Wonderful video sir thank you!! And thanks for recording in English. I’m not from India, so sometimes I see a video with an English title but the video is spoken in Hindu. Thank u!!
Correct me if I am wrong, but I think there is a little error in Hardware drawing, it shows an arrow beginning from Multiplicand M and ends at Accumulator/register A . But after every cycle where A=A+M will occur, the sum bits will be stored back into the register A, which should cause an arrow beginning from n-bit adder and ending at Accumulator A. This videos are great and his style of delivery is so involving.
Sir, thank you for this awesome tutorial. You make every topic very simple. Your teaching style and technique is also very good. Your videos have always helped me. Once again thanking you for your time and effort.
All I needed to hear was "add and shift" and I finished my python code for mult. Seriously hadn't looked at it that way yet. Now just looking for fast division code concept... I prefer to make my own implementations of math libs. My python math lib is limited only by available RAM. When I'm done, I'll make a C implementation as LGPL.
Sir, there is a mistake in hardware structure diagram ..... Addition of M and Q must go into A where as in ur diagram Multiplicand is going into A register at 9:43
I'm having a hard time understanding through his accent (problem with my hearing, not him), but there seems to be a step missing, unless I misheard. After shifting the multiplier right by one bit, you must compare the resulting multiplier with zero and exit if the multiplier is zero. Without this step, a multiplier like 00000001 would give the correct product immediately, but then the product would be shifted left 7 times, throwing off the result. It is obvious, but should still be noted. Naively, I would have thought to cycle through all bits of the multiplier.
Suppose B = 1101 and Q = 0001. After the first step - adding and shr, EAQ = 0 0110 1000 After the second step - shr, EAQ = 0 0011 0100 After the third step - shr, EAQ = 0 0001 1010 After the fourth step - shr, EAQ = 0 0000 1101 If you exit after the first step because Q = 0, you're result would be 0110 1000 which is not equal to 0000 0110.
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Watched your video just the day before my exam. Very clearly explained sir! Thank you so much!
Best handwriting .. best explanation .. wow .. thanks sir
Unironically a great tutorial, thank you.
Excellent video. Clean handwriting, clear explanation. Thanks!
So far the best explanation i can find, truly appreciate it
even our professor were confused for this topic. Thank you sir. All clear
my teachers are total crap
you are amazing
Thank you. You are a really good teacher.
Great lecture and clear explanation, thank you.
Concept crystal clear.🙏🏽🙏🏽
Wonderful video sir thank you!! And thanks for recording in English. I’m not from India, so sometimes I see a video with an English title but the video is spoken in Hindu. Thank u!!
tbh i dont understand your booth because of the flow chart but i understand this.... passing is enough for me right now hahah thks
Correct me if I am wrong, but I think there is a little error in Hardware drawing, it shows an arrow beginning from Multiplicand M and ends at Accumulator/register A . But after every cycle where A=A+M will occur, the sum bits will be stored back into the register A, which should cause an arrow beginning from n-bit adder and ending at Accumulator A.
This videos are great and his style of delivery is so involving.
Ya, you're correct!
Crystal clear explanation 🤌🏻❣️
actual dub man fr thanks for breaking it down so it's actually digestible
i am close to an exam and this just saved me. Thank you very much
SUPER MACHA NINU EN ADRU AGLI👍👍👍👍👍👍👍👍👍👍👍👍
Good tutorial Sir ,your passion is so much appreciated
Thank you sir for explaining it in such an easy way...
Very clear tutorial. Thank you.
Thank you very much sir, you always play good role and teaching method as well.
way better than my professor
Sir, thank you for this awesome tutorial. You make every topic very simple. Your teaching style and technique is also very good. Your videos have always helped me. Once again thanking you for your time and effort.
thank u so much.such a very perfect and very nice explaination sir thanu u thank u so much sirrrr🙏🙏
Thanks for your help !
this was helpful..thanks sir
Thank you so much for this explanation!
You made things so much easier thanks!!
