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What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on TH-cam) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chap 10 | MECHANICAL PROPERTIES OF FLUIDS 01 | Introduction : Pressure in a Fluid JEE/NEET th-cam.com/video/KJKKYjJyBDc/w-d-xo.html Class 11 chap 10 || Fluids 02 || Variation Of Pressure in an Accelerated Fluid JEE MAINS / NEET || th-cam.com/video/gzyV6z-qlg8/w-d-xo.html Class 11 chap 10 || Fluids 03 || Barometer and Manometer and U - Tube problems JEE MAINS /NEET | th-cam.com/video/BgYxdQJyxnI/w-d-xo.html Fluids Mechanics 04 || Upthrust and Law Of Floatation for IIT JEE MAINS / JEE ADVANCE / NEET || th-cam.com/video/kOGw8hjBTCQ/w-d-xo.html Fluids 05 || Fluid Dynamics 1 || Introduction | Bernoulli's Theorem: JEE MAINS / NEET th-cam.com/video/Ptf8icUjT1U/w-d-xo.html Fluid 06 | Applicaion of Bernoulli's Principle -Venturimeter & Speed of efflux- Torricelli's Theorem th-cam.com/video/2O1wWt2Etzw/w-d-xo.html Fluid 07 : Viscosity and Viscous Force IIT JEE MAINS / NEET (Watch Fluid 08 for Stokes Theorem) th-cam.com/video/TBP3T9MMLAI/w-d-xo.html Fluid 08 || Stokes Theorem and Terminal Velocity IIT JEE MAINS / NEET || th-cam.com/video/O86kWLgMbl8/w-d-xo.html Fluid 09 || SURFACE TENSION 01 : Introduction and Surface Energy IIT JEE MAINS / NEET || th-cam.com/video/9K09rSXhKaw/w-d-xo.html Fluid 10 || Surface Tension 02 || Excess Pressure inside a Liquid Drop IIT JEE MAINS / NEET || th-cam.com/video/Us7sk1OrcUc/w-d-xo.html Fluid 11 || Surface Tension 03 || CONTACT ANGLE and Shape of Meniscus IIT JEE MAINS / NEET th-cam.com/video/PziAQZbiCpc/w-d-xo.html Fluid 12 || Surface Tension 04 || Capillary Action and Capillary Rise IIT JEE MAINS / NEET || th-cam.com/video/2wVR9m8MxO4/w-d-xo.html
At 36:07 the answer : viscous force is 10 N and the external force is 20 N so the net force on boat is (fext.- fv) =10N and F=ma where F = 10N , m=2kg so the acceleration will get 5 m/s². Thanks for this most greatful video sir ☺
@@rudebaddie9 parent ka pta nhi....par haan senior jarur hu aur ek acche senior ka kaam accha suggestion Dena hai....waise which class mujhe puchna chahiye kyuki harkaton se to tm bohot immature lg rhi ho👎
Waise thermal properties easy chapter hai... Aur jab tak sir use cover nahi Kara rahe, aap wo chapter Pradeep Kshetrapal sir ke channel se padh Sakti hain..
14:33 , Ladies and gentlemen that is y this man is called the God of concept! I don't know if you read comments on these older videos but genuinely phenomenal job sir! Thanks a lot! All the best for the journey!(to you as well reader!)
Hw question: 10 poise = 10-¹ X 10=1 N sec/m² F=ñAdv/dz= 1 X 1 X 10 X 1=10 N 10 N 20N Net force=20-10=10 N a=net force/mass a=10/2=5m/sec² ANSWER : [5M/SEC²]
SOLUTION OF LAST QUESTION 👇👇 friction= -nA*(∆v/∆z) f=-(10 * 10^ -1)*10 f= -10 N Net force = 20N -10N=10N Now, F = ma = 10 Therefore, a = 10/2 = 5m/s² Thank u sir😊🙏🙏🙇♂️
Advertisement of other online study platform on his channel ..... confidence level at peak 😊 Btw you are our lifeline sir...we can't imagine our day without you and your lectures 😁
No other physics Teacher can match your level of Teaching. You are God of Physics as well as online education. You genre of teaching is just Awesome. Congratulations for 3.5 Million subscribers. I really appreciate your hard as well as selfless work of imparting Quality Education and knowledge to the whole generation free of cost. Hats off to you, sir.
