.
      Now, for very close distances, energy can be transmitted "contact-less" (as used in wireless charging of e.g. smart phones) with high efficiency. I think I even (partially) understand that some sort of dampening makes the wireless energy transfer over large distances inefficient, but not impossible (I think any radio wave is transporting energy). So for "large" distances (e.g. already just a few meters in a house) we need wires to transport the energy. We cannot use a small loop with a bulb at e.g. level 2 and an energy source at the ground level with another loop. We need to connect both with a wire in a loop. But why do we need the wires if the energy is not transported along the wire?

    • @rustycherkas8229
      @rustycherkas8229 2 ปีที่แล้ว +20

      Thank you for this explanation. Two observations:
      1) "Disingenuous"... Derek made a "clickbait" video and is smiling as dollars are transmitted into his bank account.
      2) You address the crux of the controversy at 37:37 in your video... The power transferred at t=3x10^-9s is "naff all"... The bulb would not light... Derek lied.
      Again, thank you for making your response to a "scientist's" fake science video in which he works very hard to deceive.
      Next up: Veritasium demonstrates that smoking is good for you!

    •  2 ปีที่แล้ว +3

      @@slowhornet4802 Wires are needed because they lead the electromagnetic waves where to go. If two wires go to the moon parallel to each other, one meter apart, then the bulb would be lit up one second after the switch turns on. Because the distance between the electric generator (battery) and the bulb would be a little more than one light second.

    • @AlienRelics
      @AlienRelics 2 ปีที่แล้ว +4

      @ You should look up time domain reflectrometry, and see how transmission lines are modeled.
      You haven't described your scenario. Is the bulb on the moon at the end of the parallel wires (a balanced transmission line) with the battery on Earth? Then it will take about 1 second to light.
      Or are the bulb and battery each on the Earth, each connected to their own end of the wires, then the circuit is closed between the bulb and battery? In that case, the bulb gets current right away and a wave begins travelling down the transmission lines to the moon.
      How bright the bulb is depends on the resistance of the bulb versus the characteristic impedance of the wires. And it will take about 2 seconds for you to find out if the other end of the wires are short or open.

  • @robegatt
    @robegatt 2 ปีที่แล้ว +2064

    "a huge part of practical engineering is ignoring maxwell's equations". Exactly, we are busy reading datasheets, lol.

    • @MetalheadAndNerd
      @MetalheadAndNerd 2 ปีที่แล้ว +341

      And finding replacements for non-available parts. 😭

    • @robegatt
      @robegatt 2 ปีที่แล้ว +80

      @@MetalheadAndNerd it seems the preferred sport lately... sigh.

    • @matsv201
      @matsv201 2 ปีที่แล้ว +20

      Its like everything else... you simplyfy to the most usefull system. Calculating magnet flux inna Electric cricut is pretty much impossible.
      But when doing magnetism you have to do it of cause.

    • @matsv201
      @matsv201 2 ปีที่แล้ว +9

      Worth adding... this is actually whats limit current in a super conductor.. this fact was discoveted fairly recently

    • @OnboardG1
      @OnboardG1 2 ปีที่แล้ว +67

      Surely 90% of modern electronics engineering is knowing the exact thing you need but surfing RS, Digikey and Mouser trying to find what it's called?

  • @xXxLolerTypxXx
    @xXxLolerTypxXx 2 ปีที่แล้ว +743

    As an electronic engineering student I had lectures about all of this, but I didn't really make the connection that power is always transmitted through the fields. I understood it at the special case of the space between capacitor electrodes, but never generalized that idea. Veritasium's video and your explanation to it flicked a switch in my brain. Thank you so much for that!

    • @NuclearSavety
      @NuclearSavety 2 ปีที่แล้ว +57

      Well, fields carry energy, but the fields are generated by the moving charges .... its a question what is first, the chicken or the eggs .... claiming one or the other does something separately gives bad pictures ...

    • @aredditor4272
      @aredditor4272 2 ปีที่แล้ว +10

      I'm a non engineer, but I want it to click in my brain, too. I'm gonna keep watching this vid and others. I just can't focus that hard, and there's some whoosing going on.

    • @opotime
      @opotime 2 ปีที่แล้ว +5

      Telling about Elektro that way makes it easy to understand how a primary and secondary coil Work.
      Have a nice Day and
      Greatz from Germany
      opo

    • @kingsglaive7639
      @kingsglaive7639 2 ปีที่แล้ว +1

      its not electrical engineer? electrical and electronic is different

    • @Maver1ck911
      @Maver1ck911 2 ปีที่แล้ว +8

      For his light bulb in a field idea to even work on pure field propagation you would need a tesla coil to create a high enough field strength at operating frequencies to light the bulb "wirelessly".
      You still need to take into account impedance, dielectric, conductivity, angular propagation, reflections, and you'll arrive at a speed of propagation and VA required to operate the circuit
      The simulation he performed as well assumes the capacitors have a static charge*(steady state) from T-0. if they were discharged you'd have to calculate the time constant in an LRC circuit based on the characteristic capacitance of the circuit.

  • @mr_tugs
    @mr_tugs ปีที่แล้ว +26

    Excellent analysis, Dave. I’m reminded of Physics and Chemistry classes at school: “So class, remember how we taught you about X last year? Well that’s not entirely true, so let’s look at what really happens.” And then a year or two later they do it again, and peel another layer from the onion. Makes complete sense as to fully understand the topic would just be too much, so we start with a simplistic explanation and slowly head towards the truth…

    • @spot997
      @spot997 3 หลายเดือนก่อน +2

      And in some cases 30 years later it turns out that even the last version at university was wrong.

  • @foxfire7604
    @foxfire7604 2 ปีที่แล้ว +75

    I'm a retired Director of Engineering with my field in Electronics. I love your videos. I especially like it when you destroy scammers like Solar Roadways. I worked for a small defense contractor and I'm very aware of SBR's. There are people who take advantage of people's ignorance of science, electronics, etc.

    • @stickfijibugs
      @stickfijibugs 2 ปีที่แล้ว +6

      Careful! Dave here uses the wrong model for Derek's experiment setup. A transmission line model is not applicable, the better model is a dipole antenna model. See my explanation in the main thread.

    • @barbcarbon9440
      @barbcarbon9440 2 ปีที่แล้ว +3

      I’m so sad to find out that solar roadways is bullshit. I don’t really know anything about electricity beyond what I have to know to run my amplifiers, but that video gave me so much hope for the future. Makes me mad to think that people were just pulling on heartstrings.

  • @jasonpatterson8091
    @jasonpatterson8091 2 ปีที่แล้ว +61

    My main objection to the Veritasium video was the implication that the electrons don't really matter. They don't carry energy, and look at how slowly they're moving!?!?! No, it's the fields they generate that carry energy. Well sure, but those fields don't exist without the electrons and their ever so slow motion. I know that he never would actually say that outright because he knows it's not true, but he leaned really hard into a semantic argument that got close. It's like saying that people don't actually buy things in a shop, no, it's their money that buys things. Well yeah, that's true, it's the exchange of currency that allows for a purchase (in most cases these days anyway) but it's the people who bring the money to the shop. They're not separable.

    • @not_my_fn_real_name2689
      @not_my_fn_real_name2689 2 ปีที่แล้ว +4

      Thanks for this comment, I'm no physicist, but have had some college level courses in electronics, electricity, X-rays, and passed the first 2 ham radio license tests, and his video threw me off of almost everything I understood about electromagnetism.
      This is the point I was grasping at, and it really seems like the two can't really be separated out from each other.
      The moving electrons generate the electromagnetic field, and without electrons there would be no field, and no power.
      Derrick showed the hosw/chain/wheel analogy which is a pretty good way to demonstrate how electricity works. I suppose the point of his video is that the chain is not representing electrons, but the en field. That means that the electrons would be represented by pulling the chain back and forth, and it seems that without the hands, the work isn't getting done.

    • @beingsentient
      @beingsentient 2 ปีที่แล้ว +1

      Why is it so difficult for you to understand that the flow of charge, called current, is not the flow of energy?

    • @not_my_fn_real_name2689
      @not_my_fn_real_name2689 2 ปีที่แล้ว +1

      @@beingsentient I am not quite sure, but other science based channels state that the the magnetic field is intrinsically tied to the electronic field. These other videos state that they can't be separated, and just because the electrons themselves don't actually flow entirely through the wires like water molecules through a pipe, it is their change in state that results in the pulse of energy.
      It seems like it similar to a wave in a rope, we can hold one end and move it up and down to create a wave. The rope molecules don't actually travel down the rope to the end, where something may be happening due to the waves movement, but no one can argue that the wave is a result of a change in the rope's state.
      This is how it seems electrons are used to produce electricity, we charge the electrons on the wire, which causes a chain reaction in the adjacent electrons, creating a wave.
      In any case, from what I have gathered, the charge generated at 1m/c is due to magnetic induction from the battery side, similar to how a transformer or wireless charger works, only at a greater distance. This makes sense and matches the physics I learned about electricity. If you know of videos that explain something different happening, please post the links.

    • @beingsentient
      @beingsentient 2 ปีที่แล้ว +2

      @@not_my_fn_real_name2689 You are missing the necessary details, if you really want to understand the physics. IF you're like the vast majority here and don't care to understand, I'll be wasting my time on you. So let's see where it goes.
      Previous to throwing the switch, the entire wire and the bulb in the circuit is at the voltage of the end of the battery that is attached to it. The switch is connected to the other polar end of the battery, and when the switch is thrown, that polarity is transferred to the end of the wire the switch touches, changing it's polarity and the interface of that jump in polarity travels at the speed of light down the wire. You can use transmission line theory to calculate how that E-Field travels along the wire, but it would have to be very sophisticated because it's a transient with many details.
      Throwing the switch completes a closed loop circuit, "almost" immediately enabling electrons (charge) to flow in the establishing electric field; i.e., there is a continuous circuit that the electrons can circulate within. Previous to switch closure, the broken circuit could not allow such electron flow. I say "almost" because nothing in nature is instantaneous, and it takes finite time for the electrons to feel the E-field and for them to accelerate up to speed. "Almost" immediately after that, the flowing current sets up a magnetic field, and so now we have a bona-fide EM-field around the wire that directs a flow of electromagnetic energy radially into the wire. The current (flow of charge) is inside the wire, along the wire, and the electric energy is at right angles to that, radially into the wire, as the Poynting Vector requires.
      That's a big part of what's going on in the circuit, and I describe it so that you understand what you mean by saying, "the the magnetic field is intrinsically tied to the electronic field." Notice the sequence: First there is the establishment of an electrostatic field; Second, the electrons flow because of that electrostatic field; and Third, the flow of charge (electrons) creates a magnetic field, and Fourth, the resulting electromagnetic field creates a flow of electric energy. The E-Field and the M-Field are at right angles to each other, and the Poynting Vector says that the flow of electric energy is at right angles to both of those, from the space around the wire radially into the wire. The E-field is in the direction of current, and thus, the direction of current is at right angles to the flow of electric energy. Current flow is not energy flow.
      That's what the basic laws of electromagnetic field theory show us. No if, ands, or buts. It's not up for negotiation or opinion. If you don't understand it, you flunk the course.

    • @scottdurgin9895
      @scottdurgin9895 2 ปีที่แล้ว

      Most electrical engineers have a hard time graduating from DC to RFM microwave. In fact all of electromagnetism everywhere in the universe it's an AC phenomenon any DC electricity is simply electromagnetism where the frequency equals zero, so it is it is an extraordinarily isolated case. And to an extent the electrons and the fields are quite separable: just consider the entire radiation field of the sun which contains a practically infinite (but not infinite, simply integrate the Planck distribution) spectrum of frequencies propagating outward, some of it intercepted by the earth. Anybody on the earth can measure the intensity of the field at any given frequency...when so doing where is the electron?

  • @cryptocurrents946
    @cryptocurrents946 2 ปีที่แล้ว +192

    at 13:07 the interviewee says: "People seem to think you are pumping electrons..." and Dave chuckles at the idea - "nobody thinks that". However, this belief is pervasive amongst non-engineers because this is what most of us were taught in physics at school. And, ironically, this belief is prevalent amongst astronomers and cosmologist, too, because they are constantly trying to explain the presence of magnetism in the cosmos (and our solar system) by gravitational spin and "remnants" - not attributing it to energy and electric flow because there is no evident wire to provide an electron "circuit"

    • @mathis8210
      @mathis8210 2 ปีที่แล้ว +62

      I was smirking at that "nobody thinks that" aswell. Actually as far as i know this is actually what the vast majority of people think.
      "There is this electrical current thingy that flows out of the wall plug and makes my stuff work."

    • @ortzinator
      @ortzinator 2 ปีที่แล้ว +38

      I distinctly remember a faucet being used as a metaphor in my high school science textbook

    • @VincentGroenewold
      @VincentGroenewold 2 ปีที่แล้ว +8

      Exactly, this is what I learned in school. Simple as that. That needs to change is my idea, it doesn't make things very clear if you go any further than what you were taught and what's really the point then to learn it in a bad way?

    • @chaos.corner
      @chaos.corner 2 ปีที่แล้ว +5

      Maybe most people think it but I think it's a fairly common exercise to calculate the speed of an electron in a circuit and find out its slow. The chain model he uses is actually fair too but you need to be aware that the speed of sound in the metal is more like the propagation of the signal than the movement of the chain (we learned of virtual "phonons" as the equivalent to photons then never used the term again).

