Assuming O is the center of the circle. ORT = 90 - 30, ORT = 60. OSR = 30 [By Angle Segment Theorem] Since OS = OR, [Radii of the same circle] OSR = ORS = 30. [Equal sides of an isosceles triangle have equal angles] PRS + ORS + ORT + 30 = 180 [Straight line] PRS + 30 + 60 + 30 = 180 PRS = 180 - 120 Thus PRS = 60. PRS = RTS [By Angle Segment Theorem] ROT + RTS + ORT = 180 [Angles in a triangle add up to 180] ROT + 60 + 60 = 180 ROT = 180 - 120 ROT = 60 My apologies for not using the degree symbol and angle symbol due to technical difficulty.
HOMEWORK FROM GIVEN FIGURE, OR⊥PQ HERE,∠ORQ=90°,∠TRQ=30° ∠ORQ-∠TRQ=∠ORT THEREFORE ∠ORT=60° OR=OT (BCZ CHORD OF SAME CIRCLE ARE SIMILAR) ∠ORT=∠OTR=60° BY ANGLE SUM PROPERTY ∠ROT=60° (ii)Now ∠PRS=∠STR ANGLES IN ALTERNATE SEGMENT
@@mdhasanmujtabajamal9833 see u can find ang. ORT that is 60 coz OR is perpendicular.Second the tri. SRT is right angle triangle so Ang. SRO is 30 and then u can find Ang. PRS by 90-30 that is 60.
Sir honestly, you're a great teacher! I hated studying online because i never understood anything and i easily used to get distracted but the way you teach is really understandable. Thank you so much for uploading videos of all chapter & saving my marks in maths 😆😅
Sirr amzing session!! I'm able to attend ur class becoz today is sunday😂 otherwise due to my schl hrs it's get difficult to attend ur live session😅 H. W ans-- 60° for both✌⚡
56:04 if u will observe it carefully ik triangle acd =30+90+30 which is not 150*. So my question is that in triangle bcd that adds upto 180*. So how can this pe possible that the sum of acd is not 180. Plz anyone reading this comment explain it to me.
Sir thank you so much.. i have understood all the theorems.... i have enjoyed the whole video, it has also helped me with my pre-board exam... Thank you once again sir.. 😇🙂🙂
@@kushal01k ∴OR⟂PQ ∴∠ORT=90° => ∠TRQ=90°-30°=60° But in ΔOTR, OT=OR(Radii of the same circle) ∴∠OTR=60° Or ∠STR=60° But, ∠PRS =∠STR =60° (Angle in the alternate segment) In ∠ORT, ∠ORT =60° ∠OTR =60° ∴∠ROT =180°-(60°+60°) ∠ROT =180°-120°=60° ∴∠ROT =60°
sir you are such amazing person you just made me get interested in circles which was my one of the fear i never get understood this clearly before my entire math classes😄😄😄 THANKYOU sir GOD BLESS YOUUU😇🥰
✔ FREE Scholarship Test Class 10th Link 👉 vsat.vedantu.com/?Ref_code=VVD1015
Ultra legend just few hours. Before board exam
Mujhe nahi pata tha ek gol cheez meri life jhand kar degi
Trueee 😂😂
Fr😂
Relatable 😅😢
Truee 😭
Tommoorw is my exam of maths 😅
✅ 0:00 - Introduction
✅ 4:35 - Arc and its Types
✅ 6:05 - Segment & Sector
✅ 6:15 - Angle Properties
✅16:30 - Question No 1
✅ 19:22 - Vedantu IOQM Essential
✅ 19:42 - Vedantu ICSE Crash Course
✅ 20:57 - Cyclic Properties
✅ 22:32 - Question No 2
✅ 25:07 - Question No 3
✅ 26:07 - Question No 4
✅ 30:46 - Vedantu Term 2 Crash Course
✅ 31:52 - Tangent & Secant Properties
✅ 46:17 - Question No 5
✅ 50:27 - Question No 6
✅ 52:52 - Question No 7
✅ 56:52 - Home Work Question
legends came here 1 day before board exam
U 😂😊said it
😂🙌
yes sir
Assuming O is the center of the circle.
ORT = 90 - 30, ORT = 60.
OSR = 30 [By Angle Segment Theorem]
Since OS = OR, [Radii of the same circle]
OSR = ORS = 30. [Equal sides of an isosceles triangle have equal angles]
PRS + ORS + ORT + 30 = 180 [Straight line]
PRS + 30 + 60 + 30 = 180
PRS = 180 - 120
Thus PRS = 60.
PRS = RTS [By Angle Segment Theorem]
ROT + RTS + ORT = 180 [Angles in a triangle add up to 180]
ROT + 60 + 60 = 180
ROT = 180 - 120
ROT = 60
My apologies for not using the degree symbol and angle symbol due to technical difficulty.
Wow!!!!
🎉
Good👍
I have a little dout in the first step ORT : 90 - 30 . In that why are u subtracting ?? We should add right ?