Fex=20N M=2kg Area=1m² Height=1m Cofficient of visocity (eta)=1NS/M² So we know that f=(eta)(A)(dv/dX) F=10M We have studied Fex-F=ma 20-10=2a 10/2=a 5m/s²=a
Ans. to last Question:. 5m/s² My feedback: It was an amazing lecture, learning basics of viscousity & a slight hints towards Stooke's Law. In Short, "A Short & Sweet lecture".
For intro music I have edit video using my editor which takes extra 1 hour for processing. These days I am trying to shoot videos in one go so that no editing is required to merge parts of videos...I hope ..That's the answer. I also miss it.
1 poise = 10^-1 newton -s/m^2 now friction = n*A*change in V/ change in z given n= 10 poise = 10*10^-1 N-s/m^2 f= -(-10*10^-1)*1*10 = -10 N Net Force = Fext-f = 20-10 10N M*A = 10 a = 10/2= 5ms^-2
"Duniyaa me naam use ka hota hai Jo ladta hai" and sir is the biggest example for us. By start uploading videos on TH-cam.. And now become the hero of all the aspirants ❤ Thank you so much sir 🙏❤
Firstly Find the viscous force , which is Fv = 10 N , Net Force = Fext - Fv = 20 - 10 = 10N we know that , F = ma , a = F/m ( Putting the values ) a = 10 / 2 = 5m/s^2
i was demotivated because i was facing many difficulties in this chp. but now so happy.you developed my interest in physics and chemistry. ALLAH ap ko is ka ajre khaire atta kare. jazakillah hu khaira
To calculate acceleration in last question - first, calculate friction. then calculated net-force by Subtracting friction force from ext-force. thus we all know "F=Ma" So "a=F/m" (here F= net-force). so find the value of accerleration by A=net-force/M which is 20-10/2 (where 2 is mass of person) value will be 5 m/s^2. Thanks like this comment.
Sir First I Finded Friction Force Then Did Vector Addition Of Friction And The Force Which Is Applied On The Boat To Get F(net)= 10N Then Applied Formula A=F/M And Got Acceleration (A)= 5m/s^2 Loved The Video Best Explanation...🙏😊
Sir , ans of homework question is 5m/s² Solution:- After calculating viscosity = 10N Net force on the boat will be = 20N - 10N = 10N Hence acc. = F(net)/ mass = 10 / 2 = 5m/s²
the point/fact u told in the early of this video was very required at this time sir.......thank u and I request u ki aap videos ke start main aise kuch points btaye ......coz exam time bohot samney hai and we need all such motivations
U r not only a best teacher , but u r also a motivator for all the students , we gets motivated from ur great inspiration , we r very happy to see ur thinking , 🙂🙂
1:40 ,I was watching this video with disappointment as I suffering from fever and tomorrow's my exam. But he just ignited something inside me. PW you are great ❤️
External force =20N given Viscous force = nAdv/DX n=1Nm/S2. A=1m2. dv=10m/s. dx=1m Viscous force= 1×1×10/1=10N Net force = 20-10= 10N F=ma. a=F/m. a=10/2 5 m/s2
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1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey.
2)Live Classes and recorded Video Lectures (New, different from those on TH-cam)
3)PDF Notes of each class.
4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.
5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.
6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
7)In case you missed a live class, you can see its recording.
8)You can view the videos any number of times.
9)Each chapter will be discussed in detail with all concepts and numericals
10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.
****Test Series for XI & XII****
We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.
