I've been struggling with perms and combs since the start my A levels, and finally now, after a year, I understand them, maybe now I'll pass my A level! Thank you so much!
You are one in a million or one in 100 years kind of a teacher. It is hard to find one like you, you deserve special mathematics society honor confirmed upon to teachers like you similar to fields medal. Always stay upbeat, you are blessed. Thanks a million. You should train and produce mathematics teachers like u.
I'm having my examination on Monday! I was still finding a way to solve this stuff but later when I got into this channel I understood nearly 90% of this Permutations and combinations in Probability
Good day sir, I just want to ask quick question, where did you get the 120 and the 48 from? I tried to work it out where you actually get the 120 and 48 from, can you explain on the comment box please!
It is most wonderful series of lectures i have ever seen on Utube for aforesaid topic do u have few more lectures on the same pls do upload the lec for circular permutation & pls do inform me i very much greatful to u for ur lectures
In the second example, when finding the no of arrangements where A and B are together, shouldn't we divide by 2! instead of multiplying? Also, thank you very much your videos explain the concepts very well!
no you should multiply. since a and b can swapped and still be grouped together (b before a), that effectively doubles the number of possible arrangements that have a and b being beside each other which is why you multiply the 4! by 2.
@ExamSolutions hey im in 7th grade and learning this and this was helpful a lot but how did u know wether or not it was combination or permutation? If u have a trick with this it would help a lot and i am now going to use these videos for future reference all of the time get it or not. Thanks for being such a smart person and being able to do this stuff. To me this is difficult
I didn't quite follow you on the ABCDE problem. How exactly did you come up with 4! ways of A and B being together? There are only 5 places for an A; out of those 5 places, for 2 of them - first and last, there's only one place a 'B' can be put, to be next to A, and out of remaining 3 middle places for 'A', there are only two neighboring places for 'B' to be next to 'A'. Which gives us total of 1+1+2+2+2 = 8 combinations for A and B to be next to each other. thanks.
Sean Tristan Francisco...because there are different sets... So we have to use the multiplication operation. However, if we have the same set then we can use adition.
A multiple-choice question on an economics quiz contains 10 questions with five possible answers each. Compute the probability of randomly guessing the answers and getting exactly 9 questions correct. I figured the answer should be 10C9*((1/5)^9)*(4/5). But a website says it is 9*4/(5^10). I will be grateful if you can clear the confusion.
@@ExamSolutions_Maths Hi sir can you tell me the answer for this question. A coach has 16 players and can pick from 11 players for a match. it consist of 7 specialist batsmen, 4 fast bowlers, 3 spinner and 2 wicketkeeper. how many different teams can be formed if it must comprised of 6 specialist batsmen, 3 fast bowlers , 1 spinner and a wicketkeeper.
In how many ways can seven students from a class of 30 be chosen for a field trip if Jack must go on the field trip. I'm assuming this is the same equation as 6 out of 29 students being chosen (29 nCr 6 on a graphing calculator). Is that correct? I'm assuming on the next question (what if Jack can't go on the trip) is the same formula. I just want to make sure I'm doing it right. Thanks, guys! You rock!
Donice Sneed because the committee needed 5 people out of 11. Once 1 person is picked, they can't be re-picked. So the 'pool' to choose from goes from 11 to 10. And goes down 5 times. So it's 11x10x9x8x7
dont worry ur stil in grade 7^^ permutations: order matters (how many ways can 5 books be arranged on a shelf) the way you order the books. Combinations: order doesn't matter. eg (how many ways can 3 groups be formed from 7 ppl, the order doesn't matter)
I am shocked literally you post this video 10 years ago..... youtube give you award for the founder of educational content on youtube
I would recommend this playlist to anyone struggling with perms and combs.
BEST EXPLAINATION EVER
faxxx
Searched this over the whole Indian TH-cam only to find a foreigner explain it, Thank you so much
I have been looking for a good hour now for a clear tutorial on probability with combinations, and I have finally found it here! Thank you so much
I've been struggling with perms and combs since the start my A levels, and finally now, after a year, I understand them, maybe now I'll pass my A level! Thank you so much!
I always wonder if you passed ur A levels
@@internetborn I did, I have my bachelor's now
@@ZazzlesGS shoutout
could i bag you
youre so cute @@ZazzlesGS
Thanks! You remind me of Ross from F.R.I.E.N.D.S.
Cheers - that's a new one.
I can't unhear his voice now
@Grady Rowen dunno if anyone told u but you are a lifesaver lmaoo
@@ExamSolutions_Maths hey how you make these videos ?
If he was British
No probs, pleased to hear they helped
Thank you and all the best for tomorrow.
