6 Transformer | Losses in transformer | Efficiency of transformer | Alternating current

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  • เผยแพร่เมื่อ 24 ธ.ค. 2024

ความคิดเห็น • 175

  • @rashmigupta7073
    @rashmigupta7073 4 ปีที่แล้ว +76

    Thank you sir. Team competishun is a blessing for all aspirants.🙏🙏🙏

  • @orewagamin
    @orewagamin 4 ปีที่แล้ว +69

    5 lecture 24 hours me wow sir.

  • @jaskaransinghsodhi3152
    @jaskaransinghsodhi3152 4 ปีที่แล้ว +59

    3 videos in 1 day. Thank you so much sir. Please start modern/thermo

  • @infinatorix1276-m4u
    @infinatorix1276-m4u หลายเดือนก่อน +1

    this playlist is the finest conclusion of entire electrodynamics...thank you sir.

  • @saurabhmaurya841
    @saurabhmaurya841 4 ปีที่แล้ว +19

    thank you so much sir you are such a great teacher

  • @amitsingh2782
    @amitsingh2782 3 ปีที่แล้ว +22

    Another chapter completed 😁😁

  • @AshishJoshi-tj3qs
    @AshishJoshi-tj3qs ปีที่แล้ว +11

    completed AC in a day thanks sir for this amazing lecture series :)

  • @NEET-eb3ve
    @NEET-eb3ve ปีที่แล้ว +6

    criminally underrated content, explanation and concepts📑

  • @debashis_
    @debashis_ ปีที่แล้ว +8

    Done sir this ch felt so easy❤

  • @AbhishekKumar-c7e8j
    @AbhishekKumar-c7e8j 3 หลายเดือนก่อน +5

    Abj sir hair is too good😊❤

    • @AbhishekKumar-c7e8j
      @AbhishekKumar-c7e8j 3 หลายเดือนก่อน

      Sahi me😂😂

    • @Its_Ari24
      @Its_Ari24 3 หลายเดือนก่อน +1

      Bhai tu kis mayajal me phasa hua hai🤣

  • @savkushage
    @savkushage ปีที่แล้ว +4

    thnx sir for such high effort teaching and celebration...mahaveer swami bless you sir

  • @the_iit_aspirant
    @the_iit_aspirant 5 วันที่ผ่านมา

    8:32 transformer
    12:38 reasons
    21:00
    39:17 feel aa chuka bhai
    49:00 53:26
    58:19 flux leakage
    1:04:12 eddy current
    1:09:18

  • @sohamjavheri3715
    @sohamjavheri3715 3 ปีที่แล้ว +5

    Competishun zindabad...!!!

  • @monkey-ob9fb
    @monkey-ob9fb 7 หลายเดือนก่อน +8

    I don't know why everyone in the comment section has doubt in the secondary circuit which is absolutely correct but no one saw the actual mistake in the primary circuit i.e what sir were trying to teach in the secondary circuit, it seems that he himself forgot to apply that in the primary circuit. The mistake is that sir took the voltage across primary coil to be 1000V which he used to calculate the emf induced across the secondary coil and got 200V. But the voltage across the primary coil is not 1000V, it is 990V because 1000V is across the source and the current in the circuit is 10A. So there will be a potential drop of (10x1=10V) across the internal resistance of the primary coil and hence (1000-10=990V) across the primary coil. So now if we use [ Ep/Es=Np/Ns ], we will get [Es=990x1/5=198V] . So the actual potential difference across the secondary coil is 198V rather than 200V.
    Hope that i have explained it correctly. Feel free to ask if there is something which i haven't explained completely/correctly. 🙏

    • @monkey-ob9fb
      @monkey-ob9fb 7 หลายเดือนก่อน

      Please correct me if I am wrong

    • @NandiniJyoti
      @NandiniJyoti 7 หลายเดือนก่อน

      hi there

    • @NandiniJyoti
      @NandiniJyoti 7 หลายเดือนก่อน

      there is no error, because Ep is given in question, not calculated.

