Oxford Linear Algebra: Linear Transformations Explained

[@Bengolstar300]

Thank you Dr Crawford for giving us this fantastic lesson ❤️

[@TomRocksMaths]

Check out ProPrep with a 30-day free trial to see how it can help you to improve your performance in STEM-based subjects: www.proprep.uk/info/TOM-Crawford

[@demiladesegun-omosehin7609]

I might actually just stop showing up to class and only watch your videos

[@jeee2025]

I don't like math but watch you give me inspiration to understand math

[@gi0nic40]

at 24:24 you are claiming that by expanding the bracket we should also have xyhat and xhaty. Arent we considering vectors tho so that operation would actually be the dot product whose result doesnt have xyhat and xhaty?

[@bamboybang3640]

yes the result is scalar, for simplification just use that the dot product is xy, or test it with 1 dimensional vectors
let x=1,y=2,z=1 let x=xhat,y=yhat ,z=zhat
expand the bracket in the term ((x+x)(y+y),z+z,(y+y)(z+z) gives
(4xy,2z,4yz).
compare it with the term
(xy+xy,z+z,yz+yz) gives
(2xy,2z,2yz)

[@soroushsoltani919]

i got good basis for this chapter, thank u

[@Thecannibalfrombeyond]

Thanks man, got my exam tomorrow, hope I will ace .

[@TomRocksMaths]

Best of luck!

[@science0064]

Pls make a video on Riemann Hypothesis
Please Dr. Tom

[@learnmathematicswithme847]

How I study topology suggest me a beautiful channel I shall be very thankful

[@cco9162]

Why do you call it Oxford linear algebra? Isn't it the same all over the globe?

[@amritlohia8240]

Yes - it's just to point out that this presentation of it is based on the first-year lecture course taught at Oxford.

[@darkounet2585]

How the fuck did I end up here. Anyway, seem like a good vid? Can't know for sure i only understood the part where you introduce yourself.

[@Tyln93]

Awkward Emo Nerd Boy!!!