⏳ Timestamps 00:00 - Introduction 09:29 - Factorial Notation 16:08 - Fundamental Principle of Counting 41:38 - Formula For nPr 48:26 - Theorems of Permutation 01:11:01 - Permutation of Alike Objects 01:35:44 - Finding Rank According to Dictionary 01:50:30 - Circular Permutation (of Distinct Objects) 02:10:12 - Combinations (Selections) 02:23:23 - Properties of nCr 02:56:48 - Formation of Groups 03:24:01 - Selection of At Least One Object 03:50:12 - Distribution of Identical Objects (Beggar's Method) 04:01:43 - Topic : Theorems-Beggar's Method 04:04:43 - Finding Number of Non Negative Integral Solutions 04:25:23 - De-Arrangement/Mismatching 04:37:18 - De-Arrangement - Formula 1 like for devo ke dev mahadev😀😀😇😇😇
@__forhumanity__ In this you know that you have to form 5-digit number but the number of digits are 6. This means that you will have to leave 1 digit in each case. Also firstly you will check that the sum of digits must be divisible by 3 so that the number formed is also divisible by 3. You find only 2 cases when the number formed will be divisible by 3: Case 1: When you exclude 3. You have always been putting the inputs from the left side till now. However for this question you need to begin from the right hand side, you will find that you have only 2 digits which are even so only those 2 digits can be put at ones place (to make the number even, divisible by 2). Then the tens place remains with 4 choices. The hundreds place remains with 3 choices. The thousands place remains with 2 choices. And the ten thousands place will have only 1 choice left. Hence, no. Of permutations = 2×4×3×2×1=48 Case 2: When 6 is excluded. There is only one even number (2) that you have so the ones place has only 1 choice i.e. (2) to make the number even and divisible by 2. The tens place now has 4 digits left as 2 has already been utilized.The hundreds place remains with 3 choices. The thousands place remains with 2 choices. And the ten thousands place will have only 1 choice left. So the no. Of Permutations in this case =1×4×3×2×1=24 Total no. Of Combinations = 48+24 => 72
------------------------------------------------------------------------------------------------------------ ⏳ Timestamps 00:00 - Introduction 09:29 - Factorial Notation 16:08 - Fundamental Principle of Counting 41:38 - Formula For nPr 48:26 - Theorems of Permutation 01:11:01 - Permutation of Alike Objects 01:35:44 - Finding Rank According to Dictionary 01:50:30 - Circular Permutation (of Distinct Objects) 02:10:12 - Combinations (Selections) 02:23:23 - Properties of nCr 02:56:48 - Formation of Groups 03:24:01 - Selection of At Least One Object 03:50:12 - Distribution of Identical Objects (Beggar's Method) 04:01:43 - Topic : Theorems-Beggar's Method 04:04:43 - Finding Number of Non Negative Integral Solutions 04:25:23 - De-Arrangement/Mismatching 04:37:18 - De-Arrangement - Formula 05:01:25 - Thank You Bachoo!!
Bhai vo thumari problem hai phle concept ache se padh seeda adv level ki question solve mat kar ghanta bhi nhi hoga tumari preparation start hoke 4-5 months hi hua . Thumari batch vale me se hi badiya ranks ayega bus thu dekthe rah
------------------------------------------------------------ ⏳ Timestamps 00:00 - Introduction 09:29 - Factorial Notation 16:08 - Fundamental Principle of Counting 41:38 - Formula For nPr 48:26 - Theorems of Permutation 01:11:01 - Permutation of Alike Objects 01:35:44 - Finding Rank According to Dictionary 01:50:30 - Circular Permutation (of Distinct Objects) 02:10:12 - Combinations (Selections) 02:23:23 - Properties of nCr 02:56:48 - Formation of Groups 03:24:01 - Selection of At Least One Object 03:50:12 - Distribution of Identical Objects (Beggar's Method) 04:01:43 - Topic : Theorems-Beggar's Method 04:04:43 - Finding Number of Non Negative Integral Solutions 04:25:23 - De-Arrangement/Mismatching 04:37:18 - De-Arrangement - Formula 05:01:25 - Thank You Bachoo!!