Class 11 chap 10 | MECHANICAL PROPERTIES OF FLUIDS 01 | Introduction : Pressure in a Fluid JEE/NEET
th-cam.com/video/KJKKYjJyBDc/w-d-xo.html
Class 11 chap 10 || Fluids 02 || Variation Of Pressure in an Accelerated Fluid JEE MAINS / NEET ||
th-cam.com/video/gzyV6z-qlg8/w-d-xo.html
Class 11 chap 10 || Fluids 03 || Barometer and Manometer and U - Tube problems JEE MAINS /NEET |
th-cam.com/video/BgYxdQJyxnI/w-d-xo.html
Fluids Mechanics 04 || Upthrust and Law Of Floatation for IIT JEE MAINS / JEE ADVANCE / NEET ||
th-cam.com/video/kOGw8hjBTCQ/w-d-xo.html
Fluids 05 || Fluid Dynamics 1 || Introduction | Bernoulli's Theorem: JEE MAINS / NEET
th-cam.com/video/Ptf8icUjT1U/w-d-xo.html
Fluid 06 | Applicaion of Bernoulli's Principle -Venturimeter & Speed of efflux- Torricelli's Theorem
th-cam.com/video/2O1wWt2Etzw/w-d-xo.html
Fluid 07 : Viscosity and Viscous Force IIT JEE MAINS / NEET (Watch Fluid 08 for Stokes Theorem)
th-cam.com/video/TBP3T9MMLAI/w-d-xo.html
Fluid 08 || Stokes Theorem and Terminal Velocity IIT JEE MAINS / NEET ||
th-cam.com/video/O86kWLgMbl8/w-d-xo.html
Fluid 09 || SURFACE TENSION 01 : Introduction and Surface Energy IIT JEE MAINS / NEET ||
th-cam.com/video/9K09rSXhKaw/w-d-xo.html
Fluid 10 || Surface Tension 02 || Excess Pressure inside a Liquid Drop IIT JEE MAINS / NEET ||
th-cam.com/video/Us7sk1OrcUc/w-d-xo.html
Fluid 11 || Surface Tension 03 || CONTACT ANGLE and Shape of Meniscus IIT JEE MAINS / NEET
th-cam.com/video/PziAQZbiCpc/w-d-xo.html
Fluid 12 || Surface Tension 04 || Capillary Action and Capillary Rise IIT JEE MAINS / NEET ||
th-cam.com/video/2wVR9m8MxO4/w-d-xo.html
Yaes sir
sir we love u 😭😭😭😭😭i dnt knw somethi wrong wid me ... i think u didn't like me as a student 😭😭😭
Sir u are a very good singer l just luv ur singing
@@tejasvani7163 true that
If I crack jee mains with 200+ I will give u 10000 rupees
For me definition of happiness is When i can solve sir ka "khoobsurat sawaal "in one go
Halba sa sabal vi😃😃😃😃
Lol
@@farhinnahid3646 actually ha ....alag hi confidence aata hai ...alag hi swag😀😀
Yes
@@farhinnahid3646 ye koun si language h
At 36:07 the answer : viscous force is 10 N and the external force is 20 N so the net force on boat is (fext.- fv) =10N and F=ma where F = 10N , m=2kg so the acceleration will get 5 m/s². Thanks for this most greatful video sir ☺
which class??
@@rudebaddie9 pdh lo which class se pass nhi hogi
@@EhabShahid tum mere parent ya relative ho kya?
@@EhabShahid nai na ..fir rhe ne do👍🏻
@@rudebaddie9 parent ka pta nhi....par haan senior jarur hu aur ek acche senior ka kaam accha suggestion Dena hai....waise which class mujhe puchna chahiye kyuki harkaton se to tm bohot immature lg rhi ho👎
🙏🙏Ram Ram guruji 🙏🙏
=> F(ext) - F(v) = ma
=> 20 - 10 = 2 × a
=> a = 10 \ 2
=> 5 m/s^2
Thanks a lot sir
Mera viscous force to 1 aaya
10 nhi..
10 poise=1N-s/m^2 hota h n
@@AnshuKumari-rz2ib dv/dt = 10 lo , ho jayega
@@AnshuKumari-rz2ib hey dv/dz = 10/1 hona chahiye na
Toh
Fv = 10 * 1 * 10 = 100 hona chahiye
@@anshumanrath6703 10 poise=1N-s/m^2
@@anshumanrath6703 Y are you calculating Fv? Just calculate Fext
Itni jaldi jaldi videos..... KAMAAL KARTE HO PANDEY JI😂😂😂
Shubham Sharma 😁😁
Sir thermal properties of matter kab banhanege.....?
