गुणनखंड ज्ञात कीजिए । gunakkhand Kaise nikala jata hai | factorization | Part 4

[@Anilkumar-4515]

प्रणाम सर जी।।😊😊🙏🙏🙏 आपके पढ़ाने का तरीका ही यूनिक है।

[@RSR9598]

Sar ji Sawal number 3 mein Jaise aapane 64 ka gunankhand Kiya 2×2×2×2×2=64
To Sar ji 4 cube Kaise a gya yah to pta chal gya
Sar ji se aur video banaaiye gunan khand Kaise Ghat Mein late Hain Chhoti Chhoti sankhya Se Kaise Badi sankhya Ghat banti Hai plz 🙏🙏🙏

[@study5.6]

2×2×2×2×2×2=64 दो 6 बार है और इसका आपस में गुणा करो गे तो 64 आये गा
यदि 64 को पावर 3 के रूप में लिखना हो
तो 4×4×4=64 इसमें चार तीन बार है तो इसे हम 4 का पावर 3 लिख सकते हैं
2 x 2 x 2 x2 x2 x2 =64
इसमें शुरू का
2 x2 =4
2 x 2 =4
2 x 2 = 4
तो इससे हम तीन चार निकाल लिए
चलो किसी दिन इसको और डिटेल में समझाएंगे

[@study5.6]

Thanks 😊

[@RSR9598]

@@study5.6
ओक सर जी

[@sejal1291]

Nice 👍👍👍 you are king sir

[@study5.6]

Many many thanks 🤗

[@rajmaniyadav6034]

जीवन के असली निर्माता निर्देशक अगर स्वरूप को देख लिया जाए तो मोह माया खत्म हो जाता है उसी प्रकार अगर math's ke जड़ यानी basic information ko deemak me बैठा ले सिख ले तो maths सरल सहज हो जाता है और आप जैसे भाई का साथ हो तो hm जैसे कमजोर का उधार हो जाय love you so much ji ❤

[@study5.6]

Good 😊

[@RajkaranKol-cg5ek]

❤❤❤❤❤❤

[@sejal1291]

Nice 👍👍👍👍👍👍 you are king Sir

[@study5.6]

Many many thanks 🤗

[@Anshikayadav860]

Aap bahut achhe se samjhhate h ❤❤❤

[@study5.6]

Thanks 😊

[@UKgammer72]

Sahi bat

[@avinashrideh123]

गजब तरीका है 👌👌🔥🔥🔥🔥

[@avinashrideh123]

बहुत मस्त तरीका से बताते है sir जी 👌
हम लोग को बचपन में sir log pdhaye the इसी तरीका से,, इसमें कमजोर से कमजोर बिद्यार्थी समझ जायेगा,, बहुत बहुत धन्यवाद गुरु जी 🙏🙏🙏🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥

[@study5.6]

Good 😊

[@yadavji-dr3mo]

Ham kewal aaphi ka video dekhti hu

[@inatullahkhan5417]

[{(Attraction )}]×÷+- sir aap lajawab hai....

[@Indian.tourstip]

Thanks Guru ji ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤love you

[@RajkaranKol-cg5ek]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

[@adamgupta8229]

... Waah sir jii waah...

[@bhanusengar3082]

Jo tareeka hai apke padane ka seedhe board se dimag mai

[@study5.6]

😊😊 thanks

[@dilbagchhillar]

Great🎉🎉

[@dilbagchhillar]

Well explained🎉🎉

[@ramakantamalik1874]

Thank you very so much sir❤❤❤😂😂😂

[@study5.6]

Most welcome 🤗

[@englishwithd.s.sengar6192]

Excellent 👌❤...Sir ji 🙏

[@study5.6]

Thanks

[@corneliusmarandi7262]

‌‌Good morning Sir, you teach very well. Your way of teaching is very good sir, it is easy to understand.

[@study5.6]

Thanks and welcome 🤗

[@englishwithd.s.sengar6192]

❤❤

[@shamsfact]

Thankyou sir 😊😊😊😊

[@udakumar3331]

thank you sir

[@study5.6]

Most welcome 🤗

[@hfghfggv5346]

Zaid ahmad 😊😊😊😊😊😊😊😊🎉🎉🎉🎉🎉🎉❤❤❤❤

[@its_kapil_bhai]

Thank sir

[@study5.6]

Welcome 🤗

[@RSR9598]

Sir Ji mein 3:30 Am Morning mein Yah dekha ❤

[@study5.6]

Good 😊

[@Shyam.SinghKushram]

❤❤❤❤❤❤❤❤🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉

[@SakibAhamd-c3e]

❤❤❤ Thank you sir ❤❤❤

[@study5.6]

Welcome 😊

[@hatkarkishan2215]

​@@study5.6good tea hjng

[@rajmaniyadav6034]

❤

[@rajniyadav1787]

Sir🙏 sir aapne figer of speech English and Hindi mai padaya hai jo bahut aachha hai sir plz us book ka name bataiye n.,..sir vh book hindi medium ke liye bahut helpful hai ....

[@study5.6]

Grammer ki book le Lena
Book name - Excellent

[@VinayKumar-kq7wf]

🎉

[@lordbuddhaconventschoolnaw258]

Aq aur bq bala formula kyon nahi lagaya sir

[@ramstudypoint7252]

Nice

[@PankajKumar-f2p3y]

Hi sar
😮😮😮😊😊😊

[@VinayKumar-kq7wf]

🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉😢 11:47 11:48 11:48 11:49 11:49 11:49

[@satikexplain]

Sir aapne thumbnail mein kis font ka use kiya hain plz reply

[@study5.6]

Jo man krta hai vhi use kar lete hai
Name nhi yad hai

[@govinddurgapal2386]

Love u so much sir ji
Good morning
EXCELLENT ❤❤❤❤❤
👍🏻👍🏻👍🏻👍🏻👍🏻🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼👌🏻👌🏻👌🏻👌🏻👌🏻

[@study5.6]

Thanks 😊

[@naushabaperween2882]

Trigonometric sin cos cosec tan ka maan

[@study5.6]

Video link
th-cam.com/video/4VQQ4UaSx4M/w-d-xo.htmlsi=zoJzIjI3abWb4Iew

[@priyankasingh2163]

Fess kitni h classics ki

[@study5.6]

Ye class free hai

[@priyankasingh2163]

Sabhi savalo ki koi bhi classic ki fre h

[@ManojKumar-e3h5c]

Sums 64x^3 - 27y^3 = (4x)^3 - (3y)^3, a = 4x and b = 3y (a^3 - b^3) = ( a+b). ( a^2-ab +b^2) = (4x - 3y) ( (4x)^2 - 4x× 3y + (3y)^2), = ( 4x - 3y) ( 16x^2 - 12xy + 9y^2) answer

[@RupamKumari-x7b]

Nice