Exploring Flow & Time Constants in the mode of Pressure Control

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  • เผยแพร่เมื่อ 23 พ.ย. 2024

ความคิดเห็น • 9

  • @dougchism5085
    @dougchism5085 3 ปีที่แล้ว

    Mr. Prost, I enjoyed this very much! Nicely done!

  • @christams8863
    @christams8863 2 ปีที่แล้ว +2

    With a size 6.0 ETT, you obviously have higher resistance and, consequently, more turbulent flow through the ETT tube. Therefore, P(lung) of the lungs would reach P(mouth) much later, with a size 6.0 ETT. P(lung ) would reach P(mouth) faster with a 8.0 ETT. You can see the inspiratory pause for a size 6.0 ETT is shorter than the inspiratory pause for a size 8.0 ETT. The lungs spend more time at P(mouth pressure) with an 8.0 ETT than that of a 6.0 ETT: therefore, a smaller tidal volume for a 6.0 ETT and a larger tidal volume for a 8.0 ETT.

  • @rajasekharthottadi5151
    @rajasekharthottadi5151 6 ปีที่แล้ว +1

    Nice presentation..Very simplified , thankyou

  • @ДенисЮденков-ь5ж
    @ДенисЮденков-ь5ж 6 ปีที่แล้ว +1

    Please, make video about forced oscillation technique in ventilation

  • @sinclair657
    @sinclair657 ปีที่แล้ว

    Thank you

  • @marcopolo2028
    @marcopolo2028 5 ปีที่แล้ว +1

    i dont understand how you're getting the resitance to calculate flow. To calculate flow we got the change in pressure by subtracting Pmouth and Plung but what value are we using to calculate the resistance to divide.

  • @Suzi_P
    @Suzi_P 5 ปีที่แล้ว +1

    Thanks so much

  • @paediatriciandoctorzahidhu8360
    @paediatriciandoctorzahidhu8360 4 ปีที่แล้ว

    Hi dear, in Simv mode if set RR is 12 and patients takes 14 breathes of his own... than how many breathes will receive the set vt?

  • @venkybly
    @venkybly 3 ปีที่แล้ว

    Tq