Hello, thank you for uploading these videos they are very helpful. I just have one question. For question 10a is the vertical component of the tension in the line different to the resultant force in the vertical direction?
you should put the amount of marks on the question , it's easier to visualize what i need to do for some questions when i know how many marks ill get for it
Kinda confused about the question with the racecar... Aren't F=ma and F=mv/t basically the same equation but just different manifestations of Newton's 2nd Law? Since acceleration equals change in velocity per unit time, you're just replacing the 'a' in F=ma with 'change in velocity over time'. So therefore why is it acceptable to use the second equation if mass isn't constant but not acceptable to simply use F=ma?
They both originate from F = d(mv)/dt but that equation only simplifies like you show to F = ma when m is a constant which is why you can take it out of the change expression d(mv). If m is not constant, you can't take it out of the change expression to make it md(v).
A very good video. Nice!!!
Hello, thank you for uploading these videos they are very helpful. I just have one question. For question 10a is the vertical component of the tension in the line different to the resultant force in the vertical direction?
Also, please could you do a video on questions relating to Archimedes principle. I would really appreciate it. :)
Can you please include a document of the paper so I can do the questions along with the video
you should put the amount of marks on the question , it's easier to visualize what i need to do for some questions when i know how many marks ill get for it
Very nice
Kinda confused about the question with the racecar... Aren't F=ma and F=mv/t basically the same equation but just different manifestations of Newton's 2nd Law? Since acceleration equals change in velocity per unit time, you're just replacing the 'a' in F=ma with 'change in velocity over time'. So therefore why is it acceptable to use the second equation if mass isn't constant but not acceptable to simply use F=ma?
They both originate from F = d(mv)/dt but that equation only simplifies like you show to F = ma when m is a constant which is why you can take it out of the change expression d(mv). If m is not constant, you can't take it out of the change expression to make it md(v).
Ah awesome thanks!
Thank you Sir
11b should be X(-35)not +
What exam board is this for?
The questions are from AQA but the content is core to all of the boards
thanks
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