    • @ELLIPSIS797
      @ELLIPSIS797 3 หลายเดือนก่อน

      Bhai toh Pin-Pout = 1000 kahan aa rha usse

    • @Annnnstream
      @Annnnstream 3 หลายเดือนก่อน

      Arey Ep is given, it is fixed, it is the voltage to be changed, coming to the question, if you draw the circuit of the primary side then it will be simple, with ac source and a resistor (coil) so of course the job of the ac source is to keep the voltage across the ends of the resistor 1000v so it is fixed, Ep=1000V, and hence the power = VI, this 10000 W is the power supplied by the ac source to the transformer, now when this power goes in, first it suffers cu loss in the primary circuit, then iron loss, then another copper loss in the secondary circuit, which is in total 1000W, Now In, Es the problem is that there is a load, and the load is the one supposed to dissipate the final power and give the required voltage , i.e if you are having output power as 9000 W then this 9000 W will be dissipated across the load only,( 14:35, maybe replay this part) so to get the required voltage across the load, two resistors are involved (cu one and load one, whereas in the primary circuit, only cu one was present), so as both these resistors are dissipating power, the total power disspated will obviously be 9000+200 =9200. So ig sir is right… this was my theory from what I have understood after replaying the part 100 times😂

  • @ArRt1719
    @ArRt1719 2 ปีที่แล้ว +11

    52:15 part 8 , load ke pass power 9000w gaya woh bhi 200w loss hone ke bad iska matlab woh circuit ke pass total 9200w power tha..jiss se 200 w resistance udane ke bad baki bacha power load ke pass gaya.

    • @Pram-ly-r
      @Pram-ly-r 2 ปีที่แล้ว +2

      Nice explanation bro..

    • @ArRt1719
      @ArRt1719 ปีที่แล้ว +1

      @@Pram-ly-r thanks bro

    • @Jjk308
      @Jjk308 ปีที่แล้ว

      But if total power of circuit is 9200 then that means total power loss is 800 Watts right

    • @ashu-mb2zw
      @ashu-mb2zw ปีที่แล้ว

      ​@@Jjk3089000 watt power has to reached to out appliance hence 1000w loss

    • @existential_turtle
      @existential_turtle 7 หลายเดือนก่อน +2

      @@Jjk308 Yes, 700 watts of iron loss plus 100 watts of copper loss in the primary coil, however this current also causes 200 watt copper loss in the secondary coil resulting in a final output power of 9000 watts. The output power is not the power delivered to the secondary coil on the iron core, it is the final power sent out of the transformer.

  • @kuldeeppal179
    @kuldeeppal179 ปีที่แล้ว +3

    Thanks sir complete chapter

  • @_-537shaikshoaib-_7
    @_-537shaikshoaib-_7 7 หลายเดือนก่อน +6

    Today alternating current complete
    Thank you sir

    • @MohitTyagi
      @MohitTyagi  7 หลายเดือนก่อน +1

      All the best

  • @amarsinha866
    @amarsinha866 ปีที่แล้ว +2

    Thank u sir completed this chapter

  • @Priya-qc5qt
    @Priya-qc5qt 4 หลายเดือนก่อน +1

    Thankyou sir completed AC 19 august 2024

  • @madhuprasannalakshmiyamasa7793
    @madhuprasannalakshmiyamasa7793 11 หลายเดือนก่อน

    Thank you sir . Now feeling confident in AC ...😍😍

  • @amajadali187
    @amajadali187 3 ปีที่แล้ว +4

    I feel like a legend....💫💫

  • @adityahiremath7886
    @adityahiremath7886 4 หลายเดือนก่อน +1

    great content and explanation sir...skipping aakash classes to attend your classes

  • @lakshyakochar4620
    @lakshyakochar4620 3 ปีที่แล้ว +11

    Sir at 53:00 in 8 part if we say Esis = 9200 watts then won't it mean that total power loss = 800 watts as total power loss = Epip - Esis ?