    • @DisorderedArray
      @DisorderedArray 2 ปีที่แล้ว +8

      I learned that elastic collisions between the electrons and the atoms in the conductor is the cause of resistance/impedance. I guess this is actually wrong? How does the field model explain resistance?

  • @bitelogger
    @bitelogger ปีที่แล้ว +17

    This video was beyond my expectations, I literally learned a lot thanks so much for sharing all this

  • @scottdurgin9895
    @scottdurgin9895 2 ปีที่แล้ว +40

    Very valuable pair of videos. Kudos to both Derek and EEVBlog for appealing to general audiences in order to explain the magic of electromagnetism but also to confirm to RF engineers what they've been doing for decades, which itself is a confirmation of the physics behind electromagnetism. The physics behind electromagnetism is lucidly and brilliantly explained in the textbook Electrodynamics by Melvin Schwartz first published in the late 60s. Basically the entire field of Electrodynamics rests upon a solid underpinning of Einstein's relativity and the fact the the Electromagnetic field is a 4D Invariant Tensor, not some combination of 3D vectors. In addition, ohms law is an approximation based on the assumptions made about the drift velocity of electrons.
    Well done

    • @stickfijibugs
      @stickfijibugs 2 ปีที่แล้ว +2

      Careful! Dave here uses the wrong model for Derek's experiment setup. A transmission line model is not applicable, the better model is a dipole antenna model. See my explanation in the main thread.

    • @BillAnt
      @BillAnt ปีที่แล้ว +1

      Cool, now let's calculate the time it takes to light up a bulb if the 300k kilometers of wire was laid out in a perfect circle. ;D

  • @maxleveladventures
    @maxleveladventures 2 ปีที่แล้ว +395

    This was one of Veritasium's first videos that left me feeling like didn't really grasp what he was trying to explain. Your video helped me actually understand more about the concepts being discussed here. Cheers.

    • @georgelionon9050
      @georgelionon9050 2 ปีที่แล้ว +14

      Because I guess he didn't really grasp what the finer destails are about.

    • @xponen
      @xponen 2 ปีที่แล้ว +46

      He left out well established concept like capacitance and inductance coupling between wires making the puzzle more mysterious than it really is. I speculate he (or his writer) left those out purposely.

    • @wyattbielert2929
      @wyattbielert2929 2 ปีที่แล้ว

      th-cam.com/video/TttHkDRuyZw/w-d-xo.html

    • @wyattbielert2929
      @wyattbielert2929 2 ปีที่แล้ว +1

      Watch that video from Eric Dollard it describes everything youd like to know

    • @beyond6803
      @beyond6803 2 ปีที่แล้ว

      Trust me it is counterintuitive, you have to be ready to accept the change. Anyway, hope you will find the " Field " Way more comfortable after this.

  • @juanchoavid123
    @juanchoavid123 2 ปีที่แล้ว +269

    Something interesting I want to remark is when you said: "is nothing new for engineers" . I thought I knew about the basics of current (and I'm an electronic engineer) and honestly, during my time in the university, no teacher told me about the pointing vector (I remember a teacher mentioning it once, but just as a little mention, and honestly I am not blaming anyone) and seeing this to me is really new and honestly opened my mind on how do this world of electricity works.
    Excellent video Dave!

    • @jfbeam
      @jfbeam 2 ปีที่แล้ว +16

      Indeed. The Real World(tm) works with real world considerations, not fancy, complicated, thought experiment math models. Stretch out a million miles of super conducting wire and _prove_ it's 1(m)/c. Two wires 1m apart have f*** all for capacitance. (I've never even seen an instrument capable of measuring such a low capacitance.) The power did not flow from the battery to the bulb through 1m of open space. It's flowing along the wires, or we wouldn't need the wires in the first place.
      If the battery has been connected for more than 1s, all of the wire has been "charged". Closing the switch at that point would, in theory, instantly allow power to flow. This is the "water pipe" equivalency -- once the pipes are filled, water can appear to flow miles away almost immediately. If that hose hasn't been primed, it's going to take awhile to flow.
      This is the kind of physics experiment I'd like to see! 2ls of super conductor is hard to come by. If we do this with fiber optics (light/photons) -- and we have, this field theory math nonsense goes away. If you have 1ls of fiber, nothing comes out until 1s after you fire a photon in the other side.

    • @ODDnanref
      @ODDnanref 2 ปีที่แล้ว +3

      @@jfbeam
      Real world(TM) is too complicated to be able to usefully calculate the necessary stuff correctly. The way I remember an engineer decided to replace d/dx with a variable s and so his differential equations like you do your your normal equations. Mathematicians had a fit because it worked but there was no math to prove it true until Laplace.

    • @arinangel_
      @arinangel_ 2 ปีที่แล้ว +10

      I agree, my undergraduate degree in electronics glazed over a lot of critical theory under the guise of "you have to learn it yourself". It was disjointed and rather than focusing on the critical, fundamental theories they focused more on providing you with practical skills, which to be honest killed a lot of the joy in curiosity I had and I've been forced to learn and discover accidentally by myself, in my own time.

    • @manojlds
      @manojlds 2 ปีที่แล้ว +10

      We had this in 11th grade at school. Very surprised it wasn't taught in under grad EE.

    • @oldbloke135
      @oldbloke135 2 ปีที่แล้ว +10

      I don't know what university you studied at but this was in the first year electromagnetism module when I studied. (see Kraus "Electromagnetics" 1981)

  • @patrikmajkowski6052
    @patrikmajkowski6052 ปีที่แล้ว +2

    You rock at explaining the stuff. As electric engineering student, I very appreciate your explanations. Very on point

  • @mattisj.419
    @mattisj.419 ปีที่แล้ว +23

    Great Video. As someone who always kept asking "why?" and "how exactly does this work?" during physics classes un school, i am a bit disappointed that people aren't taught this. I know it's easier to look at it as if the energy is flowing through the wires, but nobody ever teaches the "true" version. Amazing to finally understand this. Now will it help me in any way? Probably not, but i love understanding the universe more and more.

    • @barnabaskiss2
      @barnabaskiss2 ปีที่แล้ว +6

      Let's throw away wires, who needs them when energy trawels without 'em.

    • @Leela_X
      @Leela_X ปีที่แล้ว

      @@barnabaskiss2 😏

    • @2adamast
      @2adamast 10 หลายเดือนก่อน

      Coax wires are no "true" wires as energy travels completely inside, they should burn.

    • @eric4709
      @eric4709 9 หลายเดือนก่อน +1

      If energy doesn't travel "in the wire" - then why does the wire increase in temperature when a current flows ? - Try connecting say a 9kW shower with thin wire... and see what happens!!
      Or - does it suggest that there is a "resistive" part that heats the wire... and the transmission in energy outside the wire can be thought of as a "reactive part" - ie dissipates no power..?

    • @Bunny99s
      @Bunny99s 5 หลายเดือนก่อน +1

      @@eric4709 Right. Of course the majority of the energy will actually travel IN the wire and not outside it. What most people seem to forget is that the em field also follows the inverse square law. So the further you go away from the field source (i.e. the moving electron), the weaker the field gets. So the majority of the actual power transmitted is inside the wire. Otherwise when you close your hand around an insulated wire and all the energy is transmitted outside the wire, 99% of the energy would go through your hand. However since there is no conductivity where actual electrons can enter / leave your hand, you do not get shocked.
      Technically EVERY macroscopic physical interaction is the em field or gravity. There are only 4 fundemental forces in nature and most of them are the em field. So while the weak gravity from earth pulls you towards the center of earth, it's the em field of your molecules that repell from the molecules of the ground. "Atoms" do not actually collide when you hit a solid surface with your fist. It's the em field of the atoms which repell each other. All of chemistry is only about the em field and the interactions between atoms and molecules.
      So technically the example with the metal chain, it's also the em field that is moving the chain and transmit the energy through the chain. How do you think do the chain segments "collide" with each other? Right, the em field of the molecules. So I don't get why everyone is so hyped about "yeah it's just the em field and not the electrons". That's just not true. Without the electrons you don't even have an em field. Also think abour the spatial power distribution in the field. Everybody knows magnets. Same inverse square law. If you get further away, the effect quickly becomes unnoticable. So this whole "any amount of power" (which was later added by veritasium) is complete nonsense and distorts the actual thing you want to explain. If the question was "when would you notice that the switch had been turned on at the light bulb?" everything would be fine. The amount of power that is actually induced on the other side is very small. So we're not talking about transfer or power but just signals / information.
      So just to be clear: Probably 99% of the power is transferred INSIDE the wire through the em field. The drift velocity of electrons changes proportional to the strength of the field which is also directly proportional to the current. In the veritasium video it sounded like the electrons move very slowly at a constant rate which is not true. It's directly related to the current. Yes, in AC we have no net movement but that doesn't change those facts.
      If it would only matter what happens outside the wire, why would it matter what diameter the conductor has or what material it's made of?
      I don't get why so many directly agree 100% or 80% with Derek. The way it's presented is just misleading. When I pay a house and I say "I'll pay it tomorrow" and I plan to pay only $0.2 every day, can I claim that I have paid for the house? Technically yes, but practically no.

  • @Schwuuuuup
    @Schwuuuuup 2 ปีที่แล้ว +216

    The problem I had with the veritasium video was, that some real life problems (resistance) are waved away, but others (capacitance) are not but not mentioned - and this feels like it is deliberately misleading. Also Derek should have mentioned that the layout of the cables is very important. This way the correct answer depends on effects that he made me ignore with the introduction ("we have to simplify this")

    • @MetalheadAndNerd
      @MetalheadAndNerd 2 ปีที่แล้ว +54

      He acts like many bad teachers do: He creates an environment where his specific statements are true and leaves out the factors he had to set up to make his statements true.
      BTW: I'm still curious why we need thicker wires for powerful applications if the power is not transmitted inside the cable anyway.

    • @nukularpictures
      @nukularpictures 2 ปีที่แล้ว +6

      @@MetalheadAndNerd Well he said he has to ignore resistance :) I mean then it all works out that way.

    • @michaelsommers2356
      @michaelsommers2356 2 ปีที่แล้ว +9

      Have you ever taken a physics course? Problems are always simplified in order to focus on the principles of the subject at hand, especially in introductory courses. When, for example, you are first introduced to capacitors, you ignore edge effects. You don't use Jackson in a first-year physics course.

    • @danielkohwalter5481
      @danielkohwalter5481 2 ปีที่แล้ว +2

      Imagine a different layout: a almost planar (X - Y) figure 8, crossing point distant 1m in the Z direction and the lines on the crossing plane in 90deg. The capacitance is minimal in this case and the battery and lamp will be 1m apart. If Derek is right, that the power is not transmitted over the cables, but over space (air), the lamp will turn on the same way, right? MAKE A F# EXPERIMENT! He could do it with relatively simple equipment, like an oscilloscope and differential probes. Very disappointed with Derek...

    • @Schwuuuuup
      @Schwuuuuup 2 ปีที่แล้ว +23

      @@michaelsommers2356 yes, but normally you say what you simplify but pronounce the effects, that you are going to focus on... instead of mystifying them to "totally blow you mind"

  • @SamanBahrampoor
    @SamanBahrampoor 2 ปีที่แล้ว +283

    My personal problem with Derek's analysis is that (as can be seen from your simulation), the "ON" state of the lamp lasts only a couple of miliseconds. I don't consider this to be actually "ON". Particularly in a video aimed at general public (i.e. not electrical engineers / physicists), no one would consider this to be ON. For something to be consodered ON in this context, it has to stay on (steady state). So, the answer is not 1/c. If the question was "when will you see a voltage spike across the lamp in the transient analysys of the circuit?", then the answer would be 1/c

    • @BrightBlueJim
      @BrightBlueJim 2 ปีที่แล้ว +31

      What he doesn't bother to explain, is that it isn't just the fields close to the switch that are at play. After the switch is turned on, there is an immediate step in the voltage at the wire, which gets coupled to the other wire. But also, that step is moving toward the right over time, such that for the whole time that voltage step is moving to the right in the lower wire, it is coupling to the upper wire, and takes a while to get back to the light bulb. So the whole time the pulse is traveling to the right, there is energy being transferred to the upper wire. This continues until the pulse turns around at the end, returning on the upper wire. The result is that there is a (near) instantaneous low-level lighting of the bulb for one second, followed by a brightening at the one second point. At least, this is how it works if you use a random size of wire and a random light bulb. But because the pulse is losing energy as it propagates, if the wire (actually a transmission line) and the bulb are properly matched, you won't see a change in brightness because the pulse that had to travel the whole distance will be at the same level as the current that was induced as it traveled to the right.

    • @ncmaothvez
      @ncmaothvez 2 ปีที่แล้ว +2

      @@BrightBlueJim Are you saying that if the transmission line had been perfectly matched to the light bulb in Dave's simulation, then the voltage and current would be constant after t=0 rather than instantly drop off? Is it even possible for the transmission line in Derek's hypothetical experiment to ever be matched to the light bulb?