Hope it goes well for you - Good luck.
1st 11C5 is wrong... It is 77..
Thanks to u I just found the answer to a maths problem I spent the last half hour straining my mind over, thanks!
You are one in a million or one in 100 years kind of a teacher. It is hard to find one like you, you deserve special mathematics society honor confirmed upon to teachers like you similar to fields medal. Always stay upbeat, you are blessed. Thanks a million.
You should train and produce mathematics teachers like u.
AMAZING now at least I understand how the two are different and when to use them, thank you
You are great . Many videos do not explain the same thing so well as you do. Thanks a lot.
thank you v helpful, million times better than my teacher!
Thanks a lot. I was really confused about the permutation and combination part. But you cleared it. Thanks!!!❤️
Glad it was helpful!
well elaborated.... I have got no problem at all... thank you very much🙏
You guys are good. This kind of explanations makes probability simple. Kudos!
@anglican09 Pleased to hear you found it helpful.
I'm having my examination on Monday! I was still finding a way to solve this stuff but later when I got into this channel I understood nearly 90% of this Permutations and combinations in Probability
How was your examination bro.....?😄😄
Your explaination is great and clear,thank you so much.
wow i did not understand even i took days but i understand in 5 minute on this thank u
thank you so much! it's our finals today and I really needed this I love you!
+pauline valdez I wish you every success.
You really deserve more subscription. Keep up the hard work! Really understood and would really be blessed if you are my lecturer.
Bro thank you so much. You helped me out so much. I wish i could give you a warm hug. Keep up the great work broo!👍
Omg thank u soo muchhh i owe u big bits if it werent for i i wouldnt have graduated
you explain so much better than my teacher!! Thank you so much!!
Thanks alot. I wamted this last one bit to do questions with both P and C and Probability mixed.
Cool. Keep at it and I am sure you will get there.
Thank you for saving my life.
thanks man! I have an exam today on combinations and permutations and this really helped!
You are helping me more than my teachers. I finally have a grasp on it! Thank you! :)
Well done.
Got stuck with this subject during online classes. TY
Pleased it helped. Best wishes.
thank you sir for teaching this in easiest way possible
Good day sir, I just want to ask quick question, where did you get the 120 and the 48 from? I tried to work it out where you actually get the 120 and 48 from, can you explain on the comment box please!
you are an excellent teacher ... may the King reward you
Your videos are outstanding! and I really appreciate it, thank you.
that was a really awesome series very well explained
very understandable teacher.
Thank you
This was amazing! Thank you so much.. your way of explaining is awesome! :)
Flattery will get you everywhere!
It is most wonderful series of lectures i have ever seen on Utube for aforesaid topic do u have few more lectures on the same pls do upload the lec for circular permutation & pls do inform me i very much greatful to u for ur lectures
In the second example, when finding the no of arrangements where A and B are together, shouldn't we divide by 2! instead of multiplying?
Also, thank you very much your videos explain the concepts very well!
no you should multiply. since a and b can swapped and still be grouped together (b before a), that effectively doubles the number of possible arrangements that have a and b being beside each other which is why you multiply the 4! by 2.
Found this the night before my statistics exam, thank you so much! I may have a chance now!
did you pass?
Thanks. Well explained 👏
Omg you're a lifesaver and a really awesome teacher ❤️❤️
thank you very much from oman. You have helped me a lot
so why are you keeping the rearrangmenet in denominator in 1st example and multiplying it in 2nd example
Oh so helpful! Thanks
Good to hear, thank you
If I roll 2 dice and the only thing I care about is sum of these dice should I use permutation or combination?
really helpful series, pls make 1 on geometric and binomial distribution
th-cam.com/video/NaDZ0zVTyXQ/w-d-xo.html&ab_channel=ExamSolutions Please check out our series on the binomial distribution.
Thank You! Your videos are so clear, and are really helping me get through my AS! Thanks!!! :)
can u use the notation (permutation) for the ABCDE question, as in 4 permute 2 (eg) because I dont understand how to show it.
You explain better than my professor. I can't even read half my professor's handwriting.
how come for the second video the nPr=n!/(n-r)! wasn't used?
Excellent video! Really helped! Thanks a lot!
Thanks for watching.
@ExamSolutions hey im in 7th grade and learning this and this was helpful a lot but how did u know wether or not it was combination or permutation? If u have a trick with this it would help a lot and i am now going to use these videos for future reference all of the time get it or not. Thanks for being such a smart person and being able to do this stuff. To me this is difficult
if the quesrion is asking to arrange, then permutation, if ir's asking to SELECT/CHOOSE, it's combination
@@rajdipshah9225a bit late, this person is probably working a 9 to 5 now
I didn't quite follow you on the ABCDE problem. How exactly did you come up with 4! ways of A and B being together? There are only 5 places for an A; out of those 5 places, for 2 of them - first and last, there's only one place a 'B' can be put, to be next to A, and out of remaining 3 middle places for 'A', there are only two neighboring places for 'B' to be next to 'A'.