  • @pushpalekkala3875
    @pushpalekkala3875 3 หลายเดือนก่อน +1

    Happy teachers day sir

  • @shirshgyan6778
    @shirshgyan6778 3 หลายเดือนก่อน +2

    Completed Alternating current 24/9/2024
    Thanks sir🙏🏻🙏🏻

    • @Awakening_lifes
      @Awakening_lifes 2 หลายเดือนก่อน

      @@shirshgyan6778 bhai bords bbi ho jayega na isi se??

  • @letitbex221
    @letitbex221 3 ปีที่แล้ว +5

    36:00 52:00 Mera bhi 45 A aaya tha😶🤦🏻‍♀️
    Tysm sir ♥

  • @NitinKumar-ny7rk
    @NitinKumar-ny7rk ปีที่แล้ว +2

    Thank you sir.

  • @neelakshi006
    @neelakshi006 2 หลายเดือนก่อน +2

    Thank you Sir...

    • @MohitTyagi
      @MohitTyagi  2 หลายเดือนก่อน +1

      All the best

  • @amajadali187
    @amajadali187 3 ปีที่แล้ว +2

    💖thank you AB sir 💖

  • @Kirti-ub8zy
    @Kirti-ub8zy 6 หลายเดือนก่อน +4

    Completed on 9th June for JEE 2025 thank you sir❤

    • @ranbirkaurarora9979
      @ranbirkaurarora9979 5 หลายเดือนก่อน +1

      Heyy
      U a dropper or in 12th?

    • @kashyaptandel5212
      @kashyaptandel5212 5 หลายเดือนก่อน +2

      Damn you are 1 month ahead of me

    • @itzmayankgaming5703
      @itzmayankgaming5703 5 หลายเดือนก่อน +1

      @@kashyaptandel5212 are you guys dropper

    • @Kirti-ub8zy
      @Kirti-ub8zy 5 หลายเดือนก่อน +1

      ​@@kashyaptandel5212 are u in 12

    • @Kirti-ub8zy
      @Kirti-ub8zy 5 หลายเดือนก่อน +1

      ​@@ranbirkaurarora9979 no I am in 12th

  • @kunalmandal2199
    @kunalmandal2199 2 ปีที่แล้ว +1

    Completed AC 4/11/22.

  • @sahebOp_
    @sahebOp_ ปีที่แล้ว +3

    Done 17 jan 2023 2:58am tysm sir❤

  • @ShivamAnandSpeaker
    @ShivamAnandSpeaker 3 ปีที่แล้ว +7

    At 52:15 in qsn 8,can anyone explain in little detail,why power become 9200,how 200 increase in it!

  • @unik_ankit_
    @unik_ankit_ ปีที่แล้ว +1

    Completed🎉🎉in one sitting 🪑🪑🪑😊😊😊

  • @VS-001
    @VS-001 ปีที่แล้ว +2

    Thanks Sir. Completed 27 September 2023. JEE 2024

  • @rishabhsrivastava1201
    @rishabhsrivastava1201 ปีที่แล้ว +1

    thanku very much sir😀😀

  • @silkywrm
    @silkywrm ปีที่แล้ว +1

    thank youuu!!💛💛💛

  • @kadhaipaneeer
    @kadhaipaneeer ปีที่แล้ว +1

    Completed this chapter on 27 Nov 2023

  • @k.ashvanth1735
    @k.ashvanth1735 2 ปีที่แล้ว +6

    Completed
    JEE'22
    16 May 2022

    • @lamelauncelot1385
      @lamelauncelot1385 ปีที่แล้ว +1

      hi brother, using your physics notes of abj sir, thanks.

    • @atharvatar
      @atharvatar ปีที่แล้ว +2

      @@lamelauncelot1385 from where?