    • @BrightBlueJim
      @BrightBlueJim 2 ปีที่แล้ว +47

      @@ncmaothvez Yes, that's what I'm saying. Almost. There's still the 1/c delay that the pulse has due to the 1m spacing between the wires. and yes, after around 3ns, the light bulb goes on, and stays on at a constant brightness.
      At least, that was what I thought. Turns out I was still wrong, though.
      At first, I was thrown off by the 1m spacing, because I'm used to much smaller dimensions in transmission lines, so I thought that the impedance of the line would be very high. But then I "ran the numbers" and for a reasonable range of wire diameters, like 1mm to 10mm, the impedance is actually around 500 to 1000 ohms. Using an on-line calculator for transmission line impedance, because I'm lazy, I find that making a twin-line transmission line out of 2mm wire, we get an impedance of 828 Ohm. For a 120V light bulb to have a resistance of 828 ohms, it would have to pass (120V/828 Ohm =) 145 milliamps, which would make it a (0.145A * 120V =) 17.4W light bulb. This is close enough to the 16-17W of a typical "100W equivalent" bulb to work.
      But NOW I realize that there's still a problem: the transient solution to this problem - what happens when the switch is flipped - puts the transmission line's impedance in series with the bulb, which results in half the voltage being dropped across the transmission line and the other half across the bulb, which Derek alludes to in his video. BUT, the steady-state solution - what happens when the transient electric field has faded out because both wires eventuailly reach the same potential - drops nothing, due to the hypothetical zero-ohm wire, putting the full battery voltage across the bulb. So I was wrong about that - even perfectly matched, the bulb will come on at half-brightness for one second before it abruptly rises to full brightness as the initial switch-on pulse travels around the loop and reaches the bulb.
      I don't just know this from theory - I worked for six years in high-power microwave pulsed RADAR systems, which use a modulator that incorporates a set of inductors and capacitors to make an artificial transmission line that operates much like this circuit, and the amplitude of the pulse IS pretty close to constant over the time it takes a pulse to travel through the transmission line and back. So the transient solution isn't just a quick spike caused by the capacitance between the wires, but a pulse whose length is twice the time delay of the transmission line.
      Isn't electromagnetism fun?!

    • @ncmaothvez
      @ncmaothvez 2 ปีที่แล้ว +4

      @@BrightBlueJim I've got to admit that my analog electronics theory knowledge doesn't reach very far beyond ohm's law and a crude understanding of transmission lines but I was still able to follow along in your explanation. Thanks for the reply! This got me curious, need to read a bit about transmission lines tomorrow when my brain is a bit more awake :) Yeah, I'd never have guessed the impedance would be as low as sub-1000 ohm's.

    • @Csiki27
      @Csiki27 2 ปีที่แล้ว +12

      Exactly. This spike would happen even if the circuit is not closed. And we don't call that "ON". Yes, you generated 0.00...001A in it, but you don't need 2x300000km wire for that...
      The ON state means at least that you can differentiate the current from the case when the circuit is not closed. It would be still a low current, but also at least .5sec...

  • @chrisguli2865
    @chrisguli2865 ปีที่แล้ว +13

    This is a deceptively simple problem with lots of rabbit holes to pursue, but Dave clears up this problem nicely. One of the most interesting classes I took in college was transmission lines in my senior year (BSEE curriculum). In that class the professor very clearly showed that electricity is really light, at least in terms of behavior, but I think even at a fundamental level. Even though this wasn't a class in optics, theories of refraction (lenses) , reflection (mirrors) and other topics were compared to transmission line equations and sure enough the parallels are amazing. Even a radar dish on a jumbo jet behind an "opaque" cone appears transparent at radar frequencies. The cone material is specifically chosen so the impedance is matched. If the wrong material were used the radar would be reflected back into the plane. Light is a coaxial circuit from source (eg an LED) to observer or destination (eg our eyes or a camera sensor). Our existence is a complex matrix of coaxial circuits that we take for granted every day.

  • @seanrodgers1839
    @seanrodgers1839 2 ปีที่แล้ว

    The various commentary videos have provided a lot of additional knowledge about how the energy flows from source to load.
    I have been aware of the idea that energy travels outside, or at the surface of wires, for a long time. However, I have never known any of the details of how it actually works. Very interesting. N8ce to have some understanding.

  • @IcyMidnight
    @IcyMidnight 2 ปีที่แล้ว +361

    "People seem to think that you're pumping electrons"
    "No one thinks that! Who thinks that?!"
    ...
    Me, before Derek's video. 😝

    • @MrJdsenior
      @MrJdsenior 2 ปีที่แล้ว +8

      You are, obviously, there is electron flow and hole movement. It's just that that electrical charge flow is VERY very minor.

    • @VeganSemihCyprus33
      @VeganSemihCyprus33 2 ปีที่แล้ว +1

      For those who understand this short documentary, daily life will turn upside down: The Connections (2021) [short documentary] 💖

    • @JR.M.S
      @JR.M.S 2 ปีที่แล้ว +29

      Almost every one who isn’t in the “field” thinks this way. Like high way’s cars go in one direction and then back. It may not be correct but I bet the most outside the “field” visualize it that way. BTW why has his video clip gotten so much reactions? (The question is more in general, not to this specific post). :)

    • @JR.M.S
      @JR.M.S 2 ปีที่แล้ว +7

      “Derek is correct” But the reactions point to “bloody murder!!”. Not specifically a comment on this specific video or channel (actually this clip was pretty balanced and good by me). But where is all the reactions coming from? Seems like people haven’t had a shit in two weeks and finally find a toilet.. ;)

    • @5UPRAH
      @5UPRAH 2 ปีที่แล้ว +40

      Yep! 99% of the public probably think that (myself included) - which is who Dereks videos are intended for. He's not trying to teach an electrical engineer something they most likely should already know.

  • @EEVblog
    @EEVblog  2 ปีที่แล้ว +288

    Before complaining this video is too long, use the timestamp bookmarks to jump around if you want to.

    • @alch3myau
      @alch3myau 2 ปีที่แล้ว +55

      lol too long?! Its only 45mins

    • @elyeryan8838
      @elyeryan8838 2 ปีที่แล้ว +25

      So, basically, the energy will reach the bulb through 1 meter of space, by the means of capacitive coupling, way before the far ends of the wires start conducting?

    • @EEVblog
      @EEVblog  2 ปีที่แล้ว +33

      @@elyeryan8838 Correct. You can also model it as an electromagnetic wave over the same distance if you prefer. I just like the capacitor model.

    • @elyeryan8838
      @elyeryan8838 2 ปีที่แล้ว +40

      Also, C'mon Dave, this isn't Tiktok, longer more detailed videos are _preferred_ here.

    • @gilb6982
      @gilb6982 2 ปีที่แล้ว +9

      Ok , there is to many timestamp bookmarks !
      Lol !

  • @Bad-Antix
    @Bad-Antix 2 ปีที่แล้ว +4

    I am an industrial electrician specializing in industrial automation. The examples he gives and the lump theory that he explains he thought is what electricians are tought in trade school. It's borderline amazing to me, as an electrician I feel like what I was taught in trade school is an incredibly simplified version of electrical theory to help get the masses out I'm the field pulling wire. I have increased my knowledge considerably since trade school but most electrician don't. Infact most electricians don't know what would be considered fundamental knowledge by most electrician engineers.

  • @davidjohnson497
    @davidjohnson497 ปีที่แล้ว

    Thank you for this video. I am not an engineer, but an electronics and ham radio hobbyist for about 45 years (and biologist). I like how you explain the different perspectives of engineer and physicist, and allow for the differences due to intended audiences. Usually it is not required that analogies be totally faithful and descriptive of reality, if they provide some increased understanding! I will keep studying the physics, and the transmission line theory, but I will also keep building stuff like 9:1 unun to allow me to use non-resonant wires for my antenna systems. I am often having fun with other people's designs. In our radio groups are some retired electrical engineers and I am always so amazed at how they build stuff based on their OWN designs. Wow! Keep having fun learning, and (if you are so inclined) building stuff! Both can be VERY fun. Dave WA4NID

  • @pantouffle
    @pantouffle 2 ปีที่แล้ว +245

    You're making a lot more sense than the original video. The Veritasium video seemed to imply to me that the existence of the wire would be irrelevant over that distance. Of course, it's evident for short distances that the wires don't have to be connected to transfer power, with for example transformers. But the details concerning thickness, resistance, distance, power , ac/dc, etc. matter a lot, otherwise every device and circuit would interfere with each other and be practically useless.

    • @Kanglar
      @Kanglar 2 ปีที่แล้ว +83

      It seems to me like Derek tries to make concepts appear to be as counterintuitive as possible instead of trying to explain the concept as clearly as possible. I might be wrong that he's doing this on purpose to generate more commentary/discussion/views, but the end result seems to confuse more people than it does explain the concept clearly.

    • @matsv201
      @matsv201 2 ปีที่แล้ว +9

      I would argue that the original video is wrong. The reason being that the magnetic filed is made by moving electrons. The field is just breaking the electrons from moving att full speed.

    • @JimBob1937
      @JimBob1937 2 ปีที่แล้ว +18

      @@Kanglar , I think so. He throws the baby out with the bathwater, so to speak, by making a technically correct explanation seem as though it has no value. There are different levels of abstraction that can be made for various phenomenon and those all can be correct. I found his video good, but slightly misleading because of that.

    • @TheWebstaff
      @TheWebstaff 2 ปีที่แล้ว

      hmm is the wire sort of is irrelevant because you don't require a wire to transmit power..
      There are a number of mediums that can transfer power...?...

    • @jimmcclymer4230
      @jimmcclymer4230 2 ปีที่แล้ว +6

      The surface charges are already along the wire. When the switch is thrown a current is created, making a B field, now power can flow through space. As real wires have resistance, power also flows into the wire where it is dissipated. It is not bad to say that the only purpose of the wire is to allow a current and the role of current is to make B.

  • @_2N2222
    @_2N2222 2 ปีที่แล้ว +123

    40:24 - Feynman showing that "the Poynting vector" is going into the wire: This is not the entire Poynting vector that represents the energy flow from source to load. That part that goes into the wire represents the losses in the conductor. We strive to have good conductors - the better the conductor, the smaller the electric field in the axial direction of the conductor and the smaller the component of the Poynting vector pointing into the wire. When integrating this component of the Poynting vector over the surface of the conductor, the result is I*I*R.
    There would be no voltage drop on a wire with zero resistance, so the electric field in axial direction would be zero as well and there would be no bit of the Poynting vector pointing into the wire. All the energy would remain in the field outside the wire.

    • @Wilewee
      @Wilewee 2 ปีที่แล้ว +12

      Great comment!
      Yes, it's actually weird that from the basic stand point of conservation of energy, one can so casually keep saying that the Poynting vector, i.e energy flow (flux) is towards the wire (and keep assuming a lossless wire). Dave makes it seem like it has something to do with the energy flow along the wire. (or that's how I understood him) But how would the energy the propagate to the load if this is the only direction of the Poynting vector?
      Actually I think transmission line theory for this problem is even more complicated than just imagining it as two dipole antennas. Well .. if antenna theory is any easier to understand.. but intuitively you would see why the energy travels near instantly to the load -- because they are two dipole antennas next to each other.

    • @carlosgaspar8447
      @carlosgaspar8447 2 ปีที่แล้ว +1

      i watched how powerlines were being repaired using a helicopter, and was given some explanation as to how this was possible without getting electrocuted. seems the electric field was diverted around the helicopter so that the cable could be repaired.

    • @1900OP
      @1900OP 2 ปีที่แล้ว +2

      Dave mentions about this at 11:18

    • @skulpturalol
      @skulpturalol 2 ปีที่แล้ว +2

      whatever Feynman said, that is the truth. He wrote a fucking book about quantum electrodynamics.

    • @marc_frank
      @marc_frank 2 ปีที่แล้ว +1

      and a lossless conductor could therefore be infinetely thin?

  • @camodude9224
    @camodude9224 2 ปีที่แล้ว

    After watching Dave's video I now understand Veritasium's video...great explanation Dave...glad you covered this...

  • @supralapsarian
    @supralapsarian 2 ปีที่แล้ว +71

    12:53 remember, Dave. “Most people” are “not electrical engineers.” The speaker is absolutely correct.

    • @AdityaDodda
      @AdityaDodda 2 ปีที่แล้ว +8

      I agree. Most people would learn the lumped element model in school and that is the end of it.

    • @LauroEsp
      @LauroEsp 2 ปีที่แล้ว +4

      And Veritasium is a physicist and not an engineer, it is just a difference on point of view. The information is correct considering the simplifications.

    • @patrickj1962
      @patrickj1962 ปีที่แล้ว

      And therefore the 1st explanation is the best one for us idiots or this idiot anyways this extra stuff you're adding is more confusing than the 1st 1. Otherwise you need to be in a form that's for the professionals not the idiots like us or me anyways.

  • @beardydave926
    @beardydave926 2 ปีที่แล้ว +137

    Veritasium is very much geared towards the layman and gives good insights to the more interesting aspects of science while leaving out the details. I think he steeped over the line when he mentioned that there are lies taught to us in school. There aren't any lies, just simplified versions of science that match the current understanding of the student. So unless you study engineering or physics at the college or university level, then all you have is the simplified version. I like the conversations that have been brought up from Veritasium's videos recently.

    • @interestedparty00
      @interestedparty00 2 ปีที่แล้ว +17

      Veritasium is doing more lying than any school teaching this subject. The schools are teaching this more accurately than Veritasium is doing. Sadly, Veritasium is outside his area of expertise about this topic.

