……. I’m not going to lie, I had to watch three TH-cam videos on trigonometry and it took me 4 hours to get the answer. So now I know how to calculate the height of tide 4 hours after I need it😖
kindly confirm on step for r as the sin and - cos makes it fall in the second quad so the r value will be diff and plus kindly confirm on the - 0.162 vale for R.
Good evening sir, Developed one software for prediction of tide using harmonic constituents but unable to produce accurate results using standard formulas. Request if you can help me out in any way for correction to my formulas that i have used. It will be very helpful. Regards
sir can you explain the part on how you got the value of capital R in no.37? I mean I get the part on where you solve for the small r. But, the capital R is actually a bit difficult. Especially if we are going to based it from the calculation you've made in the small r. But I appreciate this. It actually helped me a lot. Thank you!
If you have found the r value by calculating the arctan of (0.03/-0.159) you can easily find R by by taking one of the formulas above that step, so either R sin r = 0.03 or R cos r = -0.159. You already now r so you can just calculate R = (0.03/sin r).
sir, can u please eplain how you got the value for 'R" in stepno. 37
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……. I’m not going to lie, I had to watch three TH-cam videos on trigonometry and it took me 4 hours to get the answer.
So now I know how to calculate the height of tide 4 hours after I need it😖
Thankyou bro
very well explained could you please advise when to use SHM method?
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Sir appreciating your efforts for explaining very nicely, its performa tabular is avail to us in ATT during mmd exam?
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kindly confirm on step for r as the sin and - cos makes it fall in the second quad so the r value will be diff and plus kindly confirm on the - 0.162 vale for R.
Good morning
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You are right, if it falls in the second quadrant you need to add 180° to your r value. So actually r would be 169.32 and R would be 0.162.
Good evening sir,
Developed one software for prediction of tide using harmonic constituents but unable to produce accurate results using standard formulas. Request if you can help me out in any way for correction to my formulas that i have used. It will be very helpful.
Regards
very well explained.
Thank you bro
Ferry good explanasion thanks fore that. Can you explane how to do the tidal rate and direction whit the SHM forms. Thanks in advance.
please show us an example about how to work on form A and plotting on form B
In some numericals , small r values are changed-+ 180 deg .
Can u please explain
Sir I am unable to understand how in line 40 the value of d4 = 45.64??? Well... thanks a lot for guiding us on such complicated topics.
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sir can you explain the part on how you got the value of capital R in no.37? I mean I get the part on where you solve for the small r. But, the capital R is actually a bit difficult. Especially if we are going to based it from the calculation you've made in the small r. But I appreciate this. It actually helped me a lot. Thank you!
Good morning
For preparation of second mate / DNS/ BSC nautical science/NCV full course come in #kundanpatna
If you have found the r value by calculating the arctan of (0.03/-0.159) you can easily find R by by taking one of the formulas above that step, so either R sin r = 0.03 or R cos r = -0.159. You already now r so you can just calculate R = (0.03/sin r).
M2 values how to obtain n where ?
your voice is almost inaudible in all your videos
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line 16 M2 value should be 0.0021
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Increase your voice sir ji.. can't hear you clearly..
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Sir ur voice in very low.. Pls increase your voice
Ur voice is not audible
You voice is too low…. Bloody hell
Line 37 and Line 38 are wrong., r should be 169.
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169, that 's right. 180-11