Timestamps 00:00 - Introduction 09:29 - Factorial Notation 16:08 - Fundamental Principle of Counting 41:38 - Formula For nPr 48:26 - Theorems of Permutation 01:11:01 - Permutation of Alike Objects 01:35:44 - Finding Rank According to Dictionary 01:50:30 - Circular Permutation (of Distinct Objects) 02:10:12 - Combinations (Selections) 02:23:23 - Properties of nCr 02:56:48 - Formation of Groups 03:24:01 - Selection of At Least One Object 03:50:12 - Distribution of Identical Objects (Beggar's Method) 04:01:43 - Topic : Theorems-Beggar's Method 04:04:43 - Finding Number of Non Negative Integral Solutions 04:25:23 - De-Arrangement/Mismatching 04:37:18 - De-Arrangement - Formula
Kuchh mahine pehle mein sochta tha yeh sir jyada achche se explain nahi oar payenge qki sirf rank achchi aayi hai but ab pata chala ekdum 🔥 🔥🔥 teacher hai,pehli baar dekh raha hu phir bhi samajh aa gaya ❤❤❤
1:02:12 Solution = d) 72 It has to end with even and sum should be divisible by 3 Case 1) Leaving 3 then there are [1][2][3][4][2] (2 even numbers ending) = 48 Case 2) Leaving 6 then there are [1][2][3][4][1] (Only one even number ending which is 2 as 6 is removed) = 24 48 + 24 = *72*
@@techmago-sn1dg which part did you not understand In this you know that you have to form 5-digit number but the number of digits are 6. This means that you will have to leave 1 digit in each case. Also firstly you will check that the sum of digits must be divisible by 3 so that the number formed is also divisible by 3. You find only 2 cases when the number formed will be divisible by 3: Case 1: When you exclude 3. You have always been putting the inputs from the left side till now. However for this question you need to begin from the right hand side, you will find that you have only 2 digits which are even so only those 2 digits can be put at ones place (to make the number even, divisible by 2). Then the tens place remains with 4 choices. The hundreds place remains with 3 choices. The thousands place remains with 2 choices. And the ten thousands place will have only 1 choice left. Hence, no. Of permutations = 2×4×3×2×1=48 Case 2: When 6 is excluded. There is only one even number (2) that you have so the ones place has only 1 choice i.e. (2) to make the number even and divisible by 2. The tens place now has 4 digits left as 2 has already been utilized.The hundreds place remains with 3 choices. The thousands place remains with 2 choices. And the ten thousands place will have only 1 choice left. So the no. Of Permutations in this case =1×4×3×2×1=24 Total no. Of Combinations = 48+24 => 72 someone had earler commented
Thanks for this lecture , TK Sir !! The way you explain , help us develop an understanding of the question and make us know the correct approach for the question is great, and teachers like you inspire students like me to secure admission in IIT institutes.
47:50 sir ye ques mene alg method s kiya aur usse fast and aaya.. ~(2n+1)!(n-1)!/(n+2)!(2n-1)!=11/21 ~(2n+1)(2n)/(n+2)(n+1)(n) = 11/21 ~(2n+1)/(n+2)(n+1)=11/42 By hit and trial n=5 🙂
Guys Kabhi Backlog mat banne dena mera ye ch ka backlog ban giya tha abb ja ke khatam hua hai subhe 11 Am Se betha tha 7 baje khatam hua mare brain ka 100% use kr liya shiyed kyuki sir dard hone laga hai And 1 Disclaimer : Backlogs Is Injureous To our brain 😢😢😂😂
2:58:26 but here solving 5c2 we only get different groups possible for 2 object. But sir is saying its an expression for total number of groups. Total number of groups will be 5c2×2. Pls corrent me if i m wrong , its a doubt
@@AshishSinghKittu i know you you are a student who cant continue and you can say to someone you have no right to that fool its he want to do you not a book buyer for him nor a anything so should be shut its not good matters to talk like that ok understood
