sum of 1st n integers = n(n+1)/2 So A=1+ 2 + 3+...19 = 19*20/2 = 190 Similarly B= 1+ 2+ 3+..9 = 45 now we get C= 2+ 4+ 6..18 = 2B = 90 Sum in question = A-C = 100
@@_loneyy Odd numbers 1,3,...19 No of terms in ap=last-first/d +1 9+1=10 Here we want to find the sum so want to find the avg..the avg of A.p is first term + last term/2 1+19/2= 10 Finally we know that AVG= sum/number Sum= avg ×number = 10×10 =100
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Le SSLC kazhinja +1 pillar🗿
Pinne sslc kazhiyaathe plus one aavillallo
Fresh..👏@@ArjunArju-h7w
@@ArjunArju-h7w😂🗿
;))
കൊള്ളൂല
2n -1 =19
Which implementation n =10 Sum of an odd numbers =n2
Answer is :100
Intelligent🎊
ചേച്ചി മാത്സ് ടീച്ചർ അല്ലെ 😂
Super explanation Mam....😊
Sum of odd numbers=n×n
n[no . Of terms] = 10
Therefore sum = 10×10
= 💯
Sum of first n odd numbers*
(2n-1) =19
Which implies n=10
Sum of n odd numbers= n²
Ans=10²=100
Lee SSLC students : ithu nammude Maths Textbook ilee Questions Aalle...😅
Sathyam
Correct😂
Crrct😹
🤣😭🤣🤣🤣😭😭😭
Ayn....
2n-1
2x 19 -1
38-1
37
sum of 1st n integers = n(n+1)/2
So A=1+ 2 + 3+...19 = 19*20/2 = 190
Similarly B= 1+ 2+ 3+..9 = 45
now we get C= 2+ 4+ 6..18 = 2B = 90
Sum in question = A-C = 100
really great approach bro
Brruhhh 😮
@@Kritika_delhi😊
😮@@storytime1942
Answer Is 100
1+3+...19=....
19-1/2 +1=10
This is an odd no.of arithmetic sequence and also x1=1 therefore the answer=10²=100
10
Sum of odd numbers =n²(n is no of terms)
n=(l-f/d)+1=>19-1/2+1=10
Therefore sum =10²
=100
361 aan answer
@@asraasthetic noo
I got 181
@@Dvk_G the formula for finding sum of 'n' odd numbers is n²
@@Dvk_G sorry bro answer 100 thanne😁 361 aadyathe 19odd numbersinte sum aann
Thank you sir god bless you ❤
1+3+5+7+...+19=100 because the number is increasing 2 like 7+9+11+13+15 +19 like this 😂
Odd numbers..1..3...….19
Avg =10..(avg of a AP(( f+l)/2))
N=(18/2+1)=10
10×10=100(sum=avg×no)
????
@@_loneyy
Odd numbers 1,3,...19
No of terms in ap=last-first/d +1
9+1=10
Here we want to find the sum so want to find the avg..the avg of A.p is first term + last term/2
1+19/2= 10
Finally we know that AVG= sum/number
Sum= avg ×number
= 10×10 =100
Bruhhh
U nooob
ചേട്ടൻ ചെയ്തത് തെറ്റ് ആണ്
ഒറ്റ സംഖ്യകളുടെ തുക =n²
[{. n=10 (1+3+5+7+9+11+13+15+17+19). }]
=10²
=10×10
ANS =100
✅
🎉🎉🎉
Apo even numbersinte sum egana kand pidika
n(n+1)@@nanduadhin
N ( n+1)/2@@nanduadhin
100 ann
(2n-1)=19
Implies n=10
Sum of n odd number =n²
Answer is
10²=100
n(n+1)/2
19(19+1)/2
Which implies n=10
Ans=100
1. 9
2. 4
3. 90 degree
4.7/10
n=xn-x1/d+1
Xn=19
d=2
n=19-1=18/2=9+1=10
Sn=n/2(xn+x1)
Sn=10/2(19+1)
=5x20=100
🎉
🎉
d=2
Xn=19
N=xn-x1÷2+1
Sum=10÷2×19+1
5×20
=100
😅
f=1
xn=19
d=2
Number of terms=l-f/d+1
=19-1/2+1=10
Sum of odd numbers =n²
=10²=100🧠
19-1/2+1=10 how?
@@ashbineditercutz7104
19-1=18,
18÷2=9,
9+1=10.
@@ashbineditercutz7104
19-1=18,
18÷2=9,
9+1=10.
Sum of odd no = n²
n = 10
n²= 100😌💓
Sum=n/2×(first term + last term )
ie ,10/2×(1+19)
5×20=100
Ans=100
[Sum of first n odd no:s is n²
=10²
=100]
Answer n×n+1/2 190
Odd number: 1+2+3+........+19
Avg=10
N=10(19+1/2)
10x10=(sum=avg x number)
10²=100
Correct
1 to 19 there are 19 numbers
1 + 3 + 5 ..... +19
Sum of odd numbers = n²
So 19 + 1 ÷ 2 = 20 / 2 =10
So the n is 10
So Sum is 10² = 100.
POV : 10th Standard Maths.