@@anithabambary9677 Sir ki maaya... Sir hi jaanein.... 😂😂😂
Waise thermal properties easy chapter hai... Aur jab tak sir use cover nahi Kara rahe, aap wo chapter Pradeep Kshetrapal sir ke channel se padh Sakti hain..
@@anithabambary9677 yarr ek finish nahi hota tum log doosara start karane ko karte Ho 😕😕😕😕
14:33 , Ladies and gentlemen that is y this man is called the God of concept! I don't know if you read comments on these older videos but genuinely phenomenal job sir! Thanks a lot! All the best for the journey!(to you as well reader!)
Yesssss☺
Selection hua
@@rubiakhatun1124bruhhh
watching in 2023 and still relevant
@@krushagbhoraniya535same here
Hw question:
10 poise = 10-¹ X 10=1 N sec/m²
F=ñAdv/dz= 1 X 1 X 10 X 1=10 N
10 N 20N
Net force=20-10=10 N
a=net force/mass
a=10/2=5m/sec²
ANSWER : [5M/SEC²]
a= net force / mass how you changed the units N to ( m/sec2)
@@Gangsta_Evil lol
@@Gangsta_Evil just see what Newton is made up of.
thanks!!
@@jeeaspirant7206 okay
Answer is...5 m/s2
Acceleration is Net Force'by mass.... calculate viscous friction and then subtract from external force..
Yes bro i know vry well my anzwer is also matched....
Mine also
OK.. NYC
Bhai small nhi aaya yarr explain kr do yrr please 🙏🙏💓
SOLUTION OF LAST QUESTION 👇👇
friction= -nA*(∆v/∆z)
f=-(10 * 10^ -1)*10
f= -10 N
Net force = 20N -10N=10N
Now, F = ma = 10
Therefore, a = 10/2 = 5m/s²
Thank u sir😊🙏🙏🙇♂️
ya my answer is also same
@@harleendhillon6760 noice 🙂✌🏻
Yeah is right answer
Yeah...mine too
Bhai area 1m h to 10 kyo liye ho
The lecture was very good and the answer is 5ms^-2
Yes its 5
@@hariprasadta1087 thanks
Ya.. Me also getting same 👍
Answer is 5
5 answer
Index:
0:30 inspirational
2:30 start
5:30 velocity gradient
12:00 solid friction revision
15:00 woh lamhe 😄🎤🎼
15:35 viscous force
27:00 solid-liquid friction
thanks
lmao i've seen you in so many videos of sir's. keep up the work my g. respect.
Thanks
2:48 Starting
5:38 velocity gradient
Advertisement of other online study platform on his channel ..... confidence level at peak 😊
Btw you are our lifeline sir...we can't imagine our day without you and your lectures 😁
No other physics Teacher can match your level of Teaching. You are God of Physics as well as online education. You genre of teaching is just Awesome. Congratulations for 3.5 Million subscribers. I really appreciate your hard as well as selfless work of imparting Quality Education and knowledge to the whole generation free of cost. Hats off to you, sir.
Then : blackboard ,chalk,duster
Now : smartboard
Forever : his selfless service
🙇🙇🙇🙇🙏🙏🙏🙏🙏🙏
Where are you from
Totally agreed 😩
My iitian brother can teach better than him and have far better knowledge than him
@@sankalp104 but the fact is, he won't make that content available to students for free
Sir i was too much demotivated today but when i saw the starting of lecture i m felling a different type of energy that makes me motivated
Same here 😁
Me too...
Me too
@@divyakumari078 Same hereSame here
@@divyakumari078 me too
Fex=20N
M=2kg
Area=1m²
Height=1m
Cofficient of visocity (eta)=1NS/M²
So we know that f=(eta)(A)(dv/dX)
F=10M
We have studied
Fex-F=ma
20-10=2a
10/2=a
5m/s²=a
bhai eta ki value 10 di hai
@@pranjalnigam1062bruh u r crazy
@@pranjalnigam1062MKS mein convert kro
@@pranjalnigam1062SI mai 1 Ns/m² hai
ñ has to be converted to SI unit i.e. 1N-s /m²=10 poise
So as we are given ñ= 10 poise
ñ(si)= (10 ¹poise ×10-¹)N-s/m²
= 10⁰= 1
Ans. to last Question:. 5m/s²
My feedback:
It was an amazing lecture, learning basics of viscousity & a slight hints towards Stooke's Law.
