UGC NET Paper 1 and TNSET (SCORE FULL MARKS- 10/10) Data Interpretation-Part 1 (100% -Success Tech)
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- เผยแพร่เมื่อ 22 เม.ย. 2024
- 📊 Master Data Interpretation for UGC NET & TNSET | Previous Year Questions & Techniques 📊
🎓 Welcome to Asiriyar Academy, your ultimate destination for comprehensive UGC NET Paper 1 and TNSET exam preparation! Dive deep into the realm of Data Interpretation with our expert guidance and ace your exams with confidence! 🌟
🔍 In this power-packed video, we unravel the secrets of Data Interpretation, Short cut techniques to solve data interpretation problems in the UGC NET paper1 and TNSET paper1 exams. It is a pivotal topic for UGC NET and TNSET Paper 1. We go beyond the basics, solving challenging questions from previous years and sharing invaluable strategies to tackle any DI problem that comes your way! 💡
📈 Whether you're a novice looking to build a strong foundation or a seasoned aspirant aiming for perfection, this session is tailored for you! From line graphs to mixed graphs, we cover it all, ensuring you're well-equipped for success. 📊✨
#UGC NET PAPER1 #data interpretation #tnset exam preparation #ugc net paper1 exam preparation techniques #ugc net previous year question solving
🔥 Here's what you'll gain:
Step-by-Step Solutions: We break down complex DI problems into easy-to-follow steps.
Proven Techniques: Learn time-saving methods and smart shortcuts to boost your efficiency.
Practice with Real Questions: Get ahead with solved questions from actual UGC NET Exams and TNSET exams.
Expert Tips: Benefit from insider tips and tricks to maximize your score in the data interpretation subject.
🚀 Ready to elevate your Data Interpretation skills and soar in your exams? Hit that "Subscribe" button and turn on notifications to never miss an insightful video from Asiriyar Academy! Let's journey together towards exam success! 💪📚
🔎 Looking for more exam tips, study materials, and guidance? Visit our website AsiriyarAcademy.com for exclusive resources and personalized study plans!
Click to view Our Previous Videos on ICT to score full marks
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Part 4(Storage System)
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#DataInterpretation #UGCNET #TNSET #ExamPreparation#AsiriyarAcademy #DIProblems #StudyTips #ExamSuccess #SubscribeNow
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Thank you so much for such a wonderful explanation. I will score full Marks in DI this time
Pls ICT part 6 video podunga sir. Unga video va follow pannitha na exam kku prepare pandren sir. Enna mathiri erukkura students kku examkku help pannunga sir pls.
Sure Soon I will upload
Yes sir
Yes sir
Yes sir
Yes sir ! Waiting for next ICT videos
Highly informative and easy to understand. Thanks a lot
1:06:10 for this question the answer is 275 I think. Because we multiply 1.75 with 5760 we will get only 10,080 but if we multiply 2.75 with 5760 we'll get the right answer? Correct me if I'm wrong thank you.
Very useful mam first i was afraid of DI now it became very easy thank u soooooooooo much mam ❤❤
Sir answer epdi vanthuchu. Sollunga sir
The tramsmission time required- Sending 512 byte packet wing a 56 kilobites. (1kilo 1000) per second modem is about
Ans: 73 milliseconds.
Very clear explanation Mam.very easy to understand. Thank you so much mam.
18.59
If the answer is correct mam ? Please refer the previous silde and tell me. Thank you
Thank u so much mam. Very interesting video.
Thank you very much mam. I understood the DATA INTERPRETATION CLASS VERY WELL.YOUR TEACHING IS VERY VERY CLEAR AND VERY UNDERSTANDABLE.THE SESSION IS VERY GOOD
You are most welcome
Very useful video .Thank you deepa mam.lastyear la 1 paperla maths theriyala eppo nammpikkai irrukku. Clearra poriyurhu.konjsam thamila sollunga question puriyala.