Sn=n/2[a+l]
n=10
a=1
l=19
Sn=5×20=100🎉🎉❤❤
n = 10 ,n square=10 square=100 or 1+3+5+7+9+11+13+15+17+19=100
Sum of first n odd numbers =n square
n=10
n2=10square=100
a=1,d=(3-1)=2,an=19
an=a+(n-1)d
19=1+(n-1)2
18=(n-1)2
n=10
Sn=n/2(a+an)
=10/2(1+19)
=5×20=100
Ans=100
Last Ans 100
The sum of the first n odd number = n²
Total odd numbers = 100
Therefore n² = 10² = 100
n=xn-x1÷d+1=(19-1÷2)+1=10
Sn=n^2=10^2=100
Sum of 'n' consecutive odd numbers from 1 = n²
Hence, the answer is 100
n=10, d=2, a=1, sn=n/2[2a+(n-1) d], sb=100
Ans:100,ആൻസർ കറക്റ്റ് ആണെങ്കിൽ പിൻ ചെയ്യുമോ?plllzzzzz.....
a=1, l=19, n=10
Sn=n/2×(a+l)
S10=10/2×(1+19)
=10/2×(20)
=10/2×2(10) { 2 and 2 gets cancel }
=10×10
=100
5) 1+3+5+.......... 19 = 19+1 divided by 2 =
20 divided by 2 =10 n=10
n² = 10² (10×10) = 100
I am 8th standard
Good
1. Answer 9.
2. Answer d =4
3. Answer 90 degree
4. Answer 7/10
5. Answer 100
Supperrrrrr class
19+1=20
3+17=20
5+15=20
7+13=20
9+11=20
So 20x5=100
Same👍🏻
Wow
1% 1,3,5,7,9,11,13,15,17,19 and ethellam plus cheyumbo nammak 100 kittum
n/2×1+19 psc
We know that 2n-19
Since n=10
We get the answer,
100
Arthimetic progession (sum of nth term) last one answer
Sum of odd numbers n²..1-19 thereare 10 numbers 10²=100
This is the correct and easiest answer
The advic from a padippi do problems with easiest way 🎉!😏
N=xn-x1/d+1
19-1/2+1
=10
Sn=n/2(x1+xn)
=10/2(1+19)
=5×20
Ans:=100//
Answer is 100
Meanwhile normal class 10 student 😂
Saithama fan like
1+3+5+7+9+11+13+15+17+19
Aadyathe "n" Odd numbers nte sum=(n) ^2.
Here n=10
(n) ^2=100
Every one: doing calculation 😊
Meanwhile me : checking in the comments 😅
A= a + ( n-1) d
19= 1 + (n-1) 2
19-1=(n-1) 2
18/2=n-1
9=n-1
N=10
Be you own motivated
(n/2)*[2a+(n-1)d]
n = number of numbers
a= first number
d = common difference
നാളത്തെ exam A+ ഉറപ്പിച്ചു 💯 Thank you sirr❤️🙌🏻
Simple 100
Explanation :
1+19 =20
3+17=20
5+15=20
7+13=20
9+11=20
So 20×5=100
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Ithonnum padikathe high mark kittyvar like adii😜💯
All the best for onam exam👍🏻
100
Ans : stratosphere
❤❤❤
2n-1=19
N=10
Nsquare=100
N/2(x1+xn)
Where n=10
X1=1
Xn=19
10/2(1+19)
5*20
=100
Ingal USS Ratio eduth tharumo pls
1+3+5+7+9+11+13+15+17+19=100
The last one answer is 100
I got all the answers correct they are too basic for being 1%
(1+19)+(3+17)+(5+15)....(9+11) five times twenty=100
1+3+5+.…....….....+19
n=19+1=20/2
=10
n2=10square
=100
Count the numbers and find the square 1+3+5 +7+9+11+13+15+17+19=10^2=100
N/2×2a+n-1×d
bro didnt even touch basic algebra and said "Top 1% in maths" lol
(l-a)/d+1
(19-1)/2+1
10
odd number = n²
odd number = 10²
= 100
19+1/2
20/2
10^2
100
an = a + ( n - 1 ) × d
an = 19
a = 1
d = 2
19 = 1 + ( n - 1 ) × 2
19-1 = (n-1) × 2
18 /2 = (n-1)
9 =(n-1)
9 + 1 = n
10 = n
Sn=n/2(a+an)
=10/2(1+19)
=5(20
=5×20
=100
Mam adipolli class mam thanks ❤
n=19+1/2=10
Sum of odd no= n^2
.;. n^2= 10^2=100👆👆
Answer=100👍👍
Miss firstile randaamathe activity manassikunnillallo
100
All answers are right
190 is correct answer. Formula n(n+1)/2
Sn=n/2[2a+(n-1)×d] =100.
Ans=n×n+1/2= 19×20/2=190
10=n, n^2, 10^2=100
(2n+1)=n² (19+1)=20/2=10²=100
1+19= 20
n/2= 10/2=5
Ans=5*20= 100
ഇത് ശെരിയാണെങ്കിൽ എല്ലാം answer ഉം correct ആയി ☺️
Answer-190
S19=19/2(1+19)
=9.5×20=190
n/2 x (2a + (n-1) x d)
=
10/2 x (2x1 + (10-1) x 2)
=
5 x (2 + 9x2)
=
5 x (2 + 18)
=
5 x 20
=
100
29 is the answer
Nannayi manasilayi sir
1
A . 10
B. 38
S10=n/2(2A1+(n-1)d
S10=10/2(2(1)+(10-1)2)
S10=5(2+(9)2)
S10=5(20)
S10=100
Last question answer -100
100😊
1+3+..+19 is an odd sequence so use n×n so the answer is 361
Ellam seriyay 🔥🔥🔥, n^2 = 10^2 = 100
100 is the correct answer 😅
Sum of consecutive N odd no. = N`2
1+3+5+10+19=38🥰
Yes I am in top 1%😊
Arithmetic sequence 👀
Sum of odd no.s is n^2
n=10
10^2=100