it's becuase the output is not postive 2 KW and 1 KW, It's -2KW and -1KW. So when you subtract the 2 KW from 3 KW, you get 1 KW as a result. I hope this helps
You should think how much power is used in every section. In section AB until B shaft, 3kW power is used. Since B shaft uses 2kW of power, only 1kW of power is left for section BC.
The “uh huh uh huh” part always kills me😂
Jeff Hanson is everything I've ever wanted out of life.
Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))
Unit of Power should be Kgm²/s³
Thanks for putting out these lessons!! It has really helped me through my studies
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Fr though great video
Mr Hanson 🙋♀️
In cancelling out units when getting the Torque, what happened to the "rad" underneath?
Since the radian is a dimensionless unit (it's a ratio of two lengths), dividing by radians has no effect on the unit itself. So N*m/rads = N*m
Oh dear lord Thank God for Jeff hansen my teacher makes no sense
Why is the value of P in section BC is 1000 Watt, while in section AB is 3000 Watt?
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yes i noticed this as well I think this is wrong.
it's becuase the output is not postive 2 KW and 1 KW, It's -2KW and -1KW. So when you subtract the 2 KW from 3 KW, you get 1 KW as a result.
I hope this helps
@@MMMMMMMMMMBALLShow can you tell if it is positive or negative?
@@470bubbles Watch again from 7:27 sec onwards
man his good jokes are good
It’s the jokes for me 😂😂😂
What does he mean by don't get "J" confused with "I"?
why do you disregard the 2kW at Point B? how do you know when to do that?
You should think how much power is used in every section. In section AB until B shaft, 3kW power is used. Since B shaft uses 2kW of power, only 1kW of power is left for section BC.
What the hell? This man?😂😂💔
Jeff Hanson the next coming of our lord and savior