Base Compensated BJT Current Mirror

[@Exertial]

Absolutely fantastic series of videos, thank you!!!

[@mateoaboytube]

Thanks. We are glad you like them.

[@sonikumari1897]

Thanks for this video. In Sedra Smith, it isn't explained properly.
But in your video, at 5.30 duration you have done a small mistake in equations.
Ic3 is not equal to ( 2 Io / beta )
Use eqn.
Ie = Ic + Ib
Then
Ic3 = 2 Io / ( beta + 1 )
And then find the final current transfer ratio.
Final answer will include the term (( beta + 1)beta )

[@balajikalva188]

Pausing the video I solved it got the same result as u got but I don't think it will make much difference in assuming beta +1 as just beta

[@paraklesis2253]

I agree

[@zattiya]

@5:06 the emitter current is labelled 2Io/B. Why do you say it is collector?

[@armanmanukyan1970]

Thanks for video.I have a question.How does it happen, that transistor Q3 is "open", because we have primarily reverse biasing B-C of Q3, but emitter of Q3 , I think, is not defined, and B-E junction is closed.In any case, not obvious,that it is open.Please explain.Thank you in advance.

[@musicphilebd9862]

She is not Mateo Aboy. But she is a very good teacher. What's her name?

[@mateoaboytube]

Cristina (see "About" section on the channel)

[@sabahsalih9359]

Hello Cristina, Thank you for these great video series. I just have one comment: your writing is very small and crowded, I think because you do not have enough area to write. My suggestions if you decrease the area of the name and photo and added to the area of your presentation you will make your presentation big enough to write clearly and freely. Thanks