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tommorow is my board exam and i am watching this now🙂🙂
same help 😭😭
just starting
@Aliza farid same💀
Same bro
Itna risk taking capability aata kahase hai tumlog me 😂
Who is from class 10th ICSE and watching this before 14 hrs of their exam 😂
Me
Hello
My crush has the same name as you 😂
Lmfao mee
😅🙂🙋♀️
PRS=60 degree
ROT=60 degree
Live chat: cbse students present
Now: icse students present 😂😂
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56:52 angle PRS 60 AND angle ROT 60
Can please explain how
HOMEWORK
FROM GIVEN FIGURE,
OR⊥PQ
HERE,∠ORQ=90°,∠TRQ=30°
∠ORQ-∠TRQ=∠ORT
THEREFORE ∠ORT=60°
OR=OT (BCZ CHORD OF SAME CIRCLE ARE SIMILAR)
∠ORT=∠OTR=60°
BY ANGLE SUM PROPERTY ∠ROT=60°
(ii)Now ∠PRS=∠STR ANGLES IN ALTERNATE SEGMENT
Therefore,∠PRS=60°
At 52:00 I was doing same mistake that you mentioned 😅😅
Angle PRS=60 degree
ROT=60degree
1)60 degrees
2)60 degrees
Thankyou sir the chapter is clear atlast 😀
HW: i) 60 ii) 60
Enjoyed the lecture a lot, thank you sir :)
Prs is 120 na from exterior angle equals to sun of interior opposite. I am having a doubt in it .so if kindly explain.
@@mdhasanmujtabajamal9833 see u can find ang. ORT that is 60 coz OR is perpendicular.Second the tri. SRT is right angle triangle so Ang. SRO is 30 and then u can find Ang. PRS by 90-30 that is 60.
@arty 60 coz OR=OT(radius of same circle) then Ang.R is equal to Ang. T so 60+60=120 and then 180-120=Ang. O
start watching from 1:55
Sir aap Bahut Achaa padate ho me tho apka maths ka teaching ka abse fan bane rahuga thank you sir 🙏
angle ROT=60 degrees
angle PRS=60 degrees
the best explanation of this chapter.
I wasn't able to understand it and was searching for a better video from a long time , thanks alot sir
U am just watching this video three days before exam , but i really thanks you sir to explain us clearly.
Bro same
@@asmit07706 same here
me 2 days before 🥲
Yea bro just a day left 😂
One day ago 🤣🤣🤣
Homework answers
i) 60°
ii) 60°
Sir honestly, you're a great teacher! I hated studying online because i never understood anything and i easily used to get distracted but the way you teach is really understandable. Thank you so much for uploading videos of all chapter & saving my marks in maths 😆😅
Bht acche se samjhaya sir aapne maza Aa gya padhne kaaaa💯💯👌👌
thank so much sir
25:53 itna sannata kyun hai bhai 😅😂😂😂😅
Watching 1.50 hours before board exam on 1.75x speed . Really helpful
@tejbirsingh how was your exam ??
@@yashrahussain6081 🤮
@@MahajanSaab21 how much you scored in your borad exam??
@@yashrahussain6081 abhi nhi hogye icse ke March Mee hote heee
@@MahajanSaab21 I know...I thought you have given your boards
Thank you sir 😊.....this help me lot and it is much easier way to understand 😊
I m blessed to be taught by such an amazing teacher like you i really enjoyed this video
Thankyou so much answer of homework is 60° for both
Yeah right!! He is lot better than our school teacher
@@chiragbiswas8850 he is not better he is far better than any teacher whom i hv seen 😇😌
Hey! In this question you took O as the centre , right?
Goooooooood,......... 👌👌👌😊
7:00 am
Angel ROT = 60°
Angel PRS =60°
8.36 am
1) 60 degrees
2) 60 degrees
thank you sir this was a big help :)
How rot came 60 plz explain
1. 30 degree
@@kushal01k alt. Segment theorem
Home Work..done
1) angle PRS = 60°
2) angle ROT = 60°
Sir please tell me my answer correct or not.
Sirr amzing session!!
I'm able to attend ur class becoz today is sunday😂 otherwise due to my schl hrs it's get difficult to attend ur live session😅
H. W ans-- 60° for both✌⚡
Yeah met again 😆
Army ?💜
@@aditisahu8739 chal be bts fan
@@aditisahu8739 bts - band thats shit
@@KaranS2022 🤣🤣🤣🤣🤣🤣🤣🤣
In question 1, There's written OBA but it's wrong because it's OAB 16:01
56:04 if u will observe it carefully ik triangle acd =30+90+30 which is not 150*. So my question is that in triangle bcd that adds upto 180*. So how can this pe possible that the sum of acd is not 180. Plz anyone reading this comment explain it to me.