    • @hartmutholzgraefe
      @hartmutholzgraefe 2 ปีที่แล้ว +23

      I one heard Neil deGrasse Tyson describing it as "teaching on a 'need to know' basis", as going into full detail would just overwhelm any student and would take way too long to get to the actual point at hand.
      So you start with the most simplified high level view, leaving out a lot of stuff first, and then start adding things back bit by bit.
      That "leaving out the details on a 'need to know' basis" can be considered lying in a way, technically. But it lacks the intent to deceive that would be needed to make it a real lie.

    • @guilhermeteixeira4421
      @guilhermeteixeira4421 2 ปีที่แล้ว +11

      @@hartmutholzgraefe I also like the explanation of the need for these kind of primer "wrong concepts" in the Science of Discworld:
      “A lie-to-children is a statement that is false, but which nevertheless leads the child’s mind towards a more accurate explanation, one that the child will only be able to appreciate if it has been primed with the lie”. An example: teaching the nucleus of an atom with electrons going around it like a mini-solar system in clean orbits in order to later teach the electronic cloud model.

    • @arnesaknussemm2427
      @arnesaknussemm2427 2 ปีที่แล้ว +5

      Agreed, in fact his video itself leaves out some details in order to simplify this issue. Perfectly acceptable.

    • @BenFinio
      @BenFinio 2 ปีที่แล้ว +13

      If you watch some of his recent videos about TH-cam and clickbait, he probably does this on purpose - he knows how to play the TH-cam game and something about "the lies taught to you in school" or "the truth about electricity" etc. is going to get more clicks than a bland sciencey-sounding title about EM fields.

  • @milos_radovanovic
    @milos_radovanovic 2 ปีที่แล้ว +64

    Pointing vector goes into the wire IF and only IF wire has resistive losses, otherwise the tangential electric field on the surface of the prefect conductor is zero.

    • @milos_radovanovic
      @milos_radovanovic 2 ปีที่แล้ว +21

      Component of the pointing vector flowing into the wire is the resistive loss.
      The component of pointing vector along the wire is the one carrying the power to the load.
      The DC electric field inside the bulk of conductor is proportional to the resistive loss!

    • @salerio61
      @salerio61 2 ปีที่แล้ว +5

      That's Poynting

    • @couplingconstant
      @couplingconstant 2 ปีที่แล้ว +8

      @@milos_radovanovic Finally someone gives the right answer.

    • @uwezimmermann5427
      @uwezimmermann5427 2 ปีที่แล้ว +3

      Most wires which I have encountered in the real world (I am a physicist by training) have resistive losses, even though I have made experiments at an electron synchronton with superconducting magnetic coils once.. but even there most cables were actually standard, resistive copper cables.

    • @Asgaia
      @Asgaia 2 ปีที่แล้ว +1

      Yeah. The poynting vector in fig 27-5 at 43:00 is the energy flow that is converted into heat.

  • @dutchy661
    @dutchy661 2 ปีที่แล้ว

    Absolutely marvelous stuff here. Love the enthousiasme and not afraid to put it out there. I will be watching allot more. 👍

  • @MascottDeepfriar
    @MascottDeepfriar ปีที่แล้ว +7

    The youtuber "AlphaPhoenix" decided to actually do a physical test of the thought experiment in their video "I bought 1000 meters of wire to settle a physics debate". AlphaPhoenix also did a follow up video expanding on further questions "Why does WATER change the speed of electricity?"

  • @lucaslac124
    @lucaslac124 2 ปีที่แล้ว +133

    This is the vibe that I got from the Veritasium video too; not wrong, but a bit sensationalist, not sneaky, but avoiding certain key elements in order to get wants out of the audience, and the physics perspective all the way.

    • @wilbertbirdner1303
      @wilbertbirdner1303 2 ปีที่แล้ว +23

      The presentation of the video made me feel like he didn't really have a full understanding of the physics himself.

    • @alexisfrjp
      @alexisfrjp 2 ปีที่แล้ว +9

      the target audience isn't engineers, he can't list all the factors otherwise it'd just become engineering/physics courses.
      we can add temperature and so on...

    • @rallokkcaz
      @rallokkcaz 2 ปีที่แล้ว +5

      @@alexisfrjp Anybody who isn't angry about the details of this video clearly isn't an electrical engineer and even as an engineer from a different field I find it a nice mental model for my dumb ass brain.

    • @htfkid2000
      @htfkid2000 2 ปีที่แล้ว +24

      Yeah, veritasium is mainly doing things sensationalist these days because he's mainly after view count. He genuinely wants to spread good information, but he realized (and said in another video of his) that he HAS to make it sensationalist because that's the only way to survive on youtube and make money.

    • @youkofoxy
      @youkofoxy 2 ปีที่แล้ว +1

      He could have mentioned Parasitics.
      Also that his circuit uses a ideal lamp and battery uses a super conductor and it's in perfect vacuum.

  • @laltXl
    @laltXl 2 ปีที่แล้ว +101

    As a member of the general public: when I finished watching Veritasium's video I have gotten the impression that faster than light communication is possible, because i missed that the exact arrangement of the wires is important.
    Thanks for clearing this up for me, I might be interested in learning more about this as a result =]

    • @_invencible_
      @_invencible_ 2 ปีที่แล้ว +15

      the important question for me is what happens if someone cuts the cable at one of the far ends (150,000 km away), how long would it take for the bulb to turn off? it certainly has to be 1/2 second, because otherwise the information that the circuit is no longer closed would be travelling faster than light.
      But if the cable was cut before closing the switch, you could close it and see if the bulb turns on after 1 m / c seconds. If it doesn't then the information that the cable is cut traveled faster than light.
      So how can the circuit "know" that it's complete in just 1 m / c seconds

    • @tomaszwota1465
      @tomaszwota1465 2 ปีที่แล้ว +5

      @@_invencible_ Electromagnetic induction? The wires close to the battery and those close to the lightbuld are just one meter apart, the lightbulb and the battery are just one meter apart. The switch is close-by too. Flick the switch, cause the electromagnetic fields to change, cause electromagnetic induction between those close by wires, power the light bulb for a bit.
      But, without making any calculations, which I'm not even sure I could make, I doubt the energy transferred would be enough to actually light up the bulb, especially at 1m/c time.

    • @allesklarklaus147
      @allesklarklaus147 2 ปีที่แล้ว +3

      =RNGFN= _Invencible_ Well the electrical engineering answer would be that it does not matter if you cut the wire before closing the switch because the energy capacitively couples from one part to the other, just as shown in dave's video in his simulation. The lamp would turn on and eventually turn off once the transient is over. The time it can stay lit would depend on the actual capacitance between the two wires and the impedance of that light bulb and some other stuff like inductance in the wire. (well, keep in mind that with real components it might never actually light up..)
      Hope this helps and isn't too complicated for somebody with no EE background.

    • @_invencible_
      @_invencible_ 2 ปีที่แล้ว +1

      @@allesklarklaus147 yeah but what if you take a whole chunk of the cable so there's a large gap between the ends?

    • @allesklarklaus147
      @allesklarklaus147 2 ปีที่แล้ว +3

      =RNGFN= _Invencible_ Okay, I think I got what you are thinking about. The capacitance I am talking about comes from the fact that there are two wires laying 1m apart for 150.000km long ends. I am not talking about the capacitance at the point where you cut the wire. While that capacitance exists, it would be so small compared to the wire-laying-1m-apart capacitance that it is irrelevant.

  • @DaveBrown1
    @DaveBrown1 2 ปีที่แล้ว +2

    Thanks Dave,
    my head is clear on this now.
    It made me think when I viewed the original video, this upset my world of electronics!
    Mind I did think about the capacity of the connections out on both sides (it's 50 years since I did this in college)
    Thanks for the VERY clear explanation.
    Stay safe

    • @stickfijibugs
      @stickfijibugs 2 ปีที่แล้ว

      Dave here uses the wrong model for Derek's experiment setup. A transmission line model is not applicable, so what you see on his graph is incorrect, and Derek's answer of 1/c is also not right. The better model is a dipole antenna model. See my explanation in the main thread.

  • @osbjmg
    @osbjmg ปีที่แล้ว +2

    I don't feel he left out the 1m distance in a sneaky way, but he just left out the units on his script and text. He directly addresses 1m because he's indeed deliberately comparing 1 meter vs 300,000 km of wire to make us choose between the time it takes light to travel 1m vs 600,000 km.

  • @Pengochan
    @Pengochan 2 ปีที่แล้ว +150

    30:00 It's actually an important fact, that initially it doesn't matter if the circuit is closed or not. If that made a difference it would enable faster than light information transmission, which in turn, would spin up Einstein to really high rpm in his grave.

    • @DavidLindes
      @DavidLindes 2 ปีที่แล้ว +11

      What I wish there was more discussion of here (especially since it's something Derek got so into in the Slinky Drop series) is a difference between how quickly the information that the switch has closed gets to the light bulb, and how long it takes to actually light up a practical light bulb, and for how long it would stay lit, etc. Like, I can grok the information getting there, but how much power is in that brief spike Dave showed in the simulation? Not much, I should think. Enough to even light a red LED?!???

    • @manojlds
      @manojlds 2 ปีที่แล้ว +1

      What if the bulb was at one end with everything else the same?

    • @einzigermylee5996
      @einzigermylee5996 2 ปีที่แล้ว +2

      Yeah, 1/c ! LOL

    • @Pengochan
      @Pengochan 2 ปีที่แล้ว +1

      @@manojlds interesting question. Since the potential of the wire opposite the battery should initially be between the between those of the battery terminals the Poynting vector goes outwards in both directions during the first half second. That corresponds to the energy invested into charging those "capacitors" the two parallel wires on each side can be considered as. Another way to see it is as energy invested into building up the electromagnetic field between the two wires. There's an electric field between the wires due to the potential difference, and a magnetic field around each wire due to the current.
      At most that can expand outward from the battery/switch (let's keep them together) along the wire pairs with light speed at most (when/where air acts as a dielectric medium between the wires it's likely a little less). Another way to look at it is as a signal (like a step function) traveling along a wire pair, and where it has been through . When the electric field hits the end where the wires are short circuited that wave is reflected.
      This reflection of the wave at the ends where the wires meet depends on whether they are connected, and e.g. if there's a light bulb between them.
      See this for the difference between those resistances:
      th-cam.com/video/zrDxSM91Jcg/w-d-xo.html
      It'd be interesting to do a version of the experiment with just two rolls of twisted wire pair, like the one in the video.
      It's about at that point that I'd need to consult some physics books and maybe do some math to get beyond hand waving and really see what happens.
      I think the wave traveling back puts both wires on the same potential, effectively unloading the part of the capacitor behind it and the Poynting vector from the battery outwards is cancelled. This travels past the battery, the Poynting vector on the load side then doubled, as the other wire is then on the same potential as the terminal on the closed side.
      On the bulb side the impedance of the cable pair and the resistance of the bulb will probably be important, else we have some kind of reflection there too.
      If it is matched, then the bulb is lit with half voltage when the 1st wave arrives (1/2 s after the switch is turned) and with full voltage when the reflected wave arrives (1s later, so 3/2 s after the switch is turned). But I'm really guessing a bit here.
      I honestly also don't know how the thickness of the wires comes into play, because that affects the capacitance, inductance and impedance of the wire pairs. There are impedance calculators for twisted wire pairs, according to them wires with 1mm thickness would result in an impedance of about 1k Ohm. This (and the battery voltage) should determine the amount of initially outgoing current after flipping the switch (at that point the current can't be determined by the resistance of the light bulb at the far end.
      I'd also have to look into the "no resistance" thing. The dampening effect usually helps to make such systems well behaved. Maybe it's enough to assume an inner resistance of the battery (and of course the light bulb). Setting the whole system up without any resistance at all (just a closed loop) probably results in an oscillating system.

    • @nin1ten1do
      @nin1ten1do 2 ปีที่แล้ว

      Einstein was covard and hypocryt.. He even try "exorcixm" at quantum entanglement.. We have confirmed Bosson.. Specialy his TAU what is confirmed fasther than light.. Is just opening another layer of physic onion.. If you cry after you remove skin.. You shut not be a coocker

  • @HenrikDanielsson
    @HenrikDanielsson 2 ปีที่แล้ว +136

    I think the visualization is a bit misleading, giving the impression energy basically moves directly between origin and destination as long as there is a physical connection "somewhere". They have the yellow energy lines looking like they are completely independent of the physical path of the conductors (esp. the ones going straight from battery to lamp perpendicular to the wires). If there was something [impervious to em fields] blocking the straight path between the battery and lamp the yellow lines would not be as "neat" and would more conform to the shape of the wires - which also changes the permeability of space part of the formula he only mentioned quickly at the beginning.

    • @EEVblog
      @EEVblog  2 ปีที่แล้ว +55

      The visual model was impressive but quite messy. i actually mentioned that in another take I did that I couldn't use before I goofed the system audio setting.

    • @windowsxseven
      @windowsxseven 2 ปีที่แล้ว +18

      Sure Dave, blame the audio system. It's always the audio system's fault, isn't it.