In Short, "A Short & Sweet lecture".
How
Sir do work according to your wish don't listen anyone how many students agree with me
You are right
I agree
@@amarsingh6214 really
Lokesh kaushik I live in rohtak and where are you live and in which school do you read.
Sir thanks
F(v)=10N
Fext =20N
Net force =20-10=10N
10N=ma
a=10÷2=5m/seconds square
Nirmal
Sir answer for the hw Q is 5m/s^2
15:11 haayee vo lmhe yaad aa gye Sir!!! 😅😅😅
Answer for hw question option [b]
Bhaii konsi class m 11
Tera syllabus ite aaenge
"" GOD OF CHEMISTRY "" " GOD KE BHI GOD OF PHYSICS " " BAAP OF CONCEPT IN PHYSICS" I can told infinty titles on alakh sir brilliance.
Tell*
Shabdo me mat jao jazbatko samjho
He is not god, he is a leader
Kuchh bhi😅
anyone can't became God....except one almighty god ....he is a good leader and a teacher but dont make anyone god
Sir please bring back the intro music uska kuch alag hi feel ata tha
Bilkul SAHI batt ha bro.....!!!
Right bro
Right bro
For intro music I have edit video using my editor which takes extra 1 hour for processing. These days I am trying to shoot videos in one go so that no editing is required to merge parts of videos...I hope ..That's the answer. I also miss it.
@@PhysicsWallah no problem sir we know how much hardwork you do
Rare persons have guts to teach both sub..phy and chemistry..u r real hero sir
35:10 - Answer of homework question is (b) 5m/s². Thanks 😊 sir for the lecture and the motivation.
How can u explain
How can you explain me please
F= 1.1.10=10( by using formula for finding f)
then F=ma so F\m=a and on putting values 10/2=5
F= 1.1.10=10( by using formula for finding f)
then F=ma so F\m=a and on putting values 10/2=5@@HamzaKhan.egydes
Thank you so much
Answer of last question!!!!!!!
f= -nA*dv/dz
=-(10 * 10^ -1)*10
= -10 N
Net force=20-10=10
Now, 10=ma
Therefore , a=10/2==5m/s^2
✓✓✓✓✓✓✓
Ek like to bnta hai for the answer
Bhai 10/2 = 5 m/s² na
Who is watching fluid mechanics lecture in november 2020? Hit like
hi
Me
@@its_me.1109 🤓🤓🤓
@@bhednahiaabholahabhandarih8189 kaha rehte ho?
Meeee
PHYSICS has tought us
1.stress
2.tension
3.pressure
In next video 4.stroke
And new editions in future😂😂😂🤣🤣🤣🤣
taught*
absolutely
Itne sare likes
@@Haxislive766cool innit?😳 Btw edit your comment -> tough taught
Kis kis ka chemistry me course bas 1st book he hui hai or exam are at head
f=nAdv/dz
n = 10/10 = 1
A = 1
dv/dz = 10/1
Fext = f = 10
a = F/m = 10/2 = 5m s-2
I got the same answer
1 poise = 10^-1 newton -s/m^2
now friction = n*A*change in V/ change in z
given n= 10 poise = 10*10^-1 N-s/m^2
f= -(-10*10^-1)*1*10
= -10 N
Net Force = Fext-f
= 20-10
10N
M*A = 10
a = 10/2= 5ms^-2
The ans is 5m/s^2
First find friction force and then
a=F-f/m👍
Don't take -ve sign in Fnet =ma bcoz representing opp.direction 👍
thanks buddy
Sir please neet ke 1-2 previous year bhi karaya kro! :))
You're doing a great work!
God Bless You! 😍😄
tera neet ka exam clear ho gaya kya bro ???