90+60=150
Sir excellent session thank you
Homework answer of both parts is 60°
Thank you sir ji 😄😄😄
PRS=60 DEGREE
ROT=60 DEGREE
Tomorrow is my pre boards next level samajdari 😂🥴
Angle PRS = 180 - 30 = 150⁰
m(arc RT ) = 2× angle QRT
= 2 × 30 =60⁰
Angle ROT = 60⁰
40:32 auto focus aur auto exposure mai rahiye sir, probelm solve
Sir thank you so much.. i have understood all the theorems.... i have enjoyed the whole video, it has also helped me with my pre-board exam... Thank you once again sir.. 😇🙂🙂
Good
Tomorrow is my pre broad ka paper and i am watching now 👍👍👍
Thank You sir in 3 days my board exams are going to start
Sir the session was the best , it helped me to finish the chapter just before 2 weeks before semester 2 exam . Thank you very much
Same
@@realarkblademe also trying
@@realarkblade I am doing it 2 days before sem 2😭😭
@@durgeshkumari7080 i am doing on the exam days 🙂
I am doing it just before my exam🙃...
Sir angle o 30 and r is 90
real legends watching this even tho we r cbse but dont have a cbse one shot for this chapter
Homework answer
1- 60 degree
2- 60 degree
Amazing session sir
1-120
2-60
Answer:
i) ∠PRS = 60°
ii) ∠ROT = 60°
How rot came 60 ?
Plz explain..
@@kushal01k
∴OR⟂PQ
∴∠ORT=90°
=> ∠TRQ=90°-30°=60°
But in ΔOTR,
OT=OR(Radii of the same circle)
∴∠OTR=60° Or ∠STR=60°
But,
∠PRS =∠STR =60°
(Angle in the alternate segment)
In ∠ORT,
∠ORT =60°
∠OTR =60°
∴∠ROT =180°-(60°+60°)
∠ROT =180°-120°=60°
∴∠ROT =60°
Homework answer
60
Excited to come in homework rockers 🤘
Can please explain how
@@kartikeyraj7972 can you explain please
Fun Fact: We do not have Proving Problems
- Reduced Syllabus
😂😂❤🔥
hai na, i was wondering why sir is explaining proofs eventho its not in the syllabus.. par chalo acha hai, knowledge badhao
@@saachikanchan6276 haa
Sur prs 60 and rot 60
Both angle prs and angle rot will be 60 degree
Sir plz upload the remaining chapters soon...
HW answer
angle PRS = 60°
angle ROT = 60°
Can please explain how
Thank you sir it helped me a lot
Angle PRS & ANGLE ORT both are 60°.......
btw thanx a lot sir ❤
Sir great video thanku very much.
It helped a lot.
These teachings are best than my tuition teacher
But our parents never understands
Goooo Tuition!!
Same here bro 🤣😂
Same here🤣🤣
Sir paper bohot hard gaya English aur science ka kuch to bolo plz 🥺🥺🥺 hum bacho ke liye
Koi na term 2 mai phod dena
@@gamingtips2941 bhaiya nichood duga board walo ko term 1 kitta hard deya 😭
Work hard and you'll get good result.
Sir aapke mic mein shayad koi problem hai ya fir koi high frequency wave generate ho raha hai
i-60,ii-60.
SiR PRS
SINCE OR=OS RADIUS
^PRO=90'
^PRS=45
SRO=45
ISOSULUS TRIANGLE
^S=45
Bohat maza aa gaya sir tera session dek kar circles chapter pura achaa sa sekhila
Thank you for this vidoe Sir. Last day beffore exam
I was really tensed about this chapter, but after this video, this chapter is makkhan
Thank u sir ☺😊
I. 60°and II. 60°
Sir both the angles are =60degree
Angel PRS And Angle ROT are equal to 60°
Thank you sir
HOME WORK QUESTIONS (i) 60 (ii) 60
Session sahi hai achaa hai..
Sir sir sir
amazing and very helpful session
ANS OF H.M 1. /_ ROT = 60 '
2. /_ PRS = 30'
It is really a helpful video
Sir thank you so much. Your explanation really helped me.
PRS and ROT both 60°
📚Home work answer :both are 60°
Can please explain how
both angles are 60 degrees
60° is the answer for both
circles is easy
thank you sir
Sir will we write the property in short during exam while using it as a reason?? Sir please answer.
You are the best maths teacher on TH-cam
(i) angle R = 60°
(ii) angle O = 60°
Can u explain pls
Very well explained
sir thanks last minute revision was needed🙏💜
absolutely 🔥❤️
60°will be the homework answers
Sir thank you maths is my fav subject but circles kuch dimaag me nahi aa raha tha aapne samjha diya
I am watching this video 2months after it's live session and I was shocked when he said good morning it's Sunday because it is today
Today is even Sunday 😁
Today is Sunday too
Oooo bhai aaj bhi sunday heee hai 😂😂😂
Yes I am also watching on Sunday 😄
Today also 😅😅😂
Sir... homework ans is
Angle PRS=60 degree
Angle ROT=60 degree(Alternate segment Angle)
Sir you are the best teacher ! You make the toughest as easy as ABC ! Thank you so much.
🌶️
@@revisionconsistency ? What?
Really dude...toughest as easy as ABC!
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Can u read the hidden message
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U thought amazing sir!!!
sir you are such amazing person you just made me get interested in circles which was my one of the fear i never get understood this clearly before my entire math classes😄😄😄 THANKYOU sir GOD BLESS YOUUU😇🥰
Homework
1.60°
2.60°
Explain plss😑
Sir Mark toh utne lambe solution me hi milenge paper me figure me thodi solve karnege 😂