    • @jimmcclymer4230
      @jimmcclymer4230 2 ปีที่แล้ว +3

      The wires control the current and the current makes B. In this way the wires influence the power flow. The Veritasium video shows power along the wires, something left out by almost every text book ( well physics text book, I don’t expect engineering texts to do any better).

    • @robegatt
      @robegatt 2 ปีที่แล้ว +4

      It seems that if you screened the battery and wires with metal foil the lamp never lit. Not really my experience actually.

    • @robegatt
      @robegatt 2 ปีที่แล้ว

      @@mattmurphy7030 something like that

  • @robbaldwin3546
    @robbaldwin3546 ปีที่แล้ว +28

    It might be well known to you and any electric engineer, but to us ordinary people, it is new and really interesting!

    • @2adamast
      @2adamast 10 หลายเดือนก่อน

      Pure sophisme

  • @rc7074
    @rc7074 ปีที่แล้ว

    The difference between thinking outside the box vs. inside the box. Both great educational videos.

  • @stuartofblyth
    @stuartofblyth 2 ปีที่แล้ว +13

    It's all about models. If you want to derive the ideal gas equation, your atoms or molecules are tiny billiard balls. If you want to explain the Rutherford experiment your atoms have a positive nucleus and negative electrons. If you want to explain the Chadwick experiment then the nucleus has neutral particles as well as positive ones. And so on. In electrical theory, electric current flowing in wires like water in pipes is a perfectly adequate model for explaining what's going on. You choose your model to fit your purpose.

  • @drstrangelove09
    @drstrangelove09 2 ปีที่แล้ว +189

    The "low frequency" "circuit type" engineers do not necessarily know the transmission line details. I can remember talking to a digital design engineer that I worked with at IBM, who had graduated from Cornell, and I was trying to tell him about how a step function can bounce off the end of an open circuited transmission line and the voltage will double... so a 10 V step can produce a 20 V voltage for a time... and he would not believe me.

    • @hausaffe100
      @hausaffe100 2 ปีที่แล้ว +35

      unill he gets emc problems

    • @drstrangelove09
      @drstrangelove09 2 ปีที่แล้ว +7

      @@mattmurphy7030 Did I say otherwise? I think you read something into my post that I did not say.

    • @Majestic1987
      @Majestic1987 2 ปีที่แล้ว +16

      Well, a degree does not prevent from being clueless…

    • @Kirillissimus
      @Kirillissimus 2 ปีที่แล้ว +30

      He just probably never had any experience with RS485 lines, never connected an oscilloscope to the lines at different places and newer given the question of spacially distributed elements of the circuits enough thought. Just give him some time, reality tends to enlighten us once we lose any way around properly facing such a problem in a design and have to understand what is going on.
      Many other small discoveries are awaiting him along the way as well! Like having a voltage between different "grounds" or magic changes of voltage levels, magic 110ohm load from even an open twisted pair and many others. I am even a bit jealous. I wish I could experience that one more time.

    • @drstrangelove09
      @drstrangelove09 2 ปีที่แล้ว +32

      @@Kirillissimus he just thought that Kirchhoff's Voltage Law always applied. He thought that you cannot have a 10 V voltage source creating a 20 V voltage without a negative 10 V voltage somewhere in the loop. He said "you don't know what you're talking about, you are obviously wrong." There was a bit of "I went to a better school than you and you're out of your league and claiming ridiculous nonsense since you don't know better, and I do."

  • @allanolley4874
    @allanolley4874 2 ปีที่แล้ว +1

    I'm sure others have pointed this out but a quick point about the 1/c thing, if you do unit (dimensional) analysis on 1 m / c = 1 m / 3*10^8 m/s, so unit analysis the fraction we get is m / (m /s) = s. So it is 1/3*10^8 second not 1 m / c second or whatever.
    Ideally if we had a standard math function like absolute value but that was unitless value that turned a quantity in some units into a unitless coefficient you could use that. I'm not aware of such a function but taking a cue from absolute value function if |x| is the absolute value of x, let >x< be the unitless value of x. So >c< = 3*10^8 [where c is specified in meters per second].
    So using that the answer d) should have been given as either:
    1/>c< s
    or
    >(1 m /c)< s
    or if your willing to let the reader do one's own unit analysis etc.
    1 m / c [in meters per second]
    or if you want to have a bunch of ugly number hanging about
    1/3*10^8 s
    Obviously unit analysis gets more of an emphasis in chemistry or solid state physics (personally I only passed stat mech by looking at a problem looking at the equations I had access to and figuring out how to Rube Goldberg myself from the set of units specified in the problem to that required in the solution), but it can trips us up almost anywhere.

  • @beerreeb123
    @beerreeb123 2 ปีที่แล้ว +1

    Not an engineer...totally did not know this... totally loved your analysis.. To me, this is an amazing way to learn.. listening to a play by play of two really smart people.. awesome.. thanks.

    • @livesonjura
      @livesonjura 5 หลายเดือนก่อน

      YOU sound like a smart person. Maybe smarter than the two people you praised.

  • @radiow4qa71
    @radiow4qa71 2 ปีที่แล้ว +110

    Derek did not give all the details of the wire used (other than "no resistance"), but for what it is worth -- one can model a parallel transmission line to develop the characteristics that may be usable in a circuit simulator. For example, if we assume the wire is 10 gauge and is separated by 1 meter (center to center), the characteristic impedance (Zo) of this transmission line is about 798 Ohms. The capacitance is about 0.04 pf/cm and the inductance is about 26.6 nH/cm (all assuming a dielectric constance of 1.0 -- free space).
    When the switch is closed, the current that flows will be based on this surge impedance (x2) -- ignoring any lamp impedance -- until the sytems reaches steady state DC conditions. It is not going to be much current during this transient period: 12 Volts / (2 x 798 Ohms) = 7.5 mA ..... Doubt this is enought to light the bulb "instantaneously".

    • @DeadCatX2
      @DeadCatX2 2 ปีที่แล้ว +40

      Boom, this is EXACTLY what I was looking for - thank you! The author of the original video conflates steady-state analysis of power with the dynamic step-response of the signal. Before the steady-state is achieved, the initial power delivery is only 90 mW. That would be

    • @nophead
      @nophead 2 ปีที่แล้ว +12

      @@DeadCatX2 I think the power in the bulb would be even more minute because the cold resistance of the filament is about 10 times less than its resistance when lit. So the Veritasium video is wrong. The bulb will not light until the wave travels to the ends, sees the short circuit and reflects back to the bulb. He should have used an LED as that would light with 12V through 1.6K.

    • @Uterr
      @Uterr 2 ปีที่แล้ว +6

      Yep, at this time a lot of people figured it out, that there will be current on bulb, but only small. Lets imagine, you have to have a substantial part of current of your sorce on a bulb to light, lets say, 10% of a source, and your light bulb would not light up on a AC coupling only in this case. And video makers keep ignoring this point of view, concentrating attention that we will have potential difference on a bulb.

    • @profdc9501
      @profdc9501 2 ปีที่แล้ว +2

      This is a great analysis. I had imagined the two wires coming from the battery as an electric dipole and the two wires from the light bulb as another dipole, so it is (for short times) two coupled electric dipoles. Your analysis is a great back ofthe envelope calculation.

    • @stargazer7644
      @stargazer7644 2 ปีที่แล้ว

      So at 0.04 pf/cm it is the equivalent of having two 12,000 uF caps in series with the light (ignoring resistance and before the current gets all the way around and it reaches steady state)

  • @Gunbudder
    @Gunbudder 2 ปีที่แล้ว +36

    17:13 if an ethernet cable is submerged in water, or if its casement is flooded, you will have noticeable attenuation in the transmission. its specific enough that Fluke has a cable tester that can detect if a cable is submerged, and how far down the line the fault is. as far as i know, Fluke engineers have the patent on that. i happened to meet one of the Fluke engineers working on this problem, and he did his testing with a big plastic tub of water next to his desk, and a coil of ethernet cable in the water lol

  • @YuyinSports
    @YuyinSports ปีที่แล้ว +1

    I'm learning so much from these videos, I knew nothing just yesterday about electricity even though I really should sine I had electricity and magnetism courses that I don't even know how I passed, in university (industrial engineering) about 6? years ago... Now that I'm 27, I'm fascinated by all this, It's very rewarding trying to understand these topics and learn more on about STEM.

    • @arthurmoore9488
      @arthurmoore9488 ปีที่แล้ว

      It's amazing to me just how much I don't know about how this stuff works. Of course, as the video notes, the caveat is that most of the time it doesn't matter.

  • @das250250
    @das250250 2 ปีที่แล้ว +2

    Maxwell and his students were truly so incredibly insightful to model such a significant phenomenon.

  • @0xde57
    @0xde57 2 ปีที่แล้ว +65

    As a computer engineer, we focused more on the practical side than the theory side when we covered electricity and circuit building, and this was news to me. (It's possible we glossed over this in class and I don't remember but we definitely never went in this much depth). This was rather counter intuitive to me and my mind is blown. I love that I can be this wrong, the more I learn the less I know. Thank you for the knowledge and praise Maxwell!

    • @thomasnowell
      @thomasnowell 2 ปีที่แล้ว +20

      Same for me. I don't understand Dave's exasperated "WHO THINKS THAT?" followed by "All engineers know that". He keeps on answering his own question: the rest of the world. Veritasium is not aimed exclusively towards engineers. Actually, I'd say its rather the opposite. Derek never claim that this is unknown. Just that it's a common misconception, which I can bet everybody's asses that it is.

    • @georgigeeksky8349
      @georgigeeksky8349 2 ปีที่แล้ว

      Yup same!

    • @shellsterdude
      @shellsterdude 2 ปีที่แล้ว +1

      Same for me. I'm also an amateur electronics enthusiast and I learned something from this and Derek's video.

    • @tomgroover1839
      @tomgroover1839 ปีที่แล้ว

      If you had taken power systems engineering (I had one semester) electromagnetics, or RF design (which requires the previous as prerequisite), Poynting vectors and fields in general are thoroughly dealt with in those courses. Computer engineering blows past a lot of fundamental engineering. I was an embedded systems and instruments guy myself, the computer engineer in me was developed because of market conditions, not coursework. Although I had 1 graduate course in computer architecture and 3 courses in C/C++ years later in community college.

  • @_jmeg_3436
    @_jmeg_3436 2 ปีที่แล้ว +42

    I have to point out the comment where it was said that “everyone knows this,” when referring to EEs. I can’t speak to physicists, but I can tell you that if I asked my colleagues at work what drift velocity was, even just at a high level, they would scratch their heads in confusion. Some might say “oh, I believe we learned that in General Physics in undergrad.”

    • @REVOLUTIONS51
      @REVOLUTIONS51 2 ปีที่แล้ว +2

      Well it depends on the field of study and working environment obviously. I'm studying mechatronic engineering and we do see quite in the details the physics behind semiconductors in various courses about design of electrical control for motors for example, but we've done drift velocity during the introduction to "electronic & electrical motors"

    • @wileecoyoti
      @wileecoyoti 2 ปีที่แล้ว +7

      This. 99% of the population probably has never heard of any of this and at best thinks magic electricity (maybe electrons) is being pumped through hoses (wires) in to the end device. Among engineers: would bet an EE knows this, but probably not an ME (short of some elective class they barely remember). Physicist: same thing, depends on the type. Virtually any other major is probably shocked to hear the answer.

    • @whuzzzup
      @whuzzzup 2 ปีที่แล้ว +2

      @@wileecoyoti Drift velocity is basic undergrad physics every physicist takes.

    • @bajavas21
      @bajavas21 2 ปีที่แล้ว +1

      @@whuzzzup if you dont use it, you forget it and it is berried in the void :)

    • @njipods
      @njipods 2 ปีที่แล้ว +3

      i agree. i asked some engineers and physicist. the physicist knew the drift velocity speed roughly but didn't really understand the answer to Derek's question.
      the electrical engineers didn't know the drift speed and when presented with the answer to dericks question was "Sure if you say so"
      i certainly was not taught propagation speed or drift speed in my formal education. I worked out the propagation was roughly speed of light when i started working with transient situations and always assumed electrons moved very quickly but less than speed of light. that was interesting to find out but frankly arbitrary

  • @cherriagana
    @cherriagana 2 ปีที่แล้ว

    Big thank you for this detailed explanation.
    The veritasium's video brought me back a bit since I switched to network engineering from electrical/electronic engineering and I kept thinking "wait, isn't he going back and forth from DC power lines to transmission lines?"
    Big thanks

  • @syuan1038
    @syuan1038 2 ปีที่แล้ว +5

    The bulb will actually blink several times due to the reflection at the end of the Transmission line before it is stabilized. Of course we assume there is no loss through the TL which is not practical. A tiny bit of loss per length of the wire will render it into a resistive port considering its extreme length.

    • @tomgroover1839
      @tomgroover1839 ปีที่แล้ว

      So would that step function be reflected back in the same polarity?

  • @AndreiNeacsu
    @AndreiNeacsu 2 ปีที่แล้ว +47

    I am delighted whenever I hear engineers who are rigorous and show a proper understanding of the fundamentals down to a sufficiently low level for the topic at hand. Unfortunately, in my anecdotal experience (that is in no way a proper statistic) very few engineers care or are knowledgeable of the underlying science behind the practical equations and models. Also in my anecdotal experience, it's only the engineers who do care that make progress in their fields, either as researchers, designers, developers, or troubleshooting and optimization.
    For these reasons, I subscribe to engineering channels like this one and enjoy their content so much. Great work, Dave; thank you for the content!

