In exam if you don't want to waste your time on writing long limitation. Then you write this much only , "But practically it is impossible to achieve" Therefore: "There is no real heat engine of 100% efficiency " 👆🏻This much is enough this contain that all things..🙂
1-2 isothermal expansion 2-3 adibatc expansion 3-4 isothermal compression 4-1 adibatc compression Isothermal meant change in T equals ZERO or T is constant throughout Adibatc means change in Entropy equals ZERO.
sir, you explained very neatly but for site students it is not visible clearly from a hand distance, for now it's ok sir but from your next videos please explain on a white page where light is clearly visible, it is a request from me and the students who face the same problem.
Process 1-2 is an isothermal process, how come T2 is then different from T1, constant temp expansion means there is no change in temp during the process, which according to your derivation implies that the efficiency is zero. And how this adiabatic process equation is applicable for the process 1-2
No bro the temperature does not change in process 1-2.T1 is the constant temperature of process 1-2 and T2 is the constant temperature of the process 3-4 , so they are isothermal only
Thermodynamics gives you bounds on real engines. Moreover, the explosion of the fuel mixture is not even approximately reversible. How can thermodynamics be of any use, in designing real world internal combustion engines?
Sir value of work 3-4 was negative........so why it did not make the efficiency n= 1 - (-mRT² ln (V⁴/V³) ----------------- mRT¹ ln (V²/V¹) Please explain sir
Sir can you plz plz reply quickly my question answers 1. A piston cylinder system contained air is worked on carnot cycle to do some mechanical work. Initially ,the system contains air at 1bar ,298k and 0.01m3. the system is first compressed until the volume is 0.002m3 (isothermally) .after that, the system undergoes an expansion process (isothermally) to a point where pressure in the system is 5 bar .At that point , the system is subjected to an isothermal expansion process until system reaches the initial state completing a cycle. Calculate the net work done of the cycle and cycle efficiency.
Where did the -ve sign go because heat produced by 4---1 was -ve And V4/V3 = V1/V2 then how can you cancel them by changing denominator with numerator (i.e V2/V1)
@@goratagobuiwang6475 bro its cause Q3-4 is negative as compression i.e work done on the system is negative so the n = 1+ Q3-4/Q1-2 now n = 1 + T2ln(V4/V3)/T1ln(V2/V1) now after taking \-1 common we get n = 1- (T2/T1).
Carnot cycle is cyclic process? If it is then initial state should be equal to final state t1=t2, p1=p2 and so on. And plz explain reversible word you use in cycle? Is it means that you added hear from process 2 to 3 ,can reverse from 3 to 2 with out effecting system and surrounding In a cycle?
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OMG thanks to your video I finally understand the Carnot Cycle for my presentation. Thank you so much !
are you vietnamese
??
Yhh
😂
In exam if you don't want to waste your time on writing long limitation.
Then you write this much only ,
"But practically it is impossible to achieve"
Therefore: "There is no real heat engine of 100% efficiency "
👆🏻This much is enough this contain that all things..🙂
Liked ur style of writing 'A' 😂
Yes 😂
Ya cool A
😲🙄
🤪
1:50
Helped a lot....ill pass because of you:)
Which field u study?
When we find the value of q 3 to 4 - it negative values then why not put the value of negative in efficiency of carnot ....??????
Exactly I'm saying
He is directly putting these values and this is an incomplete process
1-2 isothermal expansion
2-3 adibatc expansion
3-4 isothermal compression
4-1 adibatc compression
Isothermal meant change in T equals ZERO or T is constant throughout
Adibatc means change in Entropy equals ZERO.
th-cam.com/video/9aKTdb3mYDU/w-d-xo.html
In adiabatic change in heat is zero right? How come change in entropy is zero
Kal mera paper h Or mujhe aaj yaad are h sir ji
Nice hand. Writing and good explanation sir ..
sir, you explained very neatly but for site students it is not visible clearly from a hand distance, for now it's ok sir but from your next videos please explain on a white page where light is clearly visible, it is a request from me and the students who face the same problem.
