MORE PROBLEMS Block on a Wedge - Friction Problem (Mechanics) : th-cam.com/video/UB79ICRNnUk/w-d-xo.html Disc / Wheel Rolling down Inclined Plane (Mechanics Problem) : th-cam.com/video/5xGTv-tfoHg/w-d-xo.html Atwood Machine - Pulley Problem (Newtonian Mechanics) : th-cam.com/video/_LQs_nJqEXI/w-d-xo.html Bead on a Rotating wire - Problem (Newtonian Mechanics) : th-cam.com/video/xe7nGSw7ZGc/w-d-xo.html Bead on a Rotating wire - (Lagrangian Mechanics) : th-cam.com/video/xmXORmm9m-o/w-d-xo.html Motion of Charged particle in E and B : th-cam.com/video/wpQJKg8Zl4s/w-d-xo.html
Sir is there a rule that we can't break the components along n perpendicular to the direction of motion of block, n should break other rest of the forces????
if u have good books like cengage they do this question by 7 methods so this is one of the methods and yes you can do that by taking components of normal
Your splitting of the weight vector into 2 components is unclear. You simply draw a component in x-direction without saying how to get the length of this component, namely by a parallelogram (which is a rectangle in this case). And promptly you draw the x-component a bit too long. Without this construction, the length of the x and y components mg sin(θ) and mg cos(θ) cannot be understood.
MORE PROBLEMS
Block on a Wedge - Friction Problem (Mechanics) : th-cam.com/video/UB79ICRNnUk/w-d-xo.html
Disc / Wheel Rolling down Inclined Plane (Mechanics Problem) : th-cam.com/video/5xGTv-tfoHg/w-d-xo.html
Atwood Machine - Pulley Problem (Newtonian Mechanics) : th-cam.com/video/_LQs_nJqEXI/w-d-xo.html
Bead on a Rotating wire - Problem (Newtonian Mechanics) : th-cam.com/video/xe7nGSw7ZGc/w-d-xo.html
Bead on a Rotating wire - (Lagrangian Mechanics)
: th-cam.com/video/xmXORmm9m-o/w-d-xo.html
Motion of Charged particle in E and B
: th-cam.com/video/wpQJKg8Zl4s/w-d-xo.html
The peoples who doesn't know hindi from South india. this video helps us tq sir for awesome video
you have solved my doubt that how we take mgsintheta or cos theta. great work. you are explaning every basic step. well done. lots of love
Tysm sir.....We want videos like this...
Yes
Next few videos are going to be in this style :)
Sir it's humble request please make more video's on mechanics
Sir is there a rule that we can't break the components along n perpendicular to the direction of motion of block, n should break other rest of the forces????
Beautiful video. Thanks sir
Well done ❤️
Sir please make some videos on Solid Mechanics
Please do a video by adding values 🤕
why we dont do components of normal in such problems ?
if u have good books like cengage they do this question by 7 methods so this is one of the methods
and yes you can do that by taking components of normal
Thank u
Nice
But you should change a bit for explanation
But nice
Sorry I m student just I felt little difficult to understand
How mgcostheta come?
The projection / component of a vector (force in this case, F) on to its base is Fcostheta
@@FortheLoveofPhysics sir u draw a perpendicular?
It is with respect to the x and y axis that I defined.. as you see the xy coordinate axes are wrt the inclined plane..
@@FortheLoveofPhysics ok thanks sir
@@shashankpandey4167 go through vectors u will understand better
Idhonn malayalathil parayo
🔥💯
Your splitting of the weight vector into 2 components is unclear. You simply draw a component in x-direction without saying how to get the length of this component, namely by a parallelogram (which is a rectangle in this case). And promptly you draw the x-component a bit too long.
Without this construction, the length of the x and y components mg sin(θ) and mg cos(θ) cannot be understood.
Thn
Sir can you use little but in hindi
mtlb kuch bhi😂