Perfect, thank you. 👍
Awesome 👍👍 👍👍
Very helpful sir 🙏🏻👏
I was about to write an exam and i was confused. Thank you. Please add a donate button
All I needed to hear was "add and shift" and I finished my python code for mult. Seriously hadn't looked at it that way yet. Now just looking for fast division code concept... I prefer to make my own implementations of math libs. My python math lib is limited only by available RAM. When I'm done, I'll make a C implementation as LGPL.
Great job sir.
Thank you so much sir!!
Will this come under vedic maths
Very useful...Thanks.
it was perfect ,Thank you
Iss Gareebh ki dua lagegi sahabh aapko 😓thanks for making this messy topic understandable !
😭
my stupid as was wondering what "jero" is💔💔😂😂
hehe lol yeah our prev gen indians usually pronounce j for z , my dad too sometimes lol
Noice sir❤
Thank you sir!
Nice lecture... really helpful
awesome sir
Thank you
this was perfect, thank you
Sir, there is a mistake in hardware structure diagram ..... Addition of M and Q must go into A where as in ur diagram Multiplicand is going into A register at 9:43
Good. Use different color marker to show bit drop off for clarity please.
Great lecture sir
nicely presented and explained really well sir, thank you
Solid video
my mans got the best bengali accent
liked for good presentation and well explained
Thank you so much
I'm having a hard time understanding through his accent (problem with my hearing, not him), but there seems to be a step missing, unless I misheard. After shifting the multiplier right by one bit, you must compare the resulting multiplier with zero and exit if the multiplier is zero. Without this step, a multiplier like 00000001 would give the correct product immediately, but then the product would be shifted left 7 times, throwing off the result.
It is obvious, but should still be noted. Naively, I would have thought to cycle through all bits of the multiplier.
U are absolutely right !!
Suppose B = 1101 and Q = 0001.
After the first step - adding and shr, EAQ = 0 0110 1000
After the second step - shr, EAQ = 0 0011 0100
After the third step - shr, EAQ = 0 0001 1010
After the fourth step - shr, EAQ = 0 0000 1101
If you exit after the first step because Q = 0, you're result would be 0110 1000 which is not equal to 0000 0110.
thanks a lot!
very nice
Nice lecture sir
Thanks a lot sir!!!
what will be A value width if M and Q doesn't match the same width?
Booths multiplication for unsigned?
My exam of COA tommorow I'm watching this video at 3:13am....
is Add Shift method and paper pencil method same for multiplication?
Thank you sir
Sir, pls also explain the refined multiplication version
Can you upload the logic for segregate 0s and 1s using only left and right shift operators
Can you do one using left shift?
bro nice bro
Y ur shifting right instead of left ?? Can u explain
Is it always a cycle of four? I got a little lost there.
only if it's a 4bit number. it's a cycle of n if there are n bit numbers.
Sir would u please solve 89*11 by this method..
Hello could you show how we can design this in multisim or on breadboard?
Does this work with more bits?
Yes
mantul bapak ko,
says bwan bwan jhero bwan to 1101😂😂😂
If i got carry in the last cycle then i should add it or not??
you will never have a carry in the last step because the last step is shifting and whenever we shift the carry becomes a 0.
Thanks a lot
could u describe a structural diagram a bit more
how its comes 128
foking good,
Thanks sir
How will I know when to stop multiplying
Yeah that the question that am I ask For 🤔
shift and add show kriye
Sir multipler must taken as "Q"
what if there signed number happened??
Can someone create a circuit of it and provide kindly 🙂
Tnq sir
At 1:20
Ty sir
ok thnks sir
At 8:41 you can take ss,, thank me later
Provide arabic cc pls
I am confused
10001111 how can it's 128?
He was saying that the 1 in the left side of that number represents 128.
The number 10001111 equals
128 + 8 + 4 + 2 + 1 = 143
@@fredwilson1448 but how it represents 128?
Roses are red
Violets are Blue
The Title is in English So the Videos should be too
👍
saale ki muh dekhke jeene ki tammana chali gayi
very good
thx sir