c1 * c2 = 0, and c1*c1 = no. of stations. This does not make any sense. c1*c2=0 is not possible unless one of them is 0, and c1*c1 = no. of stations?? what kind of stations? railway stations? sense ni bani kuch. Or FDMA ke under jo points likhe, vo saare same points hi h alag alag wording me. Doesn't make any sense.
In CDMA (Code Division Multiple Access), the codes used are typically orthogonal or nearly orthogonal to each other. Here's how the properties of these codes work: ### Orthogonal Codes 1. **Cross-Correlation:** - For two different codes \(C_i\) and \(C_j\) (\(i eq j\)): - The cross-correlation \(C_i \cdot C_j = 0\). - This means that when you multiply two different orthogonal codes and sum the result, you get zero. This property ensures that different users' signals do not interfere with each other. 2. **Auto-Correlation:** - For the same code \(C_i\): - The auto-correlation \(C_i \cdot C_i = N\), where \(N\) is the length of the code. - This means that when you multiply a code by itself and sum the result, you get the length of the code, which is the number of bits in the code. This property ensures that the signal can be reliably detected. ### Summary - **Cross-Correlation (Different Codes):** \(C_i \cdot C_j = 0\). Multiplying different codes and summing the result gives zero, ensuring no interference between users. - **Auto-Correlation (Same Code):** \(C_i \cdot C_i = N\). Multiplying a code by itself and summing the result gives the length of the code, which aids in detecting the signal. These properties of orthogonal codes make CDMA efficient in separating multiple signals transmitted over the same frequency band.
You have not mentioned SDMA in the video cauz it is also a multiple access technique that we have to learn for IPU 8 sem examination
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sir please decrese the count of advirtisement, we can't concentrate it
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Sir you have taken the picture of CDMA in FDMA and the picture of FDMA In CDMA.
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what is band width
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c1 * c2 = 0, and c1*c1 = no. of stations. This does not make any sense. c1*c2=0 is not possible unless one of them is 0, and c1*c1 = no. of stations?? what kind of stations? railway stations? sense ni bani kuch. Or FDMA ke under jo points likhe, vo saare same points hi h alag alag wording me. Doesn't make any sense.
The code will be in form of Matrix
In CDMA (Code Division Multiple Access), the codes used are typically orthogonal or nearly orthogonal to each other. Here's how the properties of these codes work:
### Orthogonal Codes
1. **Cross-Correlation:**
- For two different codes \(C_i\) and \(C_j\) (\(i
eq j\)):
- The cross-correlation \(C_i \cdot C_j = 0\).
- This means that when you multiply two different orthogonal codes and sum the result, you get zero. This property ensures that different users' signals do not interfere with each other.
2. **Auto-Correlation:**
- For the same code \(C_i\):
- The auto-correlation \(C_i \cdot C_i = N\), where \(N\) is the length of the code.
- This means that when you multiply a code by itself and sum the result, you get the length of the code, which is the number of bits in the code. This property ensures that the signal can be reliably detected.
### Summary
- **Cross-Correlation (Different Codes):** \(C_i \cdot C_j = 0\). Multiplying different codes and summing the result gives zero, ensuring no interference between users.
- **Auto-Correlation (Same Code):** \(C_i \cdot C_i = N\). Multiplying a code by itself and summing the result gives the length of the code, which aids in detecting the signal.
These properties of orthogonal codes make CDMA efficient in separating multiple signals transmitted over the same frequency band.
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