Tere jaise log hi hote h jo teacher compare karte h wo insaan hi h glti ho jati h aur kisi layak ban ja uss din akr compare kariyo teacher@@MuzammilAkhtar_IIT-D
sir jee hamai backlog khatam karna tha...apnai ek mahine mai tho hame syllabus sai aagai nikal diya...who bhi sare concept padha kar........sir jee apto best ho jee
@@shankar4686haan bhai concept sare samjh aajatai hain..aur module solve karnai baad tho ohhe hoye ....sahi bolun tho yai one shot dekhlo idea laelo ki kaisa chapter hai fir class mai dhyan de kar ques ki prep kar lo khattam
Guys is there a pattern you can follow in permutation? So When you're deciding the arrangement and the no of ways an entity can be arranged, how can we know whether it will be arranged according to factorial notation or every entity will have the same no of ways like 2x 2x2x it seems like thete is a different logic in every question. How can we learn how to get tot that logic accurately every time
00:00 - Introduction 09:29 - Factorial Notation 16:08 - Fundamental Principle of Counting 41:38 - Formula For nPr 48:26 Theorems of Permutation 01:11:01 - Permutation of Alike Objects 01:35:44 - Finding Rank According to Dictionary 01:50:30 - Circular Permutation (of Distinct Objects) 02:10:12 - Combinations (Selections) 02:23:23 - Properties of nCr 02:56:48 - Formation of Groups 03:24:01 Selection of At Least One Object 03:50:12 - Distribution of Identical Objects (Beggar's Method) 04:01:43 - Topic: Theorems-Beggar's Method 04:04:43 - Finding Number of Non Negative Integral Solutions 04:25:23 - De-Arrangement/Mismatching 04:37:18 - De-Arrangement - Formula 05:01:25 Thank You Bachoo!! Maine description me se copy kia h koi time waste nhi kiya isme jo ise paste kar ke likes lete h unse bach kar rhe 😂
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जय जय श्रीराम
I have just completed P And C from PACE Series PW..... And now this lecture appears in homepage 😅
But I will Also see this one 😊
Thanks for This PW ❤
Tahe dill se aap logon ka bhut bhut sukriya
Ye chapter hmesa hi aayenge ya arjuna ke hisab se
⏳ Timestamps
00:00 - Introduction
09:29 - Factorial Notation
16:08 - Fundamental Principle of Counting
41:38 - Formula For nPr
48:26 - Theorems of Permutation
01:11:01 - Permutation of Alike Objects
01:35:44 - Finding Rank According to Dictionary
01:50:30 - Circular Permutation (of Distinct Objects)
02:10:12 - Combinations (Selections)
02:23:23 - Properties of nCr
02:56:48 - Formation of Groups
03:24:01 - Selection of At Least One Object
03:50:12 - Distribution of Identical Objects (Beggar's Method)
04:01:43 - Topic : Theorems-Beggar's Method
04:04:43 - Finding Number of Non Negative Integral Solutions
04:25:23 - De-Arrangement/Mismatching
04:37:18 - De-Arrangement - Formula
1 like for devo ke dev mahadev😀😀😇😇😇
har har mahadev
@@LUCKY_S_VLOG har har mahadev jay shree ram
Description se chipkaya huya hai, clever
@@mansiii3119 accha description m aata h kya sorry muje nhu pata tha
Thanks I appreciate it.
One of the most passionated teacher of maths ... because of him I am able to Solve almost 60% of pyq's
Mains or advanced?
@@IITian_Shivammmains or advanced?
@@nischaybharadwaj6361 mains yaar
Advanced k questions?
PNC BECOMES EASY WHEN YOUR TEACHER IS TARUN MINATI
LOVE FROM ARJUNA ❤
Yes😂😂
Arjuna's
*SIR
tarun minati?
@@TsarAayush whats up jamres?
1:49:32
Mustafa-
A-720
F-360
Ma-120
Mf-60
Mt-60
Ms-60
Mua-24
Muf-12
Mus-aaft
Aatf
Afta
Atfa
Afat
Ataf
Ftaa
Tfaa
Taaf
Tafa
=1427
Like for tarun sir rank in iit 😊😊
rank ko like nhi I love my Tarun minati sir ji ❤
289 hai 2006 mei
28.9 in 200.6 year ×10
1:01:59 = d)72
We will break it in 2 cases
1)when 3 is not in use =48no.
