An application uses a 16- bits byte addressable virtual memory address space 1011110101111001 An application uses a 16- bits byte addressable virtual memory address space 1011110101111001. a)calculate the maximum usable size of memory in KB? b)what is the range of a address? c) write down the offset if first six bits are used for page address? Answers please!!
See the complete video to work out the answers: Max. usable size for byte-addressable memory with 16-bits address = 2^16 bytes = 64 KB Range: 0 to (2^16 - 1) - Watch video CO4 for this If six bits are for page address, the remaining bits are the offset. So offset is 0101111001 (377 in decimal) - Watch video CO51 for this
5-1. A computer uses a memory unit with 256K words of 32 bits each. A binary instruction code is stored in one word of memory. The instruction has four parts: an indirect bit, an operation code, a register code part to specify one of 64 reg isters, and an address part. a. How many bits are there in the operation code, the register code part, and the address part? b. Draw the instruction word format and indicate the number of bits in each erpart.ols c. How many bits are there in the data and address inputs of the memory? What is the difference between a direct and an indirect address instruction? mory are needed for each type of instruction to Plz solve the question
A program counter is used to store the address of the next instruction to be executed. If it is a 32-bit register, it can access maximum of 2^32 memory addresses.
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An application uses a 16- bits byte addressable virtual memory address space 1011110101111001
An application uses a 16- bits byte addressable virtual memory address space 1011110101111001.
a)calculate the maximum usable size of memory in KB? b)what is the range of a address?
c) write down the offset if first six bits are used for page address?
Answers please!!
See the complete video to work out the answers:
Max. usable size for byte-addressable memory with 16-bits address = 2^16 bytes = 64 KB
Range: 0 to (2^16 - 1) - Watch video CO4 for this
If six bits are for page address, the remaining bits are the offset. So offset is 0101111001 (377 in decimal) - Watch video CO51 for this
@@ezcse thanks slot😻👍
Thank you so much .This helped me at the last minute
Very useful thank you Mam
Great explanation
Good job
So, word addressable memory is better than byte addressible memory, right?
Thank you ma'am
Very useful. Thanks
Thanku ma'am
5-1. A computer uses a memory unit with 256K words of 32 bits each. A binary instruction code is stored in one word of memory. The instruction has four parts: an indirect bit, an operation code, a register code part to specify one of 64 reg isters, and an address part.
a. How many bits are there in the operation code, the register code part, and the address part? b. Draw the instruction word format and indicate the number of bits in each
erpart.ols c. How many bits are there in the data and address inputs of the memory?
What is the difference between a direct and an indirect address instruction?
mory are needed for each type of instruction to
Plz solve the question
Check solved examples in videos CO23a - CO23e
Thnk uuu
You should make more videos
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A CPU has 32 bit program counter. How many memory locations it can fetch?
A program counter is used to store the address of the next instruction to be executed. If it is a 32-bit register, it can access maximum of 2^32 memory addresses.