    • @MrGlenn442
      @MrGlenn442 2 ปีที่แล้ว +3

      Heh fields

  • @mrpedrobraga
    @mrpedrobraga 2 ปีที่แล้ว +61

    My biggest beef was the as considering the tiny voltage that you get through the air as "lighting it up" it basically destroys the concept of circuits to me.
    Any source that you hold technically lights every single lamp in the world because the electromagnetic field has infinite reach.

  • @John-do9ei
    @John-do9ei 2 ปีที่แล้ว +3

    Yeah, I can forget it while working on my house. The trade schools teach electricity as being like water in a hose, but consider current computer design, which you allude to, where you have to account for this stuff and more. I had a physics class in the 90's where we were talking about the future of IC design and we were talking about issues where this classical Maxwell stuff must be accounted for, as well as hitting against real effects of quantum mechanical effects like tunneling.

  • @user-rq2sy5mp8n
    @user-rq2sy5mp8n 2 ปีที่แล้ว +7

    I randomly watched the Veritasium video and was really puzzled because I couldn’t fit the bits and pieces together with what remains of my physics and engineering classes. Something just felt off but I couldn’t lay my finger on it (while I somehow guessed the „correct“ answer). Just wanted to thank you for your brillant video and the simulation explanation approach, it totally helped me to figure out what is going on and putting the bits and pieces together. The whole DC business was soooo confusing, because I did not make the connection to transmission line and transients. I was also extremely puzzled by the fact that the lamp should turn on so quickly, and was wondering what would happen to lamps at the end of those long lines - your explanation with how things would work when you used lines in a circle instead the parallel lines made my internal lightbulb light up. So thanks for helping me figuring this out. 😊

  • @LoganLovell
    @LoganLovell 2 ปีที่แล้ว +154

    I quite literally design transmission lines, and the whole time I was watching Vertiasiums video I was thinking to myself "yes but....." Generally, it's not really a useful way to frame things and it's clearly just for the 'wow' factor that it gives a general audience.

    • @morethan4mph
      @morethan4mph 2 ปีที่แล้ว +6

      As a physicist, I agree with you that this is not at all useful for day to day work, but it is cool. Typical of what we do in physics to simply the problem until it is beautiful - Oh and we got to the beers long before the engineers! (Although if I had to solve it I would treat it as a transmission line!)

    • @Baneslayer
      @Baneslayer 2 ปีที่แล้ว +14

      like all veritasiums videos.... 🙄

    • @mildlifeisatrisk5727
      @mildlifeisatrisk5727 2 ปีที่แล้ว +1

      @@morethan4mph finally a physicist, thank God
      Why doea it happen faster than the speed of light? I mean, wth, the information that the switch is closed shouldn't be capped at the speed of light to travel across the wire (or around)? Like, current, EM field, gravitational field waves, ain't *everything* capped at c?

    • @morethan4mph
      @morethan4mph 2 ปีที่แล้ว +4

      @@mildlifeisatrisk5727 it happens at the speed of light.

    • @mildlifeisatrisk5727
      @mildlifeisatrisk5727 2 ปีที่แล้ว

      @@morethan4mph oh, thank you for responding! :)
      But wait, if it happens at the speed of light, and the wire is one light-second long (or the half of it we'ee calculating on) shouldn't it take at least one second? 🤔💭
      (Supposing everything is ideal, super disclosable, don't oscilate a bit to establish, etc)

  • @captianmorgan7627
    @captianmorgan7627 2 ปีที่แล้ว +55

    I've watched a few of Veritasium's videos and on the ones I know something about he always seems to leave out important information as well as being for people who don't know anything about what he is talking. If you know anything about the subject you probably already know most, if not all, of what he is talking about. And the answers he comes to aren't necessarily the best answers since they are ignoring vital bits.

    • @DevideNull
      @DevideNull 2 ปีที่แล้ว +9

      If you go back and watch his other videos.
      You will find some videos that deliberately ask questions and then don't answer them.
      Guess where the answers are? Next video.
      More views!! baby!!
      I hated that kind video so much that I stopped watching a long time ago.
      But lately he's been fishing really hard for viewing count.
      Even though I clicked not interested, youtube kept pushing it to my feed.
      So I clicked [don't recommend his channel]

  • @davidconner-shover51
    @davidconner-shover51 ปีที่แล้ว +1

    I went to several years of school for electronics; with life's path, I ended up being an alarm/data technician for these past 20 something years.
    I had seen quite a bit pertaining to EMF inductance and stray capacitance, namely weird transient effects on equipment.
    One notable example was a system that got dropped on my lap about 18 years ago when the original contractor couldn't make the system work for very long, lot's of false alarms, alarm panels getting fried on a regular basis. The originally chosen panels used spark gap arresters built into the circuit tracings on the circuit boards, and no other surge suppression. At 2500M above sea level, they behave a little differently, namely, the breakdown voltage is much higher than at sea level, subjecting the electronics to harder hits before the suppression would kick in. the house ate panels at a rate of about every six months on average.
    I finally installed 15V varistors on EVERY conductor feeding the panel and at the field ends. This extended the panel lifespan from 6 months to about 7 years.
    A note on this home, it is about 80meters long (I work on rather large high end houses). On a general remodel 15 years after it's initial build, the main backbone bundle exposed, I found out why this place had so many issues with fried electronics; the alarm, TV coax and data runs were beautifully cigarette packed from one end of the house to the other down the main spine, all of it about 10cm from the main electrical bundle, which was also somewhat cigarette packed as tight as the electrical code of the day allowed. This house became a poster child for why the local electrical codes changed, and why the electrical inspector now pays very close attention to the low voltage as well as the high voltage wiring, long runs must be kept a minimum distance away from the high volt electrical, and no more cigarette packing, ever.

  • @jericosha2842
    @jericosha2842 2 ปีที่แล้ว

    Thanks for making this. At least his video got us all thinking. I like to know the nitty gritty details, so something like this satisfies my curiosity.

  • @KhalilEstell
    @KhalilEstell 2 ปีที่แล้ว +15

    This actually helped me better understand his video. Especially because the battery was DC and I wasn't exactly sure what was going on. The instant I saw your lumped element model I got it.
    Thanks Dave!

  • @MrRolnicek
    @MrRolnicek 2 ปีที่แล้ว +8

    I'm glad you cut the wires off at the ends in your little example.
    They were always just bait to make things messy and confusing and him putting them there just rubbed me the wrong way.
    Your explanation with no bullshit (although you didn't really say anything particularly new to me either) was very nice and clean.

  • @arnehermann3417
    @arnehermann3417 2 ปีที่แล้ว +16

    Love how you did a "I'm not worthy" when Derek introduces Maxwell. That guy was the real deal. And then, you did it again for Poynting who should really be in the popular pantheon but for some reason isn't. But I do have to add Dave that Derek's video is most certainly not aimed at 'Geers and hopefully no physicist "learned" anything from it except maybe how better to explain it!

  • @ChrisHolzer
    @ChrisHolzer 2 ปีที่แล้ว +42

    24:10 as an electrical engineer myself, *THIS* is the main issue I have with this video. It tells people that _"all energy is delivered outside the wire"_ - which will make them wonder if their electritian is trying to sell them unneccesarily thick/expensive wires, as the energy does not go "through" them.
    A followup video diving into this would be super interesting I think. :)

    • @andrewjenkinson7052
      @andrewjenkinson7052 2 ปีที่แล้ว +3

      If they employ an "electritian" I think that would be the least of their problems! (MY spell checker changed it to "electrician"!)

    • @bat__bat
      @bat__bat 2 ปีที่แล้ว +4

      The Veritasium video is spectacular. Revealing to the general populous how electricity actually transfers energy is not going to make people magically stupider. Wire sizing is a thing, and I'd suspect more people are aware of wire gauges and amperage than they are of Poynting planes. By explaining to them how the fields carry energy simultaneously while the electrons inside the wire flow, I don't see where anyone would get so confused that they begin second guessing the electrician they hired regarding anything he suggests.

  • @davidniemi4051
    @davidniemi4051 2 ปีที่แล้ว +33

    Thank you Dave, this video provided me the information that I felt was missing from the Veritasium's video. I've studied civil engineering, not electrical engr and also I have my amateur radio certificate so this helped me link the transmission line theory into all of this. I've come to realize that there was something missing from my understanding of how all this works, I guess that I need to pick up some books on Electrical Engineering to complete my understanding.
    I'll try and find these Feynman lectures, Thank you very much again for completing the picture of this for me. :)

    • @stickfijibugs
      @stickfijibugs 2 ปีที่แล้ว

      Careful! Dave here uses the wrong model for Derek's experiment setup. A transmission line model is not applicable, so what you see on his graph is incorrect, and Derek's answer of 1/c for immediate steady ON is also not entirely right, it's misleading. For the immediate transient, the better model is a dipole antenna model. Also, Derek conflates DC steady state with transient analysis which is false and folks who want to learn, get misled. See my explanation in the main thread.

  • @esepecesito
    @esepecesito 2 ปีที่แล้ว +117

    You said all I'd have liked to say. Well explained! He implies the bulb turns on, as in "it turns on normally (100% power), and remains on" and that is clearly not the case! But yeah... the physics are ok.

    • @EEVblog
      @EEVblog  2 ปีที่แล้ว +26

      Yeah, I didn't go into the wave and reflection response as the video was already long enough.

    • @__-nd4hf
      @__-nd4hf 2 ปีที่แล้ว +15

      @@EEVblog You definitely should) Need a few seconds of bulb brightness simulated and graphed under this model

    • @kabbak
      @kabbak 2 ปีที่แล้ว +7

      Yea, Not including dimensions is really irritating and potentially blocks people from understanding. Nerd click bait, lol

    • @lolaa2200
      @lolaa2200 2 ปีที่แล้ว +5

      The physics is totally wrong as he assume the bubble start emitting light instantly as the electric energy is fed to it. Sory it's wrong, that bubble first need the switch mode converter to stabilize then the decoupling cap to charge up before the LED start glowing !
      And if you want to get picky about what happens in terms of reflexion in the line, although that will only account for a super tiny irrelevant fraction of the turning on time, then you must acknowledge that the damn PSU in those modern bulb is by no mean a "nice" resistive load as used in the calculation we made at EE university (That's why for more powerfull unit you need a prefiltering stage before the actual AC/DC converter so you don't mess up too much with the cos(phi) of the power line). Fact is understanding things at this level would be a mathematical nightmare and once again it doesn't matter as in the real world that switch to light time depends probably as much on that than on the noise.
      So yes "assuming a perfect world that doesn't exist where everything would go according to the equation i want to demonstrate then the physic is right". To me that's an oxymore to say it's wrong.

    • @jacobthellamer
      @jacobthellamer 2 ปีที่แล้ว +14

      Magic light bulb, the transient will be over long before the filament heats. I thought for a incandescent bulb on time is defined as 90% filament heat. If using a LED will it even get to forward voltage?

  • @ralphralpherson9441
    @ralphralpherson9441 2 ปีที่แล้ว

    Thank you! As a layperson who has only wired up and soldered a few guitar pick-ups/pots and various lamps and repaired fixtures around the house (( NOTE: I have a "I watched my grandpa and he knows everything from WW2" grasp of electrical things )) even I, dumb as I am, found Veritasium's video hard to follow until I watched this video. The way Veritasium explained things I got the impression he was trying to say one could jump a car simply by laying the one set of jumper cables over the dead battery and not even hooking the terminals up to the cables. Or maybe I could run some 12-2 Romex up to the bathroom light, stop short by a foot or two, and just loop it back without connecting it and still get light. It caused a lot of "huh?'' and "what the hell?" utterances from me until I watched EEVblog's video and saw the trick question for what it was. As soon as he explained about the missing units and trick question I went "OH! Thank God, I'm not nearly as stupid as I just felt!" ...I mean, who knows, maybe I am... after all I am still amazed and bewitched every time someone lights up fluorescent tubes 5 feet away from a tesla coil. 🙄🤣

  • @matthewjohnstone7324
    @matthewjohnstone7324 2 ปีที่แล้ว +1

    This helped me understand Veratasium's video a lot more.
    On another note im studying mechatronic engineering and did not know a lot of the things EEVblog thought all engineers knew. Maybe he meant all transmission/ elec engineers

  • @Theo0x89
    @Theo0x89 2 ปีที่แล้ว +52

    40:24 What's missing in Feynman's Fig. 27-5 for the steady state is the electric field component perpendicular to the wire due to the charge distribution in the conductor, which together with the magnetic field makes a Poynting vector (and therefore energy flow) parallel to the wire. Feynman's figure only shows the electric field component due to resistance, which causes some of the energy flow along the wire getting directed into the wire.
    This also means that most of the energy flows outside along the wire, not directly through space from the source to the load. I would argue that answer "B) 1 s" is therefore closest to being correct since only a small amount of energy due to transient effects arrives at about 1m/c.

    • @Aor87
      @Aor87 2 ปีที่แล้ว

      With regards to fig 27-5, are you saying there is non-uniform charge radially in the conductor at steady state DC? Is this not what Dave was talking about re skin effect? Or is this another caveat?