Process 1-2 is an isothermal process, how come T2 is then different from T1, constant temp expansion means there is no change in temp during the process, which according to your derivation implies that the efficiency is zero. And how this adiabatic process equation is applicable for the process 1-2
No bro the temperature does not change in process 1-2.T1 is the constant temperature of process 1-2 and T2 is the constant temperature of the process 3-4 , so they are isothermal only
Thank you !! 👍🏻
Ok
✌ab aap kya kar rhi ho? MBBS??
A Million Thanks to you Sir☺🙏. You explained very neatly .
Fully byhearted
Awee such an awesome sound❤️👀
🧐🧐🧐😏
@@humanityspeaks3236 why so 🥺🥺🥺🧐🧐
@@priyakutti... I feel irritating 😖 from this sound 😁
@@humanityspeaks3236 why avinash
@@priyakutti... because sir sound is mixed up with background music🎶
7:27 if its ln(v4/v3)then how can the numerator and denominator get cancelled
the numerator denominators inter change
Yes there is a mistake
In process 3-4 the workdone should be [-mRT2 ln(V3/V4) ]
Yeah
Sir if adiabatic compression and adiabatic expansion is remove from carnot cycle than what happen and what is the efficiency
This what happens if you know physics but don't know maths. 🤣🤣🤣
Gand faat jaye gi 😂
Thermodynamics gives you bounds on real engines. Moreover, the explosion of the fuel mixture is not even approximately reversible. How can thermodynamics be of any use, in designing real world internal combustion engines?
we should not ask this kind of questions a day before exams 😅
This is easy method to learn tqsm sir😊
Finally mujhe carnot cycle ki efficiency samajh aa gyi. Thanku sir😇
Is it possible to perform it
th-cam.com/video/9aKTdb3mYDU/w-d-xo.html
Sir plzz draw Carnot cycle accurately...
th-cam.com/video/9aKTdb3mYDU/w-d-xo.html
Nice work brother 😍
Thank you sir . your explanation is very neatly
Sir that part Q3-4 equals minus was there but after where the minus was out
Sir thanks this is easy method to learn
Tq for good explanation
Sir ,you forget to write negative sign in Q3-4 and you written V4/V3= V1/V2 as V2/V1
Nice Voice recording 👏
Sir explain the keerchoffs law
Thank you sir I understand this topic
Sir value of work 3-4 was negative........so why it did not make the efficiency n= 1 - (-mRT² ln (V⁴/V³)
-----------------
mRT¹ ln (V²/V¹)
Please explain sir
please reply sir
Sir can you plz plz reply quickly my question answers 1. A piston cylinder system contained air is worked on carnot cycle to do some mechanical work. Initially ,the system contains air at 1bar ,298k and 0.01m3. the system is first compressed until the volume is 0.002m3 (isothermally) .after that, the system undergoes an expansion process (isothermally) to a point where pressure in the system is 5 bar .At that point , the system is subjected to an isothermal expansion process until system reaches the initial state completing a cycle. Calculate the net work done of the cycle and cycle efficiency.
You wrote the wrong thing when replacing Q³-⁴
Absolutely great way of teaching
...all understood 😊
thank you sir.very well understood
Well explained..👍😍
Where did the -ve sign go because heat produced by 4---1 was -ve
And V4/V3 = V1/V2 then how can you cancel them by changing denominator with numerator (i.e V2/V1)
Same doubt 😢
wrong at end adiabatic relating with volume
th-cam.com/video/9aKTdb3mYDU/w-d-xo.html
Tq sir 🙏🙏 adorable explanations 🙏🙏😛
What happened to the -ve sign of Q3-4 when you substituted it in 1-(Q3-4/Q1-2)
Wasn't it supposed to be
1+T2/T1
@@goratagobuiwang6475 bro its cause Q3-4 is negative as compression i.e work done on the system is negative so the n = 1+ Q3-4/Q1-2 now n = 1 + T2ln(V4/V3)/T1ln(V2/V1) now after taking \-1 common we get n = 1- (T2/T1).
@@ashishsaud6688 thank you
@@ashishsaud6688 thank you
@@ashishsaud6688 thank you
Can I write this derivation for my bsc 2nd year exam?
th-cam.com/video/9aKTdb3mYDU/w-d-xo.html
Carnot cycle is cyclic process?
If it is then initial state should be equal to final state t1=t2, p1=p2 and so on.