  • @DarshilGunjal-k5z
    @DarshilGunjal-k5z 3 หลายเดือนก่อน +1

    Completed ✅29-8-24

  • @mayank0363
    @mayank0363 3 หลายเดือนก่อน

    Sir at 53:00, secondary circuit ko Poutput mila 9000w agar isme se 200w ka copper loss hua h toh 200w minus hona chahiye so net power of secondary becomes 8800w.

    • @yukiro6417
      @yukiro6417 2 หลายเดือนก่อน

      no bro, the efficiency given tells us the power received by the load, not the entire seccondary circuit... that power is 9000, power in secondary circuit is 9200, but that 200 is lost in copper and only 9000 received by load

  • @aarkojha5710
    @aarkojha5710 4 ปีที่แล้ว +11

    Sir at 56:00 , can't we use E= IR to find the current in copper, if we use it we get different ans , why is it so? Kindly guide 🙏

    • @Human-og7oj
      @Human-og7oj 3 ปีที่แล้ว +1

      How did you find the value of R

    • @satyamsingh-jc1pl
      @satyamsingh-jc1pl 3 ปีที่แล้ว +1

      @@Human-og7oj its given in question 1 ohm

    • @RakeshKumar-rc4sj
      @RakeshKumar-rc4sj ปีที่แล้ว +5

      Hlo.... primary ke coils ka inductance bhi to hoga aur resistance vese h hi ..to LR ckt ho gya ....ise E= iR na lgke E=iZ lgna chahiye....but uski information question me nhi h

    • @RakeshKumar-rc4sj
      @RakeshKumar-rc4sj ปีที่แล้ว +2

      Is liye hme majburan P= ei use krna pda

  • @Flashbackoflife
    @Flashbackoflife หลายเดือนก่อน

    Thanks sir (:

  • @ankur.6681
    @ankur.6681 3 หลายเดือนก่อน +1

    49:35 and mai pehle se (I)s = 45A nikal karr baitha tha...🗿💀

  • @Jjk308
    @Jjk308 ปีที่แล้ว +3

    Shouldnt the power loss due to resistance of circuit be counted along with the total power loss of the circuit(including load)..then why did we take total power in that circuit to be 9200 Watts?( I was thinking the net power loss in the circuit was 9000Watts which includes the resistance)

    • @neiltauro2234
      @neiltauro2234 ปีที่แล้ว

      I too didnt understand why sir hadnt included that.
      Think of it this way
      Input source provides 10000watts, out of which 800watt goes to copper loss(primary circuit) nd iron loss, therefore 9200 watts of power goes to the secondary circuit which will be equal to EsIs.

  • @tanayapalhade1918
    @tanayapalhade1918 2 ปีที่แล้ว +1

    Completed 18th July 2022 😊

  • @Shivamverm665
    @Shivamverm665 หลายเดือนก่อน

    thank you so much sir

  • @raghuraj5954
    @raghuraj5954 3 ปีที่แล้ว +3

    Sir to wo 1st wire me power loss kyun nahi liya CU wire ke chalte??

  • @lol-xu1di
    @lol-xu1di 4 ปีที่แล้ว +4

    Sir when are you going to start the next chapter?

  • @__.financiaga._
    @__.financiaga._ 3 ปีที่แล้ว +7

    advance lvl lectures with such low views😥

  • @__.financiaga._
    @__.financiaga._ 3 ปีที่แล้ว +17

    Sir in part 5 at 46:43 , the resistance of the coil is given so why we can't use P(primary)=I²R(primary) , to get I as 100A ?
    why not possible?
    or anyone else ?

    • @dhruvsharma6880
      @dhruvsharma6880 2 ปีที่แล้ว

      bhai sir ne 44:00 pe input power ko 10000 W le liya tha

    • @cadetkhan133
      @cadetkhan133 2 ปีที่แล้ว

      BECAUSE you dont know the exact resistance of primary circuit you only know the resistance in the coils and not in the iron region, so we have to use formula independent of resistance.

