A shell of mass 0.020kg is fired by a gun of mass 100kg. If the muzzle speed of the shell is 80m/s what is the recoil speed of the gun? m = 0.020kg v = 80m/s M=100kg V=? V= - mv/M =(- 0.02x80)/100 = -0.016 m/s The negative indicates that the gun moves in a direction opposite to the direction of motion of the bullet
romba nanri akka. nobody is teaching in tamil / english. only most hindi videos are there , i coudnt understand that properly. but fortunately i found your channel.its easy for me to understand the topics. thanks.
A shell of mass 0.020kg is fired by a gun of mass 100kg. If the muzzle speed of the shell is 80m/s what is the recoil speed of the gun? answer: -0.016m/s
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Mam law of conservation of momenum. Newton nde third law bach prove cheyyan pparanjalallum itu pole cheyta matiyo.question le specific ayi second law third law enn parayandddd . previous questions I'll... Appo entelum change varattano
ma'am, enniku 4th jan exam aanu appol ee classukalum excerciseum cheythal mathiyo?? i mean to say that is it necessary to read textbook before exam??or just watch videos and do excercise qns?? i am a student from kv-2 kalpakkam..
Hiii mam. ഞാൻ ഒരു 2023-24 batch സ്റ്റുഡന്റ് ആണ് എനിക്ക് ഈ ക്ലാസ്സ് follow ചെയ്തൂടെ deleted potion വല്ലതും ഉണ്ടോ ഈ വീഡിയോകളിൽ. മറുപടി തരുമെന്ന് പ്രതീക്ഷിക്കുന്നു 🙏🏼🙏🏼
Tr, ee law of conservation of momentum lastil Fab =-Fba ennillee adutha stepil delta t engana cancel aakunne aa minus -(m2v2-m2u2÷delta t) alle ,minus delta tku varille
A shell of mass 0.020kg is fired by a gun of mass 100kg. If the muzzle speed of the shell is 80m/s
what is the recoil speed of the gun?
m = 0.020kg
v = 80m/s
M=100kg
V=?
V= - mv/M
=(- 0.02x80)/100 = -0.016 m/s
The negative indicates that the gun moves in a direction opposite to the direction of motion of the bullet
Law of conservation of linear moments mansilayilla 🥺
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-0.016m/s anno mam
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I got it right
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romba nanri akka. nobody is teaching in tamil / english. only most hindi videos are there , i coudnt understand that properly. but fortunately i found your channel.its easy for me to understand the topics. thanks.
A shell of mass 0.020kg is fired by a gun of mass 100kg. If the muzzle speed of the shell is 80m/s
what is the recoil speed of the gun?
answer: -0.016m/s
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Miss parayunna points ellam note eleekk ezhuthan pattiya modelil onn kaanichirunnenkil upakaram aayirunnu. I wish u will do it. Ur classes are very helpfull thanku mam
Ans ) -0.016m/s
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True
Truw
I think techer we can't state which the action or reaction is happens first coz, both happens in the same instant.
Ma'am law of conservative of momentum tinte proof important aano
Allam nanayi manassilavununde teacher. Thank you so much teacher
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Mam law of conservation of momenum. Newton nde third law bach prove cheyyan pparanjalallum itu pole cheyta matiyo.question le specific ayi second law third law enn parayandddd . previous questions I'll... Appo entelum change varattano
Useful👍👍👍👍
Thankyou miss
ma'am, enniku 4th jan exam aanu
appol ee classukalum excerciseum cheythal mathiyo??
i mean to say that is it necessary to read textbook before exam??or just watch videos and do excercise qns??
i am a student from kv-2 kalpakkam..
i am writing notes of this classes..
its enough for the exam..but neet oke prepare cheyyundel textbook exercises kooduthalayi padiykanam..
plz join telegram channel web.telegram.org/#/im?p=c1300895810_3765722474429891977
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-0.020*80/100
=-0.016
Miss law of conservation of momentum proof kannathe padikkenno?
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Ans : -0.016 m/s
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Mam ee derivations ellum padikkanoo???
Padikaano mam reply plsss
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Mam rocket propulsion explain cheyaaamo
ans)-0.016m/s
Hiii mam. ഞാൻ ഒരു 2023-24 batch സ്റ്റുഡന്റ് ആണ് എനിക്ക് ഈ ക്ലാസ്സ് follow ചെയ്തൂടെ deleted potion വല്ലതും ഉണ്ടോ ഈ വീഡിയോകളിൽ. മറുപടി തരുമെന്ന് പ്രതീക്ഷിക്കുന്നു 🙏🏼🙏🏼
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V= -mv/V
-0.020*80/100
- 0.016m/s
Tnq maam
Answer=-0.016m/s
thank you mam
Mam pls update the video of class 9 physics cbse
v= -0.020*80/100 = -0.016m/s
Recoil velocity of gun = -0.016 m/s
Law of conservation of momentum derivation exm varo
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Very helpful
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Linear momentum derivation chodhikkumo
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Tr, ee law of conservation of momentum lastil Fab =-Fba ennillee adutha stepil delta t engana cancel aakunne aa minus -(m2v2-m2u2÷delta t) alle ,minus delta tku varille
athu expand cheyyumbol cancel aakum..randu sidelum common aayittullth calncel cheyyam
@@Mayasclassroom expand cheyumbol -delta t alle??
Law's of motion note?
Miss law of conservation of momentum derivation important ano pls reply miss
Prove
Ans: -0.016 m/s
But I got -0.16 m/s
thank you teacher
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Answer: 0.016m/s
Tnq miss
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Teacher inertial mass and gravitational mass paranju tharamo
ethilund keto th-cam.com/video/SvFId3RA8pY/w-d-xo.html
Misss conservation of momentum lla problm okka examin varoo ath imp annoo
yes
Cbse syllabus um kerala syllabus um same aano?
yes. ncert text thanneyanu randu syllabusum
Recoil speed of the gun = 0.016
Sathyam parayalo ee teachere class kettath kond maathram njan +1 physics A+ vaangi. Njan fail aakumenn karuthiyatha
Mam i am a student studying in 9th cbse plz tell me how i can attend your class
epol online class edukkunnilla will start soon..description boxil koduthuirikkunna mail id yilek mail ayakku start cheyyumbol ariyikkam
-0.016=v
Laws of motion note ??????????
Mam i also got -0. 016
Pls upload part 4
V=-1.6/100 m/s
Teacher,ans : 0.016metreper second ano.
-0.016m/s
Teacher , Law of conservation of momentum 9th classil indo ???
yes
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_0.016m/s
Is -1.6 correct answer
Notes description boxil iduvo
join telegram athilund web.telegram.org/#/im?p=c1300895810_3765722474429891977
V=0.016m/s
Answer 0.016 m/s
0.016m/s, alle tr
-0.016
Mam ans negative 0.016 ano
yes..
Thanks mam
-0.016 m/s
Recoilne pattivnjangale padippikkeda teachare njangalum pubg kalikkunneya
oh fayangaram thanne🤢
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Ade e Newton's 3 law pragaram thane anoo e blackwholem
Missinte job nthann
0.016m/s
0.016 anno
Answer 0.016 aanu kittiyath
-
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Not sure...I will try to upload maximum videos
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Super class
-0.016