Laplace Transform (Solved Problem 13)

[@samarthagarwal417]

ANS: 1 ...option B
y(t)= (-2*exp(-t))-(t*exp(-t))
dy/dt= (2*exp(-t)) - (exp(-t) - t*(exp(-t)))
put t=0
=1

[@neeltej4123]

perfect !!

[@laxmanselvaganesan7220]

Thanks for the explanation

[@itsmehemant7]

ans. is " 1" i.e option b

[@pratyushkesharwani2179]

option b will come when we find y(t) at t=0+, the answer of its derivative at t=0+ is -5.

[@Helpme24std]

Hello

[@amitray8898]

b) 1 is the correct option

[@sachindoifode9272]

Sir plz explain homework problem...

[@itsformac]

Option B
✅✅✅

[@mr.unique7689]

option (b)...1

[@bhanu8391]

mr. unique how ?

[@JJpunk434]

find y(t) as earlier prob then differentiate it put t=0

[@mohdaqib784]

@@bhanu8391 u can also apply initial value theorem for quick solution

[@neeltej4123]

@@mohdaqib784 nope.. that might have worked here to get the ans,but when initial conditions are given u must follow the above explained way.

[@samantsrivastava8170]

1 ans.

[@priyashrivastava2230]

Sir plz atleat upload ans of typical problems
So thak we can check our result

[@kirubakaran6758]

Can anyone explain why the ULLT is not expanded to s^-1, s^-2, and so on? Why stop at s^0?

[@mobile_o_graphy4729]

bro read the formula n = 2 only

[@sheninfrancis3822]

Option b) 1.

[@nagigoud3374]

Nice xplanation sir... Superb

[@mohdshumail51]

Sir answer of HW problem please

[@shabinaa6407]

Y(t)=-2( e^-t) - t(e^-t)
After diff. Dy/dt =(2+t)e^-t
Putting t=0
I got 2, option D

[@payalsavani8562]

shabina shaikh
dy(0+)/dt = dy(0-)/dt = 2

[@jancydas5569]

After diff ...2e^-t-[e^-t-te^-t]
2e^-t-e^-t+te^-t
e^-t+te^-t
(t+1) e^-t
At t=0 ans is one
Option b

[@anasudheenp5930]

y(t) =( -2*e^-t ) - (t*e^-t);
dy/dt = (2*e^-t ) + (t*e^-t) - (e^-t);
at t = 0 => = 2+0-1= 1

[@maheswaran8729]

@@anasudheenp5930 dear friend can you say how did you get y(t)?
because i get y(s)= -3-2s /(s^2+2s+1).after how did you done partial fraction.

[@anasudheenp5930]

@@maheswaran8729 give me your mail Id...I can send the snapshot of solution to you🙂

[@Mehraj_IITKGP]

y(t)=-1.5-0.5exp(-2t),
So, y'(t)=exp(-2t), therefore, y'(0)=1

[@akanshachaurasia6226]

Did anyone get option a)-1 as the ans

[@akibjawed5076]

ans. = 1, option (b)

[@wajidbhat8258]

Option A i.e. -1

[@swastikmohanty6361]

Option d

[@shaillybhai007]

please upload the solution of HW problem

[@abhijeetvats5943]

Option b

[@syamamreddy]

Y(s)=(-2/(s+1))-(1/(s+1)^2)
y(t)=-2e^-t then how to find out inverse LT of -(1/(s+1)^2)

[@chetanteli_iitbombay]

It is equal to -e^-t. t......AS...L{.r(t)}=1/s^2

[@reficeismail6520]

option b

[@divyadeora132]

Sir pls do upload the solution of homework problem

[@ee19gauravshrivas18]

Option B (1)

[@gouthamraj1308]

option d

[@mohdaqib784]

how?

[@shivaprasad9405]

@@mohdaqib784 by taking differentiation in time domain property .

[@wajidbhat8258]

I am getting option A

[@sabiyanaikwadi641]

ans is b

[@bhanu8391]

How to do this problem?

[@prateekjaiswal8045]

Option b is correct

[@exodus5948]

When u will finish this course?

[@kityoungster6486]

@Surabhi Mondal really

[@koushikbharadwaj8215]

b) 1 is the answer

[@chirasmitadash]

Ans-1(option b)

[@pkofficl7650]

How?

[@pkofficl7650]

How could find particularly for that term?

[@swmicmajumder2168]

Answer should be 2 as t=0+, not 0. So u(t) has to be 1.

[@cemileceylan1017]

agree

[@edwardramirez824]

what if someone asks me to find h(t) or H(s)?

[@saikrishna-sh8fl]

I guess we can't find. As Transfer function is defined only for an LTI system with zero initial conditions and here as initial conditions are not neglected so we cannot find H(s) or h(t).

[@022_firdousnabi5]

@@saikrishna-sh8fl cool 👍

[@KushalSarkarOfficial]

1 is ans

[@sukhmanpreetsinghsandhub2042]

my ans of hw problem came option b i.e 1

[@ikram3551]

1

[@RafaSyed]

What's LT of Delta function?

[@yuvarajsaithadishetty8829]

1

[@r.dineshkumar3984]

1

[@stunnerlone436]

B

[@poojarajput9386]

b

[@rohitkumar-mj2je]

pooja rajput how it

[@ahmedimtiaz8241]

hw

[@maheswaran8729]

did the laplace transform of delta function is 1(one)

[@r.dineshkumar3984]

Yes

[@vinaypant557]

A

[@ee19gauravshrivas18]

0

[@SUMITKUMAR-eo9iu]

a

[@RemyaLikhil]

Option b

[@sumitkrverma]

option b is correct

[@muneshgupta4669]

Option b is correct

[@smpodcast2465]

Option d

[@jigneshvala2282]

B

[@ritikgupta2178]

B