    • @supersid078
      @supersid078 2 ปีที่แล้ว

      Same problem bro

    • @saurabhchauhan9103
      @saurabhchauhan9103 2 ปีที่แล้ว +3

      Bro it just simple as power given in trans is total power supplied which is not fully consumed by resistor

    • @saurabhchauhan9103
      @saurabhchauhan9103 2 ปีที่แล้ว +1

      Further you have to use 100watt instead of 10000watt as 100 watt is consumed by resistor

  • @dhruv15803
    @dhruv15803 3 ปีที่แล้ว +4

    at 42:33 how can sir use that result if transformer is not ideal?

    • @RakeshKumar-rc4sj
      @RakeshKumar-rc4sj ปีที่แล้ว +1

      Ye result hmesha valid h .... derive krte vkt sir ne kbhi nhi bola ki it is only for ideal transformer ....only jisme current ata h ...vo ideal k liye valid h

    • @anishsingh4790
      @anishsingh4790 ปีที่แล้ว +1

      Es/Ep = Ns/Np is always valid
      But Es/Ep = Ns/Np = Ip/Is is valid only if transformer is ideal
      (See derivation again)

  • @Legend_saber
    @Legend_saber ปีที่แล้ว +1

    lekin power dissipated to V2/R bhi hota hai, to 33000V??

  • @aayushisinha3346
    @aayushisinha3346 3 ปีที่แล้ว +2

    Thank you sir

  • @ankur.6681
    @ankur.6681 3 หลายเดือนก่อน

    sir par electric poles me jo wires use hote hai woh toh aluminium ke bne hote hai na copper ke nhi??

  • @devankvinesh2649
    @devankvinesh2649 3 ปีที่แล้ว +2

    52:40 pe humne , Es/Ep = ip/ is use kyu nhi kiya 🙄

    • @watermelonsugar9933
      @watermelonsugar9933 2 ปีที่แล้ว +2

      since it is not an ideal transformer as efficiency is 90%.

  • @punit2052
    @punit2052 11 หลายเดือนก่อน +3

    sir transformer wale Q8 me to 200W uss 9000W ka hi part hai na
    Kyuki total Power loss = PCu + PFe
    to Phir correct answer 45A hi aa raha hai
    Aur sir agar ye correct hai to phir same concept primary ke liye bhi lagta na

    • @krrishkumar6812
      @krrishkumar6812 11 หลายเดือนก่อน

      Vhi to mai bhi revise krte samay confuse ho gya

    • @existential_turtle
      @existential_turtle 7 หลายเดือนก่อน +2

      ​@@krrishkumar6812 The induced EMF in the secondary coil is 200V. The power delivered to the secondary circuit is 9200W. Now, the current of 46A due to the induced EMF would result in a 200W copper loss in the secondary coil and the final power delivered to the load is 9kW. The misconception here is due to the incorrect idea that the potential difference across the load is equal to the potential difference induced in the secondary coil. There is a small potential drop due to the resistance of the coil.
      The actual potential difference across the load in this case would be 9000/46 = 195.65V, and the potential drop due to the coil would be the cause for the 4.35V deficit.

    • @monkey-ob9fb
      @monkey-ob9fb 7 หลายเดือนก่อน

      @@existential_turtle yes, your explanation is perfect.And I don't know why everyone in the comment section has doubt in the secondary circuit which is absolutely correct but no one saw the actual mistake in the primary circuit i.e what sir were trying to teach in the secondary circuit, it seems that he himself forgot to apply that in the primary circuit. The mistake is that sir took the voltage across primary coil to be 1000V which he used to calculate the emf induced across the secondary coil and got 200V. But the voltage across the primary coil is not 1000V, it is 990V because 1000V is across the source and the current in the circuit is 10A. So there will be a potential drop of (10x1=10V) across the internal resistance of the primary coil and hence (1000-10=990V) across the primary coil. So now if we use [ Ep/Es=Np/Ns ], we will get [Es=990x1/5=198V] . So the actual potential difference across the secondary coil is 198V rather than 200V.
      Hope that i have explained it correctly. Feel free to ask if there is something which i haven't explained completely/correctly. 🙏

    • @anukanabrahmachari5346
      @anukanabrahmachari5346 4 หลายเดือนก่อน

      The potential across the coil is 1000 V. The resistance of 1 ohm is of the coil itself.

