it is (x-y) not (y-x) because when you the the programming, the signal source will come from the road, r . if you use y-x, since that there is no initial value to start with y, then your programmed going to give error.
Because in most cases it is considered that the diagram is in static equilibrium, so the springs are already considering the gravitacional force and they are being forced down by the weight. Making this consideration you don't need to write the gravitacional force to the diagram.
For those wondering, there is a mix-up of notations in the Equations of Motion. m₁ẍ₁ should actually be m₁ẍ and m₂ẍ₂ should actually be m₂ÿ. The double dot notation means acceleration and the two equations of motion are in the form mass × acceleration=∑force .
Hello sir, could you please make a video for the half-car model (4DoF) and the full-car model (7DoF) or perhaps leave a link for some content that explains these two models? Thank you.
idk dude. have you seen a car w/o shocks, or have you driven a car with really hard shocks? lol. Either way is awful. The dampers on a car are ALWAYS working. Touch one after going down the road a ways. Muy caliente!
It is well known that the first derivative of position (symbol x) with respect to time is velocity (symbol v) and the second is acceleration (symbol a).. so first order derivation is termed as single dot and second order derivation are double dotted.
Thanks for explaining this 10x clearer than my professor. You rock!
is it reasonable to ignore the dashpot (?), the absorber characteristics of the tyre? It's not perfecly elastic, is it?
it is (x-y) not (y-x) because when you the the programming, the signal source will come from the road, r . if you use y-x, since that there is no initial value to start with y, then your programmed going to give error.
Thank you so much🎉
GOOD EXPLNTION
why is not f1 = - ks (y -x) as hooke's law states that a spring acts opposite to the direction of its displacement from the equilibrium position?
thanks
why is the stretch in the spring y-x and not x-y?
bcause of signs related to the directions of force, in concordance of the FBD
why we dont put the gravitacional force at the diagram?
Because in most cases it is considered that the diagram is in static equilibrium, so the springs are already considering the gravitacional force and they are being forced down by the weight. Making this consideration you don't need to write the gravitacional force to the diagram.
What about mg?
For those wondering, there is a mix-up of notations in the Equations of Motion. m₁ẍ₁ should actually be m₁ẍ and m₂ẍ₂ should actually be m₂ÿ. The double dot notation means acceleration and the two equations of motion are in the form mass × acceleration=∑force .
There should be a hidden constraint here: y>x. The option y
thanks a lot you saved me
sir ,kindly tell me which tool or software you use for creating this video.. your video are nice and clearly expressed.
thanks sir.
Hello sir, could you please make a video for the half-car model (4DoF) and the full-car model (7DoF) or perhaps leave a link for some content that explains these two models? Thank you.
excelent
sir, why a quarter car or half car model is analyzed instead of full car model?
Thank You
cool humor ;)
The system is only dampened if you hit a puddle ;)
idk dude. have you seen a car w/o shocks, or have you driven a car with really hard shocks? lol. Either way is awful. The dampers on a car are ALWAYS working. Touch one after going down the road a ways. Muy caliente!
why we here not using the weight of two masses can you explen this to me
maybe because he took that into account in m1x1 doube dot, or m2x2double dot
page 11 of this link www.me.utexas.edu/~dsclab/leks/DSC_Vibration_Modeling.pdf
how to find Kw for this quarter?I need for my thesis to find Kw..
you seriously need it? Watch out to get a brain first, then get Kw for your shitty thesis
m2.y2'' instead of m2.x2''!!
m2x2 dot or m2y
I couldn't understand what are (x double dot one ) and (x double dot two)
+Tarek Kanbar x1 double dot is the vertical acceleration of the wheel and x2 double dot is the acceleration of the car.
+Blahrg x2 double dot should be y double dot and x1 double dot should be just x double dot
yeah, I believe @burlinskas is correct.
It is well known that the first derivative of position (symbol x) with respect to time is velocity (symbol v) and the second is acceleration (symbol a).. so first order derivation is termed as single dot and second order derivation are double dotted.
those are nuts bro
Something for scratch
this will help th-cam.com/video/7fTZhBvl6GM/w-d-xo.html