CSIR-NET June 2019 Question 25 : Real Analysis (Continuous & one-one Function)

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  • เผยแพร่เมื่อ 15 ธ.ค. 2024

ความคิดเห็น • 12

  • @deepachauhan3657
    @deepachauhan3657 3 ปีที่แล้ว

    Sir I saw many you tube channels ,all of them thaught the same but the way you help us learn things ,it's very unique...sir please upload video continuously ,we want them

  • @titukumar7756
    @titukumar7756 2 ปีที่แล้ว

    thank you sir

  • @neetu896
    @neetu896 5 ปีที่แล้ว +1

    Thank you so much. It helped me a lot.

  • @P.DEY1729
    @P.DEY1729 ปีที่แล้ว

    Sir for the 4th option we can also take the function f(x)=1/(eˣ +1) ?

  • @RITESHKUMAR-fq6js
    @RITESHKUMAR-fq6js 3 ปีที่แล้ว

    Very conceptual probblem

  • @liyaaak912
    @liyaaak912 5 ปีที่แล้ว +1

    Please solve nbhm questions also

    • @Axiomatikos
      @Axiomatikos  5 ปีที่แล้ว

      Ya we will do that too

  • @venkatesuvelpula3775
    @venkatesuvelpula3775 5 ปีที่แล้ว +1

    How tanhx continuous and 1-1explain?

    • @Axiomatikos
      @Axiomatikos  5 ปีที่แล้ว +2

      tanh(x) = exp(x)-exp(-x) / exp(x)+exp(-x)
      Which is quotient of two continuous functions and denominator is never zero. So it is continuous.
      To prove that it is one-one.
      Take tanh(x)=tan(y) . Then after little calcution you will get x=y.
      Which implies tanh(x) is one-one.
      Also.
      You can see the graph of tanh(x).

  • @wasimkabir9737
    @wasimkabir9737 5 ปีที่แล้ว

    Thanks you so much sir