Ecuador | Math Olympiad | A Nice Rational Equation Challenge

Ecuador | Math Olympiad | A Nice Rational Equation Challenge
Welcome to another Math Olympiad challenge! as we tackle a fascinating rational equation using the substitution method, a popular technique in Math Olympiad problems. This video will guide you through each step of the process, helping you understand how to effectively apply substitution to simplify and solve complex equations. Perfect for students preparing for math competitions or anyone looking to enhance their algebra skills.
Don't forget to like, comment, and subscribe for more math challenges and solutions. Happy solving!
In this tutorial, you'll learn:
1- Fundamental concepts and definitions of rational equations
2- Step-by-step method of substitution to solve rational equation
3- Common pitfalls and how to avoid them
4- Expert tips and tricks for solving problems quickly and accurately
5- Practice problems with detailed solutions
Additional Resources:
• Math Olympiad Secrets:...
• Ready for a Math Chall...
• Conquer a Difficult Ra...
• Overcoming Rational Eq...
#matholympiad #ecuador #rationalequations #mathtutorial #substitution #math #mathskills #learnmath #education #algebra #problemsolving
Join us as we unlock the secrets to excelling in rational equations and take your Math Olympiad prep to the next level. Don't forget to like, subscribe, and hit the bell icon for more Math Olympiad prep videos. Let's conquer those equations together!
Thanks for Watching!!

[@tunneloflight]

Multiplying through all of the parts and simplifying yields 4x^4 - 16x^3 - x^2 + 34X + 15 = 0, synthetic division by negative 1 yields 4x^3 - 20x^2 + 19x + 15 = 0. Synthetic division by 3 yields 4x^2 - 8x minus 5 = 0. Quadratic equation yields 1 +/- 1.5 = 2.5, -0.5. x = -1, -0.5, 2.5, 3. Using the midpoint of the factors yields better symmetry. But in this case the synthetic division of the equation in x is straight forward.

[@Ds_khoka_123]

Plz upload more questions on it 😊

[@tejpalsingh366]

x=5/2; -1/2; 3; -1

[@RajeshKumar-wu7ox]

X=-1,3,(5/2),(-1/2)

[@user-kt1dm9jz5t]

X=-1, -1/2, 5/2, 3.

[@RealQinnMalloryu4]

{4x^2+2}= {6x^2 ➖ 9x^2}/1x^2 + =3x/x^2 {4x^2 ➖ 25} 1x^2/1x^2 = {21x^2 ➖ 1x^2}/1x^2= 21x^4/1x^2 {3x/1x^2+ 21x^4/1x^2 }= 24x^5/2x^4 = 12x^1.1 3^4x1^1.1^1 3^2^2 x^.1^1 3^2^1^2x.1^1^1^1 31^1^2x 3^2x (x ➖ 3x+2).