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SP will be pointing to the latest data in the stack, in case of push, SP will be decremented by one and first data will be put at that location, once again SP will be decremented by one and next data will be copied to that location and SP will be pointing to that location. In case of POP, first data will be copied from the top of stack and SP will be incremented by one, once again second data will be copied and SP will be incremented by one so that SP will be pointing to the top of the stack
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physical address has to be 20 bit , we use 16 bit IP address and 16 bit segment address to calculate 20 bit physical address.so, we left shift segemt address and right shift physical adress to make 20 bit address.For example: Base Data segment address = 7400H .....left shift address = 74000H or (7400H * 10) Instruction pointer Adress = 2000H......right shift address = 02000H physical Address = 74000H + 02000H = 76000H
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Hello Friends
Please watch the updated version here - th-cam.com/video/W4xwSW_vL-E/w-d-xo.html
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SP will be pointing to the latest data in the stack, in case of push, SP will be decremented by one and first data will be put at that location, once again SP will be decremented by one and next data will be copied to that location and SP will be pointing to that location. In case of POP, first data will be copied from the top of stack and SP will be incremented by one, once again second data will be copied and SP will be incremented by one so that SP will be pointing to the top of the stack
nice tutorial
Norevy nice
why u use Ds in XCGH? can we use other segment registers?
U can explain total 13 instructions plz
push and pop explanation is wrong
PUSH and POP is wrong mam
Nice
v v nice
Why we have to multiply 10h for stack segment
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physical address has to be 20 bit , we use 16 bit IP address and 16 bit segment address to calculate 20 bit physical address.so, we left shift segemt address and right shift physical adress to make 20 bit address.For example:
Base Data segment address = 7400H .....left shift address = 74000H or (7400H * 10)
Instruction pointer Adress = 2000H......right shift address = 02000H
physical Address = 74000H + 02000H = 76000H
@@Ekeeda shut up
How can there be 255 different ports from 000 to FFF
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@@Ekeeda Sorry, but I'm not asking for any doubt, I'm pointing out the mistake
@Avinandan Pal lol
@@avinandanpal9742 mistake se zyada dhandha zaroori hai bhai
Pls explain in hindi