I love what I have seen so far, thank you so much for the help. Is there a video that explains difference between aa, ad, q.s., aa qs like in questions #5 and #9. I don’t think my school touched many of those and I am always confused on what to do when I encounter those questions
Hello, i just wanna ask in the question with the lidocaine and epinephrine, why you multiply the 5ml(denominator) instead of the 100mcg unlike the previous questions? Im a beginner that's why i was confused ✌️😆
I believe I was previously taught to treat two numbers separated by a colon (i.e 1:4) as 1 part x and 4 parts y. Expressed as a fraction this is actually 1 / 5 parts total. What should I be looking for to distinguish these two concepts?
Thank you, Stephanie for watching and for the comment. Your reasoning is absolutely correct and can be used to find the amount of component when the total quantity is given. Using your example, the 5 will represent the total quantity of the mixture and the 1 or 4 can be used to find the amounts of the individual components. Hope this helps.
Could you possibly explain how to do this question: You are required to make 50g hydrocortisone 2% cream. You only have 1% and 2.5% hydrocortisone available. how many grams of hydrocortisone 1% cream do you need in order to make the required cream?
Please sir can you help me with this question…. A woman requires a 1 in 6,000 chlorhexidine gluconate solution for wound washing. In the pharmacy, there is a stock solution of 12.5% w/v chlorhexidine gluconate. Using this solution, the pharmacist needs to prepare an intermediate solution such that the patient will then dilute this 15-fold to obtain a solution of the appropriate concentration. What is the strength, in % w/v, of the intermediate solution? Give your answer to one decimal place.
To find the strength of the intermediate solution, we can use the concept of dilution. Let's work through the calculations step by step: 1. The desired concentration for the final solution is 1 in 6,000, which is equivalent to approximately 0.0167% w/v (1/6,000 = 0.0001667 = 0.0167%). 2. The patient needs to dilute the intermediate solution 15-fold to obtain the desired concentration. This means the final concentration of the intermediate solution should be 15 times stronger. 3. To calculate the strength of the intermediate solution, we divide the desired concentration by the dilution factor. In this case, we divide 0.0167% by 15: 0.0167% / 15 = 0.001113% w/v Therefore, the strength of the intermediate solution should be approximately 0.001113% w/v.
Bro i love yu…. You have saved me from pharmaceutics module
Glad you found the video helpful @daudamkamara6473. Thank you for watching and for the comment.
I love what I have seen so far, thank you so much for the help. Is there a video that explains difference between aa, ad, q.s., aa qs like in questions #5 and #9. I don’t think my school touched many of those and I am always confused on what to do when I encounter those questions
Hello, i just wanna ask in the question with the lidocaine and epinephrine, why you multiply the 5ml(denominator) instead of the 100mcg unlike the previous questions? Im a beginner that's why i was confused ✌️😆
God bless you Sir
Thank you @lordrinhinsonna9402 for watching and for the kind comment.
Thank you so muchhhhhhhh
Thank you, Stray for watching and for the comment.
Nice content.
Thank you Philip for the comment and for continuously supporting the channel.
Quite helpful 😅
Glad you found the video helpful, Irene. Thank you for watching and for the comment.
I believe I was previously taught to treat two numbers separated by a colon (i.e 1:4) as 1 part x and 4 parts y. Expressed as a fraction this is actually 1 / 5 parts total. What should I be looking for to distinguish these two concepts?
Thank you, Stephanie for watching and for the comment. Your reasoning is absolutely correct and can be used to find the amount of component when the total quantity is given. Using your example, the 5 will represent the total quantity of the mixture and the 1 or 4 can be used to find the amounts of the individual components. Hope this helps.
Could you possibly explain how to do this question: You are required to make 50g hydrocortisone 2% cream. You only have 1% and 2.5% hydrocortisone available. how many grams of hydrocortisone 1% cream do you need in order to make the required cream?
Please sir can you help me with this question….
A woman requires a 1 in 6,000 chlorhexidine gluconate solution for wound washing. In the pharmacy, there is a stock solution of 12.5% w/v chlorhexidine gluconate. Using this solution, the pharmacist needs to prepare an intermediate solution such that the patient will then dilute this 15-fold to obtain a solution of the appropriate concentration.
What is the strength, in % w/v, of the intermediate solution?
Give your answer to one decimal place.
To find the strength of the intermediate solution, we can use the concept of dilution. Let's work through the calculations step by step:
1. The desired concentration for the final solution is 1 in 6,000, which is equivalent to approximately 0.0167% w/v (1/6,000 = 0.0001667 = 0.0167%).
2. The patient needs to dilute the intermediate solution 15-fold to obtain the desired concentration. This means the final concentration of the intermediate solution should be 15 times stronger.
3. To calculate the strength of the intermediate solution, we divide the desired concentration by the dilution factor. In this case, we divide 0.0167% by 15:
0.0167% / 15 = 0.001113% w/v
Therefore, the strength of the intermediate solution should be approximately 0.001113% w/v.
The sound is muffled
I like the way you break things down step by step but you move way too fast for me.
Thank you for watching and for the comment. Please slow the speed to 0.75x 👍
Prepare 200ml of linctuspiadric Bpc label for baby Anita Ruth