Dr. Pat, Thank you for the video. Regarding to the symbolic integral, I want to add a constant, such as C1 as in the result, then later use B.C to solve C1 and put back into the solution. What is the best way to do this? Thank you!
Hi yevictor. I fiddled with it a bit and believe I can do what you are looking for. Was hoping I could just send you a screen shot, but no ability to do that here. I used functions... assigned a polynomial to g(x) then made f(x) equal to the integral of g(x) and solved using the symbolic solver (it doesn't add the constant). I then made a function in x and C1 by making it equal to f(x)+C1 and solved again with symbolic solver. I then used the solve block to enter my BCs and solve for C1. Plotted it just for good measure. It was easier than it sounds here... if you have a means by which I can send a screen shot, happy to do so. A fun little problem. I'll do up a proper example using beam deflections and maybe turn it into a video. Hope this helps.
@@PatJHeffernan Seriously speaking, i was not expecting a response. A big thank you is in order. I find your channel a direct to the point application of the software. You open new avenues of exploration with simplicity and methodical synergy. It is indeed engaging to follow. As to my vague question i am sorry not being explicit. If we have x and y in tabular columns like in excel. Say column A and Column B respectively. Is there any direct function to evaluate the derivative dy/ dx at each point of x? (Apart from the complicated procedure of defining a spline etc.) Thank you again for reaching out to an old post.
Thanks Rahul for your kind words. I have not done what you are asking but will give it some thought while I run an errand this afternoon to see what I can think of to try! Wish me luck! 🤞🏻
Hi Rahul. All I can think of is, as you described, getting a curve fit and taking the derivative. Alternatively you could use the point data itself to estimate the slope at each point from the adjacent points, but again not a direct function as you requested. (Caveat: just because I'm unaware of a function, doesn't mean it doesn't exist, just that I'm not familiar with it). Sorry I couldn't be of more help.
Very good. Thank you
Dr. Pat, Thank you for the video. Regarding to the symbolic integral, I want to add a constant, such as C1 as in the result, then later use B.C to solve C1 and put back into the solution. What is the best way to do this? Thank you!
Hi yevictor. I fiddled with it a bit and believe I can do what you are looking for. Was hoping I could just send you a screen shot, but no ability to do that here. I used functions... assigned a polynomial to g(x) then made f(x) equal to the integral of g(x) and solved using the symbolic solver (it doesn't add the constant). I then made a function in x and C1 by making it equal to f(x)+C1 and solved again with symbolic solver. I then used the solve block to enter my BCs and solve for C1. Plotted it just for good measure. It was easier than it sounds here... if you have a means by which I can send a screen shot, happy to do so. A fun little problem. I'll do up a proper example using beam deflections and maybe turn it into a video. Hope this helps.
what about tabular data differentiation?
Hi Rahul, can you be more specific what you are trying to do?
@@PatJHeffernan Seriously speaking, i was not expecting a response. A big thank you is in order. I find your channel a direct to the point application of the software. You open new avenues of exploration with simplicity and methodical synergy. It is indeed engaging to follow.
As to my vague question i am sorry not being explicit. If we have x and y in tabular columns like in excel. Say column A and Column B respectively. Is there any direct function to evaluate the derivative dy/ dx at each point of x? (Apart from the complicated procedure of defining a spline etc.)
Thank you again for reaching out to an old post.
Thanks Rahul for your kind words. I have not done what you are asking but will give it some thought while I run an errand this afternoon to see what I can think of to try! Wish me luck! 🤞🏻
@@PatJHeffernan Sir it has been your kindness that has graced us. Wishing you the very best.
Hi Rahul. All I can think of is, as you described, getting a curve fit and taking the derivative. Alternatively you could use the point data itself to estimate the slope at each point from the adjacent points, but again not a direct function as you requested. (Caveat: just because I'm unaware of a function, doesn't mean it doesn't exist, just that I'm not familiar with it). Sorry I couldn't be of more help.