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ANS; --1 NEGATIVE 1 e a2x+2=1a2x+2=1 and aa is a positive real number other than 1, this implies that the exponent must be zero for the equation to hold (since any non-one positive real number raised to zero is 1). So: 2x+2=0 2x+2=0 Solving for xx: 2x=−2 2x=−2 x=−1 x=−1 Thus, x=−1x= −1.
ANS ; --1 NEGATIVE 1 e a2x+2=1a2x+2=1 and aa is a positive real number other than 1, this implies that the exponent must be zero for the equation to hold (since any non-one positive real number raised to zero is 1). So: 2x+2=0 2x+2=0 Solving for xx: 2x=−2 2x=−2 x=−1 x=−1 Thus, x=−1x=−1. THAnk you exam winner
ANS; --1 NEGATIVE 1 e a2x+2=1a2x+2=1 and aa is a positive real number other than 1, this implies that the exponent must be zero for the equation to hold (since any non-one positive real number raised to zero is 1). So: 2x+2=0 2x+2=0 Solving for xx: 2x=−2 2x=−2 x=−1 x=−1 Thus, x=−1x= −1 Exam Winner 🏆 Forever
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Answer 1
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ANS; --1
NEGATIVE 1
e a2x+2=1a2x+2=1 and aa is a positive real number other than 1, this implies that the exponent must be zero for the equation to hold (since any non-one positive real number raised to zero is 1). So:
2x+2=0
2x+2=0
Solving for xx:
2x=−2
2x=−2
x=−1
x=−1
Thus, x=−1x= −1.
Ans:- 1
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Ans -1
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ANS ; --1
NEGATIVE 1
e a2x+2=1a2x+2=1 and aa is a positive real number other than 1, this implies that the exponent must be zero for the equation to hold (since any non-one positive real number raised to zero is 1). So:
2x+2=0
2x+2=0
Solving for xx:
2x=−2
2x=−2
x=−1
x=−1
Thus, x=−1x=−1.
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X= -1
10
Hindi sa bolo
ANS; --1
NEGATIVE 1
e a2x+2=1a2x+2=1 and aa is a positive real number other than 1, this implies that the exponent must be zero for the equation to hold (since any non-one positive real number raised to zero is 1). So:
2x+2=0
2x+2=0
Solving for xx:
2x=−2
2x=−2
x=−1
x=−1
Thus, x=−1x= −1
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