2)when 6 is not in use=24 no.
48+24=72
Correct hai bhai Mera bhi yahi aaya hai SAME
mujhe smjh nhi aya bta do bhai😢
@@bethebest2426mujhe smjh nhi aaya bta do bhai😢
@__forhumanity__ In this you know that you have to form 5-digit number but the number of digits are 6. This means that you will have to leave 1 digit in each case.
Also firstly you will check that the sum of digits must be divisible by 3 so that the number formed is also divisible by 3.
You find only 2 cases when the number formed will be divisible by 3:
Case 1: When you exclude 3.
You have always been putting the inputs from the left side till now. However for this question you need to begin from the right hand side, you will find that you have only 2 digits which are even so only those 2 digits can be put at ones place (to make the number even, divisible by 2). Then the tens place remains with 4 choices. The hundreds place remains with 3 choices. The thousands place remains with 2 choices. And the ten thousands place will have only 1 choice left.
Hence, no. Of permutations = 2×4×3×2×1=48
Case 2: When 6 is excluded.
There is only one even number (2) that you have so the ones place has only 1 choice i.e. (2) to make the number even and divisible by 2. The tens place now has 4 digits left as 2 has already been utilized.The hundreds place remains with 3 choices. The thousands place remains with 2 choices. And the ten thousands place will have only 1 choice left.
So the no. Of Permutations in this case =1×4×3×2×1=24
Total no. Of Combinations = 48+24
=> 72
@@__forhumanity__bro explanation has been written here by me 👆👆
------------------------------------------------------------------------------------------------------------
⏳ Timestamps
00:00 - Introduction
09:29 - Factorial Notation
16:08 - Fundamental Principle of Counting
41:38 - Formula For nPr
48:26 - Theorems of Permutation
01:11:01 - Permutation of Alike Objects
01:35:44 - Finding Rank According to Dictionary
01:50:30 - Circular Permutation (of Distinct Objects)
02:10:12 - Combinations (Selections)
02:23:23 - Properties of nCr
02:56:48 - Formation of Groups
03:24:01 - Selection of At Least One Object
03:50:12 - Distribution of Identical Objects (Beggar's Method)
04:01:43 - Topic : Theorems-Beggar's Method
04:04:43 - Finding Number of Non Negative Integral Solutions
04:25:23 - De-Arrangement/Mismatching
04:37:18 - De-Arrangement - Formula
05:01:25 - Thank You Bachoo!!
copy paste 😂😂😂😂😂😂😂😂😂😂😂😂
Arjuna 1.0 Batch me padha pr qus nhi bn rhe the lekin ek baar aur kr lete 😂 Kyuki sir ne to train me baithkr ye chpt strong kr liya tha...😢😢
Same here
Questions kyo nhi bn rhe the?
Bhai vo thumari problem hai phle concept ache se padh seeda adv level ki question solve mat kar ghanta bhi nhi hoga tumari preparation start hoke 4-5 months hi hua . Thumari batch vale me se hi badiya ranks ayega bus thu dekthe rah
@@saiakhil162 sahi baat🔥🔥
PnC agr tough lag raha hai to ncert level pe krle bss
------------------------------------------------------------
⏳ Timestamps
00:00 - Introduction
09:29 - Factorial Notation
16:08 - Fundamental Principle of Counting
41:38 - Formula For nPr
48:26 - Theorems of Permutation
01:11:01 - Permutation of Alike Objects
01:35:44 - Finding Rank According to Dictionary
01:50:30 - Circular Permutation (of Distinct Objects)
02:10:12 - Combinations (Selections)
02:23:23 - Properties of nCr
02:56:48 - Formation of Groups
03:24:01 - Selection of At Least One Object
03:50:12 - Distribution of Identical Objects (Beggar's Method)
04:01:43 - Topic : Theorems-Beggar's Method
04:04:43 - Finding Number of Non Negative Integral Solutions
04:25:23 - De-Arrangement/Mismatching
04:37:18 - De-Arrangement - Formula
05:01:25 - Thank You Bachoo!!