    • @Theo0x89
      @Theo0x89 2 ปีที่แล้ว +10

      ​@@Aor87 I am talking about surface charges in a DC circuit. This is a different concept than the skin effect, the latter of which only occurs for AC currents. Surface charges seem to be an often ignored detail when people talk about DC.
      Think of Veritasium's circuit with zero-resistance wires. In steady state, the net electric field inside the conductor is then zero, but there is an electric field on the outside of the wire coming from the surface charges. This field contains the energy, which is transported along the wire. So while it's true that the energy does not flow inside the wire, it still flows mostly close to the wire where the electric and magnetic fields are the strongest with a Poynting vector approximately parallel to the wire.

    • @dbenitopperez
      @dbenitopperez 2 ปีที่แล้ว +5

      As member of general public: when I finished viewing veritasium video, the first thing I thought was... "Ok, then if I put the bulb into a Faraday cage, the cage would block the electromagnetic field that comes through the air and the bulb wouldn't light on". And thats absurd. Therefore, it would be quite more complex. If I haven't misundertood you, your explanation saves this problem. Thank you.

    • @Wilewee
      @Wilewee 2 ปีที่แล้ว +6

      Actually at exactly 40:24 they measured exactly 6.9 level Earth quake on the magnitude scale at Altadena, California. The first responders at the scene found that the source was Richard Feynman's grave, where he had been turning violently. The cause was later determined to originate from an EE misquoting him.

    • @wbeaty
      @wbeaty 2 ปีที่แล้ว +1

      @@dbenitopperez Faraday Cages only work if there are no holes (especially no holes with wires going through!) Yes, if we connect a no-holes faraday cage ( REAL faraday cage) around the bulb, it will short out the bulb, there will be no EM fields inside the cage, and the entire current will be across the outside of the faraday cage.

  • @SerbanCMusca-ut8ny
    @SerbanCMusca-ut8ny 2 ปีที่แล้ว +7

    Also, Dave, thank you for mentioning the Feynman lectures on physics, that being available for free online made my day! I foresee many hours spent by me reading that stuff.

  • @CirclesandSounds
    @CirclesandSounds 2 ปีที่แล้ว +2

    Thank you, Dave. Another sound and excellent, scholarly discussion, with respect for all. We need more minds like you, my friend.

  • @peterc3228
    @peterc3228 2 ปีที่แล้ว

    If you cut a live wire, at high voltage, you can see the flow of the electricity in the form of the arc generated between the two cut ends, until the distance is too great for the air to act as a conductor! All the best, Pete 👍

  • @TreyRuiz
    @TreyRuiz 2 ปีที่แล้ว +17

    I guess everyone needs to define what 'on' means. For Derrick's answer, 'on' is any minute power dissipation in the lamp (and his answer is correct for that definition), but my first reaction is that 'on' is the full power dissipation allowed by the impedance of the lamp, and the power source. This version of 'on' is not reached until the EM propagation is allowed to travel through one half of the circuit. Before t=0, another assumption can be made that circuit is in state with the switch closed, meaning that the entire circuit is at the same charge between the left side of the switch, and the same charge on the right side of the switch. That EM charge is unfolded at the speed of light after t=0 and the light goes to full 'on' once there is a positive charge on both sides of the lamp (ie c times half the circuit length).

    • @jokul_
      @jokul_ 2 ปีที่แล้ว +4

      This is what confused me at first too, especially after he had all these EE guys talking his claims up. The lightbulb is probably already "on" just from random background charges moving: no power source needed! His explanation is not really what most people think of when they think of "on".

    • @raulaassisb
      @raulaassisb 2 ปีที่แล้ว

      Perfect observation. You should be a Mathematician (if you’re one not already) or a good philosopher that seeks Truth above all else. 👍👍🤜🤛

    • @Laohei0103
      @Laohei0103 2 ปีที่แล้ว +1

      Exactly! The whole topic is ill-defined. It is basically impossible to do any useful lighting (even if ignoring all the effort to make the element inside the bulb to start to glow) before 1 second.

    • @robertlee5456
      @robertlee5456 2 ปีที่แล้ว

      This is the first explanation that makes any sense. In a pedantic and nitpicky sense, the moment the switch is closed, changing electric and magnetic fields propagate from the battery terminals and its adjacent wires, to the bulb and its adjacent wires; but this power transfer is incredibly weak, and may not even cause a single photon of light to be emitted. Derek assumes that one photon DOES get released immediately after the switch is closed, calls this the "ON" state, and drops his mic.
      There's got to be a better way of teaching Poynting Vectors and EM power flow to kids, without causing this level of confusion, which is based on an impractical technicality. Maybe replace the DC battery with high frequency AC source, and have the target bulb be something that can be usefully energized by that source. I'm thinking of something along the lines of the "fluorescent bulb lights up by itself near high voltage AC lines" demos have been around since forever.

  • @blackest3314
    @blackest3314 2 ปีที่แล้ว +61

    Very interesting video even for a non engineer like me (I have a chemistry background).
    I also think your point of the different mindset is true in every field. I routinely work with electronic density (computational chemist), while I have experimentalist collegues who don't give a crap about the nature of the electrons and deal with reactants and products. We all work within some approximation, otherwise it would take forever to do anything meaningful. It's important to know what's behind the approximation and realize when the approximation break down, but we can ignore it most of the time.

    • @jmf5246
      @jmf5246 2 ปีที่แล้ว +3

      As a chemist i worked with plasma physicists and totally agree with ur points

    • @rsm3t
      @rsm3t 2 ปีที่แล้ว +1

      At last a sensible understanding.

    • @uiopuiop3472
      @uiopuiop3472 2 ปีที่แล้ว

      my wife is a german shepherd (i am hungarian and thats legal)

  • @sundog486
    @sundog486 ปีที่แล้ว

    I couldn't bear to watch the original Veritasium video. As an electronic engineer I baulked at the title. Thank you for sparing me. Your analysis was well done and saved me from that tedium.

    • @kaasmeester5903
      @kaasmeester5903 9 หลายเดือนก่อน +1

      Veritasium walks a fine line between thought provoking ideas and unbearable smugness. Ok maybe they don’t walk a fine line, they stagger from one to the other like a drunken scientist.

  • @esteticadoutordabeleza4566
    @esteticadoutordabeleza4566 2 ปีที่แล้ว +5

    Muito obrigado pela aula de engenharia! Congratulations for the video! God bless you

  • @tela5439
    @tela5439 2 ปีที่แล้ว +50

    Thanks Dave for your unagitated and professional and way reacting to this.
    I see the point made on the veritassium video, however for the general public and the average guy, it's like considering Einsteins relativity theory every time using a GPS.
    Side note: My flux capacitor equations never gave back 42, maybe because I neglected this fact we have learned now. Jeez...have to do it all over again.

    • @EEVblog
      @EEVblog  2 ปีที่แล้ว +22

      If you divide 121 by 42 and then subtract 2 and multiple by 100 you get 88. Well, 88.095 but the digital speedo was only two digits.

    • @jimmcclymer4230
      @jimmcclymer4230 2 ปีที่แล้ว +4

      GPS only works because of both general and special relativity. The fact that we don’t need to understand these subjects to use GPS does not mean some of us need to, and for the rest it is cool to know the deeper truth.

    • @larslindgren3846
      @larslindgren3846 2 ปีที่แล้ว +3

      @@jimmcclymer4230 Do you actually have a credible source for that Einsteins relativity was needed to develop GPS. I have read somewhere that the corrections for relativistic effects are done with calibration parameters on the clocks that are determined empirically through measurements rather than through theoretical calculations. I know that it is often stated that relativity theory was needed in the development of GPS but to me it makes sense that you would just measure any drift in the clocks after launch and compensate for it. From a practical point of
      view it does not matter if the drift is due to relativity or if the clocks just got out of calibration during launch.

    • @Kandralla
      @Kandralla 2 ปีที่แล้ว +3

      @@mattmurphy7030 Yeah but he does that kind of in a way that purposely misrepresents physics.

    • @joinedupjon
      @joinedupjon 2 ปีที่แล้ว +5

      @@Kandralla Yeah it annoyed me - he's structured the video like a 3 card monte to generate controversy, comments and clicks rather than trying to explain the subject in an understandable way... And he does know how to make good educational videos when he wants to.

  • @JessicaTranaker
    @JessicaTranaker 2 ปีที่แล้ว +10

    Dave made me a EE! I am thankull for that! And see him talk about my area of work is just wonderful!

  • @jlpsinde
    @jlpsinde 2 ปีที่แล้ว

    Great, thanks very much, as a physicist was wonderful to see this point of view.

  • @Lisas4us
    @Lisas4us 4 หลายเดือนก่อน

    Excellent and enlightening. Thank you.

  • @Wavicle
    @Wavicle 2 ปีที่แล้ว +275

    My biggest issue with Veritasium's video is that he makes it sound like the electron movement is essentially an inconsequential side effect of the energy flow outside of the wire. The battery isn't a magical device that contains vectors waiting to escape. The energy from his lead acid battery depends on the movement of electrons. Without it, the negative plate quickly builds up excess electrons which repels the negatively charged HSO4 ions and stops the reaction. The movement of those electrons is absolutely required.

    • @captaindred342
      @captaindred342 2 ปีที่แล้ว +51

      @@KLRJUNE But one can't happen without the other.

    • @Wavicle
      @Wavicle 2 ปีที่แล้ว +76

      @@KLRJUNE What carries charges in a wire? Electrons. The repulsive force between electrons will cause an increase of electrons per unit of volume on one end to propagate down and show up as an increase of electrons per unit of volume (and therefore increased charge) on the other end. This is why we don't have to think about drift velocity of electrons in electronics but can just think of the movement of electrons.
      It's analogous to the air ejected from your mouth when you speak - it doesn't move very fast, but the local change in pressure propagates outwards at the speed of sound. Veritasium's argument comes across to me as "people think that they're hearing the molecules of air you exhale but really it's not air you exhale but the sound waves traveling through the air!" It's a pedantic point, and you can model sound just fine using the movement of air without keeping in mind that zero of the air molecules from the audio source may arrive at the detector.

    • @richman3111
      @richman3111 2 ปีที่แล้ว +27

      @@KLRJUNE Yes, but he said it better (which usually means a few more words are transmitted).

    • @mike_o7874
      @mike_o7874 2 ปีที่แล้ว +17

      @@KLRJUNE what you said sounds like you don’t need electrons what he said is that you need but they are not what Carrie’s charge huge difference hence no one got your point at first

    • @mike_o7874
      @mike_o7874 2 ปีที่แล้ว +18

      @@KLRJUNE you said that the waves matter not the movement of electrons,
      all iam saying is that the majority of people including myself reading it think you mean electron do not matter only the waves.
      the dude above you explained it clearer, even if you meant the same thing we didn't get it. so iam glad he explained it in a longer way.

  • @spelunkerd
    @spelunkerd 2 ปีที่แล้ว +5

    I was tripped up by the lack of units on option D, too.

  • @Mike__B
    @Mike__B 2 ปีที่แล้ว +2

    Good god, this video just made me realize two things my Griffith's E&M teacher (junior/senior physics in college) was absolutely horrible in connecting with me because while I do recall some of this the biggest thing I remember was his incessant need to make sure every person's name and phrase was pronounced as originally intended e.g. how he pronounced "Poynting" (How I passed that class I'll never know), yet my Jackson E&M (graduate school) I was able to crunch through because it felt more about solving math equations than understanding what was going on... me with M.Sc. in Physics ... SMH.

  • @bluecheez555
    @bluecheez555 2 ปีที่แล้ว +12

    Good video! I think its great you brought up Feynman, as I believe his emphasis is always on understanding in general how the little pieces form the large behavior. Electricity works by pushing charges inside a wire. That intuition is extremely crucial and burying that understanding with pointless formulas and jargon does no one any good!

  • @Gemini_0815
    @Gemini_0815 2 ปีที่แล้ว +13

    What a fascinating 45 minute rant. As an engineer, I love it because I can so much relate to it. (However as a mechanical engineer, I deal with different misconceptions)

  • @martinwhitaker5096
    @martinwhitaker5096 2 ปีที่แล้ว +3

    This is a simply superb analysis... Despite having a degree in Electronic Engineering I was struggling to visualize how the energy could flow in 1 / c, right up until you showed the lumped model. Perfect explanation! Thank you.

  • @hellboy7153
    @hellboy7153 2 ปีที่แล้ว

    I wish Dave was my professor while i did electronics engineering
    I used your opamp video to do lab experiment thanks a lot we need guys like you

  • @pcdoodle1
    @pcdoodle1 2 ปีที่แล้ว

    Thanks Dave! Good breakdown.

  • @petehiggins33
    @petehiggins33 2 ปีที่แล้ว +42

    I've looked at the two "expert" references in Veritasium's video, they are both useless. The first one produces a waveform with no timescale but is actually the short transient pulse as shown in Dave's simulation. It doesn't show when the actual dc power arrives. The second one does the opposite his analysis only shows the arrival of the 12V at the lamp and the reflections that result from an unmatched transmission line. He only shows the voltage at the lamp and so doesn't show the initial delay at all. It's easy to see how Veritasiuim has been misled by these analyses.

    • @jpitt916
      @jpitt916 2 ปีที่แล้ว

      I agree with your observation as well.

