The "aha" moment 5:42 when you did the red and green boxes! Thank you so much! I kept hearing: dy/dt = dy/dx*dx/dt and how its not exactly division and I was like okay, I've heard this too many times, I need to understand! thank you!
by multiplying by 1. (g(h+x) - g(x)) /g(h+x) - g(x)) is simply 1. You are allowed to change any fraction by multiplying it by 1, to change denominators. Since both fractions are now multiplying/dividing, you can use communicative property to rearrange any numerator or denominator, which he has done, so that the left becomes the derivative of f(g(x)), and the right fraction becomes the derivative of g(x).
Apart from the microphone earrape and crazy accent, I must thank you for this very easy-to-understand proof.
The "aha" moment 5:42 when you did the red and green boxes! Thank you so much! I kept hearing: dy/dt = dy/dx*dx/dt and how its not exactly division and I was like okay, I've heard this too many times, I need to understand! thank you!
Amazing explanation sir, thanks !
Jazak Allah
How can you interchange h and g(h+x)-g(x) in the denominator
by multiplying by 1. (g(h+x) - g(x)) /g(h+x) - g(x)) is simply 1. You are allowed to change any fraction by multiplying it by 1, to change denominators. Since both fractions are now multiplying/dividing, you can use communicative property to rearrange any numerator or denominator, which he has done, so that the left becomes the derivative of f(g(x)), and the right fraction becomes the derivative of g(x).
@@peterlohnes1 what made you so sure that g(h+x) - g(x)) /g(h+x) - g(x)) is not zero?
Thank sir
Thank you so much, sir.
Sir tueber theorem ka vedio and plzz bu ke previous years exam ke objective ke right ans mil sakte h kya real analysis ke ans nahi pta hame
Great
Worth explanation bro