1:18:29
2024 - 2025 Batch Attendance Lagao 😂
Nhi lagaunga attendance
😂😂@@MarsJupiterSaturnwunderbar
padle bhai kal kya kaha tha alakh sir ne : )
Bhai agar me tarun sir se padh lunga to mera jee advanced clear ho jayega
Bhai free me study kra rhe jee level ki to or kya chye this platform is too good thanks for all teacher ......qestion tab bnega jab khud bnaoge.....🙏🏻
garna jaemrs?
Timestamps
00:00 - Introduction
09:29 - Factorial Notation
16:08 - Fundamental Principle of Counting
41:38 - Formula For nPr
48:26 - Theorems of Permutation
01:11:01 - Permutation of Alike Objects
01:35:44 - Finding Rank According to Dictionary
01:50:30 - Circular Permutation (of Distinct Objects)
02:10:12 - Combinations (Selections)
02:23:23 - Properties of nCr
02:56:48 - Formation of Groups
03:24:01 - Selection of At Least One Object
03:50:12 - Distribution of Identical Objects (Beggar's Method)
04:01:43 - Topic : Theorems-Beggar's Method
04:04:43 - Finding Number of Non Negative Integral Solutions
04:25:23 - De-Arrangement/Mismatching
04:37:18 - De-Arrangement - Formula
thx for like ,, im onlie now
Kuchh mahine pehle mein sochta tha yeh sir jyada achche se explain nahi oar payenge qki sirf rank achchi aayi hai but ab pata chala ekdum 🔥 🔥🔥 teacher hai,pehli baar dekh raha hu phir bhi samajh aa gaya ❤❤❤
4:26:24
45:07
@IND_FF444 Bhai theory wise sab complete ha aab tumpe depend karta ha tm kitne questions lagate ho
1:02:12 Solution = d) 72
It has to end with even and sum should be divisible by 3
Case 1) Leaving 3 then there are [1][2][3][4][2] (2 even numbers ending) = 48
Case 2) Leaving 6 then there are [1][2][3][4][1] (Only one even number ending which is 2 as 6 is removed) = 24
48 + 24 = *72*
provide more detail
@@techmago-sn1dg which part did you not understand
In this you know that you have to form 5-digit number but the number of digits are 6. This means that you will have to leave 1 digit in each case.
Also firstly you will check that the sum of digits must be divisible by 3 so that the number formed is also divisible by 3.
You find only 2 cases when the number formed will be divisible by 3:
Case 1: When you exclude 3.
You have always been putting the inputs from the left side till now. However for this question you need to begin from the right hand side, you will find that you have only 2 digits which are even so only those 2 digits can be put at ones place (to make the number even, divisible by 2). Then the tens place remains with 4 choices. The hundreds place remains with 3 choices. The thousands place remains with 2 choices. And the ten thousands place will have only 1 choice left.
Hence, no. Of permutations = 2×4×3×2×1=48
Case 2: When 6 is excluded.
There is only one even number (2) that you have so the ones place has only 1 choice i.e. (2) to make the number even and divisible by 2. The tens place now has 4 digits left as 2 has already been utilized.The hundreds place remains with 3 choices. The thousands place remains with 2 choices. And the ten thousands place will have only 1 choice left.
So the no. Of Permutations in this case =1×4×3×2×1=24
Total no. Of Combinations = 48+24
=> 72
someone had earler commented
Arjuna jee respect button 👇👇👇
🎉😮
bhai ye likhne se accha ek question kr leta to accha hi hota
mai vo question krne ke bad hi likh rah hu
Very Helpful for tomorrow's test in arjuna 1.0🙂
yes ❤
2:11:19
Yss bro
@@Vishnilu 🤣🤣haaa
@@Vishnilu Kya mil gya bhai?😏😏Naughty ho ra ke😂 btw hum bhi arjuna 1.0 se hai
1:34:48 here the trick is valid but sir said that do direct for 1*1 grid ...So don't get confused.