    • @moisesjerez3324
      @moisesjerez3324 2 ปีที่แล้ว

      "misled", or mastering clickbait

  • @AndreasRavnestad
    @AndreasRavnestad 2 ปีที่แล้ว +24

    The counter-intuitive workings of electromagnetic fields was actually what pushed me over to computer science from electronics. I had so many unanswered questions about why we were using the notion of current being a flow of electrons when it seemed flat out wrong after learning about electromagnetic fields. Turns out that it was just an abstraction (albeit a useful one), but I never "got it" back then. Still puzzled that my teachers couldn't explain this in a better. Mind you this was still at high school level (three year service electronics path), but in the end I felt that I was missing so many pieces of the puzzle that I just changed over to computer science instead when starting college. Very informative video, thank you very much.

    • @illygah
      @illygah 2 ปีที่แล้ว

      when did you change majors? I dropped out of Chem before transferring to New Media. I was looking at a geology course' curriculum and like... I want to go back because it looks like they filled in a lot of holes.

    • @bocoroth915
      @bocoroth915 2 ปีที่แล้ว +2

      @@illygah that's weird, I would think filling in the holes would make it harder to do geology

    • @rboes208
      @rboes208 2 ปีที่แล้ว

      Interesting! Your understanding of the word abstraction has probably changed so much due to your CS education, you may not have liked that answer any more as a high schooler

  • @elliotess
    @elliotess 2 ปีที่แล้ว

    You answered my question when you said, “right hand rule.” Thank you!

  • @junkmail4613
    @junkmail4613 2 ปีที่แล้ว

    Electroboom, I'm a retired electrical engineer. I love your video. I wanted to say, importantly, the word is impedance NOT impotence!!! Yours is the third of three videos I've watched on this. First was Veritasiums, then Dave at EEVblog, then yours. Dave said that we engineers think about things differently. That we have tools to analyze things and validly track physics and the rules of science. You fellows have collectively reminded me of much of the complexity we were trained to understand and analyze and calculate. I've much forgotten what I was trained and educated to deal with. I've been so browbeaten by the mindless politics and public chaos of people and the media news etc. I've forgotten the promises of my youth and education. TH-cam, multimedia and Internet is a terrible way to waste a capable mind. You've helped to retrieve my past capabilities. Thank you. Amind is a terrible thing to waste, and you've given me a wake-up call.

  • @whome8192
    @whome8192 2 ปีที่แล้ว +22

    The video triggered me. I was like yes…what he says is true, but there is a trick here. Oh it’s a transmission line 300 million meters across and only one meter long. The old physics trick of assuming ideal conditions, and drawing the problem differently to throw us regular folks off. Thanks for the explanation, I needed the refresher…have not done drift velocity since 2nd year, and attempted maxwell equations since 3rd and 4th year of engineering school. Great video for us out of practice EEs

    • @115maxx
      @115maxx 2 ปีที่แล้ว

      I am wondering thought, what does ideal conditions imply? Does it imply that the impedance is zero? Wouldn't that also mean that the capacitance and inductance of the wire must be zero?

    • @goodwillhart
      @goodwillhart 2 ปีที่แล้ว +1

      Derek claimed that the light would come on after just nanoseconds. That means the length of the wires past the first few metres is irrelevant due to causality. So if he is correct, he is talking about a transmission line a few metres across and one metre long. Certainly not enough to turn on any bulb I'm aware of. And he directly implied in the video that this was directly testable with actual "power lines".

    • @user255
      @user255 2 ปีที่แล้ว

      ​@@goodwillhart He did mention it is hypothetical unrealistic lamp that turn on right away.

  • @jeremiefaucher-goulet3365
    @jeremiefaucher-goulet3365 2 ปีที่แล้ว +111

    There was a lot of missleading things in Derek's video, and it took me days to finally figure it out. I never had the same definition of "turning on" as he did. Sure the initial change is at 1m/c s due to capacitive coupling between the wires, but the lamp won't see significant power until it reaches steady state, 1s later. As Dave said, make the circuit a circle, or just seperate the two wires further apart and it changes everything. Derek's video should have been more about capactive coupling between two wires instead of focusing on EM fields. The topic had nothing to do with the quesion/answer. Very missleading.
    "switching on" instead of "turn on" would have already made it a little clearer. Very missleading, since the lightbul won't be glowing at 1m/c s.

    • @parryhotter3456
      @parryhotter3456 2 ปีที่แล้ว

      Even in a classical sense the light bulb would light up in 1m/c seconds because as Power = Voltage x Current. The voltage would as explained in this video propagate at the speed of light and the current starts immediately after the switch is closed so yeah it’s still 1m/c.

    • @_mnejing
      @_mnejing 2 ปีที่แล้ว +4

      Glowing and being on are not the same thing, that's an interpretation problem (i.e. you), not an issue with the video.

    • @ModelLights
      @ModelLights 2 ปีที่แล้ว +11

      @@parryhotter3456 'the light bulb would light up in 1m/c seconds ' You guys realize the lightbulb would really never light up due to power sources not being able to drive 300,000KM of line and deliver power to the bulb, etc..
      By focusing on one variable and pretending the others are infinite and infinitely efficient, etc, the whole idea is like any other fake 1=0 proof. You're roughly accomplishing a multiply by infinity or divide by zero by calculating on the 300,000 KM lines when the reality is none of that stuff would be driven that way when you start taking the other variables into account..
      IOW a 'Reductio ad absurdum' type failure, or really probably the opposite of that. Reduced to the point it still seems to hold up, but actually the failure has been hidden in the reduction of variables..
      Start calculating all of this out with real 1 m loop numbers and real 300,000km loop numbers and it'll become a lot more obvious that reality isn't going to work this way..

    • @Kindo1085
      @Kindo1085 2 ปีที่แล้ว +10

      You are exactly correct, the question is meaningless because of the assumptions that are made. The first being you can have a 0 ohm wire. The second being that we define the bulb as being ON when ANY electrons pass through the "bulb". Does some current flow through the bulb in 3.3ns, sure! Is it enough current to be significant, hell no! My hunch is that you would actually get way more current just moving the wire 1 cm/s through the earths magnetic field. And Derek's video either fails to point out, or he didn't realize that the bulb would turn off again almost instantly as the transmission line locally meets steady state, and would only turn on again once the electrical field has populated through the wire.

    • @zhuochen6096
      @zhuochen6096 2 ปีที่แล้ว +1

      @@Kindo1085 If you had cared to read through the slides provided by Derek under his video, or if you had considered carefully Dave's lumped element model that places a capacitor every certain distance along the wire until half a light-second away, you would realize that the light bulb will not turn off almost instantaneously. The thought experiment is very meaningful to me. The assumptions help keep the video short and keep me focused: I was inspired by the fact that Maxwell's equation, the transmission line theory, and the Poynting theorem could all lead to the same answer!

  • @juan.manuel.sardon
    @juan.manuel.sardon 2 ปีที่แล้ว

    In a lossy conductor in DC, there are two components of the Poynting vector. One is parallel to the conductor and this is the power transmission part, product of the external electric field, radial to the conductor, and the magnetic field. The second component arises from product of the magnetic field and the voltage drop inside the conductor and represents the conductor power losses.

  • @sigurdss4
    @sigurdss4 ปีที่แล้ว +3

    I find Dereks framing of the transmission line problem useful when preparing for an electromagnetics exam and trying to please a professor who is a physicist, not an engineer

  • @fraginz
    @fraginz 2 ปีที่แล้ว +6

    As someone that is not an engineer, it is definitely something very new.
    Before Veritasium video, then your video and other video, I always thought that electricity is about stream of electrons moving, flowing from the power source to devices.

    • @not_my_fn_real_name2689
      @not_my_fn_real_name2689 2 ปีที่แล้ว

      I thought the same about the flow of electrons being the cause of electricity, and I had to take a digital circuits course in college and took an electricity course as an elective.
      I think one of the things I have trouble with is that the electromagnetic fields can't exist without the flow of electrons, and of course the flow of electrons can't exist without the electromagnetic force.
      The thing about electricity in the real word is we have accepted equations, for example Watts (power) is equal to the Voltage times Amperage, and Amperage is a function of the number of electrons in the transmission medium. Voltage is equal to the current times the resistance. It seems to me that you can't have electricity as we define it, without a combination of the electrons and the waves.
      I wonder if this is just arguing semantics, because in the original video Derrick says that electrons don't carry energy, but doesn't anything in motion carry kinetic energy? It almost seems like the argument is more about the fact that the electromagnetic field is the transmission medium for electricity, but we generate the field by moving electrons.
      I I were dropping a rock from the top of a building, isn't the rock delivering the energy when it hits something, even though it is gravity that is the cause of that energy?
      In the end though, it seems like movung electrons will always be required to make use of the electromagnetic field.

  • @nikitanugent7165
    @nikitanugent7165 2 ปีที่แล้ว +68

    I thought Derek's video was the equivalent of a bright kid teasing another by poking them over and over while chanting, "I'm not touching you! I'm not touching you! Technically it's only the repulsion between the electrons in the atoms of our skin that's occurring, nothing is actually touching!"
    Sure, it's correct, but also deliberately misleading. It feels like Derek's video was made to appeal to those who want to have knowledge to be more correct than others, rather than to be able to use it usefully. I was left more confused after watching it, and I don't know how much educational value it would have to someone even less familiar with electricity fundamentals than me. (I assume Dave's talking specifically about electrical engineers when you say "all engineers know this." It definitely wasn't covered in the single circuit fundamentals course we got in mech eng.)
    Thanks, Dave, for actually explaining the concepts and increasing my understanding!

    • @kayakMike1000
      @kayakMike1000 2 ปีที่แล้ว +8

      Precisely. It was just Derek reminding us that he is so much more intelligent than the rest of us mere mortals.
      I remember some kid played that game with me in grade school, the I'm not touching you game.... I smashed that kids head through a desk. Then I said... "Oops, I win."

    • @zdcyclops1lickley190
      @zdcyclops1lickley190 2 ปีที่แล้ว

      As Rush Limbaugh once said "Words mean things" Things are actually touching. They are fields. They touch by exchanging photons. If you,ve ever been hit with a snowball you will understand the analogy. There is no action at a distance. A theory can be based on incorrect assumptions and still make corrections as accurate as the current state of measuring devices. Epicycles was one such theory.

    • @VecheslavNovikov
      @VecheslavNovikov 2 ปีที่แล้ว +7

      Yeah, it's like asking "is a human made mostly of water, vacuum, or something else?" and then mocking someone for whatever answer they pick.
      "No, it's mostly water, that's the most abundant molecule in the body!"
      "No, it's mostly vacuum! By volume, all atoms are over 99% vacuum!"
      "No, it's mostly baryons! Over 99% of your mass is in baryons!"
      I mean, he went on about how power lines work, then used an experiment that works entirely differently to get that initial spike, which would still go through even if the lightbulb and battery weren't connected. I don't know why this angers me, but I had to vent. Maybe it's because flat earth proponents use the same sort of equivocation. It's maddening.

    • @MikkoRantalainen
      @MikkoRantalainen 2 ปีที่แล้ว +4

      I think Derek is trying to inspire people to learn more about stuff he has videos about. It seems to me that none of his videos are supposed to cover the video subject fully but just give a glimpse and raise additional questions.

    • @another3997
      @another3997 2 ปีที่แล้ว +4

      @@MikkoRantalainen At last, someone who "gets it". Thank you! The derisive comments above are typical of a certain mindset, they can't see beyond the end of their nose. All of Derek's videos are designed to make you think, to challenge what initially seems "obvious" and to inspire people to learn more. The fact that in doing so, he angers a few narrow minded people shouldn't stop the majority of people watching and learning.

  • @europaeuropa3673
    @europaeuropa3673 2 ปีที่แล้ว

    Thanks for the lumped circuit explanation, which is what I needed to understand.

  • @glennsmethurst2235
    @glennsmethurst2235 2 ปีที่แล้ว

    Saying “correct” is a little up one’s self.
    Saying “I agree” places your knowledge and experiences in science ( challengeable)
    I enjoy your channel and knowledge sharing, thx for the efforts.

  • @84lja
    @84lja 2 ปีที่แล้ว +5

    Electricity is really simple to pick up but bloody hard to master. You start of with comparing everything to water pipes. Valves are switches, water pressure is voltage and the volume equals current. And that simple comparison works for almost everything an electrician needs to know. The biggest difference between the run of the mill electrician and the layman is that the former is supposed to follow code. It only gets interesting once you go either really small or really large. When frequency and distance becomes an issue or electromagnetic fields get powerful enough to warp your conduits. That's were the fun stuff starts.

  • @BM-jy6cb
    @BM-jy6cb 2 ปีที่แล้ว +8

    Whilst we all treat ac and dc circuits differently for practical reasons, everything that applies to ac circuits must apply to steady state circuits otherwise our understanding of physics is shaky. Essentially a steady state circuit is just one with an infinitely long wavelength (relative to the length of the circuit), so all the relevant terms drop to (near) zero and can be ignored. When Derek started talking about undersea cables, I instantly thought "yeah, because it's now a transmission line where the length of the cable is relevant given the frequencies you are sending along it". But his video wasn't aimed at engineers - and like you said, if it sparks an interest in science/engineering, that's great news!

  • @hachanabe
    @hachanabe 2 ปีที่แล้ว

    I discovered this channel a week ago. I can tell you that this guy is the ADMIN of TH-cam 👍