Class-12th || Applied Maths || Chapter-1 ||Mixture and Alligation || Exercise 1.2

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  • เผยแพร่เมื่อ 20 ธ.ค. 2024

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  • @UponeTheedge
    @UponeTheedge ปีที่แล้ว

    Sir please upload example solutions of applied maths

  • @sivaskstudios1342
    @sivaskstudios1342 5 วันที่ผ่านมา

    Why sir? In 10 th problem, you are taking 3/2 in left side

    • @12th-Maths
      @12th-Maths  5 วันที่ผ่านมา

      B'coz it is dearer verses cheaper ratio as per question

    • @sivaskstudios1342
      @sivaskstudios1342 4 วันที่ผ่านมา

      @12th-Maths but they are given 2:3 only sir.

    • @12th-Maths
      @12th-Maths  4 วันที่ผ่านมา +1

      @@sivaskstudios1342 Actual formula is
      Qtty of cheaper/Qtty of dearer = (d-m)/(m-c);
      But in question the ratio 2:3 is representing ratio of
      milk in A (which is dearer as 3/5=0.6) to milk in B (which is dearer 7/20=.35)
      So in order to put this in formula I have to take reciprocal of this which will give me ratio of cheaper to dearer

    • @sivaskstudios1342
      @sivaskstudios1342 4 วันที่ผ่านมา

      @@12th-Maths thank you for your reply sir, but i didnt get,
      What my confusion, in other problems , we are taking d-m/m-c= what they are given ratio in question. But we r not taking reciprocal on tat. But in this question only we r taking like this.
      Y sir? I compared other problems sir. Kindly answer me

    • @12th-Maths
      @12th-Maths  4 วันที่ผ่านมา +1

      @@sivaskstudios1342
      " d-m/m-c= what they are given ratio in question" : This is not true
      The correct formula is:
      (d-m)/(m-c) = Qtty of cheaper/Qtty of dearer