Which gives us total of 1+1+2+2+2 = 8 combinations for A and B to be next to each other.
thanks.
Thank you! This helped me out a lot.
Sir may you clarify?
In the second example did you mean 4!/2! Or 4! × 4! ?
Neither. 4! x 2!
saw this questions on a cambridg statistics as level past paper, very usefull thanks!
Rly? I wished Im gonna have questions like this this coming OCT NOV AS test
Why do we multiply the combinations instead of adding them up? Can someone explain?
Sean Tristan Francisco principles of counting...multiplication rule
Sean Tristan Francisco
Sean Tristan Francisco...because there are different sets... So we have to use the multiplication operation. However, if we have the same set then we can use adition.
Yes it can be
i) 29C6 is correct and (ii) 29C7
A multiple-choice question on an economics quiz contains 10 questions with five possible answers each. Compute the probability of randomly guessing the answers and getting exactly 9 questions correct.
I figured the answer should be 10C9*((1/5)^9)*(4/5). But a website says it is 9*4/(5^10). I will be grateful if you can clear the confusion.
what if by any chance cards with letter A and B refuses to be together what would the solution be?
Im actually dont understand how and when I gonna use P and C. Thanks, now Im understand. Tomorrow I have quiz about Statistics. zzz
+NurFarrah Soda Good Luck - I hope it goes well for you.
+ExamSolutions Thanks again. 😊
me too
Thank you so much 💖
october exams are close and thank god your videos are so damn helpful keeo up the good work
Thanks and good luck.
@@ExamSolutions_Maths
Hi sir can you tell me the answer for this question.
A coach has 16 players and can pick from 11 players for a match. it consist of 7 specialist batsmen, 4 fast bowlers, 3 spinner and 2 wicketkeeper. how many different teams can be formed if it must comprised of 6 specialist batsmen, 3 fast bowlers , 1 spinner and a wicketkeeper.
@@kathleenolivier1588 7C6 * 4C3 * 3C1 * 2C1 Dude use combinations.
@@isi6402 divided by 16C11
Now I understand better! =D
Thank you! ^^
A billion thanks
watching from 2024 amazing video really 🫡🫡
is this for o level add math?
Thank you! I don’t live in an English speaking country, but your videos make much more sense than my professor (˃̵ᴗ˂̵)
Thanks Gordon
Good
thank you sir !!!
This was a great video thanks a lot!
Cheers - thanks for watching
Thanks a lot mate.
This is the easy stuff........ I need more advanced examples.
thanks man that was awesome
Thanks
is it OCR?
thank you sir 😊
In how many ways can seven students from a class of 30 be chosen for a field trip if Jack must go on the field trip. I'm assuming this is the same equation as 6 out of 29 students being chosen (29 nCr 6 on a graphing calculator). Is that correct? I'm assuming on the next question (what if Jack can't go on the trip) is the same formula. I just want to make sure I'm doing it right. Thanks, guys! You rock!
Amazing Thank You !!!!!
this is an easy question....do one where the letters of a word have to be in an order and we need that probability
thanks a LOT
thanks super helpful
Good luck
Thank you very much!!!:)
thank you very much for the video :)
7 years later, thank you
@stupermanana thanks I passed it....with a 65...now I'm in 8th grade so yea thanks again only 2 months too late tho...
thank you, friend :D
@MsHeartBreaker16 cool
how is 5! 120??
5!=5x4x3x2x1. 5x4=20, 20x3=60, 60x2=120
Sam Kelly...5x4x3x2x1
Okay you multiplied 11*10*9*8*7 why didn't you multiply 6 also when multiplying the number of committees?
Donice Sneed because the committee needed 5 people out of 11. Once 1 person is picked, they can't be re-picked. So the 'pool' to choose from goes from 11 to 10. And goes down 5 times. So it's 11x10x9x8x7
dont worry ur stil in grade 7^^ permutations: order matters (how many ways can 5 books be arranged on a shelf) the way you order the books.
Combinations: order doesn't matter. eg (how many ways can 3 groups be formed from 7 ppl, the order doesn't matter)
Care to elaborate any further?
There were 5 gaps to fill not 6
You Made this EASY - awesome teacher. you are SAVING my ass right now!
Saving ass's is what I do.
My teacher decided to teach this instead of giving us an EOC exam.