best explanation sir but i have doubt that is in reference books it is mentioned that pn codes are non-orthogonal codes but you mentioned it has orthogonal code
Hi, at 38:10, in codes C1 and C3, there is orthogonality *provided* that the encoders are synchronized. If you time-shift C1 by one bit-time, it will no longer be orthogonal with C3. How can this be worked around? Surprisingly, C0 C1 and C2 remain orthogonal even if time-shifted (i.e. with asynchronous clocks). Is this statement correct? Wouldn't it be smarter to forego C3 and stick with just C0 C1 and C2?
What an mind Blowing example to start CDMA with!!!!!!
what a lucid explanation! thanks to such dedicated and enthusiastic teachers!
CDMA starts @ exactly 09:00. The explanation was crystal clear. Thank you sir. I believe it is not ‘chips’, but ‘chirps’ @ 30:10
no its chips
Wonderful lecture......easily understood what cdma is.....thanks a lot!!!
Awesome is the word...first tym really understood wat cdma exactly is...thank u very much sir :)
Very clear explanation of CDMA and Spread Spectrum Modulation Sir.....
Excellent lectures.. Sir your explanation is just great.
THANK YOU
go to settings and change speed to 2x , save time xD.
Thanks a lot. it is really a very good lecture with brief explanation. Thanks once again.
Perfect Explanation.....hats off to you sir...(Y)
Beautifully explained... Thanks a lot nptel :)
very clear and nice presentation
Excellent and clear lecture sir...thank you so much Sir....
best explanation sir but i have doubt that is in reference books it is mentioned that pn codes are non-orthogonal codes but you mentioned it has orthogonal code
Could you explain why there is less collision in CDMA with compare to other technology.
Thank you sir nice explanation
Great lecture
Great Sir...Thanks
Thank u sir.... was really helpfull:.....
awesome sir :) very clear explanation :)
awesome lecture, thanks
Grt sir......Thanks alot
Super!
Thank you so much Sir🙏😇
What a boss!
Hi, at 38:10, in codes C1 and C3, there is orthogonality *provided* that the encoders are synchronized. If you time-shift C1 by one bit-time, it will no longer be orthogonal with C3. How can this be worked around? Surprisingly, C0 C1 and C2 remain orthogonal even if time-shifted (i.e. with asynchronous clocks). Is this statement correct? Wouldn't it be smarter to forego C3 and stick with just C0 C1 and C2?
Thank you :)
How can we transmit 2 symbols at the same time and of same frequency?
pls explain....
I think the two symbols are added as one symbol to transmit, not transmitting two symbols
Thank you sir
great:)
Thanks!
Hi!! Can you tell me how can i calculate the number of users using cdma th?
Here the bandwidth will be 500 Hertz. Because we must have to satisfy the Nyquist rate requirements!
Kota factory ke " jitu bhaiya "