Spring Stress, Deflection, & Buckling Stability | Spring Index & End Types | Active vs. Total Coils
ฝัง
- เผยแพร่เมื่อ 8 ต.ค. 2018
- LECTURE 15
At the end of the video, I report some results to questions posed in the problem statement that I do not explicitly work out in the video. There is one such item that I neglect to report: the shearing stress in the updated spring at solid height. For anyone who tried working this out and would like to check their work, this value would be 399.06ksi (ignoring for the time being whether or not there is any kind of material that would withstand that stress).
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This lecture was recorded on October 8, 2018. All retainable rights are claimed by Michael Swanbom.
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Since I know the God of the universe, I am aware how hopelessly short of the category of God I fall. But I am glad you found my work useful! You are very kind in your praise. I wouldn't turn down cash from the ME community if they wanted to send some, ha ha. Actually, I do have a patreon account if anyone wanted to pitch in! Look for TheBom_PE on there, or use this link:
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(MEEN 361 & 462 are taught from Shigley's Mechanical Engineering Design)
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At 19:28 I'm pretty sure Table A-5 was meant to be said for where to find the Modulus of Rigidity. Just in case anyone got confused. Thanks for the videos Dr. Swanbom!
You are correct! I probably said the page number instead of the table number. Thanks for helping clear that up for the other viewers!
I hope I saw your videos long ago because they're really helpful. Thank you for the great work
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Thank you professor. You helped me a lot!
I'm glad it helped! Thanks for watching!
Very helpful! Love this
I'm glad you found it useful! Thanks for watching!
U help me a lot Sir.. thank u very much..
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Impeccable
You are very kind. Thanks for watching!
I think you forgot to give your students the answer to part (h), the max stress at the solid length. Plugging in F_s in eq. (10-7) I get 399,2 ksi.
As always, great lecture! Greetings from Uruguay!
Min. 17:14...I always design helical spring for the purpose of stopping a descending car or counterweight beyond its normal limit of travel. When designing spring which Standard Specification I should use for Steel Springs? According to which code, the yielding strength achievable is 130-150ksi? You mean allowable by achievable? Thanks
HELLO SIR, IT WAS A GREAT LESSON AND THANK YOU FOR THAT,
I HAVE A QUESTIONFOR YOU IN WHICH I AM HAVING PROBLEM, CAN WE FIND THE DISPLACEMENT OR DEFLECTION LIKE IF I APPLY A WEIGHT OF 100lb ON SPRING CAN WE FIND HOW MUCH IT WILL COMPRESS OH THAT MUCH OF LOAD ?OR CAN WE CALCULATE HOW MUCH LOAD WE NEED TO COMPRESS SPRING 1mm??
THIS QUESTOIN KEPT BUGGING ME FOR A LONG TIME?
Nice video for learning and work out. Which book are you referring to all.
Shigley's Mechanical Engineering Design, 10th edition
Hello sir . I found max shear stress that is 127.233 ksi . max shear = 1.2336x(8x200x1.33in)/(3.14x0.1873**3) that is true or not
Is the outer diameter new is correct. I think it is Do= Di+2d....
plzzzz help me if i am wrong..
Your equation would be correct for relating inside diameter to outside diameter. In this problem we are relating mean coil diameter to outer diameter.
alright okay alright okay right okay alright okay right.
Do you have any lecture related to buffer dynamics? Thanks
Not at this time. If you have an interesting case to share, I would love to look at it as a potential example problem though. Thank you for watching! I hope you are doing well!
@@TheBomPE Example, design a helical compression spring for an elevator that is striking a spring with a compression of 5" at a speed of 1.25m/s, gross load say 5000kg. Regards, Dogan
This looks like a great candidate for an example for me to work and upload. I'll try to get to it sometime soon!
@@TheBomPE Thank you sir.
Can you please share the book details
I teach this course out of Shigley's Mechanical Engineering Design, 10th edition