But by common sense 2 ways is always correct.😂
Hadn't seen a teacher like him....... 😍
ikr
This video will help me for my Monday test ❤thanks sir ❤❤❤❤❤
Perfect lecture of P & C for revision and questions practice also.....❤
Who is for jee 2026? ❤
Sath mai jee fodenge
I am here 😂😂😅😊 bro
Me
@@mtg_yt_0.1 kaisi chal rhi teri, specially in physics😄😄
Preparing for Olympiad in class 9
The Best teacher ever! ❤
2:23:50
Questions practice from whole lecture
Thanks for this lecture , TK Sir !! The way you explain , help us develop an understanding of the question and make us know the correct approach for the question is great, and teachers like you inspire students like me to secure admission in IIT institutes.
2:54:50 b=8 and g=3
Who is here watching for half yearly exam😶
47:50 sir ye ques mene alg method s kiya aur usse fast and aaya..
~(2n+1)!(n-1)!/(n+2)!(2n-1)!=11/21
~(2n+1)(2n)/(n+2)(n+1)(n) = 11/21
~(2n+1)/(n+2)(n+1)=11/42
By hit and trial n=5 🙂
Every time answer is not correct
Thankyou sir for this wonderful revision session by our legendary Tarun sir love from Arjuna jee 1.O ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
bro I'm from 2.0 kya sir oneshot me bhi saare tricks batate hai ?? Pls reply
2:54:30 == b=8 and g=3 ❤❤
Howw
Kaise aayega bhai batao pls
Because only ye two numbers he satisfie kar rahe gai❤@@gauravkalra9074
Love from arjuna 1.0 ❤ sir we really need this thnkuu so much for this one shot ❤
Hii can u tell me ki ish video k baad ncert banega?
@@Garimabhatt233 yesh ofc you'll be able to solve ncert after completing this
@@vanshika_16 Ok thank u so much
Guys Kabhi Backlog mat banne dena mera ye ch ka backlog ban giya tha abb ja ke khatam hua hai subhe 11 Am Se betha tha 7 baje khatam hua mare brain ka 100% use kr liya shiyed kyuki sir dard hone laga hai And 1 Disclaimer : Backlogs Is Injureous To our brain 😢😢😂😂
revision krre the ya first time chapter padh rahe the?
wo bol rha h backlog tho obviously first time h@@adityasonawane8254
1:46:50 i think sir remembered anythhing other for ghotu :)
2:58:26 but here solving 5c2 we only get different groups possible for 2 object. But sir is saying its an expression for total number of groups.
Total number of groups will be 5c2×2.
Pls corrent me if i m wrong , its a doubt
One of the maths intrested chapter and I am learning from my best math teacher 😊😊
Who will complete this video in once😢
I can't 😴
Wonderful and fantastic concept for grid sirji.
With due respect sir,in case of one by one grid too,it is quite clear
xy,i.e,2!÷1!*1!=2ways
kuch common cheez nahi hai isiliye divide by 0!
@@7_thala_for_a_reason0! Is also 1
Sir ne bola to itna calculation nhi krna common sense lga do 1*1 grid always has 2ways 😂
1:50:25 the homework answer will be 1426 not 1427.
sir worldcup ke baad dekh raha tha yeh video aur apne IND VS AUS ke baare mai bola aab dukh ho raha hai 3:12:06
😢 shi meii but india won t20 wc❤🎉
Anyone present here?
Me
Sir Mustafa question me bahut dikat aa raha hai
I have just completed P And C from PACE Series PW..... And now this lecture appears in homepage 😅
But I will Also see this one 😊
Thanks for This PW ❤
Noice 😄
😅😅😅😅😂😂😂😂😂😂😂
Have u found that useful as compared to this?
@@vijayrani5536 Pehle Istemaal kare fir vishwas karen 😄😄😄
@@vijayrani5536 yes👍
tarun sir best maths teacher button
i see a basketball
Thank you,
Sir
Full revision ho gya🤗🤗
जय जय श्रीराम
34:11 2×3×4×2=48 not 72
Only u noticed
tarun khandelwal sir ji just supreme sir can understand our emotions
pluto batch attendance here
Studying in 10th but understood every single concept iit bombay confirm😂
Edit : studiying from uddan ❤
Me in 9th 😂😂 and i every 10th maths topic already because my brother is currently in 10 th and i also know some11th topics
Same..