@@ukiyo-kun8656 lagta h nhi hua varna reply kar deta ☹️🧐
@@mukulrana7094 uska youtube account check karo...hogaya uska clear
"Duniyaa me naam use ka hota hai Jo ladta hai" and sir is the biggest example for us.
By start uploading videos on TH-cam.. And now become the hero of all the aspirants ❤
Thank you so much sir 🙏❤
Sir🙏 answer of last question b:5m/s²
Alakh sir also can't stop himself from singing songs 💞😁
Seeing Sir's lectures means getting Whole DC Pandey book in lecture form🙏🏻❤
Hc Verma bro
@@tanishq..msdfan Haan
Dc Pandey ka form mr sir pdate hai
00:34 One of the Best Motivational Introduction ever after the Isomerism 01 video. "The best Way to Face a Crisis is to be Brave."
Last question answer will be 5 m/s^2
Yes sir music tar tar tar tu tu wale zaroor continue kiye raheye .
Best inspiration 0:00 to 3:00
Sir, the answer of homework question is option (b)...5m/s^2
❤😊
2024 gang❤️👇
Firstly Find the viscous force ,
which is Fv = 10 N ,
Net Force = Fext - Fv = 20 - 10 = 10N
we know that ,
F = ma ,
a = F/m ( Putting the values )
a = 10 / 2 = 5m/s^2
Good job
Correct
i was demotivated because i was facing many difficulties in this chp. but now so happy.you developed my interest in physics and chemistry. ALLAH ap ko is ka ajre khaire atta kare. jazakillah hu khaira
Correct answer of hw Q is
b) 5 m/s^2
You r the best teacher of world
Thanku sir
no
Velocity of fluid 0 hai toh fv bhi 0 hoga and simply F=ma
a= 5/2 m/sec2
F=ma
Thanks sir for clearing concepts.
Ans of H.W QUESTION is 5.
Can you tell the solution of this Q
@@sarojsingh7035 Fv = 1 *10* 1 = 10N
F net = ext - viscous = 10N
F net = m a
Therefore 10 = 2 a
a = 5
@@sahilshah6408 thanks
To calculate acceleration in last question - first, calculate friction. then calculated net-force by Subtracting friction force from ext-force. thus we all know "F=Ma" So "a=F/m" (here F= net-force). so find the value of accerleration by A=net-force/M which is 20-10/2 (where 2 is mass of person) value will be 5 m/s^2.
Thanks like this comment.
Frictional force=10Newton
Net force= Forward force - frictional force
=(20-10) Newton.
F=ma
10 =2×a
a=5meter/second square.
Sir First I Finded Friction Force Then Did Vector Addition Of Friction And The Force Which Is Applied On The Boat To Get F(net)= 10N Then Applied Formula A=F/M And Got Acceleration (A)= 5m/s^2 Loved The Video Best Explanation...🙏😊
This man showed us the real meaning of a good teacher
Sir , ans of homework question is 5m/s²
Solution:-
After calculating viscosity = 10N
Net force on the boat will be = 20N - 10N = 10N
Hence acc. = F(net)/ mass = 10 / 2 = 5m/s²
00:30inspirational
2:30 start
5:30 velocity gradient
12:00 solid friction revision
15:35 viscous force
23:36 q
27:00 solid-liquid friction
3:55 3:58 3:59 4:00
Hello
26:00 yes sir there is a force called cohesive force which acts between solid and liquid..
accha ji
That's adhesive force not cohesive
14:10 WOW this is called Concept of Physics!! Amazing explanation sir
SIR, Ans of the last ques is b)5 m/s^2
How ?