And plz explain reversible word you use in cycle? Is it means that you added hear from process 2 to 3 ,can reverse from 3 to 2 with out effecting system and surrounding In a cycle?
NO BRO IN CHEMISTRY THERE IS A PROCESS I.E. REVERSIBLE IT IS A SLOW PROCESS THAT CAN MOVE BAVKWARD TO WND ATTAIN EQUILIBRIUM.
Thanks🙏🙏 sir
Thanku sir👍👍
th-cam.com/video/9aKTdb3mYDU/w-d-xo.html
Nice video sir
Thank you sir, for explaining 😇
Hi
@@gowthampinninti35 th-cam.com/video/9aKTdb3mYDU/w-d-xo.html
Why have you taken T2 replacing T3 in Q3-4 ?You just copied from book not explained well
Nice video 👍
but sir Q3-4 ka minus Kahan gya
Thankyou sir
Thank you❤ sir
Amazing
WHICH IS COMPRESSION WHICH IS EXPANSION BRO IT IS AN INCOMPLETE PRESENTATION
Nice sir ❤️👍
Can the efficiency of Carnot’s engine be 0 or 1?
Thank you!
Exam se ak din pahale 😅😅😅😅
Super sir
Nice video
Tq so much bro
Nice..🇧🇩🇧🇩♥️♥️
how is - - not equal to plus?
Nice one
Yu to sir ji book se hi pd lenge 🙂
How u substute in v2/v3=v1/v3 in efficiency
Brother look in its diagram you will get it
He forgot to add negative sign while placing value of Q 3-4
1:51
🙂
TNX Bhai
Thanks you
Q3-4 value is nagetive and you use it as positive why
👍🏻👍🏻
Nice😇
Where is source or sink🤔🤔🤔???????
U said wrong 1st one isothermal expansion 2nd one adiabatic expansion 3rd one isothermal compression and last one adiabatic compression
It is correct
Kya yaar likhte time kbhi tera haath aajata h or kbhi vo typing kuch dikh bhi nhi ra 🙄
pliz explain stirling cycle
Firstly u say Q1&Q2 are adiabatic process and know u r writing in next steps that 1-2 ara reversible isothermal and 2-3 ara adiabatic wtf is that.. 🙄
CAN I BORROW UR HANDWRITING FOR MY TODAY'S EXAM !! PLEASE 🙏❤️🥺
Yav ooru
You sound like ROHIT (Hritik Roshan)from Koi mil when watched at 2x speed
🖤❤️❤️
Soo Nice
wingis 😍😍😍😍
Tnq u
It is inter
Super
Nice
Puri engineering me mko thermodynamics se bhut Dr lgta h bilkul smjh ni aati ye
Ur voice is like Hritik Roshan somehow😅
@vivek rana Wah!!! Tera khaan ko saaf bina karke kitne saal hu hai bhai 🙂
Ho it is possible 4to 2 ,4 to1
ARVIND VERMA FAIZABAD CLASSES 365🙏
Bro won't be over smart this is this is right but have got zero mark with this
Sir don't put words in the bottom of video it's hidding the video
Bearable accent. Thanks
Are bhai hindi mei bolde
Kya galt comments karte han log
Efficiency =1-(T3/T1)
Supperayi manasilayi sir
@@harithababuharitha2341 oh serikkum??🙄😆
What's mean pdv
Pdv= pressure* small change in volume tht means ( dv )
it is also equivalent to work done
Shakir
Tupac
Sir hindi me bolne me kya dikkt h
Hindi sabko nahi aati chomu, Bharat aur kai bhashayein hein
@@bonapetits chomu kis baat ka bol rhe ho fir tumhe to bolna hi nhi aata h kyu tum khu aur se ho kya...
@@FAILURESHORTS444 sabko hindi nahi aati, toh yeh rona-dhona band kar chomu
@@bonapetits chaprimon .....chomu jaisa to khud h ...bts lover....thora mature bn aache se bol rha to aache se bol jiski photo tune lgayi h na usse puch...asli rona use aata h...
@@bonapetits waise bhi Hindi mother tongue h aani chahiye India me hokr Hindi nhi aati
Sir apana contact send kr