@@AshishSinghKittu i know you you are a student who cant continue and you can say to someone you have no right to that fool its he want to do you not a book buyer for him nor a anything so should be shut its not good matters to talk like that ok understood
1:10:50 question mein galti ho gyi sir se
AIR 1 to aap logo ki hai well done guys
We never get bore coz of your teaching style😊
grid problem : 01:26:05
we need tarun sir in lakshya1.0 pleaseee🥺🥺
45:07 sir ne yaha bola tha ki 3 terms Lena hai aur khud 4 terms le Raha hai Aisa teacher nahi chahiye lakshya mein preparation barbaad kar dega
Tere jaise log hi hote h jo teacher compare karte h wo insaan hi h glti ho jati h aur kisi layak ban ja uss din akr compare kariyo teacher@@MuzammilAkhtar_IIT-D
Pw is emotion for every pwians ❤❤❤❤❤❤❤❤❤❤❤ alakh sir op
ARJUNA JEE ATTENDENCE 👍
why 😂
Sufficient for 11th class exams?
more than enough
sir jee hamai backlog khatam karna tha...apnai ek mahine mai tho hame syllabus sai aagai nikal diya...who bhi sare concept padha kar........sir jee apto best ho jee
Bhai one shot karke saare questions ban jate hai kya
@@shankar4686haan bhai concept sare samjh aajatai hain..aur module solve karnai baad tho ohhe hoye ....sahi bolun tho yai one shot dekhlo idea laelo ki kaisa chapter hai fir class mai dhyan de kar ques ki prep kar lo khattam
@@bffgamingking4479 bhai class ke agar ek bhi lecture is chapter ke nhi kiya ho to samajh aayega kya
@@shankar4686yes but tough chapter hai. If possible class se karna
Very best explaination sir. Please make other something helpful videos. This is very understanding and conceptual video👍👍👍👍👍
Best teacher of Maths ❤
Tumne Puri video dekhe Bina kaise keh Diya?
@@AmartyaAnand Dusre chap ke basis pr obv
Its rlly unfair and immature of u to make any teacher the best 🗿
@@AmartyaAnanddimag hai ki nhi !? Tere pe
@@AmartyaAnandbest teacher of maths forever video choro pura maths inse padha hu ❤❤
Sir kya ye school Wale bacho ke liye bhi hai
the best teachers mein se ek tarun sir :) ekdam op! concept sikhate hein love you sir
Sir iske notes kha milyngy ?
4:00:35 Blanket Dene ka Way thoda CASUAL HAI!!!
........Master of maths Tarun sir is best .......🙏🏻🙏🏻🙏🏻
Inclusion and exclusion principle missing
👇Vote for it guys
sets me nhi padha kya bhai?
sets me padha dete hai wo
A challenging topic explained in a very lucid manner.
5 hr vedio just completed in 2 hr because I am student of tarun minati sir
But koi saleem sir ko na batana 😂😂😂😂😂😂😂
2x 😂😂😂😂
1:01:00
Mains July mehumne 10 to the powers kyun li hai
Agr wo 6 to 8 characters long hoga toh koi 2 chutega na ??
Someone pls tell 😊
THANKS TO OUR TARUNMINATI SIR 🔥🔥🔥🔥
Kon kon coaching jane ke baad bhi pw ka lecture dekhta hai😂😂
lol i am allen student 😂😂
@@Deboshmitsalui-w4y Tumhara test paper de sakte ho mujhe
Allen students can relate because I am also allen student.. 😂😂
13:55 / 5:02:40
•
Factorial Notation
Permutation & Combinations FULL CHAPTER | Class 11th Maths | Arjuna JEE
Guys hit the like button
& for our loving teacher tarun sir op in the chat
Love from arjuna 1.0❤❤❤❤
Love u sir
why 😂
1:14:40 is there any change to lecture ?
sir literally i am very satisfied with your teaching style and become fan of you
We have to do whole lecture even for school level?😅
Love from PW vidyapeeth kolkata
Guys is there a pattern you can follow in permutation? So When you're deciding the arrangement and the no of ways an entity can be arranged, how can we know whether it will be arranged according to factorial notation or every entity will have the same no of ways like 2x 2x2x it seems like thete is a different logic in every question. How can we learn how to get tot that logic accurately every time
Happy to complete my 5 hours lecture मनापासून धन्यवाद sir ❤❤
Are bhai Marathi maanus ka shikvaly sirani
Sir marathi ahet na 😊
@@S_PAWAR_ nahi re aadnav tr nahi siranch
@@iitlover7167 adnawach marathi wattye
95 handshakes !? 2:20:24
No it's 190
20×19×18!