Yes ...the ans is option b
@@demiurgic11 first calculate the friction force and then use F=MA eazzy ✌
@@skull_wolf thanks , i got it
Yes answer is correct
f = n A dv/dt = 10
[ n=10/10=1 , A = 1 , dv/dt = 10/1 ]
Fext - f = ma
20 - 10 = 2 × a
a = 5 m/s^2
the point/fact u told in the early of this video was very required at this time sir.......thank u and I request u ki aap videos ke start main aise kuch points btaye ......coz exam time bohot samney hai and we need all such motivations
36:10 The answer is option (b) 5 m/s2
kese bro
No other Physics teacher can match your level of teaching
Salute to your hard work sir !!! 👍👍. Never seen such an inspiring teacher like you 🙂🙂
Fv= nA dv/dz
So = 1into1into 10/1. 10poise in n/ms^2 so value of fv =10N and Fext =20N so Fnet is = 20-10=10
Using F=ma
a=F/m = 10/2
=5m/s^2
=
5m/s²
REMEMBER we have to take Fnet =20-10 =10N Now divide it by mass(2)
After 3 years your's lecture is on top 🔝
Last question :
Acceleration = b) 5m/s²
Answer of question at last = (b) 5 m/s²
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Fext - Fv equal to ma sir so answer is 5m/s2
Your channel is best educational channel till date
Fext - friction = ma
20 - 10= 2 x a
a = 10/2 = 5m/sec^2
Answer is 5 m/s ...u r awsm sir feel a gaye sir☺️😊😊❤️
How can you explain me
36: 15 answering option b 5 m/s2
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Hi
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Gajab sir itni jaldi aap toh December mein hei course complete kar denge👏👏👏
Ans: 5m/s
A=1m²
n=10 poise=1Ns/m²
H=1m
V=10m/s
So , fv=-10 and net f= 20-10=10
Now, f=ma get a=5m/s²
15:13 Woh lamhe 😂😂 Kayi log doob gye 😂😂👍👌
I listened to the song in 2x speed😂
@@sohinisaha2609 🤣🤣it's sound too.... funny
A very good lecture with quality content. Concept cleared:) Thanks a lot sir.
5ms^2 is the answer for the last question.
Just came to check my answer....It's 5 .....🌸
Yes it is right
uh in 12th this year?
Can u explain it, because I got the wrong answer
@@aksh3940 yep
Sir answer is 5m/s*2
Yes ...mera bhi utna hi aaya answer ☺️
@@dayashanker3481 kaise aya?? bata do??
Yes
@@shayaniqbal2238 first find out the viscous force using the formula sir gave in the lecture then divide the given forve by mass cuz we know f=ma
Sir, you are not only the greatest teacher but also a great motivational speaker.
THANK YOU, SIR
Sir, you are blessing for the whole world.
answer is 5 m/s2 i.e. correct option is B.
How
@@Chaudhary_khushal__see viscous force =-1*1*10=-10N
F ext = 20 N
Net force on boat = Viscous force + F ext
=20+(-10)=10
Now F=ma
10=2a
a=5m/s²
Yes
Yess correct b)
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Time stamps❤
00:30 inspirational
2:30 start
5:30 velocity gradient
12:00 solid friction revision
15:35 viscous force
23:36 q
27:00 solid-liquid friction
15:12 woh lamhe
Notes Stoppage
11:17 Velocity gradient
20:00 Viscous Force
25:04 Example
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1:40 ,I was watching this video with disappointment as I suffering from fever and tomorrow's my exam. But he just ignited something inside me. PW you are great ❤️
External force =20N given
Viscous force = nAdv/DX
n=1Nm/S2. A=1m2. dv=10m/s. dx=1m
Viscous force= 1×1×10/1=10N
Net force = 20-10= 10N
F=ma. a=F/m.
a=10/2
5 m/s2
The answer of the last question is .b)5m/s^2
Wowowowowow
Thanqq so much sir ! U have helped us a lot ..keep going
The answer of last question is (b) 5m/s^2
Acceleration of boat 5 m/s2
Sir aap diye bujne se pehle hi usmi ummidoki teel bhardete hai ❤️👍🏻🙏
36:11 ans is 5m/s²
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15:18 my favourite song
F is equal to nA dv/dx put values you will get F as 10N (10poise --1Ns/m2)
We know that,
F---ma
m-2kg,F10N A-5m/s2
Thank you sir 🙏
dv??
@@ranijha6128 Yes velocity
What will be the value
@@ranijha6128 10m/s
Phir tou f = 10-¹ ×1 × 10 = 0
20:11 who else remembers seeing the Formula when we first started Dimensional Analysis, and we were finding the Dimensions of coefficent of Viscosity.
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