    • @anukanabrahmachari5346
      @anukanabrahmachari5346 4 หลายเดือนก่อน

      ​@@monkey-ob9fbThe fundamental difference between the primary and the secondary circuit is that in the primary circuit emf is supplied while in the secondary circuit emf is induced across the coil.So,the coil in the primary circuit is a load and the coil in the secondary circuit is a source.

  • @rpb007
    @rpb007 11 หลายเดือนก่อน

    thanks sir

  • @ShashwatPal-e1m
    @ShashwatPal-e1m 4 หลายเดือนก่อน

    thank you sir completed AC on 18th august 2024 ( Jee 2025)

  • @anukanabrahmachari5346
    @anukanabrahmachari5346 4 หลายเดือนก่อน

    Thanks you sir

  • @souviksingha2396
    @souviksingha2396 ปีที่แล้ว +1

    Completed
    22 Feb , 2023
    JEE 2023

  • @_-537shaikshoaib-_7
    @_-537shaikshoaib-_7 7 หลายเดือนก่อน

    Today alternating current complete
    Thank you sir❤

  • @vishaltimishra9937
    @vishaltimishra9937 4 ปีที่แล้ว +6

    sir ac completed now

    • @MANOJYADAV-gn6kg
      @MANOJYADAV-gn6kg 3 ปีที่แล้ว

      @@cuetcompetishun sir telegram ka link dedijiye

  • @KunalKumar-gq8kx
    @KunalKumar-gq8kx 4 ปีที่แล้ว +1

    Iske bad EMW hoga n sir

  • @backto90s68
    @backto90s68 ปีที่แล้ว +2

    8:25 12:48 20:31 27:08 31:30 38:05 39:00

  • @sameerkushwaha584
    @sameerkushwaha584 2 หลายเดือนก่อน

    JEE ADV. 2025 ----> AC DONE ON 5 OCT 2024 AT 1.00 AM.
    THANK YOU, SIR!

  • @Hnb781
    @Hnb781 4 ปีที่แล้ว +1

    Kya sir Prabal batch ke sabhi lecture free available honge

  • @arsh_saidpuria
    @arsh_saidpuria 3 หลายเดือนก่อน

    I have a doubt that by cal calculating current by p = vi and v/r equal to I is different ??

    • @adi._op
      @adi._op 3 หลายเดือนก่อน

      Same doubt

    • @ELLIPSIS797
      @ELLIPSIS797 3 หลายเดือนก่อน

      Yup same doubt

  • @Arthurr10098
    @Arthurr10098 ปีที่แล้ว

    Done🙂

  • @icebear670
    @icebear670 3 ปีที่แล้ว

    Thankyou sir 😈

  • @aryanarya3830
    @aryanarya3830 4 ปีที่แล้ว +1

    Sir is this chap completed now

  • @casuallyv10l3nt
    @casuallyv10l3nt 15 วันที่ผ่านมา

    58:26

  • @anirbanroy4188
    @anirbanroy4188 3 ปีที่แล้ว

    Sir sawtooth curve wala kuch problem kab karaoge

  • @SanjeevKumar-gi5et
    @SanjeevKumar-gi5et 4 ปีที่แล้ว +1

    Sir jee main ke liye reso ki package ka Kaun sa exercise Karein??
    Please reply jarur kijiyega sir 🙏🙏🙏

    • @ishasingh3095
      @ishasingh3095 4 ปีที่แล้ว

      EX 1 AND EX 3 PARTN 2 BASSSS...