____________
18! 2!
4:06:52 sabko agr 0 mil Gaye th0 equality satisfy kaise hogi
I am a neet aspirants but school me maths hei😔🙌 Thank pw team thank you sir ❤️
Same dost
To liya hi kyu maths jab neet deni hai
Any one tell me how MUSTAFA's rank was 1427....?
I didn't understand 😢
same problem bro 😢
Arjuna 1.0 attendence and combination wale like karooo India fans comment Karo
hello sister i can remember you.. i am dishan.. i saw you at community.. i am also from arjuna 1.0
@@BathroomSinger-m4i hi bro
@@BathroomSinger-m4i cann you give your no.
@@BathroomSinger-m4i give your no.
@@thelimitedjourneylive pehli baar kisi ladki ko ladke ka no. mangte hue dekh rha hu
1:10:21 Here answer should be 570 and not 569 because 4482 is also considered in the closed interval
You cannot make 4482 as there is no 8 broo
Commerce student here for concept clearity ❤😢
41:18 Anyone explain answer plz
Inclusion Exclusion Principle shayad se aap sir isme daalna bhool gaye ho
I LOVE PW ARJUNA BATCH SINCE I HAVE JOINED ❤❤
PW know much better what we need🥲
Amazing explanation sirr ,, AWESOME 💯💯💯
Bhai finally itne comment padhna k baad tere comment ko dekha aur apna aap par trust hua ki meri calculation thik h sir ki galat h😅
THANK ME LATER ❤@@vishalsandhu8808
Sir galat nahi tum tu galat hai .
@@vishalsandhu8808 bhai tu kya iske chakker mai pad raha tera answer galat aya hai sir ka sahi hai
@@divaforxtgameex8519 yes ofcourse
Sir please limits and derivatives ke upar videos bana dijiye🙏🙏🙏
My favourite teacher 🙏🙏
If we are running then PW is our stamina
Nhi pw is emootionnn ❤😂😂😂😂😂
01:18:45 why we not take 7 factorial we can sew that there are is total number is 7 so why you take 6factorial
Arjuna 1.o 🙋🏻♂️
I have taken offline batch of PW at Vidyapeeth in Arjuna Jee . But I study from YT , specially for Tarun sir 😅✌🏻
Same❤
Kis kisko lagta hai ki sir Henry Cavill jaise dikhte hain
Indian Henry Cavill
Real
Superman
Easiest explanation of this chapter available in entire youtube
Also sir started from basics
I am preparing for Olympiad and this was actually use ful
00:00 - Introduction
09:29 - Factorial Notation
16:08 - Fundamental Principle of Counting
41:38 - Formula For nPr
48:26 Theorems of Permutation
01:11:01 - Permutation of Alike Objects 01:35:44 - Finding Rank According to Dictionary
01:50:30 - Circular Permutation (of Distinct Objects) 02:10:12 - Combinations (Selections)
02:23:23 - Properties of nCr
02:56:48 - Formation of Groups
03:24:01 Selection of At Least One Object
03:50:12 - Distribution of Identical Objects (Beggar's
Method)
04:01:43 - Topic: Theorems-Beggar's Method
04:04:43 - Finding Number of Non Negative Integral
Solutions
04:25:23 - De-Arrangement/Mismatching
04:37:18 - De-Arrangement - Formula
05:01:25 Thank You Bachoo!!
Maine description me se copy kia h koi time waste nhi kiya isme jo ise paste kar ke likes lete h unse bach kar rhe 😂
1:10:50 sir question mein mistake ho gyi apse😊
How many of you think pw is best...?
👇🏻
thank you sir ek baar me pura ho gya!!!