The oxidation state of MnCL2 is used for Mn as +2 and hence the number of electrons are found. In the case of H2O where Hydrogen has an oxidation state of +1 is the number of electrons needed 1 or is it 2 since there are 2 hydrogen atoms?
What if we have a half reaction where 2 moles of the metal are formed at the cathode? Would you just use the 2 moles of metal in the formula or deduce how many electron moles it would take to produce 1 mole of that metal and then plug those values in? Thanks
Hey Cool Kid - it might depend what you are trying to calculate but as you saw in the Manganese example, each Mn requires 2 moles of electrons since it is 2+, and the coloumb is based on moles of electrons so we have to take that into account :)
Great insight. One thing that bothered me, however, is that the professor here made it too easy for lazy students to just memorize a formula to get the answer. He even encouraged it!
I'm not the biggest fan either but a little context. Most of the students in the class have not taken college physics which would make this a much more familiar topic. Current measured in Amps and charge measured in Coulombs are completely new for the majority of students. The second piece of info is that this is often taught as the last thing at the end of a unit often the lecture before an exam so not only is some of the material very unfamiliar, but students have had very little time to learn it before being tested on it. So presenting it conceptually as well as presenting it as a 'plug-and-chug' equation is a sort of compromise. If you watch the entirety of my lectures you'll find that I believe that the best way to master the subject is to thoroughly comprehend it. Happy Studying!
These calculations are part of the standard college curriculum of the chapter on Electrochemistry but have also been know to show up on a variety of standardized tests as well.
Uh oh! My goal is to make the complex simple not the other way around. Can you be specific on where and how you think I made simple stuff complex so I can improve the next time?
You're welcome! And I don't know if you're familiar with Mark Wiens, but his videos while in Pakistan really show off the people and the food. looks amazing!
I can swear this guy is a better teacher than any teacher in my school
That's why it's on TH-cam lol
this was more helpful than my teacher at school. All she does is glare at me :/
Emo Hazza same!!
Este es el tipo de contenido que debe recomendar youtube y los profesores usarlo como apoyo a los alumnos.
Thank you for saying so, Jose!
Thank you for helping me consolidate my knowledge on electrolysis.
You're welcome!
Always wondered what molecular weight I should use. I just wanted to clarify. But you taught me the reason too 😂
Amazing 😍
Awesome! Glad to help! I've always thought that it is easier to remember a principle when it is thoroughly understood. Happy Studying!
The oxidation state of MnCL2 is used for Mn as +2 and hence the number of electrons are found. In the case of H2O where Hydrogen has an oxidation state of +1 is the number of electrons needed 1 or is it 2 since there are 2 hydrogen atoms?
Thank you so much, the video was really helpful to me
Glad it helped Asnat! Happy Studying!
thx bruh, helped a lot
What if we have a half reaction where 2 moles of the metal are formed at the cathode? Would you just use the 2 moles of metal in the formula or deduce how many electron moles it would take to produce 1 mole of that metal and then plug those values in? Thanks
Hey Cool Kid - it might depend what you are trying to calculate but as you saw in the Manganese example, each Mn requires 2 moles of electrons since it is 2+, and the coloumb is based on moles of electrons so we have to take that into account :)
Thank you!!
You're welcome Kevin!
Marvelous
Thanks and glad you found it helpful!
God 😇 bless 🙏 you 🙏💕 all😇😇😘
God bless you in return Rajendrakumar!
Great insight. One thing that bothered me, however, is that the professor here made it too easy for lazy students to just memorize a formula to get the answer. He even encouraged it!
I'm not the biggest fan either but a little context. Most of the students in the class have not taken college physics which would make this a much more familiar topic. Current measured in Amps and charge measured in Coulombs are completely new for the majority of students. The second piece of info is that this is often taught as the last thing at the end of a unit often the lecture before an exam so not only is some of the material very unfamiliar, but students have had very little time to learn it before being tested on it. So presenting it conceptually as well as presenting it as a 'plug-and-chug' equation is a sort of compromise. If you watch the entirety of my lectures you'll find that I believe that the best way to master the subject is to thoroughly comprehend it. Happy Studying!
Good
Glad you enjoyed the video, Jessica.
my head will explode. is this math for school?
These calculations are part of the standard college curriculum of the chapter on Electrochemistry but have also been know to show up on a variety of standardized tests as well.
Very simple stuff is made complex here..
Uh oh! My goal is to make the complex simple not the other way around. Can you be specific on where and how you think I made simple stuff complex so I can improve the next time?
Help, I have a problem, what I need to control (volts or Ampere) to recovery gold in AuCN- without recovery Copper?
amazing , just made it so much easier
POV: You blinked during class so you're trying to catch up on what you missed
👀 Stay alert and keep your eyes open!! 👀
You are a gift from god🙏🏻.thank you so much for your amazing explanation
You are welcome, Rita - thanks for commenting!
Thank you so much! This video was really easy to understand
You're welcome! 🙂
You are a great teacher!
Best lessons i could have hoped for, and that too free, thanks from pakistan
You're welcome! And I don't know if you're familiar with Mark Wiens, but his videos while in Pakistan really show off the people and the food. looks amazing!
well, im not sure about the people, but the food is great here xD
thank you you solve my one headque
You're welcome Dhaval! 🙂