VERY USEFUL
Good morning mam
(31×25)/3=175?
Please explain mam
Thank you mam, for uploading your classes which were conducted via zoom call, here. Its highly beneficial ❤
Super mam.excellent...data interpretation unga teaching only im impressed
Hlo mam please slove 2022 june yoga paper 1 data interpretation problem mam. Thanks in advance.
Very interesting class mam
Quickly I learnt thank you
Mam your explanation is super.Ithuvarai yarum ippadi solli tharalai.super Great mam
Thank you so much for your appreciation
Thanks a lot Sir
Useful vedio mam ❤❤❤ excellent other units vedio apload mam
Super explanation..tq
Very nice mam.i am very clear that today topic
Thank you very much ma'am
Super🎉❤
Super mam thank you mam
Thank you mam very useful class....
Superb mam.
Thank you
Yes mam
Data interpretation class was very excellent and usefulness
Thank you so much
Superb mam
Thank you so much
Mam vanakkam unga video s super clear explanation 👍💯best teaching mam ungaludaiya acdemy videos ellam freeaa mam tnset ku daily examku unga videos follow panninal pothuma mam doubt clear pannunga mam i will writefirst time mam
Sir ICT topic le abbreviation videos podunge sir
Tq sir😊
Mam this is only for cs subject or all major subject
Currently we have live classes for CS, Maths and Commerce
Super mam...
Thank you mam clear
Thank you ma'am ☺️
Percentage decrease formula ku keezha Tex la sam salary increased nu iruku
1) 42
2) 5%
3)10
Plz share the next video sir
Thank you so much mam very clear explanation 🙏 upload ict part 6 please sir🙏🙏🙏
Super mam
Very excellent explanation mam.thank you very much mamx🙏👏👏
Thank you
31×25÷3 =175 answer puriyala mam,enakku 258 answer varudhu mam,clear pannunga
Same dout
Can you please suggest any good book for tnset paper 1 sir
PW question bank both topic and pyqs
Nice teaching mam.... Way of teaching is really super....
Thanks a lot
Free class attend panala mam
Nice teaching Mam... thoroughly learned from this.. Thank you.kindly post Teaching aptitude Mam
Thank You, Soon, I will upload
How to attend your class mam..now only I'm watching your videos..ur videos are very useful and easy to understand
please call to 9790085836
Mam communication videos poduga
Good job helpful vedio class❤
Thanks a lot
G 16
B 24
👍
👏👏
Mam teaching aptitude & research
Nice teaching..plz upload research aptitude sir
As soon as possible
👏
Class super mam 🎉Logical reasoning related videos podunga sir🙏
Will upload soon
Sir ict la ( part 6) video podunga
Ok
Suppose percentage ask me
(2000÷2500)×100=80
Research aptitude class
Vema poringa mam gocham puriya kastama iruku mam
Life sciences class upload mam
B
Very nice mam
MR part4 video podunga
Will upload soon
Daily oru sum practice potunga mam
Teach panra mam konjam nenga que la clear ah irunthingana listener Kum inum correct ah purium.ur focusing on language nt in que I think so.to my opinion ict teach pana sir correct ah teach panaru na ninakaren.
b
37
42
Mam academy num anupunga. Na join pankiraa
please call 9790085836 for more details about to join the live class, Thank You
42
5
250
Your class is suitable for maths students only.
Going to fast
I am a maths student but couldn't follow you
Very sad.
Send pdf mam
A b c
175
1680
X =5
7×25 = 175
9500
2640
250
X = 50
259/7=37
63/9 =7
Thankyou mam
But you are going too fast
It's maths you know.
Please little care about the timing .
5280
259
4500-2500=2000
10560
32
40
32
44
45
16 girls
690
17:18
Ict part 6 video podunga sir
Sure sir , Today I will upload
Mam reading comprehension podunga
Will upload soon
Hi mam class super mam your good name???
Yes, thanks, Deepa