  • @HarshYadav2004
    @HarshYadav2004 3 ปีที่แล้ว +1

    Sir last question mein primary circuit k power ko 10000 liya gya hai aur secondary circuit ko 9200. Sir secondary wale se ham Fe loss hata diye hain par primary wale se ni hataye usko poora 10000 rakha gya hai. Sir aisa kyun? Primary wale ka power toh 9300 watt hona chaahiye na ?

    • @aaditya_aspirant
      @aaditya_aspirant 2 หลายเดือนก่อน

      i know i am late but bhai ye toh source hai na secondary mein jake power loss hoga na

  • @aahikks
    @aahikks ปีที่แล้ว

    completed

  • @not_mukul
    @not_mukul หลายเดือนก่อน

    Completed on 12 November 2024

  • @rishirajverma8350
    @rishirajverma8350 4 ปีที่แล้ว +1

    First ❤️

  • @chanderboss975
    @chanderboss975 4 ปีที่แล้ว +1

    Sir plz start thermo

  • @govindjha8434
    @govindjha8434 ปีที่แล้ว +1

    Completed
    Jee '24
    30 july 2023

  • @suryakanttiwary9873
    @suryakanttiwary9873 3 ปีที่แล้ว

    Srr please take quetion sessions

  • @siddhantnagdeote
    @siddhantnagdeote ปีที่แล้ว

    chapter complete..... :)
    Dt. 7 Aug 2023

  • @clashwithfire2150
    @clashwithfire2150 2 ปีที่แล้ว

    at 47.05 why Ip=Ep/(resistance)p

  • @tanishabansal3297
    @tanishabansal3297 4 ปีที่แล้ว

    thanku sir

  • @RevantRaj-p5n
    @RevantRaj-p5n ปีที่แล้ว

    Completed on 16/07/2023 at 4:00 pm makiiiiinnnnnnnnnnnnnnnn histtttttttttooooooooorrrrrrrrrrrrrryyyyyyyyyy

  • @user-metheboss
    @user-metheboss 4 ปีที่แล้ว

    Sir modern physics kb start karenge?

  • @Createbyhe11111
    @Createbyhe11111 2 หลายเดือนก่อน

    42:00 3 D

  • @anishsingh4790
    @anishsingh4790 ปีที่แล้ว +1

    Completed Alternating Current
    15/feb/2023
    Thank you sir !!

  • @archanasharma513
    @archanasharma513 4 ปีที่แล้ว +1

    Sir please correct the alternating current playlist
    One vedio is out of the track..

  • @mathematicsman7454
    @mathematicsman7454 2 ปีที่แล้ว

    Sir chapter ki limitations hill jayega

  • @SLASH.27
    @SLASH.27 2 ปีที่แล้ว +1

    khatam😊

  • @kartiksharma6334
    @kartiksharma6334 4 ปีที่แล้ว +3

    Is this chapter completed ???

  • @messi0510
    @messi0510 3 ปีที่แล้ว

    39:32

  • @shonnie2923
    @shonnie2923 ปีที่แล้ว

    Completed
    JEE-2024
    13 Oct 2024

  • @amajadali187
    @amajadali187 3 ปีที่แล้ว

    I am 2022 aspirant...for jee

  • @karatekid8312
    @karatekid8312 2 ปีที่แล้ว

    👑👑👑

  • @doreamonrobot9260
    @doreamonrobot9260 2 ปีที่แล้ว

    09/09/2022 to 16/09/2022

  • @fab6324
    @fab6324 2 ปีที่แล้ว

    Done 3 Jan 2023

  • @himanshumaurya480
    @himanshumaurya480 3 ปีที่แล้ว

    Hysteris

  • @lostgirldesk7578
    @lostgirldesk7578 2 ปีที่แล้ว

    completed
    23rd december 2022
    Jee 2023