can you make a video explaining the isolated amplifier and how to use it in voltage measurement?Just want to suggest an idea for a video. I'm struggling to learn about this, and things seem to be so easy to understand when you explain it.
I'm willing to bet $50 that he uses PowerPoint to design the slides. I'm just 99.9% positive tho (not HIV-positive or something!!), so if you wanna take that bet lemmino!
Hello Sir, after watching your video i still dont understand that you said that buffer had almost no current go through it due to high impedance. But if buffer have no current go through it, how it can supply current for the next circuit? . Hope you help me Sir.
Buffer has high input impedance. So, the circuit before the buffer (from which the signal is applied to the buffer) won't draw much current. The input impedance of the buffer will act as a load. But buffer itself can provide larger currents. So, buffer can provide the relatively more current to the circuit connected at the output side of the buffer. Sp, of course, buffer is drawing more current from the power supply source and provides to the output stage. But the stage prior to buffer won't draw much current (because of the high input impedance of the buffer). I hope, it will clear your doubt.
@@ALLABOUTELECTRONICS i wonder what is effect of " the circuit before the buffer (from which the signal is applied to the buffer) won't draw much current" ? . - As far as i know that if the circuit before the buffer won't draw much current so its voltage will not be decreased, and when that voltage apply to buffer, it will be the same as its volatge when apply to input of buffer. Therefore, volatge won't be decreased - Secondly, based on your video, buffer also have high current capacity which help buffer provide enough current for the next circuit. Therefore, using buffer it make : + Voltage won't be decreased + Provide enough current - Based on your example in your video, the 5V of the first circuit won't be decreased due to high impedance of buffer(no current go through buffer => voltage before buffer won't be decreased) then that 5V go through buffer and output of buffer will still 5V (because : 5V/250ohm=20mA but buffer can provide up to 50mA so it will provide enough current for the next circuit so the 5V won't be decreased, cause based on your video if we dont have buffer then the first circuit only have 10mA and can not provide the second circuit with requirement 5/250=20mA or if we assume that the second circuit got maximum current from the first circuit which is 10mA then, 10mA*250ohm=2.5V, so the logic high will not go to the second circuit) - Could you check if my understands are wrong or true Sir ? - Thank you so much for taking time read my comment ^.^.
I try to use NOR gate IC which get input from CD4026 and the result doesn't follow the truth table. Instead of getting 1&1=0, I get 1&1=1 I suspect that current the flow into the input of NOR gate is not enough. So the NOR gate interpret the signal as LOW. Is this reason that I need to use Buffer? Sorry for my English. Hope you understand the question.
The circuit of TTL buffer is similar to TTL logic gate. But the final stage is open collector. It means, you need to connect external pull-up resistor. In some buffer ICs, the final stage used to be a darlington pair.
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Explained much more beautiflly than the lecture notes and my prof.
Keep it up!
Best channel out there for electronics students or enthusiasts.♥️🔥
great video !!!! I can't understand my professor when he tried to explain buffer at the first time. Now, I can understand thanks to this video.
Best explanation , soooo useful, thank you 👌🏻👍🏻
you saved my life bro
Computer organisation subject made me to think like an ECE student
Coz it is an APPLICATION of maths, physics and engineering
i am from cs but you clear my concept about tri state buffer
thankyou
Great work.👌 Grand salute to you man.
Very nice presentation 👍👍
Please complete these topics :-
Digital communications:- PSK, ASK,FSK,
Fiber optic system,
Pulse modulation, frequency modulation,
Basic antenna principle, directive gain, directivity, radiation pattern,
can you make a video explaining the isolated amplifier and how to use it in voltage measurement?Just want to suggest an idea for a video. I'm struggling to learn about this, and things seem to be so easy to understand when you explain it.
Very good and clear explanation Thank you
Wow this is great video... Keep up the good job and godbless ☺️
Hey can you make Verilog playlist? Your videos are easy to understand
Yes, will definitely consider it. It will take some time. But yes, will try to provide that playlist.
@@ALLABOUTELECTRONICS thank you so much
Is schmitt trigger already included inside every octal buffer ICs?
Sir could you please let me know the tools which you are using to design the content
I'm willing to bet $50 that he uses PowerPoint to design the slides. I'm just 99.9% positive tho (not HIV-positive or something!!), so if you wanna take that bet lemmino!
Great explanation
why the buffer can source a current up to 50mA at 2:34?
It has been designed to drive more current. Many buffers use the external Pull-up resistor, which increases their driving capability.
Super brother
Hello Sir, after watching your video i still dont understand that you said that buffer had almost no current go through it due to high impedance. But if buffer have no current go through it, how it can supply current for the next circuit? . Hope you help me Sir.
Buffer has high input impedance. So, the circuit before the buffer (from which the signal is applied to the buffer) won't draw much current. The input impedance of the buffer will act as a load. But buffer itself can provide larger currents. So, buffer can provide the relatively more current to the circuit connected at the output side of the buffer. Sp, of course, buffer is drawing more current from the power supply source and provides to the output stage. But the stage prior to buffer won't draw much current (because of the high input impedance of the buffer). I hope, it will clear your doubt.
@@ALLABOUTELECTRONICS i wonder what is effect of " the circuit before the buffer (from which the signal is applied to the buffer) won't draw much current" ? .
- As far as i know that if the circuit before the buffer won't draw much current so its voltage will not be decreased, and when that voltage apply to buffer, it will be the same as its volatge when apply to input of buffer. Therefore, volatge won't be decreased
- Secondly, based on your video, buffer also have high current capacity which help buffer provide enough current for the next circuit. Therefore, using buffer it make :
+ Voltage won't be decreased
+ Provide enough current
- Based on your example in your video, the 5V of the first circuit won't be decreased due to high impedance of buffer(no current go through buffer => voltage before buffer won't be decreased) then that 5V go through buffer and output of buffer will still 5V (because : 5V/250ohm=20mA but buffer can provide up to 50mA so it will provide enough current for the next circuit so the 5V won't be decreased, cause based on your video if we dont have buffer then the first circuit only have 10mA and can not provide the second circuit with requirement 5/250=20mA or if we assume that the second circuit got maximum current from the first circuit which is 10mA then, 10mA*250ohm=2.5V, so the logic high will not go to the second circuit)
- Could you check if my understands are wrong or true Sir ?
- Thank you so much for taking time read my comment ^.^.
Yes, what you understood is correct.
@@ALLABOUTELECTRONICS Thank you so much Sir, i am very lucky to be your student
Keep it up!
I try to use NOR gate IC which get input from CD4026 and the result doesn't follow the truth table. Instead of getting 1&1=0, I get 1&1=1
I suspect that current the flow into the input of NOR gate is not enough. So the NOR gate interpret the signal as LOW. Is this reason that I need to use Buffer?
Sorry for my English. Hope you understand the question.
Yes, that might be the reason. You can try the same with adding a buffer in between.
@@ALLABOUTELECTRONICS Thank you
Very well explained. Thank you
Sir, what is the main circuitry inside buffer?
The circuit of TTL buffer is similar to TTL logic gate. But the final stage is open collector. It means, you need to connect external pull-up resistor. In some buffer ICs, the final stage used to be a darlington pair.
what does mean short circuit?
you re a god
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Aa
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